Texas Geometry Staar Diagnostic Exam Hints and Study Guide

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  • 7/30/2019 Texas Geometry Staar Diagnostic Exam Hints and Study Guide

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    Draw in a segment connecting points X and Z.

    We know that for a triangle to be possible, any side

    length must be less than the sum of the other two

    sides. Imagine that XY and YZ both were 5 units long,

    then XZ would have to be less than 10 units long.

    Pg. 334

    XZ must be less than what?

    A counterexample disproves a conjecture/statement

    or makes it false. We need a counterexample where

    2 triangles have 2 pairs of sides that are congruent

    and a pair of non-included angles that are congruent.Remember non-included means notbetween.

    Pg. 242-255

    Ex:

    Statement: If it is the weekend, then it is Saturday.

    Counterexample: Sunday

    A deductive argument is an argument made from

    rules. You must pick out the valid argument. It will

    be helpful to look at the final sentence in eachanswer choice and determine which one is true.

    Pg. 88-90

    A Are all quadrilaterals parallelograms? Can you

    think of some quadrilaterals that are not

    parallelograms?

    B Do all polygons whose diagonals bisect each other

    have opposite sides that are parallel?

    C Are all rectangles squares?

    D Are all parallelograms quadrilaterals?

    For each figure, there is an angle that is inside thecircle but not at the center (central angle) or on the

    circle (inscribed angle). Look at the sum of the

    intercepted arcs for each figure. What relationship is

    there between the measure of an inside angle and

    the measure of its intercepted arcs?

    Pg. 783

    x =

    Remember: Dividing by two is the same as

    multiplying by

    X

    Y

    Z

    z yx C

    inside angle

    1

    2

    3

    4

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    Reflections look like two congruent images side by

    side in a mirror.

    Rotations look like two congruent images and one of

    the images has been turned.

    Translations look like two congruent images, but one

    of the images has been moved up or down/left orright.

    Pg. 824-841

    If you divide a 45-45-90 triangle in half it makes 2

    45-45-90 triangles. What is the length of the

    hypotenuse?

    Pg. 356

    When you make a horizontal cut, the resulting cross

    section is the same shape as the base but smaller.

    Pg. 656-657

    Square Pyramid Cone

    Cross section Cross Section

    Label each answer choice front, top, and side. Whichof the figures could not be one of these?

    Pg. 661-662

    Ex:

    45

    45

    45

    45

    45

    45

    45

    45

    10 ft.

    ???

    5

    6

    7

    8

    Top Front Right

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    Find the midpoint of segment RG. The equation will

    contain this point. Next, find the slope of segment

    RG. The perpendicular bisector should have a slope

    that is the opposite reciprocal of the slope of RG.

    Pg. 182-184

    Equations -

    Midpoint: (

    )

    Slope =

    (Convert meters to feet first!!)

    The shaded region is made up of two shapes: a

    trapezoid and a semicircle. The equation for area of

    a trapezoid:

    The equation for area of a semicircle is half the

    equation for the area of a circle:

    Pg. 606-607

    Draw the quadrilateral. Since segment AB and CD

    are parallel but not congruent and A B, yourfigure should look something like this:

    Pg. 429

    Since one side and one angle are congruent

    on the triangles, you need another pair of

    congruent sides or angles to prove thetriangles are congruent by one of the

    following congruence theorems:

    SAS (Side-Angle-Side)

    AAS (Angle-Angle-Side)

    ASA (Angle-Side-Angle)

    SSS (Side-Side-Side)

    HL (Hypotenuse-Leg)

    Pg. 242-252

    SAS AAS ASA

    SSS HL

    r = ?

    h

    9

    10

    11

    12

    A B

    CD

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    Which trig. function compares the opposite

    side (height of tree) to the adjacent side

    (length of trees shadow)?

    Pg. 525

    Sine of =

    Cosine of =

    Tangent of =

    Some old hippie

    What is the similarity ratio for these solids if the

    dimensions of the larger solid are double that of the

    smaller solid?

    Once you find the similarity ratio how do you find the

    area ratio and volume ratio?

    Pg. 700 (ex 4)

    Segment BC will be perpendicular to segment AB

    because adjacent sides of a square are perpendicular

    (all angles are 90).

    Remember: perpendicular lines have slopes that are

    opposite reciprocals.

    Pg. 184

    Mark the diagram with the givens and all the

    statements. What things are congruent on

    the triangles?Here are the rules to prove triangles are

    congruent:

    SAS (Side-Angle-Side)

    AAS (Angle-Angle-Side)

    ASA (Angle-Side-Angle)

    SSS (Side-Side-Side)

    HL (Hypotenuse-Leg)

    Pg. 242-252

    SAS AAS ASA

    SSS HL

    50

    Opposite

    side

    Adjacent

    side

    Similarity

    Ratio

    Area

    Ratio

    Volume

    Ratio

    3

    3

    13

    14

    15

    16

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    Mark the givens on the diagram. You have a side and

    an angle that are congruent. If you have another

    side, you can use SAS (Side-Angle-Side) as long as the

    congruent angles are included or between the

    congruent sides.

    Pg. 242-252

    Ex:

    Similar triangles have congruent angles and

    corresponding sides that are proportional.

    There are 3 ways to prove triangles are

    similar:

    AA (Angle-Angle)

    SSS (Side-Side-Side)

    SAS (Side-Angle-Side)

    Pg. 470-473

    AA

    SSS

    SAS

    For a triangle to be possible, any side length must be

    greater than the sum of the other two sides. If oneside is 15 the sum of the other two sides must be

    greater than 15.

    Pg. 334

    Ex:

    To find the probability that a point will be randomlychosen in a certain area, find the area of the region

    of success and divide it by the total area.

    Pg. 630-633

    Side

    Angle

    Side

    Angle

    SideSide

    17

    18

    19

    20

    5 10

    3 6

    4 8

    365

    10

    A

    B

    C

    8 5

    11

    8 + 5 > 11

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    If mGLK = 55, what is the mJKL? When lines are

    parallel, alternate interior angles are congruent.

    If mEFJ = 120, what is the measure of the angle

    adjacent or right next to it?

    Pg. 155-157

    Ex:

    The equation for circumference of a circle is

    2 times pi times the radius (C = 2r). Youare given the circumference; find the radius

    by solving backwards (plug in what you

    know, to find what you dont know). Once

    you find the radius, you should be able tofind the side length of the square fence and

    then the perimeter.

    The ratio of the side lengths is the same as

    the ratio of the perimeters. Find the

    perimeter ofABC. What is the ratio ofthe perimeters of the two triangles? Once

    you find the ratio of the perimeters, youll

    need to set up a proportion to solve for the

    shortest side ofDEF.

    Pg. 470-473

    If the diameter = 10, what is the radius? Theequation for surface area of a cylinder is:

    Surface Area (SA) = LA + 2B = 2rh + 2r2

    Pg. 681-682

    A

    B

    C

    8 5

    11

    Perimeter = ?

    D

    E

    F

    Perimeter = 60

    x = ?

    21

    22

    23

    24

    60

    60

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    Drop an altitude like its hot, drop it like its

    hot, drop it like its hot

    Use the Pythagorean theorem to find the

    height of the triangle. The area =

    Find the missing side of the triangular base

    and then add up the sides to get P (the

    perimeterof the base). The equation for

    surface area of a prism is:

    Surface Area (SA) = LA + 2B = Ph + 2B

    B = area of the base (remember: the base is a

    triangle!)

    h (height) = distance between the bases

    Pg. 681-682

    Use the equation for area of a circle (A = r2) to findthe radius by solving backwards (plug in what you

    know, to find what you dont know). The perimeter

    of the sector (pie slice) has two sides that are radii.

    To find the arc length use this equation:

    Arc Length = ( 3) [x = the central angle]

    Pg. 764-766

    There are 2 similar triangles formed by the

    intersecting roads -- a big and a little one.

    Pg. 470-473

    36

    18

    ?

    18

    36

    36

    radius

    radius

    arc length

    1st

    St 2nd

    St 3rd

    StKyle St 500 ft 375 ft

    375 ft.x ft.

    875 ft.(x +650)

    375 ft500 ft

    25

    26

    27

    28

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    The longest side of the triangle is across from the

    largest angle and the shortest side is across from the

    smallest angle.

    Pg. 333

    Do supplementary angles always form a

    linear pair?

    Angles 1 & 2 are both 90 and aresupplementary but they are not a linear pair.

    If angles 1 & 2 are supplementary, does it

    mean they are congruent?

    The equation for volume is:

    V = Bh (B = area of the base)

    Make the 8 x 12 rectangle your base. Find the

    volume of the original flower box, and then find the

    volume using the new length of 24 inches.

    Pg. 697-698

    Find the difference in the number of dots in each

    figure. How much does it go up by from the first

    figure to the second figure? From the second figure

    to the third figure?

    Pg. 74-77

    1

    2

    1 5 11

    +4 +6

    ?

    +?

    29

    30

    31

    32

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    The equation of a line can be written in

    slope-intercept form:

    y = mx + b

    Where m is the slope and b is the y-intercept.

    Perpendicular lines have slopes that areopposite reciprocals. The slope of line m is 7.

    What will the slope of line n be? To find the

    y-intercept plug in the x and y values of the

    point provided and solve for b. (Pg. 184)

    The house and garage together have a length of 13.5

    inches in the outline. 1.5 inches = 14 ft.

    DBR is an inscribed angle. An inscribed angle is half

    the intercepted arc. What is the measure of arc DR?

    mDAR is a central angle. A central angle and the

    intercepted arc have the same measure.

    Pg. 772-773

    z = or y = 2z

    The key to this problem is drawing a correct

    diagram and then using the Pythagorean

    theorem to find the sides of the rhombus.

    12

    5

    5

    12

    ?

    33

    34

    35 y

    z

    5

    12

    36

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    The midsegment of a trapezoid is equal to the sum of

    the bases, divided by 2. The bases are segments RA

    and TP.

    Pg. 431

    The intersection forms a 45-45-90 triangle.

    Pg. 356-358

    Ex: To go from leg to hypotenuse multiply by .

    Since a tessellation is a tiling of shapes with no gaps,

    the angles where the tiles meet add up to 360.

    Pg. 863-864

    Things to remember about tessellations:

    - Triangles, quadrilaterals, and regularhexagons always tessellate

    - The sum of the angles at any vertex is 360

    To write a contrapositive statement you must flip

    and negate the hypothesis and conclusion of the

    original conditional statement.

    Pg. 81-83

    Converse flip the hypothesis and conclusion

    Inverse negate the hypothesis and conclusion

    Contrapositive flip and negate the hypothesis and

    conclusion

    x

    45

    x

    45

    Hypotenuse

    Legs 45

    2

    Multiply

    by

    45

    37

    38

    39

    40

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    2 planes perpendicular to the same line are parallel.

    The triangle is isosceles if the distance between

    points A & C and points B & C are equal.

    Use the distance formula:

    Pg. 43-44

    A(-1,0) and B(4,-3)

    Use the distance formula:

    Pg. 43-44

    First, find one interior angle of the regular

    hexagon. To do this, youll need to find thesum of the interior angles and divide by the

    number of angles.

    Sum of interior angles = (n - 2)180

    Once you find the interior angle of the

    hexagon, you can solve for x.

    Pg. 382-385

    x

    y

    B(5, 6)

    C (x, y)

    A (4, 5)

    41

    42

    43

    44

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    Volume of a rectangular prism:

    V = Bh (B is area of the base)

    Since the base is a rectangle, B = Length x

    Width.

    ThereforeVolume = length x width x height

    If the tank is full, you will have the

    volume. Multiply your volume byto get

    the volume of the tank when it isfull.

    The truck bed forms a 30-60-90 triangle.

    Pg. 356-358

    Ex: Hypotenuse to short leg

    Solve for a by using the Pythagorean theorem. The

    side lengths must be some multiple of a Pythagoreantriple. Find the greatest common factor of each side,

    and then divide each side by it to find what

    Pythagorean triple is related.

    Pg. 348-350

    Common Pythagorean Triples

    Triples Multiples3-4-5 6-8-10, 9-12-15, 12-16-20, 15-20-255-12-13 10-24-26, 15, 36, 397-24-25 14-48-50, 21, 72, 758-15-17 16-30-34, 24-45-519-40-41 18-80-82, 27-120-123

    Properties of Rectangles:

    -Opposite sides are parallel and congruent-Diagonals bisect each other

    -Diagonals are congruent

    -Angles are 90

    Pg. 418-420

    2x

    60

    x

    30

    Short leg

    HypotenuseLong leg

    40

    60

    20

    30

    Divide

    by 2

    45

    46

    47

    48

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    There are 3 ways to prove triangles are

    similar:

    AA (Angle-Angle)

    SSS (Side-Side-Side)

    SAS (Side-Angle-Side)

    Which one of the answer choices has 2 sidesthat are proportional and an included angle

    that is congruent to the originals triangle?

    Pg. 470-473

    The 35 angle is an angle of elevation.

    Pg. 544-546

    Sine of =

    Cosine of =

    Tangent of =

    Some old hippie

    The equation for surface area of a prism is:

    Surface Area (SA) = Ph + 2B

    Choose the bottom rectangle (2 x 1.5) to be

    your base. What is P (the perimeter of the

    base)? What is B (the area of your base)?

    Pg. 681-682

    Here are the rules to prove triangles are

    congruent:

    SSS (Side-Side-Side)

    SAS (Side-Angle-Side)

    AAS (Angle-Angle-Side)

    ASA (Angle-Side-Angle)

    HL (Hypotenuse-Leg)

    Pg. 242-252

    SAS AAS ASA

    SSS HL

    35

    Opposite side

    (height)

    Hypotenuse

    (rope)

    49

    50

    51

    52

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