Test Item Specification

8/7/2019 Test Item Specification

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TEST ITEM SPECIFICATION

Level of Study : Senior High School

Subject : PhysicsGrade/Semester : X/II

Topic : Electrodynamics

Standard of Competence : 5. Applying concept of electricity in many problem solving and various technological products.

Basic Competence : 5.1 Formulate electric quantities in simple closed circuit (one loop).

Indicator Learning Objective No. Question

Domains /

Cognitive

Level

Answer

KeyScore

Describing

definition of

electric current

and electric

voltage.

Explain the concept of

electric current.

1.

2.

3.

Electric current flows ....

a.From the higher to lower potentialb.From the lower to higher potentialc.From the higher to lower resistanced.From the lower to higher resistancee.From the switch to the voltage source

The direction of conventional current in a circuit is .

a.In line with the electronb.Clockwisec.Against the electrond.Antirclockwisee.In line with the proton

Electric current is defined as .

a.The amount of electrical charge which flows in aconductor per unit time

b.The amount electric charge that flows in a conductor

C1

C1

C2

a

e

a

1

1

2


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Cognitive

Level

Answer

KeyScore

Determining the

relationship

Explain the concept of

electric voltage.

Determine the

relationship between

4.

5.

6.

7.

c.Electric charge that flow from high to low potentiald.Electric charge that flow from low to high potentiale.Divide results for electric charge with the distance

The relationship between the electric current and other quantities

are as follows, except.a.Inverse with resistanceb.Inverse with timec.Proportional with potential differenced.Proportional with electric chargee.Proportional with time

Mathematical equation of the potential difference is .

a.V = I.P d. RIV b. tQV e. V = W.Qc. QWV

The unit of potential difference is .

a.Ohm d. Coulombb.Volt e. Amperec.Watt

The following statements are true is .

a.Electric currents flow in a conductor proportional to the

C2

C1

C1

C2

e

c

b

a

2

1

1

2


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Domains /

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Level

Answer

KeyScore

between electric

current withelectric voltage.

electric current with

electric voltage.

8.

9.

potential difference between the ends of conductor

b.Electric currents flow in a conductor is inverse to thepotential difference between the ends of conductor

c.Electric currents flow in a conductor with a potentialdifference between the ends of conductor

d.Electric currents flow in a conductor is always greater thanthe potential difference between the ends of conductor

e.Electric currents flow in a conductor is always smallerthan with the potential difference between the ends of

conductor

It is known table the potential difference measurements and

electric current below:

No V (volt) I (ampere)

1 1,40 0,07

2 2,90 0,14

3 4,25 0,21

Where: R (Ohm) = 20

Base on table above, the relationship between V, I, and R is .

a.The value of I is proportional to R and inverse to Vb.The value of V is proportional to R and inverse to Ic.The value of I is proportional to V and inverse to Rd.The value of R is proportional to I and Ve.The value of I is proportional to R and V

The relation between potential difference (V) between the ends ofconductor with electric current (I) through conductor with

C4

C4

c

c

4

4


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KeyScore

10.

constant resistance (R) expressed by the graph of the number .

a.(1) d. (4)b.(2) e. (5)c.(3)

Four identical elements arranged to light a lamp

C4

a

4

(1)

V

I

(2)

V

I(3)

V

I

(5)

V

I

(4)

V

I

(1) (2)


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11.

The lamp are the brightest flame on the circuit .

a.(1) d. (4)b.(2) e. (5)c.(3)

The list below states the relationship between I, V and R

V (volt) R (Ohm) I (ampere)

2 4 0,50

2 8 0,25

2 10 0,20

From the list can be concluded that electric current .

a.Proportional with resistanceb.Proportional with voltagec.Inverse with resistanced.Inverse with voltagee.Proportional with the resistance and voltage

C4

c

4

(4) (5)(3)


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KeyScore

Applying Ohm'sLaw concept in

solving various

problems in daily

life.

Formulate Ohm's Law

equation.

Apply Ohm's Lawconcept in solving

various problems in

daily life.

12.

13.

14.

15.

From the experimental result, voltage relationship (V) with

electric currents (I) on the resistor, the resulting graph ofV-Iinthe picture below. IfV = 4,5 volts, the large currents flowing is.

a.5 mAb.10 mAc.20 mAd.30 mAe.35 mA

Ohm's law can be expressed in the form of equation .

a.I = V2. R d. I = Q . tb. RVI e. 2R

VI

c. VRI

An electrical instrument has resistance of 60 ohm passed an

electric current 0,5 A. Potential difference is .

a.120 volt d. 1/30 voltb.60 volt e. 1/120c.30 volt

Conductor given a 14 volt potential difference at its ends. Electric

current that flow on the conductor is 2 A. The resistance ofconductor is .

C4

C1

C3

C3

d

b

c

a

4

1

3

3

0,02

V (volt)

I (ampere)

3


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16.

17.

18.

19.

a.7 d. 24

b.12 e. 30 c.14

In an electrical resistance, when given a voltage 40 volts and flow

electric current 120 mA. Voltage at the resistance if by flowedelectric current 0,6 A is .

a.100 volt d. 400 voltb.200 volt e. 500 voltc.300 volt

A motorcycles accumulator give electric currents 2,5 mA at a

circuit where there is a resistor 4,4 x 103. The voltageaccumulator is .


The potential difference that must be given at the ends of a wirethat has resistance 2 and the electric current 12 A flowing

through the wire is .


A wire has a resistance 0,4 given the potential difference 200

mV at its ends. The electric current flowing on the wire is .

C4

C3

C3

C3

b

a

d

b

4

3

3

3


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KeyScore

Discribing the

factors that affect

the resistance ofconductor wire.

Explain the factors

that affect the

resistance ofconductor wire.

20.

21.

22.

a.

1/50 A d. 50 A

b.0,5 A e. 500 Ac.5 A

Electric heater required 5 A if it is connected to 110 V. The value

of resistance is .a.0,05 d. 110 b.5 e. 550 c.22

This following are the factors of determine the resistance of a

conductor, except.

a.Cross-sectional area of conductorb.Density of conductorc.Temperature of konductord.Length of conductore.Type of conductor

Resistance wire electricity networks will increase in daylight,because:

(1) The wire becomes longer

(2) Electric current decreases during the day

(3) Resistivity of wire is increase

(4) Cross-sectional area of wire enlarge

The statement is true .

a.(1), (2) and (3) d. (4)b.(1) and (4) e. All

C3

C2

C4

c

b

b

3

2

4


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Answer

KeyScore

Determine the

relationship betweenlength and cross-

sectional area of wirewith the resistance of

conductor wire.

23.

24.

25.

c.

(2) and (3)

A copper wire has a resistance R. Another copper wire has weighs

the same but the diameter is twice the original copper wire.Resistance to this copper wire is .

a.R d. 1/8Rb.1/2R e. 1/16Rc.1/4R

The table below as the results of experiments from five types of

wire that have the same resistivity.

Based on the table above, the wire which has the largestresistance of wire is .

a.(1) d. (4)b.(2) e. (5)c.(3)

If a piece of wire is divided into four sections of the same length,

then the resistance of each part equals .

a. times of the first resistance

Wire Length Section Area(1)

(2)

(3)

(4)

(5)

l

2l

0,5l

0,2l

5l

A

A

3A

2A

0,5A

C4

C3

C3

b

e

e

4

3

3


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KeyScore

26.

27.

b.

times of the first resistance

c. times of the first resistanced.2 times of the first resistancee.4 times of the first resistance

The figure below shows three copper conductors with cross-sectional area and length as shown.

If the ends of the three conductors are given the same voltage (V),

the electric current flowing through a conductor is .

a.(1) > (2) > (3) d. (1) = (2) < (3)b.(2) > (1) > (3) e. (1) = (3) > (2)c.(3) = (2) > (1)

A wire has electrical resistance 2 . This wire is then pulled up

without changing the volume, temperature, and resistivity, so that

its diameter is become reduced half its original value. Now, the

resistance of wire right .

a.2 d. 16b.4 e. 32c.8

C5

C3

e

b

5

3

L

A

(1)

1,5 L

A/2

(2)

L/2

A/2

(3)


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Domains /

Cognitive

Level

Answer

KeyScore

Determine the

relationship material

type of wire with the

resistance of

conductor wire.

28.

29.

30.

A piece of metal wires 60 pull up to the length to one half times

the length originally. New resistance would be .a.60 d. 90 b.70 e. 100 c.80

It is known that the resistivity conductor material type as follows:

1. Iron 0,0038

2. Aluminium 0,0040

3. Tungsten 0,0045

4. Copper 0,0039

5. Silicon -0,0700

We will get the biggest resistance, the material choosen as a good

conductor is .

a.Iron d. Copperb.Aluminum e. Siliconc.Tungsten

The sequence of the resistivity below from the smallest to the

largest is .

a.

Conductor, semiconductor, isolator

b.Conductor, isolator, semiconductorc.Isolator, semiconductor, conductord.Isolator, conductor, semiconductore.Semiconductor, isolator, conductor

C3

C2

C2

d

c

a

3

2

2


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Level

Answer

KeyScore

Determining the

resistance of a

conductor wire.

Describing theKirchhoffs First

Law.

Determine the

resistance of a

conductor wire.

Describe theKirchhoffs First Law.

31.

32.

33.

34.

A wire has a resistance 30 ohm. If the wire length 1 m and cross-

sectional area 0,4 mm2

. The resistivity of wire is .( = 3,14) a.1,2 .mm2/m d. 12.mmb.1,2 .m e. 12.mc.12 .mm2/m

The length of conductor is 10 m, with a diameter 2 mm. The wire

has a resistance type of 3,14 x 10-5

.m. The resistance of wire is

.( = 3,14)

a.60 d. 90 b.70 e. 100 c.80

Sum of electric current entering a node point is equal to sum

electric current leaving that node point.This statement is known.

a.Electric currents lawb.Ohms lawc.Kirchhoffs first lawd.Kirchhoffs second law e.Sum of electric currents law

Consider the picture below:

The correct statement to say a magnitude electric current of flow

is .

C3

C3

C1

C2

c

e

c

e

3

3

1

2

I1

I2

I3

I4


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35.

36.

a.

I1 = I2 + I3 + I4 d. I1 + I4 = I2+ I3

b.I1 = I2 + I3 - I4 e. I1 = I2 + I3 = I4c.I1 + I2 = I3 + I4

From the circuit above, the magnitude and direction of electric

current of X is.a.3,5 A enter branch pointb.4,5 A exit branch pointc.4,5 A enter branch pointd.7,5 A exit branch pointe.7,5 A enter branch point

Consider the circuit figure below!

Electric current in the I3 is.

a.1 A d. 6 A

C3

C3

e

b

3

3

5 A

9 A

2 A

1,5 A

X

I= 12

I1 = 2 I2 A

I2 = 3 A

I3 = ? BA


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Answer

KeyScore

Describing theseries and

parallel circuit.

Explain thecharacteristics of

series and parallelcircuit.

37.

38.

39.

b.

3 A e. 9 A

c.4 A

If there is resistance R1, R2 and R3 is connected series, then the

formula to determine the resistance equivalent of true is .

a.R1 + R2 + R3 d. R1 : R2 : R3b.R1 - R2 - R3 e. 1/R1 + 1/R2 + 1/R3c.R1 x R2 x R3

If there is resistance R1, R2 and R3 is connected parallel, then the

formula to determine the resistance equivalent of true is .

a.R1 + R2 + R3 d. R1 : R2 : R3b.R1 - R2 - R3 e. 1/R1 + 1/R2 + 1/R3 c.R1 x R2 x R3

Which shows the characteristics of the parallel circuit is .a.The resistance equivalent always smaller than the smallest

resistance

b.The resistance equivalent always smaller than the largestresistance

c.The resistance equivalent always larger than the smallestresistance

d.The resistance equivalent always larger than the largestresistancee.The resistance equivalent equals with total every smaller

resistance

C1

C1

C5

a

e

b

1

1

5


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Level

Answer

KeyScore

Distinguish series and

parallel circuit.

40.

41.

42.

Resistance equivalent from a circuit of compose three resistor of 2

probable cannot has value is .a.2/3 d. 3 b.4/3 e. 6 c.1,5

The figure below shows the same four resistors are connected in a

square. If this arrangement is connected to a circuit, this

arrangement will give the smallest resistance if a connection is

made at the ends .

a.P and Qb.Q and Rc.R and Sd.S and Pe.Q and S

Consider the circuit below!

Lamp L1 and L2 is installed parallel and connected with a battery

possibility of the lamp L1 and L2 will occur as follows:

a.If L1 switch off than L2 is turn offb.If L2 switch off than L1 is turn off

C4

C4

C4

c

e

c

4

4

4

R

L1

L2

QP

RS


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Level

Answer

KeyScore

Determine thestrength of

current, voltage

and total

resistance in

series and

parallel circuit.

Determine thestrength of current,

voltage and total

resistance in series

and parallel circuit.

43.

44.

45.

c.If L1 switch off than L2 is turn ond.L1 and L2 turn on and are getting lightere.L1 and L2 are turn off and are switch on

Lamps A, B, C and E, if lamp A off, hence.

a.Fourth lamp are turn onb.Only lamp B, D and E which are turn onc.Only lamp C, D dan E which are turn ond.Only lamp D dan E which are turn one.Fourth lamp are turn off

The value of resistance equivalent according circuit above is .

a.1,3 d. 36b.4 e. 60c.12

The value of resistance equivalent from circuit the below is .

a.1

C5

C3

C3

c

c

a

5

3

3

5 4 3

A B

C

DE


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KeyScore

46.

47.

48.

b.3 c.6 d.12 e.36

The value of resistance between A and B are .

a.10 b.16 c.25 d.80 e.100

Consider a resistance circuit at picture the below! The resistance

equivalent from five resistors are .

a.10 b.16 c.20 d.25 e.100

To picture circuit the below be known, R1= 9 , R2= 6 , R3= 3

, and R4= 2 . The resistance equivalent is .

a.10 b.15 c.20

C3

C3

C3

b

a

a

3

3

3

6

3

5 2 1

20 30

40 10

B

A C

D

3

6

2


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49.

50.

d.25 e.30

If electrical resistance is measured between point A and point B inthe circuit below, so the value will be obtained is .

a.6 b.8 c.10 d.12 e.16

Consider the following circuit!

The potential defference between P and Q is .

a.5 V d. 30 Vb.10 V e. 40 Vc.20 V

C3

C3

b

a

3

3

P

Q

10 V

20

20

2

6

2

2

2

2

2

2

4

2

A

B

R1

R2R3

R4

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