Teaching trigonometry
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Transcript of Teaching trigonometry
Erlina R. RondaUP NISMED
Teaching trigonometry through problem solvingAn introductory lesson on tangent and cotangent
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How would you determine the width of a river if you cannot measure it directly? You cannot cross the other side, too, but you have with you a meterstick and a big protractor.
PROBLEM
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Solution 1: using 45-degree angle
river
x = k
x
k45o
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Solution 2: congruent triangles
river
mo
mo
k
b
x
x = b
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Solution 3: using 60 or 30-degree angle
river x
k
60o
3kx
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Solution 4: similar triangle, geometric mean
riverx
ka
x
a
k
x
mo90o - mo
akx 2
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Solution 5: similar triangle
riverx
k ab
b
a
k
x
mo
b
akx
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Solution 6: similar triangle
riverx
k
a
b
b
a
k
x
mo
mo
b
akx
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Questions for discussion
1) Which solution do you like most? Like least? WHY?
2) What quantities are involved in the solutions?
3) Which quantities are related as
function?
4) How can other cases be generated for this function?
5) What are other ways of representing this function?
Through use of grid and protractor, students can get the value of the ratios
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38.06
540
40o
2.15
650
Relationship 1: angle →opp/adj
2.15
640
38.06
550
Relationship 2: angle →adj/opp
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Table of valuesAngles(in degrees)
30 40 45 50 60
Value of the ratio of opp/adj
0.58 0.84 1.0 1.19 1.73
Value of the ratio of adj/opp
1.73 1.19 1.0 0.84 0.58
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Going back to the initial problem …
• How will you use the idea of the ratio of the shorter sides in a right triangle to solve the problem about the width of the river?
• How does this solution compare with the one using similar triangles?
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Let g: x →
This mapping is called the
cotangent function. It is
defined by the equation
cotangent x = g(x)
or cotangent x = .
Given rtΔABC. Let A = xo
side opposite A = a;side adjacent to A = b.
Let f: x →
This mapping is called the tangent function. It isdefined by the equation
tangent x = f(x)
or tangent x = .
A
B
C
a
b
xo
b
a
b
a
a
b
a
b