TCS Aptitude Test 1

Question No : 1If the word 'ddosszm' is changed to 'central' then what will be the change for 'rtjbl' ?A. manual

B. quick

C. jump

D. life

ExplanationDiscuss the solutionChanges happening to letters in the pattern -1 +1 -1 ...So rtjbl will become quickQuestion No : 2What is the largest prime number in 8 digit number?A. 251

B. 253

C. 251

D. 257

ExplanationDiscuss the solutionLargest number that you can store in 8bit memory is 255. The largest prime below 255 is 251Question No : 3The word unimpressive was given. They asked us to do change 1st & 2nd,3rd & 4th,so on. Then they asked what will be 10th letter from right?A. L

B. M

C. N

D. O

ExplanationDiscuss the solutionAnswer is MQuestion No : 4g[0]=1,g[1]=-1,g[n]=2*g[n-1]-3*g[n-2] then calculate g[4]= ?A. 1

B. -1

C. 2

D. -2

ExplanationDiscuss the solutiong[4] = 2 * g[3] - 3*g[2]........On expanding like this ans substituting final values you will get result as 1Question No : 5Complete the series : 5,6,7,8,10,11,14,..?A. 17

B. 15

C. 14

D. 17

ExplanationDiscuss the solutionPattern is a3-a1 = 2a4-a2 = 2a5-a3 = 3a6-a4 = 3a7-a5 = 4a8-a6 = 4So the next number in series : 15Question No : 6A man,a woman and a boy finish work together in 6 days.man takes 10 days,woman takes 24 days then how much boy will take?A. 30 days

B. 40 days

C. 20 days

D. 35 days

ExplanationDiscuss the solutionTotal work = 1/6Hence work done by boy = 1/6 - (1/10+1/24) = 1/40Time taken by boy = 40 DaysQuestion No : 7The matrix of a(7,9) was given. The address of the first byte of a(1,1)=1258. It takes 4 bytes to store the nuymber.Then calculate the address of the last byte of a(5,8). [Assume row major form]A. 1434

B. 1433

C. 1473

D. 1474

ExplanationDiscuss the solutionIn column address increments by (8x4+4)36=column-gapIn row address increments by 4=row-gapSoaddress of (5,8) element (4 clmn-gaps & 7 row-gaps )=1258+4x36+4x7=1430address of last byte=[1430,1431,1432,1433]Ans 1433Question No : 8The program requires 4000(n)1/2 [ie square root of n]. If size of program was increased by 1% then calculate the percentage change in size of program.A. 0.4968%

B. 0.4688%

C. 0.4988%

D. 0.4686%

ExplanationDiscuss the solutionIf n is increased by 1% then the program increases by 0.4988%. (0.4988% is the difference between the square root of 1 and the square root of 1.01)Question No : 9modulo(373,7) + round(5.8) + truncat(7.2) - round(3.4) = ?A. 10

B. 12

C. 18

D. 20

ExplanationDiscuss the solution373/7 will give remainder = 2round(5.8) will give = 6Truncate 7.2 gives 7round(3.4) = 3

Answer is 2 + 6 + 7 - 3 = 12Question No : 10If VXUPLVH is written as SURMISE, what is SHDVD ?A. PEAFG

B. PEASA

C. CCASA

D. NMASA

ExplanationDiscuss the solutionhint: in the first word, the alphabets of the jumbled one is three alphabets after the corresponding alphabet in the word SURMISE. S = V-3, similarly find the one for SHDVDQuestion No : 11If DDMUQZM is coded as CENTRAL then RBDJK can be coded as ---------A. QCEIO

B. FCEIL

C. QCEIL

D. QCESF

ExplanationDiscuss the solutionhint: Write both the jumbled and the coded word as a table, find the relation between the corresponding words, i.e C= D-1, N=M+1 & so onQuestion No : 12In the word ECONOMETRICS, if the first and second , third and forth ,forth and fifth, fifth and sixth words are interchanged up to the last letter, what would be the tenth letter from right?A. D

B. S

C. N

D. J

ExplanationDiscuss the solutionWord is CENOMOTEIRSC tenth word is NQuestion No : 13Find the result of the following expression if, M denotes modulus operation, R denotes round-off, T denotes truncation: M(373,5)+R(3.4)+T(7.7)+R(5.8)A. 22

B. 12

C. 44

D. 19

ExplanationDiscuss the solutionModulus gives a remainder: M(373,5) = 3, since 5*74 = 370

Rounding rounds to the nearest integer:so R(3.4) = 3, and R(5.8) = 6

and Truncation 'rounds' to an integer by removing any decimal fractions,

so T(7.7) = 7

adding the answers above gives 3+3+6+7 = 19Question No : 14Find the physical quantity in units from the equation: (Force*Distance)/(Velocity*Velocity)A. Ns2/cm

B. Ns/m

C. Ns2/m

D. Ns2

ExplanationDiscuss the solutionSolution not available right now. Please check in the discussion page. Question No : 15Find the value of @@+25-++@16, where @ denotes "square" and + denotes "square root".A. 621

B. 567

C. 234

D. 921

ExplanationDiscuss the solution(@@sqrt(25))-(++square(16))(@@5)-(++256)(@25)-(+16)(625)-4621Question No : 16If f(0)=1 and f(n)= f(n-1)*n, find the value of f(4).A. 25

B. 24

C. 23

D. 22

ExplanationDiscuss the solutionf(4)=f(3)*4=f(2)*3*4=f(1)*2*3*4=f(0)*1*2*3*4=1*1*2*3*4 (since f(0)=1)=24Question No : 17Convert the decimal number 310 to the base 6.A. 1272

B. 1267

C. 1246

D. 1234

ExplanationDiscuss the solution1234Question No : 18Find the missing number in the series: 2, 5,__ , 19 , 37, 75A. 6

B. 7

C. 8

D. 9

ExplanationDiscuss the solution99 * 2 + 1 = 19..

Question No : 19In a two-dimensional array, X(9,7), with each element occupying 4 bytes of memory, with the address of the first element X(1,1) is 3000, find the address of X(8,5).A. 3212

B. 3196

C. 3168

D. 3216

ExplanationDiscuss the solutionUse the formulaeX(i,j)=Base+w[N(i-1)+(j-1)]where m=9 ,n =7 ,i=8 ,j=5hence 3000+4*[7(8-1)+(5-1)]=3000+4*(49+4)=3000+53*4=3212Question No : 20Find the fourth row, having the bit pattern as an integer in an 8-bit computer, and express the answer in its decimal value.A 0 0 0 0 1 1 1 1B 0 0 1 1 0 0 1 1C 0 1 0 1 0 1 0 1(AU(B-C)) ?A. 28

B. 29

C. 30

D. 31

ExplanationDiscuss the solutionSolution not available right now. Please check in the discussion page. Question No : 21Complete the series 2, 7, 24, 77,__A. 220

B. 240

C. 260

D. 280

ExplanationDiscuss the solution(hint: 2*12= 24, 7*11= 77, therefore 24*10= 240)Question No : 22If the vertex (5,7) is placed in the memory. First vertex (1,1) ?s address is 1245 and then address of (5,7) is ----------A. 1269

B. 1358

C. 1129

D. 1279

ExplanationDiscuss the solutionThat means there are maximum of 5 rows and 7 columns.Total is 5 * 7 = 35 cells.Let us consider defaultly each cell has one value in increasing order, ( "But to replace the cells(N) with numbers(Address) use N-1 because, no.s between start and end point is total-1 values. " )Then at (5,7) after (1,1) in 1245 is (35-1) * 1=34 more.ie., 1245 + 34 = 1279Question No : 23In Madras , temperature at noon varies according to -t^2/2 + 8t + 3, where t is elapsed time. Find how much temperature more or less in 4pm to 9pm.A. 7.5

B. 8.4

C. 34.5

D. 27

ExplanationDiscuss the solutionSubstitute t=4 in the equation and you will get 27Next substitute t=9 then you will get 34.5So the anwer is 34.5 - 27 = 7.5Question No : 24The size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a program to receiver. There it waits for 10 milliseconds. And response will be back to programmer in 20 milliseconds. How much time the program takes to get a response back to the programmer, after it is sent?A. 30

B. 35

C. 55

D. 50

ExplanationDiscuss the solutionAfter reaching program it waits there for 10ms and back to the programmer in 20 ms.then total time to get the response is 20ms + 10 ms = 30msQuestion No : 25The size of a program is N. And the memory occupied by the program is given by M = square root of 100N. If the size of the program is increased by 1%then how much memory now occupied ?A. SQRT(200N)

B. SQRT(101N)

C. SQRT(111N)

D. SQRT(102N)

ExplanationDiscuss the solutionBefore Increase: M = SQRT(100 x 1N)After Increase: M = SQRT(100 x 1.01N) => SQRT(101N)Question No : 26A power unit is there by the bank of the river of 750 meters width. A cable is made from power unit to power a plant opposite to that of the river and1500mts away from the power unit. The cost of the cable below water is Rs. 15/- per meter and cost of cable on the bank is Rs.12/- per meter. Find the totalof laying the cable.A. 22,300

B. 22,400

C. 22,500

D. 22,600

ExplanationDiscuss the solution(hint: the plantis on the other side of the plant i.e. it is not onthe same side as the river)Question No : 27If A can copy 50 pages in 10 hours and A and B together can copy 70 pages in 10 hours, how much time does B takes to copy 26 pages?A. 11

B. 12

C. 13

D. 14

ExplanationDiscuss the solutionIf A takes 10 hrs for 50 pagesA and B takes 10 hrs for 70 pagesmeans in 10 hrs B can print 20 pages

for 20 pages 10 hrsthen 26 print 26*10/20=13 hrsQuestion No : 28Two stations A & B are 110 km apart. One train starts from A at 7 am, and travels towards B at 20kmph. Another train starts from B at 8 am andtravels towards A at 25kmph. At what time will they meet?A. 9am

B. 10am

C. 11am

D. 10.30am

ExplanationDiscuss the solutionLet T=x hrsA-->Distance = 20xKmB-->Distance = 25(x-1)km[because diff(7,8) is 1]20x+25(x-1) = 110km then x=3hrso 7am+3hr = 10am.Question No : 29If a man can swim downstream at 6kmph and upstream at 2kmph, his speed in still water is:A. 4

B. 8

C. 3

D. 6

ExplanationDiscuss the solutionSpeed in still water = (speed in upstream + speed in downstream) / 2(6 + 2 ) / 2 = 4

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