Task 1Problem 1IP address>172.25.114.250Net Mask>255.255.0.0(/16)Find

1.Network addressIP Address172.25.114.25010101100000110010111001011111010

Subnet Mask255.255.0.011111111111111110000000000000000

Network Address172.25.0.010101100000110010000000000000000

How to get the binary number for IP Address

17225114250

172/2 = 0

86/2 = 0

43/2 = 1

21/2 = 1

10/2 = 0

5/2 = 12/2 = 0 = 1

25/2=1

12/2=0

6/2=0

3/2=1

1/2=1

0/2=0

0/2=0

0/2=0114/2=0

57/2=1

28/2=0

14/2=0

7/2=1

3/2=1

=1

0/2=0250/2=0125/2=1

62/2=0

31/2=1

15/2=1

7/2=1

3/2=1

=1

The final answer in the binary number

10101100

000110010111001011111010

2.Network broadcast addressHow to get a broadcast address :See the results of the binary IP address and subnet mask , focus on Subnet , turn all grades Subnet 1 becomes 0 and 0 becomes 1.Until obtained 00000000.00000000.00001111.11111111 like this:IP Address: 172.25.114.250Binary :10101100.00011001.01110010.11111010Subnet Mask Binary:11111111.11111111.00000000.00000000After that,you must convert the number 1 to 0 and number 0 to 1,so you will get the broad cast binary.Broadcast Binary:00000000.00000000.11111111.11111111Then,you must convert the number 0 in the network address binary into 1 to become the network broadcast address binary.Network broadcast address binary : 10101100.00011001.11111111.11111111So, the final answer is:Network broadcast address:172.25.255.255Subnet Mask:255.255.0.0.

3.Total number of host bitsTo find the total number of host bits, you must use the formula in the IP address that is Possible Host.Formula of the Possible Host:2n - 2Where n the number of host bits,so to find the number of host bits in this IP address the solution are like this.Using formula of the Possible Host.= 2n - 2SOLVING METHOD

= 216 - 2= 65536 - 2= 65534So,the final answer for the number of host bits for this IP address is 65534.4. Number of HostTo find the total number of the host,you just substract the number of bits in the IP address with the number of host bits.Number of bits in IP address = 32SOLVING METHOD

Number of host bits = 16So, the solution is:32 16 = 16So, the number of host in this IP address is 16.

Problem 2Host IP address = 172.30.1.33/24Network Mask = 255.255.255.0Find

1.Network addressIP Address172.30.1.3310101100000111100000000100100001

Subnet Mask255.255.255.011111111111111111111111100000000

Network Address172.30.1.010101100000111100000000100000000

How to get the binary number for IP Address

17230133

172/2 = 0

86/2 = 0

43/2 = 1

21/2 = 1

10/2 = 0

5/2 = 12/2 = 0 = 1

30/2 = 0

15/2 = 1

7/2 = 1

3/2 = 1

= 1

0/2 = 0

0/2 = 0

0/2 = 0 = 1

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 033/2 = 1

16/2 = 0

8/2 = 0

4/2 = 0

2/2 = 0

= 1

0/2 = 0

0/2 = 0

The final answer in the binary number

10101100

000111100000000100100001

2.Network broadcast addressHow to get a broadcast address :See the results of the binary IP address and subnet mask , focus on Subnet , turn all grades Subnet 1 becomes 0 and 0 becomes 1.Until obtained 00000000.00000000.00001111.11111111 like this:IP Address: 172.30.1.33Binary :10101100.00011110.00000001.00100001Subnet Mask Binary:11111111.11111111.11111111.00000000After that,you must convert the number 1 to 0 and number 0 to 1,so you will get the broad cast binary.Broadcast Binary:00000000.00000000.00000000.11111111Then,you must convert the number 0 in the network address binary into 1 to become the network broadcast address binary.Network broadcast address binary : 10101100.00011110.00000001.11111111So, the final answer is:Network broadcast address:172.30.1.255Subnet Mask:255.255.255.0

3.Total number of host bitsTo find the total number of host bits, you must use the formula in the IP address that is Possible Host.Formula of the Possible Host:SOLVING METHOD

2n - 2Where n the number of host bits,so to find the number of host bits in this IP address the solution are like this.Using formula of the Possible Host.= 2n - 2SOLVING METHOD

= 28 - 2= 256 - 2= 254So,the final answer for the number of host bits for this IP address is 256.4. Number of HostTo find the total number of the host,you just substract the number of bits in the IP address with the number of host bits.Number of bits in IP address = 32SOLVING METHOD

Number of host bits = 24So, the solution is:32 24 = 8So, the number of host in this IP address is 8.

Problem 3Host IP address:192.168.10.234Network Mask:255.255.255.0Find

1.Network addressIP Address192.168.10.23411100000101010000000101011101010

Subnet Mask255.255.255.011111111111111111111111100000000

Network Address192.168.10.011100000101010000000101000000000

How to get the binary number for IP Address

19216810234

192/2 = 0

96/2 = 0

48/2 = 0

24/2 = 0

12/2 = 0

6/2 = 13/2 = 1 = 1

168/2 = 0

84/2 = 0

42/2 = 0

21/2 = 1

10/2 = 0

5/2 = 1

2/2 = 0

= 1

10/2 = 0

5/2 = 1

2/2 = 0

= 1

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0234/2 = 0

117/2 = 1

58/2 = 0

29/2 = 1

14/2 = 0

7/2 = 1

3/2 = 1

1/2 = 1

The final answer in the binary number

11100000

101010000000101011101010

2.Network broadcast addressHow to get a broadcast address :See the results of the binary IP address and subnet mask , focus on Subnet , turn all grades Subnet 1 becomes 0 and 0 becomes 1.Until obtained 00000000.00000000.00001111.11111111 like this:IP Address: 192.168.10.234Binary :11100000.10101000.00001010.11101010Subnet Mask Binary:11111111.11111111.11111111.00000000After that,you must convert the number 1 to 0 and number 0 to 1,so you will get the broad cast binary.Broadcast Binary:00000000.00000000.00000000.11111111Then,you must convert the number 0 in the network address binary into 1 to become the network broadcast address binary.Network broadcast address binary : 11100000.10101000.00001010.11111111So, the final answer is:Network broadcast address:192.168.10.255Subnet Mask:255.255.255.0

3.Total number of host bitsTo find the total number of host bits, you must use the formula in the IP address that is Possible Host.Formula of the Possible Host:SOLVING METHOD

2n - 2Where n the number of host bits,so to find the number of host bits in this IP address the solution are like this.Using formula of the Possible Host.= 2n - 2SOLVING METHOD

= 28 - 2= 256 - 2= 254So,the final answer for the number of host bits for this IP address is 256.4. Number of HostTo find the total number of the host,you just substract the number of bits in the IP address with the number of host bits.Number of bits in IP address = 32SOLVING METHOD

Number of host bits = 24So, the solution is:32 24 = 8So, the number of host in this IP address is 8.

Problem 4Host IP address:172.17.99.71Network Mask:255.255.0.0Find

1.Network addressIP Address172.17.99.7110101100000100010110001101000111

Subnet Mask255.255.0.011111111111111110000000000000000

Network Address172.17.0.010101100000100010000000000000000

How to get the binary number for IP Address

172179971

172/2 = 0

86/2 = 0

43/2 = 1

21/2 = 1

10/2 = 0

5/2 = 12/2 = 0 = 1

17/2 = 1

8/2 = 0

4/2 = 0

2/2 = 0

1/2 = 1

0/2 = 0

0/2 = 0

0/2 = 0

99/2 = 1

49/2 = 1

24/2 = 0

12/2 = 0

6/2 = 0

3/2 = 1

1/2 = 1

0/2 = 071/2 = 1

35/2 = 1

17/2 = 1

8/2 = 0

4/2 = 0

2/2 = 0

1/2 = 1

0/2 = 0

The final answer in the binary number

10101100

000100010110001101000111

2.Network broadcast addressHow to get a broadcast address :See the results of the binary IP address and subnet mask , focus on Subnet , turn all grades Subnet 1 becomes 0 and 0 becomes 1.Until obtained 00000000.00000000.00001111.11111111 like this:IP Address: 172.17.99.71Binary :10101100.00010001.01100011.01000111Subnet Mask Binary:11111111.11111111.00000000.00000000After that,you must convert the number 1 to 0 and number 0 to 1,so you will get the broad cast binary.Broadcast Binary:00000000.00000000.11111111.11111111Then,you must convert the number 0 in the network address binary into 1 to become the network broadcast address binary.Network broadcast address binary : 10101100.00010001.11111111.11111111So, the final answer is:Network broadcast address:172.17.255.255Subnet Mask:255.255.0.0

3.Total number of host bitsTo find the total number of host bits, you must use the formula in the IP address that is Possible Host.Formula of the Possible Host:SOLVING METHOD

2n - 2Where n the number of host bits,so to find the number of host bits in this IP address the solution are like this.Using formula of the Possible Host.= 2n - 2SOLVING METHOD

= 216 - 2= 65536 - 2= 65534So,the final answer for the number of host bits for this IP address is 65534.4. Number of HostTo find the total number of the host,you just substract the number of bits in the IP address with the number of host bits.Number of bits in IP address = 32SOLVING METHOD

Number of host bits = 16So, the solution is:32 16 = 16So, the number of host in this IP address is 16.

Problem 5Host IP Address:192.168.3.219Net Mask:255.255.0.0Find

1.Network addressIP Address192.168.3.21911101100001010000000001111011011

Subnet Mask255.255.0.011111111111111110000000000000000

Network Address192.168.0.011101100001010000000000000000000

How to get the binary number for IP Address

1921683219

192/2 = 0

96/2 = 0

48/2 = 1

24/2 = 1

12/2 = 0

6/2 = 13/2 = 1 = 1

168/2 = 0

84/2 = 0

42/2 = 0

21/2 = 1

10/2 = 0

5/2 = 1

2/2 = 0

1/2 = 0

3/2 = 1

1/2 = 1

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0219/2 = 1

109/2 = 1

54/2 = 0

27/2 = 1

13/2 = 1

6/2 = 0

3/2 = 1

1/2 = 1

The final answer in the binary number

11101100

001010000000001111011011

2.Network broadcast addressHow to get a broadcast address :See the results of the binary IP address and subnet mask , focus on Subnet , turn all grades Subnet 1 becomes 0 and 0 becomes 1.Until obtained 00000000.00000000.00001111.11111111 like this:IP Address:192.168.3.219Binary :11101100.00101000.00000011.11011011Subnet Mask Binary:11111111.11111111.00000000.00000000After that,you must convert the number 1 to 0 and number 0 to 1,so you will get the broad cast binary.Broadcast Binary:00000000.00000000.11111111.11111111Then,you must convert the number 0 in the network address binary into 1 to become the network broadcast address binary.Network broadcast address binary : 10101100.00010001.11111111.11111111So, the final answer is:Network broadcast address:192.168.255.255Subnet Mask:255.255.0.0

3.Total number of host bitsTo find the total number of host bits, you must use the formula in the IP address that is Possible Host.Formula of the Possible Host:SOLVING METHOD

2n - 2Where n the number of host bits,so to find the number of host bits in this IP address the solution are like this.Using formula of the Possible Host.= 2n - 2SOLVING METHOD

= 216 - 2= 65536 - 2= 65534So,the final answer for the number of host bits for this IP address is 65534.4. Number of HostTo find the total number of the host,you just substract the number of bits in the IP address with the number of host bits.Number of bits in IP address = 32Number of host bits = 16SOLVING METHOD

So, the solution is:32 16 = 16So, the number of host in this IP address is 16.

Problem 6Host IP address:192.168.3.219Net Mask:255.255.255.224Find

1.Network addressIP Address192.168.3.21911101100001010000000001111011011

Subnet Mask255.255.255.22411111111111111111111111111100000

Network Address192.168.3.19211101100001010000000001111000000

How to get the binary number for IP Address

1921683219

192/2 = 0

96/2 = 0

48/2 = 1

24/2 = 1

12/2 = 0

6/2 = 13/2 = 1 = 1

168/2 = 0

84/2 = 0

42/2 = 0

21/2 = 1

10/2 = 0

5/2 = 1

2/2 = 0

1/2 = 0

3/2 = 1

1/2 = 1

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0

0/2 = 0219/2 = 1

109/2 = 1

54/2 = 0

27/2 = 1

13/2 = 1

6/2 = 0

3/2 = 1

1/2 = 1

The final answer in the binary number

11101100

001010000000001111011011

2.Network broadcast addressHow to get a broadcast address :See the results of the binary IP address and subnet mask , focus on Subnet , turn all grades Subnet 1 becomes 0 and 0 becomes 1.Until obtained 00000000.00000000.00001111.11111111 like this:IP Address:192.168.3.219Binary :11101100.00101000.00000011.11011011Subnet Mask Binary:11111111.11111111.11111111.11100000After that,you must convert the number 1 to 0 and number 0 to 1,so you will get the broad cast binary.Broadcast Binary:00000000.00000000.00000000.00011111Then,you must convert the number 0 in the network address binary into 1 to become the network broadcast address binary.Network broadcast address binary : 11101100.00101000.00000011.11011111So, the final answer is:Network broadcast address:192.168.3.223Subnet Mask:255.255.255.224

3.Total number of host bitsTo find the total number of host bits, you must use the formula in the IP address that is Possible Host.Formula of the Possible Host:SOLVING METHOD

2n - 2Where n the number of host bits,so to find the number of host bits in this IP address the solution are like this.Using formula of the Possible Host.= 2n - 2SOLVING METHOD

= 25 - 2= 32 - 2= 30So,the final answer for the number of host bits for this IP address is 304. Number of HostTo find the total number of the host,you just substract the number of bits in the IP address with the number of host bits.Number of bits in IP address = 32SOLVING METHOD

Number of host bits = 27So, the solution is:32 27 = 5So, the number of host in this IP address is 5.