T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

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TRANSITIVE AND SUBSTITUTION PROPERTY Lesson 2.7

Transcript of T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

Page 1: T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

TRANSITIVE AND SUBSTITUTION PROPERTY

Lesson 2.7

Page 2: T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

Suppose A B and A C.

Is B C?

Page 3: T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

THEOREM 16:

If angles (or segments) are congruent to congruent angles (or segments), they are congruent to each other. (Transitive Property)

THEOREM 17:

If angles (or segments) are congruent to the same angle (or segment), they are congruent to each other. (Transitive Property)

Page 4: T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

1. FG KJ2. GH KJ3. FG GH

4. KG bisects FH

1. Given2. Given3. If segments are to the

same segment, they are . (Transitive Property)

4. If a line divides a segment into two segments, it bisects the segments.

Page 5: T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

If A B, find m A.

2x – 4 = x + 10 x = 14We can now substitute 14 in for x in mA = x + 10 to find mA = 14 + 10 = 24.

This is the Substitution Property. It can be applied when you have variables or not.

Page 6: T RANSITIVE AND S UBSTITUTION P ROPERTY Lesson 2.7.

1. 1 + 2 = 90°2. 1 33. 3 + 2 = 90°

1. Given2. Given3. Substitution (step 2

into step 1)