Swimming Pool Program

8/17/2019 Swimming Pool Program

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Swimming Pool CalculationEnter Your Numbers In GreenCells Only: Swimming Pool e$ig

Surface Area of Swimming Pool 1.4 prepared * 'ng.>ah

Pool average depth = -.% m

Pool Volume = 10.1

!. "ater #nlet$ = -.%56So &et the o. !f inlet$ = 1 inlet$

'nter o. !f (urn !ver Period 3 time ) da*

&et Swimming Pool Pump Capacit* = Pool Volume ) + turn over period , 6-

= -.-/5111

o. !f pump will u$ed = 1 pump$

&et pump flow rate = -.-/5111

To calculate pipe sizing

Supply pipe maximum velocity will be 2 m/so. !f inlet = 1 #nlet

Pump flow rate = 5.0-6660

'ach inlet give flow rate = 5.0-6660

A$$uming that all inlet in $euence

ia 1 = 31.001%% (a2ing it 3 5- mm. Take just

Suction pipe maximum velocity will be 1.5 m/s


o. !f outlet = 1 !utlet

'ach outlet give flow rate = 5.0-6660ia 1 = 4-.61-60 (a2ing it 41 5- mm. Take just

Getting the flter area to be used


ilter area = -.163-4%

$eating Calculation for s%imming pools

Heater is required for heating purposes at winter seasons if required take inconsiderationit's not particle to heat the pool without covers at coldest winter months

For calculation purposes the following conditions to be considered:-

The recommended Pool water temperature is around 2 ! " deg#

$utdoor air condition : %& () deg ! " *+,+ summer condition. ma/ 022deg F 1

7 6) 1- deg 8 C )" 9winter condition

From 4P5T5 p. 4ec(. the 5verage *ail6 heat loss 1*H3 in 7,hr m2 of pool surface area

m

m3

m3)min

m3)min

m3)hr

m3)hr

m3)hr

m3

)hr

m3)hr

m at 15 gpm ) ft


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correction value to 1.5

8o# of hours per da6 available for heati 4% hour$

Heater required 4.6%15 w

cooling Calculation for s%imming pools To cool 0gpm and maintain at 2!"12#%!F3 will require the corresponding 0#2 "fm of a

"ooling capacit6 1%0.6/ C>/-4-0.3 tu)hr

0.533/4 (?

pump &ea! calculation for s%imming poolsheater pre$$ure drop = 1- ft

filter pre$$ure drop = 3- ft

chlorination auto pilot unit 5 ft

pipe$ and fitting$ lo$$e$ = 0 ft

Static head heat pump = 1%./3 ft

pump head = %5.116 ft

pump @P = -.3--01 hp

'esult of Calculation :(

Pump Capacit* = 5.150 with 1

Pump @ead = %5.116 t

Pump @P = -.3--01 @P

alance tan2 V. = B?'

ilter Area = -.163-4%@eater Capacit* = 4.6%15 w

Cooling Capacit* = 0.533/4 (? 1%0.6/ C>

m3)hr

m3

m

at 15 gpm ) ft


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ir 9 #; +tumin to re


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Swimming Pool CalculationEnter Your Numbers In GreenCells Only: Swimming Pool e$ig

Surface Area of Swimming Pool / prepared * 'ng.>ah

Pool average depth = -.% m

Pool Volume = 3.

!. "ater #nlet$ = 1.16So &et the o. !f inlet$ = 1 inlet$



= -.3%6660

o. !f pump will u$ed = pump$

&et pump flow rate = -.1/3333

alance tan2 volume =

= 3.3%3333

alance tan2 volume = 3.4

To calculate pipe sizing

Supply pipe maximum velocity will be 2 m/s

o. !f inlet = 1 #nlet

Pump flow rate = 3.

'ach inlet give flow rate = 3.


ia 1 = 64.-61% (a2ing it 64 65 mm. Take just

ia = /-.5/634 (a2ing it /1 1-- mm. for inletia 3 = 11-./504 (a2ing it 111 1-- mm.

ia 4 = 1%.16 (a2ing it 1% 15- mm.

ia 5 = 143.454 (a2ing it 143 15- mm.

ia 6 = 156./105 (a2ing it 150 15- mm.

ia 0 = 16/.4/- (a2ing it 16/ 15- mm.

ia % = 1%1.1/0 (a2ing it 1%1 15- mm.

ia / = 1/.1%3% (a2ing it 1/ 15- mm.

ia 1- = -.50/6 (a2ing it -3 15- mm.

ia 11 = 1.460 (a2ing it 1 15- mm.

ia 1 = 1./14% (a2ing it 15- mm.


Pump flow rate = 3.

o. !f outlet = !utlet

'ach outlet give flow rate = 11.6

ia 1 = 50.%///1 (a2ing it 5% 65 mm. Take just

ia = %1.%%%4 (a2ing it % 05 mm. for " outle

ia 3 = 1--.%56 (a2ing it 1-- 1-- mm.

m

m3

m3)min

m3)min

4- :)m ; Pool Surface area < 1- min ; pump flow rate < -.-1 ;

m3

m3

m3)hr

m3)hr

m3)hr

m3)hr


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ia 4 = 115.0//% (a2ing it 116 1-- mm.

Over fow pipe Grille velocity will be 0.3m/s the o. !f grille = 0 &rille$

Pump flow rate = 3.

A$$uming that all grille$ in $euence

ia 1 = 33.60/5% (a2ing it 34 5- mm. Take justia = 40.63-1 (a2ing it 4% 5- mm. for # grille

ia 3 = 5%.33405 (a2ing it 5% 65 mm.

ia 4 = 60.35/10 (a2ing it 60 65 mm.

ia 5 = 05.3-/%4 (a2ing it 05 05 mm.

ia 6 = %.4/00/ (a2ing it % 05 mm.

ia 0 = %/.1-0% (a2ing it %/ 1-- mm.

ia % = /5.6-5 (a2ing it /5 1-- mm.

ia / = 1-1.-3%0 (a2ing it 1-1 1-- mm.

ia 1- = 1-6.5-4 (a2ing it 1-0 1-- mm.

Getting the flter area to be usedPump flow rate = 3.

ilter area = -.66%50


Heater is required for heating purposes at winter seasons if required take inconsideration

it's not particle to heat the pool without covers at coldest winter months



$utdoor air condition : %& () deg ! " *+,+ summer condition. ma/ 022deg F 1


From 4P5T5 p. 4ec(. the 5verage *ail6 heat loss 1*H3 in 7,hr m2 of pool surface area

correction value to 1.5

8o# of hours per da6 available for heati 4% hour$

Heater required 6.34305 w

cooling Calculation for s%imming pools To cool 0gpm and maintain at 2!"12#%!F3 will require the corresponding 0#2 "fm of a

"ooling capacit6 535.-1 C>

360543.0 tu)hr

3-.6%64 (?

pump &ea! calculation for s%imming poolsheater pre$$ure drop = 1- ft

filter pre$$ure drop = 3- ft


m3)hr

m3)hr

m at 15 gpm ) ft


9/21


Static head heat pump = 1%./3 ft

pump head = %5.116 ft

pump @P = -.61-364 hp


Pump Capacit* = 51.-030 with

Pump @ead = %5.116 t

Pump @P = -.61-364 @P

alance tan2 V. = 3.4

ilter Area = -.66%50

@eater Capacit* = 6.34305 w

Cooling Capacit* = 3-.6%64 (? 535.-1 C>

m3)hr

m3

m at 15 gpm ) ft


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$heet ?ev9- +49119-1-

oud Selim

o. Of inlet for your calculation

take to !ia

o. Of outlet for your calculation

t take to !ia"

pool $urface area


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o. Of grille for your calculationtake to !ia #

that

) "3

ir 9 #; +tumin to re


12/21

Pump$


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Pump flow rate = 44.06660

o. !f outlet = 3 !utlet

'ach outlet give flow rate = 14./

ia 1 = 65.66/% (a2ing it 66 65 mm.

ia = /.%011 (a2ing it /3 1-- mm.

ia 3 = 113.0434 (a2ing it 114 1-- mm.

ia 4 = 131.33/6 (a2ing it 131 15- mm.

Getting the flter area to be usedPump flow rate = 44.06660

ilter area = 1.0/-4%


Heater is required for heating purposes at winter seasons if required take inconsi

's not particle to heat the pool without covers at coldest winter months



ondition : %& () deg ! " *+,+ summer condition. ma/ 022deg F 1) "3


T5 p. 4ec(. the 5verage *ail6 heat loss 1*H3 in 7,hr m2 of pool surface area

correction value to be -.%

8o# of hours per da6 available for heatin 1 hour$

Heater required %%.4% w

cooling Calculation for s%imming pools To cool 0gpm and maintain at 2!"12#%!F3 will require the corresponding 0#2

"ooling capacit6 1-1-1.46 C>

0-/11.5 tu)hr

5/.1--/6 (?

pump &ea! calculation for s%imming pools

heater pre$$ure drop = 1- ftfilter pre$$ure drop = 3- ft



Static head heat pump = 3 ft

pump head = 64.% ft

m3)hr

m3)hr

m3)hr

m at 15 gpm ) ft


15/21

pump @P = %.-635/6 hp


Pump Capacit* = 1/0.1-10 with

Pump @ead = 64.% t

Pump @P = %.-6353 @P

alance tan2 V. = 15.4

ilter Area = 1.0/-4%@eater Capacit* = %%.4% w

Cooling Capacit* = 5/.1--/6 (? 1-1-1.46

m3)hr

m3

m

at 15 gp


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Swimming Pool Calculation

'nter Dour umer$ #n &reenCell$ !nl*7 Swimming Pool e$ig

Surface Area of Swimming Pool 15% m prepared * 'ng.>ah

Pool average depth = 1.0 m

Pool Volume = 6%.6 m3

!. "ater #nlet$ = 6.3

So &et the o. !f inlet$ = 6 inlet$



= -.046111 m3)min

o. !f pump will u$ed = 1 pump$

&et pump flow rate = -.046111 m3)min

alance tan2 volume = 4- :)m ; Pool Surface area < 1- min ; pump flow rate < -.-1 ;

= 15.36111 m3

alance tan2 volume = 15.4 m3

(o calculate pipe $iEing

Suppl* pipe maFimum velocit* will e m)$

o. !f inlet = 6 #nlet

Pump flow rate = 44.06660 m3)hr

'ach inlet give flow rate = 0.461111 m3)hr


ia 1 = 36.3/ (a2ing it 36 5- mm. (a2e Gu$t n

ia = 51.306/6 (a2ing it 51 5- mm. for 4 inlet t

ia 3 = 6./360 (a2ing it 63 65 mm.

ia 4 = 0.650// (a2ing it 03 05 mm.

ia 5 = %1.341 (a2ing it %1 05 mm.ia 6 = %%./%05 (a2ing it %/ 1-- mm.

ia 0 = /6.1104/ (a2ing it /6 1-- mm.

ia % = 1-.053/ (a2ing it 1-3 1-- mm.

ia / = 1-%./%0 (a2ing it 1-/ 1-- mm.

ia 1- = 114.%%4 (a2ing it 115 1-- mm.

ia 11 = 1-.4%/6 (a2ing it 1- 1-- mm.

ia 1 = 15.%403 (a2ing it 16 15- mm.

Suction pipe maFimum velocit* will e 1.5 m)$

Pump flow rate = 44.06660 m3)hr

o. !f outlet = !utlet

'ach outlet give flow rate = .3%333 m3)hr

ia 1 = %-.4%05 (a2ing it %- 05 mm. (a2e Gu$t n

ia = 113.0434 (a2ing it 114 1-- mm. for outlet

ia 3 = 13/.3-60 (a2ing it 13/ 15- mm.

ia 4 = 16-.%505 (a2ing it 161 15- mm.

!ver flow pipe &rille velocit* will e -.3m)$

the o. !f grille = 0 &rille$


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18/21

Pump Capacit* = 1/0.1-10 m3)hr with 1

Pump @ead = 134.4 t

Pump @P = 16.030% @P

alance tan2 V. = 15.4 m3

ilter Area = 1.0/-4% m at 15 gpm ) f

@eater Capacit* = 44.4 w

Cooling Capacit* = 5/.1--/6 (? 1-1-1.46 C>


19/21

$heet ?ev9- +49119-1-

oud Selim

pool $urface area

o. !f inlet for *our calculation

2e to dia4

o. !f outlet for *our calculation

ta2e to dia


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o. !f grille for *our calculation

a2e to dia 6

u)min to reGect the heat.


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Pump$

Swimming Pool Program

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