Suppose you are in a small restaurant and are ready to order a soup, a main course, and a beverage....
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Transcript of Suppose you are in a small restaurant and are ready to order a soup, a main course, and a beverage....
Suppose you are in a small restaurant and are ready to order a soup, a main course, and a beverage.
(Unfortunately, you will need to go somewhere else for dessert!) The restaurant has 2 different soups, 3
different main courses, and 5 different beverages. If a meal consists of one item from each of the three
categories, how many different meals are possible?
2x3x5 = 30 ways to select one item from each of the three categories.
Counting Methods – Part 1
Use basic counting methods to determine the number of ways of getting a sequence of events.
Practical Situations
1. Selecting a batting order for a team of baseball players
2. Selecting a set of courses to take at a college
3. Selecting a soup, dessert, and beverage when having dinner at a restaurant
Let’s visit a better restaurant!!!• Suppose this restaurant has 4 different soups, 12
different main courses, 10 different desserts, and 8 different beverages. (Of course, you will have the opportunity to select a dessert after finishing the main course!) If a meal consists of one item from each of the four different categories, how many different meals are possible?
4x12x10x8 = 3840
Factorial!
• 5! Read as “five factorial”• 5 x 4 x 3 x 2 x 1 = 120• The product involves starting with a
positive integer and multiplying by each decreasing consecutive integer, until reaching the number 1.
• Factorials are not defined for fractions or decimals.
What is 0!?
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4!=4x3x2x1=243!=3x2x1=62!=2x1=21!=1
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Notice:4!÷4 =3!3!÷3 =2!2!÷2 =1!1!÷1=0!
1!Since =1, 1!then ÷1=1÷1=1
0! is 1
Six people are to be assigned to 6 different seats. In how many ways can this be done?Seats 1 2 3 4 5 6
Choices 6 5 4 3 2 1
6! = 720To enter 6! on calculator:•MATH•Arrow right to PRB•Choose 4
Ten people wish to line up for a photograph. How many different arrangements are possible?
10! = 3,628,800 different arrangements
A high school bowling club consists of 8 members. A president, vice president and a
treasurer are to be chosen. If 3 different people will be selected, in how many ways
can this be done?
Since there are only 3 available positions:8(7)(6)=336 ways can be done
4!
• What is another way to express 4!?
Properties of factorials:
• Factorials cannot be used for decimals, fractions or any negative numbers.
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12
⎛
⎝ ⎜
⎞
⎠ ⎟!, (2.42)!, (-6)! .have no meaning
Properties of factorials:
• The product of two factorial numbers is not equal to the factorial of their product or any arithmetic operation.
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2!+4!≠6!, 3! 5!x ≠15!, 20!÷10!≠2!
Properties of factorials:
• If n is any positive integer, then n! x(n+1)=(n+1)!
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12!×13 =13!12!÷12 =11!
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or (n+1)!÷(n+1) = !n