Precalculus Lesson 2.6 – Lesson 2.7 Rational Functions, Asymptotes & Graphs of Rational Functions.
Sullivan PreCalculus Section 3.4 Rational Functions II: Analyzing Graphs Objectives Analyze the...
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Transcript of Sullivan PreCalculus Section 3.4 Rational Functions II: Analyzing Graphs Objectives Analyze the...
Sullivan PreCalculusSection 3.4
Rational Functions II: Analyzing Graphs
Objectives
• Analyze the Graph of a Rational Function
• Solve Applied Problems Involving Rational Functions
To analyze the graph of a rational function:
a.) Find the Domain of the rational function.
b.) Locate the intercepts, if any, of the graph.
c.) Test for Symmetry. If R(-x) = R(x), there is symmetry with respect to the y-axis. If - R(x) = R(-x), there is symmetry with respect to the origin.
d.) Write R in lowest terms and find the real zeros of the denominator, which are the vertical asymptotes.
e.) Locate the horizontal or oblique asymptotes.
f.) Determine where the graph is above the x-axis and where the graph is below the x-axis.
g.) Use all found information to graph the function.
Example: Analyze the graph of 9
642)(
2
2
x
xxxR
R x
x x
x x( )
2 2 3
3 3
2
2 3 13 3
x xx x
2 1
33
xx
x,
Domain: x x x 3 3,
a.) x-intercept when x + 1 = 0: (-1,0)
b.) y-intercept when x = 0: 3
2
)30(
)10(2)0(
R
y - intercept: (0, 2/3)
3
12)(
x
xxR
c.) Test for Symmetry: R xx
x( )
( )( )
2 13
)()()( xRxRxR No symmetry
R xx
xx( ) ,
2 1
33
d.) Vertical asymptote: x = -3
Since the function isn’t defined at x = 3, there is a whole at that point.
e.) Horizontal asymptote: y = 2
f.) Divide the domain using the zeros and the vertical asymptotes. The intervals to test are:
x x x3 3 1 1
x x x3 3 1 1
Test at x = -4
R(-4) = 6
Above x-axis
Point: (-4, 6)
Test at x = -2
R(-2) = -2
Below x-axis
Point: (-2, -2)
Test at x = 1
R(1) = 1
Above x-axis
Point: (1, 1)
g.) Finally, graph the rational function R(x)
8 6 4 2 0 2 4 6
10
5
5
10
(-4, 6)
(-2, -2) (-1, 0) (0, 2/3)
(1, 1) (3, 4/3)
y = 2
x = - 3
Example: The concentration C of a certain drug in a patients bloodstream t minutes after injection is given by:
)25(
50)(
2
t
ttC
a.) Find the horizontal asymptote of C(t)
Since the degree of the denomination is larger than the degree of the numerator, the horizontal asymptote of the graph of C is y = 0.
b.) What happens to the concentration of the drug as t (time) increases?
The horizontal asymptote at y = 0 suggests that the concentration of the drug will approach zero as time increases.
c.) Use a graphing utility to graph C(t). According the the graph, when is the concentration of the drug at a maximum?
The concentration will be at a maximum five minutes after injection.