Subnetting A Network
36
_______________________________________________ ________________________ ________________________ ______________________________________ 192.10.10.48 to 192.10.10.63 192 . 10 . 10 . 112 192 . 10 . 10 . 207 192.10.10.129 to 192.10.10.142 28 Subnetting Problem 1 Number of needed subnets Number of needed usable hosts Network Address Address class Default subnet mask Custom subnet mask Total number of subnets Total number of host addresses Number of usable addresses Number of bits borrowed 14 14 192.10.10.0 __________ _______________________________ _______________________________ ___________________ ___________________ ___________________ ___________________ C 255 . 255 . 255 . 0 255 . 255 . 255 . 240 16 16 14 4 What is the 4th subnet range? What is the subnet number for the 8th subnet? What is the subnet broadcast address for the 13th subnet? What are the assignable addresses for the 9th subnet?
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Transcript of Subnetting A Network
_______________________________________________
________________________
________________________
______________________________________
192.10.10.48 to 192.10.10.63
192 . 10 . 10 . 112
192 . 10 . 10 . 207
192.10.10.129 to 192.10.10.142
28
Subnetting
Problem 1Number of needed subnets
Number of needed usable hostsNetwork Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
1414192.10.10.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
C
255 . 255 . 255 . 0
255 . 255 . 255 . 240
16
16
14
4
What is the 4thsubnet range?
What is the subnet numberfor the 8th subnet?
What is the subnetbroadcast address for
the 13th subnet?
What are the assignableaddresses for the 9th
subnet?
Show your work for Problem 1 in the space below.
192.10.10.0 to 192.10.10.15192.10.10.16 to 192.10.10.31192.10.10.32 to 192.10.10.47192.10.10.48 to 192.10.10.63192.10.10.64 to 192.10.10.79192.10.10.80 to 192.10.10.95192.10.10.96 to 192.10.10.111192.10.10.112 to 192.10.10.127192.10.10.128 to 192.10.10.143192.10.10.144 to 192.10.10.159192.10.10.160 to 192.10.10.175192.10.10.176 to 192.10.10.191192.10.10.192 to 192.10.10.207192.10.10.208 to 192.10.10.223192.10.10.224 to 192.10.10.239192.10.10.240 to 192.10.10.255
192. 10 . 10 . 0 0 0 0 0 0 0 0 192. 10 . 10 . 0 0 0 0 0 0 0 0 192. 10 . 10 . 0 0 0 0 0 0 0 0 192. 10 . 10 . 0 0 0 0 0 0 0 0 192. 10 . 10 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1 - Binary values
Number of Subnets - 2 4 8 16 2 4 8 16 2 4 8 16 2 4 8 16 2 4 8 16 32 64 128 256
Number of256 128 64 32 16 8 4 2 - Hosts
16-214
16-214
1286432
+16240
The binary value of the last bit borrowed is the range. In thisproblem the range is 16.
The first address in each subnet range is the subnet number.
The last address in each subnet range is the subnet broadcastaddress.
Custom subnetmask
Usable hostsUsable subnets
29
0101010101010101
0011001100110011
0000111100001111
0000000011111111
(0)(1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14)(15)
_______________________________________________
________________________
________________________
______________________________________
165.100.3.128 to 165.100.3.191
165 . 100 . 1 . 64
165 . 100 . 1 . 127
165.100.2.1 to 165.100.0.62
30
Subnetting
Problem 2Number of needed subnets
Number of needed usable hostsNetwork Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
100060165.100.0.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
B
255 . 255 . 0 . 0
255 . 255 . 255 . 192
1,024
64
62
10
What is the 15thsubnet range?
What is the subnet numberfor the 6th subnet?
What is the subnetbroadcast address for
the 6th subnet?
What are the assignableaddresses for the 9th
subnet?
165
. 10
0 . 0
0
0
0 0
0
0
0 .
0 0
0
0
0 0
0
016
5 .
100
. 0
0 0
0
0
0 0
0
. 0
0
0 0
0
0
0 0
165
. 10
0 . 0
0
0
0 0
0
0
0 .
0 0
0
0
0 0
0
016
5 .
100
. 0
0 0
0
0
0 0
0
. 0
0
0 0
0
0
0 0
165
. 10
0 . 0
0
0
0 0
0
0
0 .
0 0
0
0
0 0
0
016
5.1
00.0
.0to
1
65.1
00.0
.63
165
.100
.0.6
4to
1
65.1
00.0
.127
165
.100.0
.12
8to
1
65.1
00.0
.191
165
.100.0
.192
to
165
.100
.0.2
55
165
.100.1
.0to
1
65.1
00.1
.63
165
.100
.1.6
4to
1
65.1
00.1
.127
165
.100.1
.12
8to
1
65.1
00.1
.191
165
.100.1
.192
to
165
.100
.1.2
55
165
.100.2
.0to
1
65.1
00.0
.63
165
.100
.2.6
4to
1
65.1
00.0
.127
165
.100.2
.12
8to
1
65.1
00.0
.191
165
.100.2
.192
to
165
.100
.0.2
55
165
.100.3
.0to
1
65.1
00.3
.63
165
.100
.3.6
4to
1
65.1
00.3
.127
165
.100.3
.12
8to
1
65.1
00.3
.191
165
.100.3
.192
to
165
.100
.3.2
55
Dow
n to
165
.100
.25
5.1
28
to
16
5.1
00.2
55
.191
165
.100
.25
5.1
92 t
o 1
65.1
00.2
55
.25
5
The
bina
ry v
alue
of t
he la
st b
it bo
rrow
ed is
the
rang
e. In
this
pro
blem
the
rang
e is
64.
The
first
add
ress
in e
ach
subn
et r
ange
is th
esu
bnet
num
ber.
The
last
add
ress
in e
ach
subn
et r
ange
is th
esu
bnet
bro
adca
st a
ddre
ss.
31
64 -2 62U
sabl
eho
sts
128
64 32 16 8 4 2 +12
55
128
+64
192
Cus
tom
subn
et m
ask
Show your work for Problem 2 in the space below.
128
64
32 16
8
4
2
1
Num
ber
of S
ubne
ts
-
2
4
8
16 3
2 6
4 1
28
25
6 .
. 25
6 12
8 6
4 32
16
8
4
2
128
64
32
16
8
4
2
1
.... .
512
Bin
ary
valu
es -
Num
ber
ofH
osts
-
102420484,0968,192
16,384
32,76865,536
512
1,024
2,048
4,096
8,192
16,384
32,768
65,536
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 1 0 0 1 1 0 0 1 1 0 0 1 1 1 1
1 1 1 1 0 0 0 0 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
. . . . . . . . . . . . . . .
(0)
(1)
(2)
(3)
(4)
(5)
(6)
(7)
(8)
(9)
(10)
(11)
(12)
(13)
(14)
(15)
1
1 1
1 1
1 1
1 1
1 1
1(1
022)
(102
3)
_______________________________________________
________________________
________________________
______________________________________
32
Subnetting
Problem 3Number of needed subnets
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
2195.223.50.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 3rdsubnet range?
What is the subnet numberfor the 2nd subnet?
What is the subnetbroadcast address for
the 1st subnet?
What are the assignableaddresses for the 3rd
subnet?
Show your work for Problem 3 in the space below.
33
128 64 32 16 8 4 2 1 - Binary values
Number of Subnets - 2 4 8 16 2 4 8 16 2 4 8 16 2 4 8 16 2 4 8 16 32 64 128 256
Number of256 128 64 32 16 8 4 2 - Hosts
195. 223 . 50 . 0 0 0 0 0 0 0 0 195. 223 . 50 . 0 0 0 0 0 0 0 0 195. 223 . 50 . 0 0 0 0 0 0 0 0 195. 223 . 50 . 0 0 0 0 0 0 0 0 195. 223 . 50 . 0 0 0 0 0 0 0 0
_______________________________________________
________________________
________________________
______________________________________
34
Subnetting
Problem 4Number of needed subnets
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
750190.35.0.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 15thsubnet range?
What is the subnet numberfor the 13th subnet?
What is the subnetbroadcast address for
the 10th subnet?
What are the assignableaddresses for the 6th
subnet?
_______________________________________________
________________________
________________________
______________________________________
36
Subnetting
Problem 5Number of needed usable hosts
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
6126.0.0.0
__________
_______________________________
_______________________________
___________________
________________
___________________
___________________
What is the 2ndsubnet range?
What is the subnet numberfor the 5th subnet?
What is the subnetbroadcast address for
the 7th subnet?
What are the assignableaddresses for the 10th
subnet?
_______________________________________________
________________________
________________________
______________________________________
38
Subnetting
Problem 6Number of needed subnets
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
10192.70.10.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 9thsubnet range?
What is the subnet numberfor the 4th subnet?
What is the subnetbroadcast address for
the 12th subnet?
What are the assignableaddresses for the 10th
subnet?
40
Subnetting
Problem 7Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
10.0.0.0 /16
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 11thsubnet range?
What is the subnet numberfor the 6th subnet?
What is the subnetbroadcast address for
the 2nd subnet?
What are the assignableaddresses for the 9th
subnet?
_______________________________________________
________________________
________________________
______________________________________
_______________________________________________
________________________
________________________
______________________________________
42
Subnetting
Problem 8Number of needed subnets
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
5172.50.0.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 4thsubnet range?
What is the subnet numberfor the 5th subnet?
What is the subnetbroadcast address for
the 6th subnet?
What are the assignableaddresses for the 3rd
subnet?
_______________________________________________
________________________
________________________
______________________________________
44
Subnetting
Problem 9Number of needed usable hosts
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
28172.50.0.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 2ndsubnet range?
What is the subnet numberfor the 10th subnet?
What is the subnet broadcastaddress for
the 4th subnet?
What are the assignableaddresses for the 6th
subnet?
_______________________________________________
________________________
________________________
______________________________________
46
Subnetting
Problem 10Number of needed subnets
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
45220.100.100.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 5thsubnet range?
What is the subnet numberfor the 4th subnet?
What is the subnetbroadcast address for
the 13th subnet?
What are the assignableaddresses for the 12th
subnet?
_______________________________________________
________________________
________________________
______________________________________
48
Subnetting
Problem 11Number of needed usable hosts
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
8,000135.70.0.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 6thsubnet range?
What is the subnet numberfor the 7th subnet?
What is the subnetbroadcast address for
the 3rd subnet?
What are the assignableaddresses for the 5th
subnet?
_______________________________________________
________________________
________________________
______________________________________
50
Subnetting
Problem 12Number of needed usable hosts
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
45198.125.50.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 2ndsubnet range?
What is the subnet numberfor the 2nd subnet?
What is the subnetbroadcast address for
the 4th subnet?
What are the assignableaddresses for the 3rd
subnet?
_______________________________________________
________________________
________________________
______________________________________
52
Subnetting
Problem 13Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
165.200.0.0 /26
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 10thsubnet range?
What is the subnet numberfor the 11th subnet?
What is the subnetbroadcast address for
the 1023rd subnet?
What are the assignableaddresses for the 1022nd
subnet?
_______________________________________________
________________________
________________________
______________________________________
54
Subnetting
Problem 14Number of needed usable hosts
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
16200.10.10.0
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 7thsubnet range?
What is the subnet numberfor the 5th subnet?
What is the subnetbroadcast address for
the 4th subnet?
What are the assignableaddresses for the 6th
subnet?
56
Subnetting
Problem 15Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
93.0.0.0 \19
__________
_______________________________
_______________________________
___________________
___________________
___________________
___________________
What is the 15thsubnet range?
What is the subnet numberfor the 9th subnet?
What is the subnetbroadcast address for
the 7th subnet?
What are the assignableaddresses for the 12th
subnet?
_______________________________________________
________________________
________________________
______________________________________
58
Practical Subnetting 1
F0/1F0/0
S0/0/0 S0/0/1Router A
Router B
Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for100% growth in both areas. Circle each subnet on the graphic and answer the questionsbelow.
Marketing24 Hosts
Management15 Hosts
F0/0
Reasearch60 Hosts
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 100% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for100% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Research
IP address range for Marketing
IP address range for Management
IP address range for Router Ato Router B serial connection
IP Address 172.16.0.0
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
B255.255.224.0
44
8
60
60
120
+
+
=
=
172.16.0.0 to 172.31.255172.16.32.0 to 172.63.255172.16.64.0 to 172.95.255
172.16.96.0 to 172.127.255
59
Show your work for Practical Subnetting 1 in the space below.
172
. 16
. 0
0
0 0
0
0
0 0
. 0
0
0
0 0
0
0
017
2 .
16 .
0 0
0
0
0 0
0
0 .
0
0 0
0
0
0 0
0
172
. 16
. 0
0
0 0
0
0
0 0
. 0
0
0
0 0
0
0
017
2 .
16 .
0 0
0
0
0 0
0
0 .
0
0 0
0
0
0 0
0
172
. 16
. 0
0
0 0
0
0
0 0
. 0
0
0
0 0
0
0
012
8 6
4 3
2 16
8
4
2
1
Num
ber
of S
ubne
ts
-
2
4
8
16 3
2 6
4 1
28
25
6 .
. 25
6 12
8 6
4 32
16
8
4
2
128
64
32
16
8
4
2
1
.... .
512
Bin
ary
valu
es -
Num
ber
ofH
osts
-
102420484,0968,192
16,384
32,76865,536
512
1,024
2,048
4,096
8,192
16,384
32,768
65,536
0 1 0 1 0 1 0 1
1 1 0 0 1 1
1 1 1 1
172
.16.
0.0
172
.16.
32.0
172
.16.
64.0
172
.16.
96.0
172
.16.
128.
017
2.1
6.16
0.0
172
.16.
192
.017
2.1
6.2
24.
0
to to to to to to to to
172
.16.
31.2
55
172
.16.
63.2
55
172
.16.
95.2
55
172
.16.
127.
25
517
2.1
6.15
9.2
55
172
.16.
191.
25
517
2.1
6.2
23.
25
517
2.1
6.2
55
.25
5
(0)
(1)
(2)
(3)
(4)
(5)
(6)
(7)
60 x1.0 604
x1.0 4
60
Practical Subnetting 2
F0/0S0/0/0
S0/0/1Router A
Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 30% growth in all areas. Circle each subnet on the graphic and answer the questionsbelow.
Science Lab10 Hosts
Tech Ed Lab20 Hosts
F0/0
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 30% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for30% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Tech Ed
IP address range for English
IP address range for Science
IP address range for Router Ato Router B serial connection
IP address range for Router Ato Router B serial connection
IP Address 135.126.0.0
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Router BS0/0/1
Router C
English Department15 Hosts
F0/1
F0/1
S0/0/0
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
52
7
20
6
26
B255.255.255.224
135.126.0.0 to 135.126.0.31135.126.0.32 to 135.126.0.63135.126.0.64 to 135.126.0.95
135.126.0.96 to 135.126.0.127
135.126.0.128 to 135.126.0.159
61
Show your work for Problem 2 in the space below.
135
. 12
6 . 0
0
0
0 0
0
0
0 .
0 0
0
0
0 0
0
013
5. 1
26
. 0
0 0
0
0
0 0
0
. 0
0
0 0
0
0
0 0
135
. 12
6 . 0
0
0
0 0
0
0
0 .
0 0
0
0
0 0
0
013
5. 1
26
. 0
0 0
0
0
0 0
0
. 0
0
0 0
0
0
0 0
135
. 12
6 . 0
0
0
0 0
0
0
0 .
0 0
0
0
0 0
0
012
8 6
4 3
2 16
8
4
2
1
Num
ber
of S
ubne
ts
-
2
4
8
16 3
2 6
4 1
28
25
6 .
. 25
6 12
8 6
4 32
16
8
4
2
128
64
32
16
8
4
2
1
.... .
512
Bin
ary
valu
es -
Num
ber
ofH
osts
-
102420484,0968,192
16,384
32,76865,536
512
1,024
2,048
4,096
8,192
16,384
32,768
65,536
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
1 1 0 0 1 1 0 0 1 1 0 0 1 1
1 1 1 1 0 0 0 0 1 1 1 1
1 1 1 1 1 1 1 1
. . . . . . . . .
135.
126.0
.013
5.12
6.0.32
135.
126.0
.6413
5.12
6.0.96
135.
126.0
.128
135.
126.0
.160
135.
126.0
.192
135.
126.0
.224
135.
126.1
.013
5.12
6.1.32
135.
126.1
.6413
5.12
6.1.96
135.
126.1
.128
135.
126.1
.160
135.
126.1
.192
135.
1261
.224
to to to to to to to to to to to to to to to to
135.
126.0
.3113
5.12
6.0.63
135.
126.0
.9513
5.12
6.0.12
713
5.12
6.0.15
913
5.12
6.0.19
113
5.12
6.0.2
2313
5.12
6.0.2
5513
5.12
6.1.31
135.
126.1
.6313
5.12
6.1.95
135.
126.1
.127
135.
126.1
.159
135.
126.1
.191
135.
126.1
.223
135.
126.1
.255
(0)
(1)
(2)
(3)
(4)
(5)
(6)
(7)
(8)
(9)
(10)
(11)
(12)
(13)
(14)
(15)
5 x.3 1.5
(Rou
nd u
p to
2)
20 x.3 6
62
Practical Subnetting 3Based on the information in the graphic shown, design a classfull network addressing schemethat will supply the minimum number of hosts per subnet, and allow enough extra subnetsand hosts for 25% growth in all areas. Circle each subnet on the graphic and answer thequestions below.
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 25% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for25% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Sales
IP address range for Marketing
IP address range for Administrative
IP address range for Router Ato Router B serial connection
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
F0/0
Administrative30 Hosts
Sales185 Hosts
F0/0
IP Address 172.16.0.0
S0/0/1
Marketing50 Hosts
F0/1 S0/0/0Router A
Router B
64
Practical Subnetting 4
F0/0 S0/0/0S0/0/1Router A
Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for 70%growth in all areas. Circle each subnet on the graphic and answer the questions below.
Dallas150 Hosts New York
325 Hosts
F0/0
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 70% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for70% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for New York
IP address range for Washington D. C.
IP address range for Dallas
IP address range for Router Ato Router B serial connection
IP address range for Router Ato Router C serial connection
IP Address 135.126.0.0
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Router BS0/0/1
Router C F0/0F0/1
S0/0/0
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
Washington D.C.220 Hosts
66
Practical Subnetting 5Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 100% growth in all areas. Circle each subnet on the graphic and answer thequestions below.
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 100% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for100% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Router F0/0 Port
IP address range for Router F0/1 Port
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
F0/0
Science Room10 Hosts
Tech Ed Lab18 Hosts
English classroom15 Hosts
F0/1
Art Classroom12 Hosts
IP Address 210.15.10.0
68
Practical Subnetting 6Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for 20%growth in all areas. Circle each subnet on the graphic and answer the questions below.
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 20% growth
Total number of subnets needed
IP address range for Technology
IP address range for Science
IP address range for Arts & Drama
IP Address range Administration
IP address range for Router Ato Router B serial connection
IP address range for Router Ato Router C serial connection
IP address range for Router Bto Router C serial connection
IP Address 10.0.0.0
_____________________________
_____________________________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
=
F0/0
S0/0/1Router A
Administration35 Hosts
TechnologyBuilding320 HostsF0/0 Router B
S0/0/1
Router C
F0/1
F0/1
S0/0/0
Science Building225 Hosts
S0/0/0
S0/0/1S0/0/0Art & Drama
75 Hosts
70
Practical Subnetting 7Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 125% growth in all areas. Circle each subnet on the graphic and answer thequestions below.
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 125% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for125% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Router A Port F0/0
IP address range for Research
IP address range for Deployment
IP address range for Router Ato Router B serial connection
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
Marketing75 Hosts
IP Address 177.135.0.0
Administration33 Hosts Sales
255 Hosts
Research135 Hosts
F0/0S0/0/0 F0/0
F0/1
S0/0/0Router A
Router B
Deployment63 Hosts
72
Practical Subnetting 8
F0/0 S0/0/0S0/0/1Router A
Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number subnets, and allow enough extra subnets and hosts for 85%growth in all areas. Circle each subnet on the graphic and answer the questions below.
New York8 Hosts
F0/0
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 85% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for85% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Router A F0/0
IP address range for New York
IP address range for Router Ato Router B serial connection
IP Address 192.168.1.0
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Router B
F0/1
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
Boston5 Hosts
Research & Development8 Hosts
Practical Subnetting 9
F0/0
S0/0/0S0/0/1Router A
Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 15% growth in all areas. Circle each subnet on the graphic and answer the questionsbelow.
Dallas1500 Hosts
F0/0
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 15% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for15% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Ft. Worth
IP address range for Dallas
IP address range for Router Ato Router B serial connection
IP address range for Router Ato Router C serial connection
IP address range for Router Cto Router D serial connection
IP Address 148.55.0.0
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Router BS0/0/1
Router C
F0/1
S0/0/0
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
Router D S0/0/0S0/0/1
74
Ft. Worth2300 Hosts
76
Practical Subnetting 10Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for110% growth in all areas. Circle each subnet on the graphic and answer the questions below.
Address class
Custom subnet mask
Minimum number of subnets needed
Extra subnets required for 110% growth
Total number of subnets needed
Number of host addresses in the largest subnet group
Number of addresses needed for110% growth in the largest subnet
Total number of addressneeded for the largest subnet
IP address range for Sales/Managemnt
IP address range for Marketing
IP address range for Research
IP address range for Router Ato Router B serial connection
IP Address 172.16.0.0
_____________________________
_____________________________
_________
_________
_________
_________
_________
_________
_____________________________
_____________________________
_____________________________
_____________________________
(Round up to the next whole number)
(Round up to the next whole number)
Start with the first subnet and arrange your sub-networks from the largest group to the smallest.
+
+
=
=
F0/0S0/0/0
S0/0/1Router A
F0/0
Router B
F0/1
Sales115 Hosts
Management25 Hosts
Research35 Hosts
Marketing56 Hosts
Valid and Non-Valid IP Addresses
Using the material in this workbook identify which of the addresses below are correct andusable. If they are not usable addresses explain why.
IP Address: 0.230.190.192 ________________________________Subnet Mask: 255.0.0.0 ________________________________
IP Address: 192.10.10.1 ________________________________Subnet Mask: 255.255.255.0 ________________________________
IP Address: 245.150.190.10 ________________________________Subnet Mask: 255.255.255.0 ________________________________
IP Address: 135.70.191.255 ________________________________Subnet Mask: 255.255.254.0 ________________________________
IP Address: 127.100.100.10 ________________________________Subnet Mask: 255.0.0.0 ________________________________
IP Address: 93.0.128.1 ________________________________Subnet Mask: 255.255.224.0 ________________________________
IP Address: 200.10.10.128 ________________________________Subnet Mask: 255.255.255.224 ________________________________
IP Address: 165.100.255.189 ________________________________Subnet Mask: 255.255.255.192 ________________________________
IP Address: 190.35.0.10 ________________________________Subnet Mask: 255.255.255.192 ________________________________
IP Address: 218.35.50.195 ________________________________Subnet Mask: 255.255.0.0 ________________________________
IP Address: 200.10.10.175 /22 ________________________________________________________________
IP Address: 135.70.255.255 ________________________________Subnet Mask: 255.255.224.0 ________________________________
The network ID cannot be 0.
OK
78
Reference Pages 28-29
Reference Page Inside Front Cover
Reference Pages 48-49
Reference Pages 54-55
Reference Page Inside Front Cover
Reference Page Inside Front Cover
Reference Pages 54-55 and/or Inside Front Cover
Reference Pages 56-57
Reference Pages Inside Front Cover
Reference Pages 34-35
Reference Pages 30-31
Reference Pages 48-49
0-127
128-255
0-34-78-11
12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99
100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255
/308+8+8+6
255.255.255.2524 Hosts
/298+8+8+5
255.255.255.2488 Hosts
/288+8+8+4
255.255.255.24016 Hosts
/278+8+8+3
255.255.255.22432 Hosts
/268+8+8+2
255.255.255.19264 Hosts
/258+8+8+1
255.255.255.128128 Hosts
/248+8+8
255.255.255.0256 Hosts
0-7
8-15
16-23
24-31
32-39
40-47
48-55
56-63
64-71
72-79
80-87
88-95
96-103
104-111
112-119
120-127
128-135
136-143
144-151
152-159
16-167
168-175
176-183
184-191
192-199
200-207
208-215
216-223
224-231
232-239
240-247
248-255
0-15
16-31
32-47
48-63
64-79
80-95
96-111
112-127
128-143
144-159
160-175
176-191
192-207
208-223
224-239
240-255
0-63
64-127
128-191
192-255
0-255
IP Address Breakdown
79
/24255.255.255.0
256 Hosts1 Subnet
Start with a square. The whole squareis a single subnet comprised of 256addresses.
Visualizing Subnets UsingThe Box Method
The box method is the simplest way to visualize the breakdown ofsubnets and addresses into smaller sizes.
/25255.255.255.128
128 Hosts2 Subnets
/26255.255.255.192
64 Hosts4 Subnets
80
Split the box in half and you get twosubnets with 128 addresses,
Divide the box into quarters and youget four subnets with 64 addresses,
81
/27255.255.255.224
32 Hosts8 Subnets
Split each individual square and youget eight subnets with 32 addresses,
/30255.255.255.252
4 Hosts64 Subnets
/29255.255.255.248
8 Hosts32 Subnets
/28255.255.255.240
16 Hosts16 Subnets
Split the boxes in half again and youget sixteen subnets with sixteenaddresses,
The next split gives you thirty twosubnets with eight addresses,
The last split gives sixty four subnetswith four addresses each,
82
# of BitsBorrowed
012345678910111213141516171819202122
SubnetMask
255.0.0.0255.128.0.0255.192.0.0255.224.0.0255.240.0.0255.248.0.0255.252.0.0255.254.0.0255.255.0.0
255.255.128.0255.255.192.0255.255.224.0255.255.240.0255.255.248.0255.255.252.0255.255.254.0255.255.255.0
255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252
Total # ofSubnets
1248163264128256512
1,0242,0484,0968,19216,38432,76865,536131,072262,144524,288
1,048,5762,097,1524,194,304
Total # ofHosts
16,777,2168,388,6084,194,3042,097,1521,048,576524,288262,144131,07265,53632,76816,3848,1924,0962,0481,02451225612864321684
Usable # ofHosts
16,777,2148,388,6064,194,3022,097,1501,048,574524,286262,142131,07065,53432,76616,3828,1904,0942,0461,02251025412662301462
# of BitsBorrowed
01234567891011121314
SubnetMask
255.255.0.0255.255.128.0255.255.192.0255.255.224.0255.255.240.0255.255.248.0255.255.252.0255.255.254.0255.255.255.0
255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252
Total # ofSubnets
1248163264128256512
1,0242,0484,0968,19216,384
Total # ofHosts65,53632,76816,3848,1924,0962,0481,02451225612864321684
Usable # ofHosts65,53432,76616,3828,1904,0942,0461,02251025412662301462
Class C Addressing Guide# of Bits
Borrowed0123456
SubnetMask
255.255.255.0255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252
Total # ofSubnets
1248163264
Total # ofHosts
25612864321684
Usable # ofHosts
25412662301462
CIDR/8/9/10/11/12/13/14/15/16/17/18/19/20/21/22/23/24/25/26/27/28/29/30
CIDR/16/17/18/19/20/21/22/23/24/25/26/27/28/29/30
CIDR/24/25/26/27/28/29/30
Class B Addressing Guide
Class A Addressing Guide
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_____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
Produced by: Robb Jones [email protected] Frederick County Career & Technology Center Cisco Networking Academy Frederick County Public Schools Frederick, Maryland, USA
