Study of a Single Effect Evaporator
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Transcript of Study of a Single Effect Evaporator
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ChE 30
Chemical engineering laboratory - II
Experiment No. Group No. 03 (A2)
Name of the experiment:
STUDY OF A SINGLE EFFECT EVAPORATOR
Submitted by:
Md. Hasib Al Mahbub
Student Id: 0902045
Level: 3; Term: 2
Section: A2
Date of performance:28/01/2014
Date of submission:11/02/2014
Partners Student Id.0902041
0902042
0902043
0902044
Department of Chemical Engineering.
Bangladesh University of engineering and technology, Dhaka.
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Summary
The main objective of this experiment was to study, operate and obtain characteristics, to
perform material and energy balance and to determine steam economy which denotes the
efficiency of the whole evaporating operation of a single effect evaporator. This process
involved evaporation of only water in a still and steam at 10 psig is supplied to the still to heat
the water for evaporating. The vapor produced in the column goes to condenser and in a
condensate collected tank it was collected to find out the total amount of vapor formed with
time. Using the observed experimental data cumulative steam economy as well as overall steam
economy was calculated .The values of cumulative steam economy range was 0-0.19548 and
steam economy range for each observation was 0-0.960837and the overall steam economy was
0.1955 .The overall heat loss was 131.902 MJ. A graph between vapor condensation rates vs.
cumulative time was plotted. The graph shows that the time required to reach steady state
condition was high. There were some discrepancies in the experiment. The possible cause of
other discrepancies discussed in discussions.
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Temperature
of Vapor
Steam Pressure
EvaporatorPressure
Temperature
of Still
Steam In
Feed In
Drain
Stream Trap
Steam Chest
Evaporator
Water Level
Entrain
Separator
Condenser
CondensateDrum
Cooling
Water Temp.
Figure 1: Experimental setup of a single effect evaporator
ExperimentalSetup
2
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Flow Diagram
Figure 2: Flow diagram of the system
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Observed Data
Steam pressure = 10 Psig
Weight of bucket1=0.65 Kg
Weight of bucket2= 0.70 KgTime interval = 180 Sec
Condensate tank perimeter = 76 inch
Cooling water flow rate = 0.23 Kg/Sec
Cooling water inlet temperature = 74 oF
Cooling water outlet temperature = 80 oFTable-1: Observed data for study of single effect evaporator.
Obs.
No.
Vapor space
Temperature
( oF )
Still
Temperature
( oF )
Steam
condensate
Time (Sec)
Level of
vapor
condensate
( cm)
Steam
condensate
+
Bucket1
(kg)
Steam
condensate
+
Bucket2
(kg)1 68 100 180 91.9 6.5 -
2 72 122 180 91.9 - 5
3 76 144 180 91.9 4.35 -
4 84 160 180 91.9 - 3.95
5 96 174 180 91.9 3.3 -
6 108 180 180 91.9 - 2.87 120 186 180 91.9 2.75 -
8 130 190 180 91.9 - 2.5
9 146 196 180 91.9 2.3 -
10 188 206 180 91.9 - 2.5
11 210 206 180 91.9 2.25 -
12 212 206 180 91.3 - 2.55
13 212 206 180 91.1 2.45 -
14 212 206 180 90.9 - 2.4
15 212 206 180 90.7 2.5 -
16 212 206 180 90.5 - 2.6
17 212 206 180 90.3 2.3 -18 212 206 180 90.0 - 2.3
19 212 206 180 89.8 2.6 -
20 212 206 180 89.5 - 2.6
21 212 206 180 89.2 2.72 -
22 212 206 180 88.9 - 4.15
23 212 206 180 88.6 3.5 -
24 212 206 180 88.2 - 4
25 212 206 180 87.9 2.6 -
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Calculated DataTable-2: Calculated data for study of single effect evaporator.
Obs.
No.
Time
(sec)
Cumulative
height ofvapor
condensate(m)
Water
evaporated(Kg)
Water
condensationrate
Kg/Sec
Steam
condensate(Kg)
Rate of steam
condensation(Kg / Sec )
1 180 0 0 5.85 0.0325
2 180 0 0 0 4.30 0.0238
3 180 0 0 0 3.70 0.0205
4 180 0 0 0 3.25 0.0180
5 180 0 0 0 2.65 0.0147
6 180 0 0 0 2.10 0.0116
7 180 0 0 0 2.10 0.0116
8 180 0 0 0 1.80 0.01009 180 0 0 0 1.65 0.0091
10 180 0 0 0 1.80 0.0100
11 180 0 0 0 1.60 0.0088
12 180 0.006 1.7775 0.0098 1.85 0.0103
13 180 0.008 0.5925 0.0033 1.80 0.0100
14 180 0.010 0.5925 0.0033 1.70 0.0094
15 180 0.012 0.5925 0.0033 1.85 0.0103
16 180 0.014 0.5925 0.0033 1.90 0.0106
17 180 0.016 0.5925 0.0033 1.65 0.0092
18 180 0.019 0.8887 0.0049 1.60 0.0088
19 180 0.021 0.5925 0.0033 1.95 0.010820 180 0.024 0.8887 0.0049 1.90 0.0105
21 180 0.027 0.8887 0.0049 2.07 0.0115
22 180 0.030 0.8887 0.0049 3.45 0.0191
23 180 0.033 0.8887 0.0049 2.85 0.0158
24 180 0.037 1.1850 0.0065 3.30 0.0183
25 180 0.040 0.8887 0.0049 1.95 0.0108
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Table-3: Calculated data for study of single effect evaporator.
Obs. No. Cumulative
wt. of steam
cond.(Kg)
Cumulative
Steam
economy
Steam
economy
for each
observation
Heat
recovered
by
steam(MJ)
Heat
absorbed
by
water(MJ)
Heat
loss(MJ)
1 5.850 0 0 15.789 0 15.789
2 10.15 0 0 27.394 0 27.394
3 13.85 0 0 37.380 0 37.380
4 17.10 0 0 46.152 0 46.152
5 19.75 0 0 53.304 0 53.304
6 21.85 0 0 58.972 0 58.972
7 23.95 0 0 64.640 0 64.640
8 25.75 0 0 69.498 0 69.498
9 27.40 0 0 73.952 0 73.952
10 29.20 0 0 78.810 0 78.810
11 30.80 0 0 83.128 0 83.128
12 32.65 0.05444 0.960837 88.121 4.755 83.365
13 34.45 0.06879 0.329176 92.979 6.341 86.638
14 36.15 0.08195 0.348539 97.568 7.926 89.641
15 38.00 0.09355 0.320279 102.56 9.511 93.049
16 39.90 0.10395 0.311851 107.68 11.09 96.592
17 41.55 0.11408 0.359101 112.14 12.68 99.460
18 43.15 0.13044 0.555484 116.46 15.06 101.40
19 45.10 0.13794 0.303854 121.72 16.64 105.07
20 47.00 0.15128 0.467776 126.85 19.02 107.82
21 49.07 0.16301 0.429359 132.43 21.40 111.03
22 52.52 0.16922 0.257616 141.75 23.77 117.9723 55.37 0.17656 0.311851 149.44 26.15 123.28
24 58.67 0.18683 0.359101 158.34 29.32 129.02
25 60.62 0.19548 0.455782 163.61 31.70 131.90
Table-4: Calculated data for study of single effect evaporator.
Overall steam
economy
Overall heat
released from
steam (MJ)
Overall heat
recovered by
water(MJ)
Overall Heat loss
(MJ)
0.1955 163.612 31.705 131.902
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Sample CalculationFor Observation no. 16
Steam condensate flow rate = {(2.60.7) / 180} kg /sec= 0.011 kg /sec
Perimeter of storage tank = 76 inch = 1.9304 m
Inner radius of storage tank, r = {1.9304 / (2)} m
= 0.3072 m
Level of water vapor storage tank, h12= 90.3 cm =0.903 m
Level of water vapor storage tank, h13= 90.0 cm =0.90 m
Volume of water vapor condensate = r2h
= { (0.3072)2 (0.903-0.90)} m3
= 8.8943x 10-4m3
Water vapor condensed in the condenser = Water evaporated in the feed tank
From Franzini (Table: A-1)
Density of water, = 1000 kg /m3
Mass of water evaporated, m = (8.8943 10-41000) kg
= 0.88943 kg
Total mass of steam condensate, m1= 60.62 kg
Total mass of water evaporated, m2 = 11.85 kg
Overall steam economy = (Total mass of water evaporated / Total mass of steam consumed)
= (11.85 / 60.62)
= 0.1955
Cumulative mass of water evaporate = 4.1476 kg
Cumulative mass of steam condensate= 39.9 kg
Cumulate steam economy= (Cumulative mass of water evaporated / Cumulative mass of
steam)
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Cumulate steam economy = (4.1476/39.9)
= 0.1039
Calculation of steam economy for Observation no. 15
Mass of water evaporate = 0.5925 Kg
Mass of steam condensate = 1.9 Kg
Steam economy = (Mass of water evaporated / Mass of steam consumed)
= (.5925/1.9)
= 0.3118
Enthalpy balance
Steam pressure = 10 psig = 24.7 psia
At 24.7 psia , Tsat= 115.203oC
Enthalpy of evaporation, Hv1= 2698.985 KJ /Kg
Cumulative heat released from steam, Q1= m13 Hv1
= (39.9 x 2698.985) KJ
= 107.69 MJ
Overall heat released from steam, Q1,ov= mtotalHv1
= (60.62 2698.985) KJ
=163.612 MJ
At, condenser pressure= 14.7 Psia , Tsat=100oC
Enthalpy of evaporation, Hv2= 2675.57 kJ/ kg
Cumulative heat recovered by water, Q2= m13 Hv2
= (4.1476 2675.57) KJ
= 11.097MJ
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Overall heat recovered by water, Q2 ov= mtotal Hv2
= (11.85 2675.57) KJ
= 31.705 MJ
Cumulative heat loss , H = Q1Q2
= (107.6911.097) MJ
= 96.586 MJ
Overall heat loss, H = Q1 ovQ2 ov
= (163.61231.705) MJ
= 131.902 MJ
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Results and Discussions
Table-5: Range of result for various observation of single effect evaporator.
Ranges of steam
economy for
each observation
Range of
cumulative heat
loss (MJ)
Range of
cumulative
steam economy
Overall heat
loss(MJ)
Overall steam
economy
0-0.960837 15.789-131.90 0-0.19548 131.902 0.1955
From vapor condensation rate Vs. cumulative time curve, it was observed that at beginning rate
increases with time and go through the pick point its to a steady state condition. This state arrived after
40 minutes.
In this experiment, the steam economy is very low because of single effect evaporator. Steam economy
would be greater if multiple effect evaporator was used. Heat loss is very high .The possible reasons for
this high heat loss are discussed below
In this experiment, we converted a double effect evaporator to a single effect evaporator byclosing some valves. The total unit of heat exchanger was too old to perform and lost its actual
insulation. Therefore, energy could be lost in the surroundings.
The inlet steam was collided at the steam chest and thus condensed and lost its energy. The evaporator, condenser, other apparatus used, and the internal pipe network could absorb
some energy.
Moreover, the result could be varied due to the error reading of the mass of condensed steamand height of condensed vapor.