STRUCTURAL CALCULATIONS FOR REAR EXTENSION AND LOFT … … · New Lintel L2 is to be 1No. 1950mm...
Transcript of STRUCTURAL CALCULATIONS FOR REAR EXTENSION AND LOFT … … · New Lintel L2 is to be 1No. 1950mm...
Structural Calculations for Double Storey Rear Extension and Loft Conversion
Samir PatelDW 06/05/2018 A
Ruthin Road Blackheath
SE3 7SH
CALCULATION SHEET
PROJECT
CALCULATIONS FOR
ORIGINATOR DATE PAGE REVISION
00
This calculation pack contains the following:
Beam and Roof Layout PlansLintel Calculation Beams Calculation Connection DetailsTimber DesignStrip Footing Design Structural design notes
(Pages 01 - 02)(Pages 03 - 11)(Pages 12 - 29)(Pages 30 - 35)(Pages 36 - 42)(Pages 43 - 44)(Pages 45)
STRUCTURAL CALCULATIONS FOR DOUBLE STOREYREAR EXTENSION AND LOFT CONVERSION
New Lintel L1 is to be 1No. 3150mm Catnic LintelNew Lintel L2 is to be 1No. 1950mm Catnic LintelNew Lintel L3 is to be 1No. 2250mm Catnic LintelNew Beam B1 is to be 1No. 152x152x30 UBNew Beam B2 is to be 1No. 152x152x30 UBNew Beam B3 is to be 1No. 254x254x73 UBNew Beam B4 is to be 1No. 254x254x73 UB Extension Floor Joists are to be 47x175 C24 Timbers at Max. 400mm centres
Loft Floor Joists are to be 47x200 C24 Timbers at Max. 200mm centresLoft Floor Joists are to be 47x175 C24 Timbers at Max. 600mm centresNew Strip Footing is to be 500x400 Unreinforced Concrete
Executive Summary
2
Lintel Calculation
Lintel L1
LINTEL ANALYSIS
In accordance with BS5977-1:1981 incorporating Amendment No. 1 Tedds calculation version 1.1.00
Masonry
2750
302527
00
Basic lintel dimensions;Lintel clear span; Lc1 = 2750 mm
Lintel load application length; L = Lc1 1.1 = 3025 mm
Load zone height; hLZ = tan(45) L / 2 = 1513 mm
Interaction zone height; hIZ = tan(60) L / 2 = 2620 mm
Load factorsDead load factor; LFd = 1.40Imposed load factor; LFI = 1.60
MasonryMasonry height; hm = 2700 mm
Leaf 1;
Masonry density; mi = 20.00 kN/m3
Masonry thickness; twi = 100 mm
Load at midspan; wmi = hLZ twi mi = 3.025 kN/m
Cavity width; tcav = 100 mm
Leaf 2;
Masonry density; mo = 20.00 kN/m3
Masonry thickness; two = 100 mm
Load at midspan; wmo = hLZ two mo = 3.025 kN/m
Lintel Calculation
Lintel L1
Lintel self weightSelf weight of lintel; wlsw = 1.000 kN/m
Masonry load zoneHeight of load zone; hLZ = L / 2 = 1513 mm
Total masonry area; ALZ = hLZ L / 2 = 2.288 m2
Total masonry load; WLZ = ALZ (two mo + twi mi) = 9.151 kN
Equivalent UDL; wEquiv_LZ = WLZ 1.33 / L = 4.023 kN/m
Load application summary;
Load DescriptionUDL total
length(mm)
Start of UDLon lintel
(mm)
End of UDLon lintel
(mm)
Equiv.dead loadon lintel(kN/m)
Equiv.imposed load
on lintel(kN/m)
Masonry from load triangle 3025 0 3025 4.023 0.000
Analysis results at ULSMaximum moment; Mmax = 8.060 kNm
Maximum shear; Vmax = 8.523 kN
Maximum reaction at support A; RA_max = 8.523 kN
Maximum reaction at support B; RB_max = 8.523 kN
Support reactions at SLSDead loads
Reaction at support A; RA_DL = 6.088 kN
Reaction at support B; RB_DL = 6.088 kN
Imposed loads
Reaction at support A; RA_IL = 0.000 kN
Reaction at support B; RB_IL = 0.000 kN
Equivalent UDL at SLSTotal equivalent UDL (inc. selfweight); we = 5.023 kN/m
8.1
0
Moment
Lintel Calculation
Lintel L1
8.5
-8.5
Shear
Choosen Catnic lintel size: 3150 mm
Lintel Calculation
Lintel L2
LINTEL ANALYSIS
In accordance with BS5977-1:1981 incorporating Amendment No. 1 Tedds calculation version 1.1.00
Masonry
1728
1901
270
0
Basic lintel dimensions;Lintel clear span; Lc1 = 1728 mm
Lintel load application length; L = Lc1 1.1 = 1901 mm
Load zone height; hLZ = tan(45) L / 2 = 950 mm
Interaction zone height; hIZ = tan(60) L / 2 = 1646 mm
Load factorsDead load factor; LFd = 1.40Imposed load factor; LFI = 1.60
MasonryMasonry height; hm = 2700 mm
Leaf 1;
Masonry density; mi = 20.00 kN/m3
Masonry thickness; twi = 100 mm
Load at midspan; wmi = hLZ twi mi = 1.901 kN/m
Cavity width; tcav = 100 mm
Leaf 2;
Masonry density; mo = 20.00 kN/m3
Masonry thickness; two = 100 mm
Load at midspan; wmo = hLZ two mo = 1.901 kN/m
Lintel Calculation
Lintel L2
Lintel self weightSelf weight of lintel; wlsw = 1.000 kN/m
Masonry load zoneHeight of load zone; hLZ = L / 2 = 950 mm
Total masonry area; ALZ = hLZ L / 2 = 0.903 m2
Total masonry load; WLZ = ALZ (two mo + twi mi) = 3.613 kN
Equivalent UDL; wEquiv_LZ = WLZ 1.33 / L = 2.528 kN/m
Load application summary;
Load DescriptionUDL total
length(mm)
Start of UDLon lintel
(mm)
End of UDLon lintel
(mm)
Equiv.dead loadon lintel(kN/m)
Equiv.imposed load
on lintel(kN/m)
Masonry from load triangle 1901 0 1901 2.528 0.000
Analysis results at ULSMaximum moment; Mmax = 2.235 kNm
Maximum shear; Vmax = 3.860 kN
Maximum reaction at support A; RA_max = 3.860 kN
Maximum reaction at support B; RB_max = 3.860 kN
Support reactions at SLSDead loads
Reaction at support A; RA_DL = 2.757 kN
Reaction at support B; RB_DL = 2.757 kN
Imposed loads
Reaction at support A; RA_IL = 0.000 kN
Reaction at support B; RB_IL = 0.000 kN
Equivalent UDL at SLSTotal equivalent UDL (inc. selfweight); we = 3.528 kN/m
2.2
0
Moment
Lintel Calculation
Lintel L2
3.9
-3.9
Shear
Choosen Catnic lintel size: 1950 mm
Lintel Calculation
Lintel L3
LINTEL ANALYSIS
In accordance with BS5977-1:1981 incorporating Amendment No. 1 Tedds calculation version 1.1.00
Masonry
2010
2211
27
00
Basic lintel dimensions;Lintel clear span; Lc1 = 2010 mm
Lintel load application length; L = Lc1 1.1 = 2211 mm
Load zone height; hLZ = tan(45) L / 2 = 1106 mm
Interaction zone height; hIZ = tan(60) L / 2 = 1915 mm
Load factorsDead load factor; LFd = 1.40Imposed load factor; LFI = 1.60
MasonryMasonry height; hm = 2700 mm
Leaf 1;
Masonry density; mi = 20.00 kN/m3
Masonry thickness; twi = 100 mm
Load at midspan; wmi = hLZ twi mi = 2.211 kN/m
Cavity width; tcav = 100 mm
Leaf 2;
Masonry density; mo = 20.00 kN/m3
Masonry thickness; two = 100 mm
Load at midspan; wmo = hLZ two mo = 2.211 kN/m
Lintel Calculation
Lintel L3
Lintel self weightSelf weight of lintel; wlsw = 1.000 kN/m
Masonry load zoneHeight of load zone; hLZ = L / 2 = 1106 mm
Total masonry area; ALZ = hLZ L / 2 = 1.222 m2
Total masonry load; WLZ = ALZ (two mo + twi mi) = 4.889 kN
Equivalent UDL; wEquiv_LZ = WLZ 1.33 / L = 2.941 kN/m
Load application summary;
Load DescriptionUDL total
length(mm)
Start of UDLon lintel
(mm)
End of UDLon lintel
(mm)
Equiv.dead loadon lintel(kN/m)
Equiv.imposed load
on lintel(kN/m)
Masonry from load triangle 2211 0 2211 2.941 0.000
Analysis results at ULSMaximum moment; Mmax = 3.377 kNm
Maximum shear; Vmax = 4.970 kN
Maximum reaction at support A; RA_max = 4.970 kN
Maximum reaction at support B; RB_max = 4.970 kN
Support reactions at SLSDead loads
Reaction at support A; RA_DL = 3.550 kN
Reaction at support B; RB_DL = 3.550 kN
Imposed loads
Reaction at support A; RA_IL = 0.000 kN
Reaction at support B; RB_IL = 0.000 kN
Equivalent UDL at SLSTotal equivalent UDL (inc. selfweight); we = 3.941 kN/m
3.4
0
Moment
Lintel Calculation
Lintel L3
5
-5
Shear
Choosen Catnic lintel size: 2250 mm
Load Calculation
Beam B1
Item Unfactored Load (KN/m2) Load Type GK/QK Factored Load (KN/m
2)
Floor joists 0.3 Dead 1.4 0.42
Chipboard 0.15 Dead 1.4 0.21
Timber Floorboards 0.16 Dead 1.4 0.224
Plasterboard 0.12 Dead 1.4 0.168
Insulation 0.03 Dead 1.4 0.042
Residential Live Loading 2 Live 1.6 3.2
Total 4.27 (KN/m2)
Table 1.1 ‐ Internal Floor Loads
Item Span (m) Load (KN/m2) Comments UDL Load (KN/m)
First Floor Loading 2 4.27 See Load Table 1.1 8.54
Total 8.54 (KN/m)
Table 1.2 ‐ Proposed UDLs
Beams Calculations
Beam B1
STEEL BEAM ANALYSIS & DESIGN (BS5950)
In accordance with BS5950-1:2000 incorporating Corrigendum No.1TEDDS calculation version 3.0.05
Load Envelope - Combination 1
0.0
8.835
mm 41501A B
Bending Moment Envelope
0.0
19.019
kNm
mm 41501A B
19.0
Shear Force Envelope
0.0
18.332
-18.332
kN
mm 41501A B
18.3
-18.3
Support conditionsSupport A Vertically restrained
Rotationally free
Support B Vertically restrained
Rotationally free
Applied loadingBeam loads Dead self weight of beam 1
Dead full UDL 8.54 kN/m
Load combinationsLoad combination 1 Support A Dead 1.00
Imposed 1.00
Span 1 Dead 1.00
Imposed 1.00
Support B Dead 1.00
Imposed 1.00
Beams Calculations
Beam B1
Analysis resultsMaximum moment; Mmax = 19 kNm; Mmin = 0 kNm
Maximum shear; Vmax = 18.3 kN; Vmin = -18.3 kN
Deflection; max = 9.5 mm; min = 0 mm
Maximum reaction at support A; RA_max = 18.3 kN; RA_min = 18.3 kN
Unfactored dead load reaction at support A; RA_Dead = 18.3 kN
Maximum reaction at support B; RB_max = 18.3 kN; RB_min = 18.3 kN
Unfactored dead load reaction at support B; RB_Dead = 18.3 kN
Section detailsSection type; UC 152x152x30 (BS4-1)Steel grade; S275
From table 9: Design strength py
Thickness of element; max(T, t) = 9.4 mm
Design strength; py = 275 N/mm2
Modulus of elasticity; E = 205000 N/mm2
152.9
6.5
15
7.6
9.4
9.4
Lateral restraintSpan 1 has lateral restraint at supports only
Effective length factorsEffective length factor in major axis; Kx = 1.00Effective length factor in minor axis; Ky = 1.00
Effective length factor for lateral-torsional buckling; KLT.A = 1.00; + 2 D
KLT.B = 1.00;
Classification of cross sections - Section 3.5 = [275 N/mm2 / py] = 1.00
Internal compression parts - Table 11Depth of section; d = 123.6 mm
d / t = 19.0 <= 80 ; Class 1 plastic
Beams Calculations
Beam B1
Outstand flanges - Table 11Width of section; b = B / 2 = 76.5 mm
b / T = 8.1 <= 9 ; Class 1 plastic
Section is class 1 plastic
Shear capacity - Section 4.2.3Design shear force; Fv = max(abs(Vmax), abs(Vmin)) = 18.3 kN
d / t < 70 Web does not need to be checked for shear buckling
Shear area; Av = t D = 1024 mm2
Design shear resistance; Pv = 0.6 py Av = 169 kN
PASS - Design shear resistance exceeds design shear force
Moment capacity - Section 4.2.5Design bending moment; M = max(abs(Ms1_max), abs(Ms1_min)) = 19 kNm
Moment capacity low shear - cl.4.2.5.2; Mc = min(py Sxx, 1.2 py Zxx) = 68.1 kNm
Effective length for lateral-torsional buckling - Section 4.3.5Effective length for lateral torsional buckling; LE = ((1.0 + 1.0) Ls1 + 2 D) / 2 = 4308 mm
Slenderness ratio; = LE / ryy = 112.552
Equivalent slenderness - Section 4.3.6.7Buckling parameter; u = 0.849Torsional index; x = 15.999
Slenderness factor; v = 1 / [1 + 0.05 ( / x)2]0.25 = 0.732
Ratio - cl.4.3.6.9; W = 1.000
Equivalent slenderness - cl.4.3.6.7; LT = u v [W] = 69.950
Limiting slenderness - Annex B.2.2; L0 = 0.4 (2 E / py)0.5 = 34.310
LT > L0 - Allowance should be made for lateral-torsional buckling
Bending strength - Section 4.3.6.5Robertson constant; LT = 7.0
Perry factor; LT = max(LT (LT - L0) / 1000, 0) = 0.249
Euler stress; pE = 2 E / LT2 = 413.5 N/mm2
LT = (py + (LT + 1) pE) / 2 = 395.8 N/mm2
Bending strength - Annex B.2.1; pb = pE py / (LT + (LT2 - pE py)0.5) = 188.5 N/mm2
Equivalent uniform moment factor - Section 4.3.6.6Moment at quarter point of segment; M2 = 14.3 kNm
Moment at centre-line of segment; M3 = 19 kNm
Moment at three quarter point of segment; M4 = 14.3 kNm
Maximum moment in segment; Mabs = 19 kNm
Maximum moment governing buckling resistance; MLT = Mabs = 19 kNm
Equivalent uniform moment factor for lateral-torsional buckling;
mLT = max(0.2 + (0.15 M2 + 0.5 M3 + 0.15 M4) / Mabs, 0.44) = 0.925
Beams Calculations
Beam B1
Buckling resistance moment - Section 4.3.6.4Buckling resistance moment; Mb = pb Sxx = 46.7 kNm
Mb / mLT = 50.5 kNm
PASS - Buckling resistance moment exceeds design bending moment
Check vertical deflection - Section 2.5.2Consider deflection due to dead and imposed loads
Limiting deflection;; lim = Ls1 / 360 = 11.528 mm
Maximum deflection span 1; = max(abs(max), abs(min)) = 9.522 mm
PASS - Maximum deflection does not exceed deflection limit
Structural calculations for padstones
Beam B1
Beam End Reaction = 18.4 KN (factored) Variable Load Safety Factor = 1.5
Permanent Load Safety Factor = 1.35
Characteristic strength of masonry = 2.8 N/mm2 (Brickwork Usually = 4.5 N/mm2)
(3.6N Blockwork usually = 2.6 N/mm2)
Width of beam end bearing = 153 mm (A Engineering Brick = 13.2 N/mm2)
Length of beam end bearing = 100 mm (B Engineering Brick = 10.5 N/mm2)
(Weak Brickwork = approx 2.8 N/mm2)
(7.3N Blockwork usually = 4.2 N/mm2)
(10.4N Blockwork usually = 5.4 N/mm2)
ᵧm = 3
Bearing Factor = 1.25
Results
Maximum Bearing Stress = 1.17 N/mm2
Actual Bearing Stress = 1.2 N/mm2
Padstone Results
Characteristic strength of padstone = 30 N/mm2
Width of Padstone = 100 mm
Length of Padstone = 200 mm
Allowable padstone stress = 12.5 N/mm2
Stress under beam end bearing = 1.2 N/mm2 Therefore Padstone Stress OK
Allowable masonry stress = 1.17 N/mm2
Stress under padstone = 0.92 N/mm2 Therefore Masonry Stress OK
Padstone Required for Loads Applied
Load Calculation
2Beam B
Item Span (m) Load (KN/m2) Comments UDL Load (KN/m)
Dormer Walls 2.6 1 1 KN/m2 assumed for mber construc on 2.6
Wall ( Span is effective height of wall
loading beam )5.5 4.74
External walls‐ 302.5mm thick; 102.5mm
outer brick skin, 150mm blockwork skin,
plaster finish
26.07
Beam B1 Reac on ‐ ‐ KN @ 1830mm
Total 28.67 (KN/m)
Table 2.1 ‐ Proposed UDLs
18.3
Beams Calculations
Beam B2
STEEL BEAM ANALYSIS & DESIGN (BS5950)
In accordance with BS5950-1:2000 incorporating Corrigendum No.1TEDDS calculation version 3.0.05
Load Envelope - Combination 1
0.0
28.965
mm 26001A B
Bending Moment Envelope
0.0
32.028
kNm
mm 26001A B
32.0 30.3
Shear Force Envelope
0.0
43.074
-50.534
kN
mm 26001A B
43.1
-9.9
-50.5
Support conditionsSupport A Vertically restrained
Rotationally free
Support B Vertically restrained
Rotationally free
Applied loadingBeam loads Dead self weight of beam 1
Dead full UDL 28.67 kN/m
Dead point load 18.3 kN at 1830 mm
Load combinationsLoad combination 1 Support A Dead 1.00
Imposed 1.00
Span 1 Dead 1.00
Imposed 1.00
Support B Dead 1.00
Beams Calculations
Beam B2
Imposed 1.00
Analysis resultsMaximum moment; Mmax = 32 kNm; Mmin = 0 kNm
Maximum shear; Vmax = 43.1 kN; Vmin = -50.5 kN
Deflection; max = 6.3 mm; min = 0 mm
Maximum reaction at support A; RA_max = 43.1 kN; RA_min = 43.1 kN
Unfactored dead load reaction at support A; RA_Dead = 43.1 kN
Maximum reaction at support B; RB_max = 50.5 kN; RB_min = 50.5 kN
Unfactored dead load reaction at support B; RB_Dead = 50.5 kN
Section detailsSection type; UC 152x152x30 (BS4-1)Steel grade; S275
From table 9: Design strength py
Thickness of element; max(T, t) = 9.4 mm
Design strength; py = 275 N/mm2
Modulus of elasticity; E = 205000 N/mm2
152.9
6.5
15
7.6
9.4
9.4
Lateral restraintSpan 1 has lateral restraint at supports only
Effective length factorsEffective length factor in major axis; Kx = 1.00Effective length factor in minor axis; Ky = 1.00
Effective length factor for lateral-torsional buckling; KLT.A = 1.00; + 2 D
KLT.B = 1.00;
Classification of cross sections - Section 3.5 = [275 N/mm2 / py] = 1.00
Internal compression parts - Table 11Depth of section; d = 123.6 mm
d / t = 19.0 <= 80 ; Class 1 plastic
Beams Calculations
Beam B2
Outstand flanges - Table 11Width of section; b = B / 2 = 76.5 mm
b / T = 8.1 <= 9 ; Class 1 plastic
Section is class 1 plastic
Shear capacity - Section 4.2.3Design shear force; Fv = max(abs(Vmax), abs(Vmin)) = 50.5 kN
d / t < 70 Web does not need to be checked for shear buckling
Shear area; Av = t D = 1024 mm2
Design shear resistance; Pv = 0.6 py Av = 169 kN
PASS - Design shear resistance exceeds design shear force
Moment capacity - Section 4.2.5Design bending moment; M = max(abs(Ms1_max), abs(Ms1_min)) = 32 kNm
Moment capacity low shear - cl.4.2.5.2; Mc = min(py Sxx, 1.2 py Zxx) = 68.1 kNm
Effective length for lateral-torsional buckling - Section 4.3.5Effective length for lateral torsional buckling; LE = ((1.0 + 1.0) Ls1 + 2 D) / 2 = 2758 mm
Slenderness ratio; = LE / ryy = 72.052
Equivalent slenderness - Section 4.3.6.7Buckling parameter; u = 0.849Torsional index; x = 15.999
Slenderness factor; v = 1 / [1 + 0.05 ( / x)2]0.25 = 0.839
Ratio - cl.4.3.6.9; W = 1.000
Equivalent slenderness - cl.4.3.6.7; LT = u v [W] = 51.320
Limiting slenderness - Annex B.2.2; L0 = 0.4 (2 E / py)0.5 = 34.310
LT > L0 - Allowance should be made for lateral-torsional buckling
Bending strength - Section 4.3.6.5Robertson constant; LT = 7.0
Perry factor; LT = max(LT (LT - L0) / 1000, 0) = 0.119
Euler stress; pE = 2 E / LT2 = 768.2 N/mm2
LT = (py + (LT + 1) pE) / 2 = 567.3 N/mm2
Bending strength - Annex B.2.1; pb = pE py / (LT + (LT2 - pE py)0.5) = 234.7 N/mm2
Equivalent uniform moment factor - Section 4.3.6.6Moment at quarter point of segment; M2 = 21.9 kNm
Moment at centre-line of segment; M3 = 31.5 kNm
Moment at three quarter point of segment; M4 = 26.7 kNm
Maximum moment in segment; Mabs = 32 kNm
Maximum moment governing buckling resistance; MLT = Mabs = 32 kNm
Equivalent uniform moment factor for lateral-torsional buckling;
mLT = max(0.2 + (0.15 M2 + 0.5 M3 + 0.15 M4) / Mabs, 0.44) = 0.920
Beams Calculations
Beam B2
Buckling resistance moment - Section 4.3.6.4Buckling resistance moment; Mb = pb Sxx = 58.1 kNm
Mb / mLT = 63.2 kNm
PASS - Buckling resistance moment exceeds design bending moment
Check vertical deflection - Section 2.5.2Consider deflection due to dead and imposed loads
Limiting deflection;; lim = Ls1 / 360 = 7.222 mm
Maximum deflection span 1; = max(abs(max), abs(min)) = 6.281 mm
PASS - Maximum deflection does not exceed deflection limit
Structural calculations for padstones
2Beam B
Beam End Reaction = 51 KN (factored) Variable Load Safety Factor = 1.5
Permanent Load Safety Factor = 1.35
Characteristic strength of masonry = 4.2 N/mm2 (Brickwork Usually = 4.5 N/mm2)
(3.6N Blockwork usually = 2.6 N/mm2)
Width of beam end bearing = 153 mm (A Engineering Brick = 13.2 N/mm2)
Length of beam end bearing = 150 mm (B Engineering Brick = 10.5 N/mm2)
(Weak Brickwork = approx 2.8 N/mm2)
(7.3N Blockwork usually = 4.2 N/mm2)
(10.4N Blockwork usually = 5.4 N/mm2)
ᵧm = 3
Bearing Factor = 1.25
Results
Maximum Bearing Stress = 1.75 N/mm2
Actual Bearing Stress = 2.22 N/mm2
Padstone Results
Characteristic strength of padstone = 30 N/mm2
Width of Padstone = 250 mm
Length of Padstone = 150 mm
Allowable padstone stress = 12.5 N/mm2
Stress under beam end bearing = 2.22 N/mm2 Therefore Padstone Stress OK
Allowable masonry stress = 1.75 N/mm2
Stress under padstone = 1.36 N/mm2 Therefore Masonry Stress OK
Padstone Required for Loads Applied
Load Calculation
3 & B4s BBeam
Item Unfactored Load (KN/m2) Load Type GK/QK Factored Load (KN/m
2)
Floor joists 0.3 Dead 1.4 0.42
Chipboard 0.15 Dead 1.4 0.21
Timber Floorboards 0.16 Dead 1.4 0.224
Plasterboard 0.12 Dead 1.4 0.168
Insulation 0.03 Dead 1.4 0.042
Residential Live Loading 2 Live 1.6 3.2
Total 4.27 (KN/m2)
Table 4.1 ‐ Internal Floor Loads
Item Span (m) Load (KN/m2) Comments UDL Load (KN/m)
Loft Floor Loading 2 4.27 See Load Table 4.1 8.54
Dormer Walls 5.8 1 1 KN/m2 assumed for mber construc on 5.8
Total 14.34 (KN/m)
Table 4.2 ‐ Proposed UDLs
Beams Calculations
Beams B3 & B4
STEEL BEAM ANALYSIS & DESIGN (BS5950)
In accordance with BS5950-1:2000 incorporating Corrigendum No.1TEDDS calculation version 3.0.05
Load Envelope - Combination 1
0.0
15.057
mm 58001A B
Bending Moment Envelope
0.0
68.898
kNm
mm 58001A B
62.968.9
Shear Force Envelope
0.0
47.579
-45.549
kN
mm 58001A B
47.6
19.2
-45.5
Support conditionsSupport A Vertically restrained
Rotationally free
Support B Vertically restrained
Rotationally free
Applied loadingBeam loads Dead self weight of beam 1
Dead full UDL 14.34 kN/m
Dead point load 5.8 kN at 1885 mm
Load combinationsLoad combination 1 Support A Dead 1.00
Imposed 1.00
Span 1 Dead 1.00
Imposed 1.00
Support B Dead 1.00
Beams Calculations
Beams B3 & B4
Imposed 1.00
Analysis resultsMaximum moment; Mmax = 68.9 kNm; Mmin = 0 kNm
Maximum shear; Vmax = 47.6 kN; Vmin = -45.5 kN
Deflection; max = 10.3 mm; min = 0 mm
Maximum reaction at support A; RA_max = 47.6 kN; RA_min = 47.6 kN
Unfactored dead load reaction at support A; RA_Dead = 47.6 kN
Maximum reaction at support B; RB_max = 45.5 kN; RB_min = 45.5 kN
Unfactored dead load reaction at support B; RB_Dead = 45.5 kN
Section detailsSection type; UC 254x254x73 (BS4-1)Steel grade; S275
From table 9: Design strength py
Thickness of element; max(T, t) = 14.2 mm
Design strength; py = 275 N/mm2
Modulus of elasticity; E = 205000 N/mm2
254.6
8.6
254
.1
14
.21
4.2
Lateral restraintSpan 1 has lateral restraint at supports only
Effective length factorsEffective length factor in major axis; Kx = 1.00Effective length factor in minor axis; Ky = 1.00
Effective length factor for lateral-torsional buckling; KLT.A = 1.00; + 2 D
KLT.B = 1.00;
Classification of cross sections - Section 3.5 = [275 N/mm2 / py] = 1.00
Internal compression parts - Table 11Depth of section; d = 200.3 mm
d / t = 23.3 <= 80 ; Class 1 plastic
Beams Calculations
Beams B3 & B4
Outstand flanges - Table 11Width of section; b = B / 2 = 127.3 mm
b / T = 9.0 <= 9 ; Class 1 plastic
Section is class 1 plastic
Shear capacity - Section 4.2.3Design shear force; Fv = max(abs(Vmax), abs(Vmin)) = 47.6 kN
d / t < 70 Web does not need to be checked for shear buckling
Shear area; Av = t D = 2185 mm2
Design shear resistance; Pv = 0.6 py Av = 360.6 kN
PASS - Design shear resistance exceeds design shear force
Moment capacity - Section 4.2.5Design bending moment; M = max(abs(Ms1_max), abs(Ms1_min)) = 68.9 kNm
Moment capacity low shear - cl.4.2.5.2; Mc = min(py Sxx, 1.2 py Zxx) = 272.8 kNm
Effective length for lateral-torsional buckling - Section 4.3.5Effective length for lateral torsional buckling; LE = ((1.0 + 1.0) Ls1 + 2 D) / 2 = 6054 mm
Slenderness ratio; = LE / ryy = 93.446
Equivalent slenderness - Section 4.3.6.7Buckling parameter; u = 0.849Torsional index; x = 17.259
Slenderness factor; v = 1 / [1 + 0.05 ( / x)2]0.25 = 0.798
Ratio - cl.4.3.6.9; W = 1.000
Equivalent slenderness - cl.4.3.6.7; LT = u v [W] = 63.289
Limiting slenderness - Annex B.2.2; L0 = 0.4 (2 E / py)0.5 = 34.310
LT > L0 - Allowance should be made for lateral-torsional buckling
Bending strength - Section 4.3.6.5Robertson constant; LT = 7.0
Perry factor; LT = max(LT (LT - L0) / 1000, 0) = 0.203
Euler stress; pE = 2 E / LT2 = 505.1 N/mm2
LT = (py + (LT + 1) pE) / 2 = 441.3 N/mm2
Bending strength - Annex B.2.1; pb = pE py / (LT + (LT2 - pE py)0.5) = 205 N/mm2
Equivalent uniform moment factor - Section 4.3.6.6Moment at quarter point of segment; M2 = 53.2 kNm
Moment at centre-line of segment; M3 = 68.8 kNm
Moment at three quarter point of segment; M4 = 50.2 kNm
Maximum moment in segment; Mabs = 68.9 kNm
Maximum moment governing buckling resistance; MLT = Mabs = 68.9 kNm
Equivalent uniform moment factor for lateral-torsional buckling;
mLT = max(0.2 + (0.15 M2 + 0.5 M3 + 0.15 M4) / Mabs, 0.44) = 0.924
Beams Calculations
Beams B3 & B4
Buckling resistance moment - Section 4.3.6.4Buckling resistance moment; Mb = pb Sxx = 203.4 kNm
Mb / mLT = 220.1 kNm
PASS - Buckling resistance moment exceeds design bending moment
Check vertical deflection - Section 2.5.2Consider deflection due to dead and imposed loads
Limiting deflection;; lim = Ls1 / 360 = 16.111 mm
Maximum deflection span 1; = max(abs(max), abs(min)) = 10.333 mm
PASS - Maximum deflection does not exceed deflection limit
Structural calculations for padstones
s B3 & B4Beam
Beam End Reaction = 46 KN (factored) Variable Load Safety Factor = 1.5
Permanent Load Safety Factor = 1.35
Characteristic strength of masonry = 4.2 N/mm2 (Brickwork Usually = 4.5 N/mm2)
(3.6N Blockwork usually = 2.6 N/mm2)
Width of beam end bearing = 254 mm (A Engineering Brick = 13.2 N/mm2)
Length of beam end bearing = 100 mm (B Engineering Brick = 10.5 N/mm2)
(Weak Brickwork = approx 2.8 N/mm2)
(7.3N Blockwork usually = 4.2 N/mm2)
(10.4N Blockwork usually = 5.4 N/mm2)
ᵧm = 3
Bearing Factor = 1.25
Results
Maximum Bearing Stress = 1.75 N/mm2
Actual Bearing Stress = 1.81 N/mm2
Padstone Results
Characteristic strength of padstone = 30 N/mm2
Width of Padstone = 250 mm
Length of Padstone = 300 mm
Allowable padstone stress = 12.5 N/mm2
Stress under beam end bearing = 1.81 N/mm2 Therefore Padstone Stress OK
Allowable masonry stress = 1.75 N/mm2
Stress under padstone = 0.61 N/mm2 Therefore Masonry Stress OK
Padstone Required for Loads Applied
Connection Details
SC1
;BEAM TO BEAM - CLEAT CONNECTION TEDDS calculation version 2.0.16
Section Details
Supporting Beam - UC 152x152x30;; Gradesupporting = "S275"
Supported Beam - UC 152x152x30;; Gradesupported = "S275"
Cleats 2 x RSA 70x70x10;; Gradecleats = "S275"
Bolts M12 (Grade 8.8)
A
A
SECTION THROUGH SUPPORTING BEAM
30
10
0
10 Gap
SECTION A - A
30
Connection Details ; Bolt eccentricity for supported beam; abolts = 50 mm
; number of bolt rows; nbolts = 3
; Bolt pitch;; pbolts = 30 mm
; Bolt gauge; gbolts = 107 mm
; End projection; t1 = 10 mm
; Cleat end distance (top & bottom); e1cleats = 20 mm
; Cleat edge distance on supported beam; e2cleatssupported = 20 mm
; Cleat edge distance on supporting beam; e2cleatssupporting = 20 mm
Cleat length; lcleats = pbolts(nbolts-1)+2e1cleats = 100 mm
;Supported Beam end reaction; Q = 18.5 kN
Notch details; Top notch length; ctopnotch = 83 mm
; Top notch depth; dctopnotch = 20 mm
; Bottom notch length; cbottomnotch = 83 mm
; Bottom notch depth; dcbottomnotch = 20 mm
Check 1 - Essential detailing requirements
; Cleat thickness; tcleats = 10 mm; PASS
; Bolt gauge; gbolts = 107 mm; PASS
; Cleat Length; lcleats = 100 mm
; Cleat length for torsional requirements : PASS; ; Cleats fit between beam fillets : PASS
Check 2 - Shear capacity of bolt group connecting cleats to web of supported beam (taking account of eccentricity 'a') ;;;; Elastic section modulus of bolt group
Zbolts = nbolts (nbolts + 1) pbolts / 6 = 60 mm
Force on outermost bolt due to moment
Fm = Q abolts / Zbolts = 15 kN
Connection Details
SC1
Force on bolt due to shear
Fv = Q / nbolts = 6.2 kN
Resultant force on bolt due to direct shear and moment
Fr = (Fv2 + Fm
2)= 16.6 kN
Shear capacity of a single bolt in double shear
;2 Psbolts = 63.2 kN
Utilisation factor; Ucheck2shear = Fr / (2 Psbolts) = 0.263
Shear capacity to web : PASS
Check 3 - Shear and bearing capacity of cleat connected to supported beam
for shear
;;
pycleats = 275 N/mm2
;; e1acleats = e1cleats = 20 mm
;; Avcleats = 0.9 (2 e1acleats + (nbolts - 1) pbolts) tcleats = 900 mm2
; Avnetcleats = Avcleats - nbolts Dhbolts tcleats = 480 mm2
Effective net area coefficient
Kecleats = 1.20
Plain shear capacity of cleats
PvPcleats = min(0.6 pycleats Avcleats, 0.7 Kecleats pycleats Avnetcleats) = 110.9 kN
Av1cleats = (e1acleats + (nbolts - 1) pbolts) tcleats = 800 mm2
; Ateffcleats = (e2cleatssupported - 0.5 Dhbolts) tcleats = 130 mm2
PvBcleats = 0.6 pycleats Av1cleats + 0.6 Kecleats pycleats Ateffcleats = 157.7 kN
Shear capacity of the angle cleat leg; Pvcleats = min (PvPcleats, PvBcleats) = 110.9 kN
;Shear force on angle cleat; Q / 2 = 9.3 kN
Utilisation factor; Ucheck3shear = Q / (2 Pvcleats) = 0.083
Shear capacity of cleats to beam: PASS
for bearing
ecleats = min (e1cleats, e2cleatssupported) = 20 mm
bearing strength of the cleat
pbscleats = 460 N/mm2
bearing capacity of the leg of the angle cleat per bolt
Pbscleats = min(dbolts tcleats pbscleats, 0.5 ecleats tcleats pbscleats) = 46.0 kN
;Bearing force on cleat; Fr / 2 = 8.3 kN
Utilisation factor; Ucheck3bearing = Fr / (2 Pbscleats) = 0.180
Bearing capacity of cleats to beam: PASS
Check 4b - shear and bearing capacity of the supported beam (2 notches)
;;;;for shear
;;
pysupported = 275 N/mm2
Connection Details
SC1
; Distance top supported beam to 1st hole; etsupported = 50 mm
;;; etasupported = etsupported - dctopnotch = 30 mm
; ebsupported = Dsupported - etsupported - (nbolts - 1) pbolts = 48 mm
ebasupported = ebsupported - dcbottomnotch = 28 mm
; Avsupported = 0.9 (etasupported + (nbolts - 1) pbolts + ebasupported) tsupported = 688 mm2
; Avnetsupported = Avsupported - nbolts Dhbolts tsupported = 415 mm2
Effective net area coefficient
Kesupported = 1.20
Plain shear capacity of beam
PvPsupported = min(0.6 pysupported Avsupported, 0.7 Kesupported pysupported Avnetsupported) = 95.9 kN
Av1supported = (etasupported + (nbolts - 1) pbolts) tsupported = 585 mm2
;; e3supported = abolts - t1 = 40 mm
Ateffsupported = (e3supported - 0.5 Dhbolts) tsupported = 215 mm2
Block shear capacity of beam
PvBsupported = 0.6 pysupported Av1supported + 0.6 Kesupported pysupported Ateffsupported = 139.0 kN
Shear capacity of the beam; Pvsupported = min (PvPsupported, PvBsupported) = 95.9 kN
;Shear force on beam; Q = 18.5 kN
Utilisation factor; Ucheck4shear = Q / Pvsupported = 0.193
Shear capacity of beam : PASS
for bearing
bearing strength of the beam
pbssupported = 460 N/mm2
bearing capacity of the beam per bolt
Pbssupported = min(dbolts tsupported pbssupported, 0.5 e3supported tsupported pbssupported) = 36 kN
;Resultant bearing force on bolts; Fr = 16.6 kN
Utilisation factor; Ucheck4bearing = Fr / Pbssupported = 0.463
Bearing capacity of beam : PASS
Check 4c - bending capacity of reduced beam section at the notch - 2 flanges notched ;;;;;; Znotched = tsupported (Dsupported - dctopnotch - dcbottomnotch)2 / 6 = 14982 mm3
;Moment capacity of notched section; Mcapnotched = pysupported Znotched = 4.1 kNm
;Moment applied to notched section; Mappnotched = Q max(ctopnotch, cbottomnotch) = 1.5 kNm
Utilisation factor; Ucheck4cmoment = Mappnotched / Mcapnotched = 0.374
Moment capacity of notched section : PASS
Check 4d - local stability of notched beams restrained against lateral torsional buckling - 2 flanges notched
;;;; Depth of top notch; dctopnotch = 20 mm
Length of top notch; ctopnotch = 83 mm
Depth of bottom notch; dcbottomnotch = 20 mm
Length of bottom notch; cbottomnotch = 83 mm
Connection Details
SC1
Checkdepth = max(dctopnotch, dcbottomnotch) = 20 mm
Checklength = max(ctopnotch, cbottomnotch) = 83 mm
;Depth of both notches less than limit of D/5 : PASS
; Gradesupported = "S275"
;; dot = Dsupported/tsupported = 24.2
climit = if(or(Gradesupported == “S275”, Gradesupported == “300”), if(dot<=54.3,Dsupported,160000 Dsupported/dot3),
if(dot<=48.0,Dsupported,110000 Dsupported/dot3))
climit = 157.6 mm
Length of both notches less than limit : PASS
Check 5 - Shear capacity of bolt group connecting cleats to supporting beam
Shear capacity of top pair of bolts
;;;;; Psbolts1 = min(Psbolts, 0.5 e1cleats tcleats pbscleats) = 31.6 kN
Shear capacity of other bolts
Psbolts = 31.6 kN
Shear capacity of bolt group - sum of bolt capacities
;Psboltssum = 2 Psbolts1 + 2 (nbolts - 1) Psbolts = 189.7 kN
;Shear on bolt group; Q = 18.5 kN
Utilisation factor; Ucheck5 = Q / Psboltssum = 0.098
Shear capacity of bolt group to supporting beam : PASS
Check 6 - Shear and bearing capacity of cleats connected to supporting beam
for shear
;;
pycleats = 275 N/mm2
;; e1acleats = e1cleats = 20 mm
;; Avcleats = 0.9 (2 e1acleats + (nbolts - 1) pbolts) tcleats = 900 mm2
Effective net area coefficient
Kecleats = 1.20
; Avnetcleats = Avcleats - nbolts Dhbolts tcleats = 480 mm2
Plain shear capacity of cleats
PvPcleats = min(0.6 pycleats Avcleats, 0.7 Kecleats pycleats Avnetcleats) = 110.9 kN
Av1cleats = (e1acleats + (nbolts - 1) pbolts) tcleats = 800 mm2
; Ateffcleatssupporting = (e2cleatssupporting - 0.5 Dhbolts) tcleats = 130 mm2
Block shear capacity of cleats
PvBcleatssupporting = 0.6 pycleats Av1cleats + 0.6 Kecleats pycleats Ateffcleatssupporting = 157.7 kN
Shear capacity of the angle cleat leg; Pvcleatssupporting = min (PvPcleats, PvBcleatssupporting) = 110.9 kN
;Shear force on angle cleat; Q / 2 = 9.3 kN
Utilisation factor; Ucheck6shear = Q / (2 Pvcleatssupporting) = 0.083
Shear capacity of cleats to supporting beam: PASS
Connection Details
SC1
for bearing
ecleatssupporting = e1cleats = 20 mm
bearing strength of the cleat
pbscleats = 460 N/mm2
For top bolt,
bearing capacity of the leg of the angle cleat per bolt
Pbscleatssupporting1 = min(dbolts tcleats pbscleats, 0.5 ecleatssupporting tcleats pbscleats) = 46.0 kN
For other bolts,
bearing capacity of the leg of the angle cleat per bolt
Pbscleatssupporting = dbolts tcleats pbscleats = 55.2 kN
Capacity of bolt group;
Pbscleatssupportingsum = 2 Pbscleatssupporting1 + 2 (nbolts - 1) Pbscleatssupporting = 312.8 kN
Bearing force on bolt group; Q = 18.5 kN
Utilisation factor; Ucheck6bearing = Q / Pbscleatssupportingsum = 0.059
Bearing capacity of cleats to supporting beam: PASS
Check 7 - Local shear and bearing capacity of supporting beam web
for shear;;;;;
;ebsupporting = min(pbolts, Dsupporting - etsupporting - (nbolts - 1) pbolts) = 30 mm
Avsupporting = (ebsupporting + (nbolts - 1) pbolts + etsupporting) tsupporting = 910 mm2
; Avnetsupporting = Avsupporting - nbolts Dhbolts tsupporting = 637 mm2
;
pysupporting = 275 N/mm2
Effective net area coefficient
Kesupporting = 1.20
Pvsupporting = min(0.6 pysupporting Avsupporting, 0.7 Kesupporting pysupporting Avnetsupporting) = 147.1 kN
;Shear load on supporting beam; Q / 2 = 9.3 kN
Utilisation factor; Ucheck7shear = Q / (2 Pvsupporting) = 0.063
Local shear capacity of supporting beam web: PASS
for bearing
pbssupporting = 460 N/mm2
Pbssupporting = dbolts tsupporting pbssupporting = 35.9 kN
Q / (2 nbolts) = 3.1 kN
Utilisation factor; Ucheck7bearing = Q / (2 nbolts Pbssupporting) = 0.086
Local bearing capacity of supporting beam web : PASS
SUMMARY OF RESULTS
Check 2 - Capacity of bolt group connecting cleats to web of supported beam (taking account of eccentricity 'a')
Shear utilisation factor; Ucheck2shear = 0.263; PASS
Check 3 - Capacity of cleat connected to supported beam
Connection Details
SC1
Shear utilisation factor; Ucheck3shear = 0.083; PASS
Bearing utilisation factor; Ucheck3bearing = 0.180; PASS
Check 4b - Capacity of the supported beam Shear utilisation factor; Ucheck4shear = 0.193; PASSBearing utilisation factor; Ucheck4bearing = 0.463; PASS
Check 4c - bending capacity of reduced beam section at the notch - 2 flanges notched Moment Utilisation factor; Ucheck4cmoment = 0.374; PASS
Check 4d - local stability of notched beams restrained against lateral torsional buckling - 2 flanges notched Local stability limit; climit = 157.6 mm; PASS
Check 5 - Capacity of bolt group connecting cleats to supporting beam
Shear utilisation factor; Ucheck5 = 0.098; PASSCheck 6 - Capacity of cleats connected to supporting beam
Shear utilisation factor; Ucheck6shear = 0.083; PASSBearing utilisation factor; Ucheck6bearing = 0.059; PASS
Check 7 - Local capacity of column webShear utilisation factor; Ucheck7shear = 0.063; PASSBearing utilisation factor; Ucheck7bearing = 0.086; PASS
;
Floor Joists
Floor Extension & Dormer stFloor Joist Sizing for 1
Item Unfactored Load (KN/m2) Load Type GK/QK Factored Load (KN/m
2)
Floor joists 0.3 Dead 1.4 0.42
Chipboard 0.15 Dead 1.4 0.21
Timber Floorboards 0.16 Dead 1.4 0.224
Plasterboard 0.12 Dead 1.4 0.168
Insulation 0.03 Dead 1.4 0.042
Residential Live Loading 2 Live 1.6 3.2
Total (Dead) 1.07 (KN/m2)
Total (Live) 3.2 (KN/m2)
Total 4.27 (KN/m2)
Table 5.1 ‐ Internal Floor Loads
1st Floor Extension
1st Floor Extension- Span 3.00m
TIMBER JOIST DESIGN (BS5268-2:2002)Tedds calculation version 1.1.04
Joist detailsJoist breadth; b = 47 mm
Joist depth; h = 175 mm
Joist spacing; s = 400 mm
Timber strength class; C24Service class of timber; 1
mm 30001A B
Span detailsNumber of spans; Nspan = 1Length of bearing; Lb = 50 mm
Effective length of span; Ls1 = 3000 mm
175
47
50
Section propertiesSecond moment of area; I = b h3 / 12 = 20990885 mm4
Section modulus; Z = b h2 / 6 = 239896 mm3
Loading detailsJoist self weight; Fswt = b h char gacc = 0.03 kN/m
Dead load; Fd_udl = 1.07 kN/m2
Imposed UDL(Long term); Fi_udl = 3.20 kN/m2
Modification factorsService class for bending parallel to grain; K2m = 1.00
1st Floor Extension
1st Floor Extension- Span 3.00m
Service class for compression; K2c = 1.00Service class for shear parallel to grain; K2s = 1.00Service class for modulus of elasticity; K2e = 1.00Section depth factor; K7 = 1.06
Load sharing factor; K8 = 1.10
Consider long term loadsLoad duration factor; K3 = 1.00Maximum bending moment; M = 1.953 kNm
Maximum shear force; V = 2.604 kN
Maximum support reaction; R = 2.604 kN
Maximum deflection; = 8.500 mm
Check bending stressBending stress; m = 7.500 N/mm2
Permissible bending stress; m_adm = m K2m K3 K7 K8 = 8.754 N/mm2
Applied bending stress; m_max = M / Z = 8.142 N/mm2
PASS - Applied bending stress within permissible limits
Check shear stressShear stress; = 0.710 N/mm2
Permissible shear stress; adm = K2s K3 K8 = 0.781 N/mm2
Applied shear stress; max = 3 V / (2 b h) = 0.475 N/mm2
PASS - Applied shear stress within permissible limits
Check bearing stressCompression perpendicular to grain (no wane);cp1 = 2.400 N/mm2
Permissible bearing stress; c_adm = cp1 K2c K3 K8 = 2.640 N/mm2
Applied bearing stress; c_max = R / (b Lb) = 1.108 N/mm2
PASS - Applied bearing stress within permissible limits
Check deflectionPermissible deflection; adm = min(Ls1 0.003, 14 mm) = 9.000 mm
Bending deflection (based on Emean); bending = 8.077 mm
Shear deflection; shear = 0.422 mm
Total deflection; = bending + shear = 8.500 mm
PASS - Actual deflection within permissible limits
Loft Floor Joists
Loft Floor- Span 2.20m
TIMBER JOIST DESIGN (BS5268-2:2002)Tedds calculation version 1.1.04
Joist detailsJoist breadth; b = 47 mm
Joist depth; h = 175 mm
Joist spacing; s = 600 mm
Timber strength class; C24Service class of timber; 1
mm 22001A B
Span detailsNumber of spans; Nspan = 1Length of bearing; Lb = 50 mm
Effective length of span; Ls1 = 2200 mm
175
47
50
Section propertiesSecond moment of area; I = b h3 / 12 = 20990885 mm4
Section modulus; Z = b h2 / 6 = 239896 mm3
Loading detailsJoist self weight; Fswt = b h char gacc = 0.03 kN/m
Dead load; Fd_udl = 1.07 kN/m2
Imposed UDL(Long term); Fi_udl = 3.20 kN/m2
Modification factorsService class for bending parallel to grain; K2m = 1.00
Loft Floor Joists
Loft Floor- Span 2.20m
Service class for compression; K2c = 1.00Service class for shear parallel to grain; K2s = 1.00Service class for modulus of elasticity; K2e = 1.00Section depth factor; K7 = 1.06
Load sharing factor; K8 = 1.10
Consider long term loadsLoad duration factor; K3 = 1.00Maximum bending moment; M = 1.567 kNm
Maximum shear force; V = 2.849 kN
Maximum support reaction; R = 2.849 kN
Maximum deflection; = 3.824 mm
Check bending stressBending stress; m = 7.500 N/mm2
Permissible bending stress; m_adm = m K2m K3 K7 K8 = 8.754 N/mm2
Applied bending stress; m_max = M / Z = 6.532 N/mm2
PASS - Applied bending stress within permissible limits
Check shear stressShear stress; = 0.710 N/mm2
Permissible shear stress; adm = K2s K3 K8 = 0.781 N/mm2
Applied shear stress; max = 3 V / (2 b h) = 0.520 N/mm2
PASS - Applied shear stress within permissible limits
Check bearing stressCompression perpendicular to grain (no wane);cp1 = 2.400 N/mm2
Permissible bearing stress; c_adm = cp1 K2c K3 K8 = 2.640 N/mm2
Applied bearing stress; c_max = R / (b Lb) = 1.212 N/mm2
PASS - Applied bearing stress within permissible limits
Check deflectionPermissible deflection; adm = min(Ls1 0.003, 14 mm) = 6.600 mm
Bending deflection (based on Emean); bending = 3.485 mm
Shear deflection; shear = 0.339 mm
Total deflection; = bending + shear = 3.824 mm
PASS - Actual deflection within permissible limits
Loft Floor Joists
Loft Floor- Span 4.00m
TIMBER JOIST DESIGN (BS5268-2:2002)Tedds calculation version 1.1.04
Joist detailsJoist breadth; b = 47 mm
Joist depth; h = 200 mm
Joist spacing; s = 250 mm
Timber strength class; C24Service class of timber; 1
mm 40001A B
Span detailsNumber of spans; Nspan = 1Length of bearing; Lb = 50 mm
Effective length of span; Ls1 = 4000 mm
200
47
50
Section propertiesSecond moment of area; I = b h3 / 12 = 31333333 mm4
Section modulus; Z = b h2 / 6 = 313333 mm3
Loading detailsJoist self weight; Fswt = b h char gacc = 0.03 kN/m
Dead load; Fd_udl = 1.07 kN/m2
Imposed UDL(Long term); Fi_udl = 3.20 kN/m2
Loft Floor Joists
Loft Floor- Span 4.00m
Modification factorsService class for bending parallel to grain; K2m = 1.00Service class for compression; K2c = 1.00Service class for shear parallel to grain; K2s = 1.00Service class for modulus of elasticity; K2e = 1.00Section depth factor; K7 = 1.05
Load sharing factor; K8 = 1.10
Consider long term loadsLoad duration factor; K3 = 1.00Maximum bending moment; M = 2.200 kNm
Maximum shear force; V = 2.200 kN
Maximum support reaction; R = 2.200 kN
Maximum deflection; = 11.249 mm
Check bending stressBending stress; m = 7.500 N/mm2
Permissible bending stress; m_adm = m K2m K3 K7 K8 = 8.626 N/mm2
Applied bending stress; m_max = M / Z = 7.020 N/mm2
PASS - Applied bending stress within permissible limits
Check shear stressShear stress; = 0.710 N/mm2
Permissible shear stress; adm = K2s K3 K8 = 0.781 N/mm2
Applied shear stress; max = 3 V / (2 b h) = 0.351 N/mm2
PASS - Applied shear stress within permissible limits
Check bearing stressCompression perpendicular to grain (no wane);cp1 = 2.400 N/mm2
Permissible bearing stress; c_adm = cp1 K2c K3 K8 = 2.640 N/mm2
Applied bearing stress; c_max = R / (b Lb) = 0.936 N/mm2
PASS - Applied bearing stress within permissible limits
Check deflectionPermissible deflection; adm = min(Ls1 0.003, 14 mm) = 12.000 mm
Bending deflection (based on Emean); bending = 10.833 mm
Shear deflection; shear = 0.416 mm
Total deflection; = bending + shear = 11.249 mm
PASS - Actual deflection within permissible limits
Foundation Design
Strip 1 - Central Wall
STRIP FOOTING ANALYSIS AND DESIGN (BS8110-1:1997)Tedds calculation version 2.0.07
89.4 kN/m 89.4 kN/m2 2
400
200
500
125 250 125
Strip footing detailsWidth of strip footing; B = 500 mm
Depth of strip footing; h = 400 mm
Depth of soil over strip footing; hsoil = 200 mm
Density of concrete; conc = 23.6 kN/m3
Load detailsLoad width; b = 250 mm
Load eccentricity; eP = 0 mm
Soil detailsDense, moderately graded, rounded to sub-angular, course to medium sand
Mobilisation factor; m= ;1.5;
Density of soil; soil = 20.0 kN/m3
Design shear strength; ’ = 24.2 deg
Design base friction; = 18.6 deg
Allowable bearing pressure; Pbearing = 105 kN/m2
Axial loading on strip footingDead axial load; PG = 27.0 kN/m
Imposed axial load; PQ = 11.0 kN/m
Wind axial load; PW = 0.0 kN/m
Total axial load; P = 38.0 kN/m
Foundation Design
Strip 1 - Central Wall
Foundation loadsDead surcharge load; FGsur = 0.000 kN/m2
Imposed surcharge load; FQsur = 0.000 kN/m2
Strip footing self weight; Fswt = h conc = 9.440 kN/m2
Soil self weight; Fsoil = hsoil soil = 4.000 kN/m2
Total foundation load; F = B (FGsur + FQsur + Fswt + Fsoil) = 6.7 kN/m
Calculate base reactionTotal base reaction; T = F + P = 44.7 kN/m
Eccentricity of base reaction in x; eT = (P eP + M + H h) / T = 0 mm
Base reaction acts within middle third of base
Calculate base pressuresq1 = (T / B) (1 - 6 eT / B) = 89.440 kN/m2
q2 = (T / B) (1 + 6 eT / B) = 89.440 kN/m2
Minimum base pressure; qmin = min(q1, q2) = 89.440 kN/m2
Maximum base pressure; qmax = max(q1, q2) = 89.440 kN/m2
PASS - Maximum base pressure is less than allowable bearing pressure
Material detailsCharacteristic strength of concrete; fcu = 30 N/mm2
Calculate base lengthsLeft hand length; BL = B / 2 + eP = 250 mm
Right hand length; BR = B / 2 - eP = 250 mm
Calculate rate of change of base pressureLength of base reaction; Bx = B = 500 mm
Rate of change of base pressure; Cx = (q1 - q2) / Bx = 0.000 kN/m2/m
Calculate minimum depth of unreinforced strip footingAverage pressure to left of strip footing; qL = q1 - Cx (BL - b / 2) / 2 = 89.440 kN/m2
Minimum depth to left of strip footing; hLmin = (BL-b/2)max(0.15[(qL/1 kN/m2)2/(fcu/1 N/mm2)]1/4,1) =
125 mm
Average pressure to right of strip footing; qR = q2 + Cx (BR - b / 2) / 2 = 89.440 kN/m2
Minimum depth to right of strip footing; hRmin = (BR-b/2)max(0.15[(qR/1kN/m2)2/(fcu/1N/mm2)]1/4,1) =
125 mm
Minimum depth of unreinforced strip footing; hmin = max(hLmin, hRmin, 300 mm) = 300 mm
PASS - Unreinforced strip footing depth is greater than minimum
1. This structural design is based upon information provided by the architect, should any
variation between site conditions and the information provided by the architect be
identified, this design will be void.
2. No details in this pack should be scaled.
3. All construction work should be carried out by a competent contractor.
4. The contractor is responsible for all temporary supports and is to ensure that the structure
is adequately supported during the works.
5. Steel beams are heavy components and may require mechanical lifting aids.
6. All weak or damaged masonry is to be re-built.
7. Existing foundations are assumed to be adequate, however, this is subject to exposing
the existing foundations and an inspection for the satisfaction of the Building Control
Officer.
8. Steel beam end bearing not to be inserted into a chimney or chimney breast.
9. Steel beam end bearing not to be located within 50mm of a flue.
10. .All steel is to be Grade S275 to BS EN 10025 and shall be primed with zinc rich primer
11. Steel beam end bearings to be located on mass concrete padstones.
12. Padstones to be minimum grade C30 concrete.
13. The minimum end bearing length at supports to be 100mm.
14. Supporting masonry to comply with Eurocode 6 or BS 5628.
15. New steel beams to be encased in 12.5mm Gyproc fireline board with staggered joints
nailed to timber cradles or painted in Nullifire S or similar intumescent paint to provide 1/2
hour fire resistance accordance with manufacturer's recommendations.
16. Timber to be Grade C24
17. These calculations / designs should be read in conjunction with Architects drawings.