Spring Objectives 2013: Unit XEnergy (is Work) Energy and power expended:Kinetic and Potential...
Transcript of Spring Objectives 2013: Unit XEnergy (is Work) Energy and power expended:Kinetic and Potential...
Spring Objectives 2013:Unit X Energy (is Work)Energy and power expended: Kinetic and Potential (Chapter 11) \Conservation of energy (Chapter 11) Unit XI ThermodynamicsThermodynamics
First and Second Laws of Thermodynamics (Chapter 12)Internal energy and heat engine efficiency (Chapter 12)Specific and latent heats (Chapter 12)
Gases and Kinetic TheoryMolecular properties (Chapter 13)Heat transfer and expansion (Chapter 13)Pressure (Chapter 13)
Unit XII Waves
Speed, frequency, wavelength, (Chapter 14)Sound, Doppler effect (Chapter 15)Light Fundamentals (Chapter 16)Reflection and refraction (Chapter 17) Snell’s LawRefraction and Lenses (Chapter 18)Interference and diffraction (Chapter 19)
Spring 2015 Exam: Solve the energy crisis.
Physics Spring Term 2015
Unit XIII ElectricityElectricity
Electric fields, Electric forces, Potentials, Coulombs law (Chapter 20 / 21)Circuits and Circuit elements (Chapter 22 / 23)
Unit XIV MagnetismMagnetism (Chapter 24)
Magnetic FieldsMagnetic Forces
Unit XV Modern Physics I
Quantum Theory (Chapter 27)Photoelectric effect (Chapter 27)Spectra and energy levels (Chapter 27)Nuclear particle theory (Chapter 27)
Radioactivity and nuclear particle interactionsRelativity (Chapter 27)
Atomic Models (Bohr, Rutherford) (Chapter 28) Spring 2015 Exam: Solve the energy crisis.
Physics Spring Term 2015
Physics INDIVIDUAL Units
Energy Quiz
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The tallest roller coaster in the world is the “Steel Dragon” in Japan. The cars are raised from the loading platform to the top of the initial hill using a series of hydraulic and pneumatic lifters. It takes 35.00 seconds to reach the top of the hill. The first hill has a vertical drop of 93.5 meters and has an initial angle of 60 degrees from the base of the ride. The length of the first hill is 107.965 meters. The initial velocity of the cars at the top of the hill is 0.00 m/s. The mass of the fully loaded six cars is 2.825 X 103 Kg. As soon as the cars reach the bottom of the first hill, they enter a vertical loop that has more of an “egg shape”Rather than a perfect circle. The top and bottom of the loop have a radius of 18.50 meters with the top at 43.50 meters from the base of the ride. Half way up the loop the radius is 22.50 m and the height of the cars is 20.00 meters from the base of the ride.
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1) What is the total energy available for the six cars at the top of the hill?
2) How much work was done to get the cars to the top of the hill?
3) What was the power expended to get the cars to the top of the ride?
4) What is the velocity of the cars at the bottom of the first hill assuming no friction ?
Do Now
5) Now what is the velocity of the car at the top of the loop (No Friction)?
6) How many NET “g’s” do the riders feel at the top of the loop?_________
7) If the actual velocity at the bottom of the hill is 41.00 m/s what is the force of friction on the cars while going down the first hill?
F net = F app – F friction
F friction = ____________________________
8) What is the coefficient of friction of the track on the first 107.965 meter hill? µ = __________________ {hint: F friction = µ mg COS θ}
9) What was the Energy LOST during the first hill due to friction? (hint: W = Energy = F fric * d)
10) WITH FRICTION What will be the velocity at the top of the loop? -Assume a constant coefficient of friction of 1.43920 X 10-1
throughout the ride, and a loss of 2.14147 X 10 5 J on the first hill due to friction. -Assume that the total energy at the start of the ride
was 2.58855 X 106 Joules.-Assume the distance around the first half of the 22.5 meter radius loop to the top of the loop is 1.4137 X 10 2 meters. -Assume the apparent weight is due to the centripetal force and this force
is the average of the centripetal force at three points on the loop.
THREE STAGES
Find the NEW total Energy at the BOTTOM of the first hill, Velocity at bottom of 1st Hill:
Find the NEW total Energy at the half way point of the loop Velocity at the half way point of the loop
Find the NEW total Energy at the top point of the loopVelocity at the top point of the loop