Special Products and Factoring Strategies
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Transcript of Special Products and Factoring Strategies
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Special Products and Factoring Strategies
Review of Three Special Products
Recall the three special products:
1. Difference of Squares
x2 - y2 = (x - y) (x + y)
2. Square of Su
x2 + 2xy + y2 = (x + y)2
!. Square of Difference
x2 - 2xy + y2 = (x - y)2
Special Products Involving Cubes
"ust as there is a difference of squares forula# there is also a difference of cu$esforula.
%. x! - y! = (x - y) (x2 + xy + y2)
Proof:
&e use the distri$uti'e la on the riht hand side
x (x2 + xy + y2) - y (x2 + xy + y2)
= x! + x2y + xy2 - x2y - xy2 - y!
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*. o co$ine li,e ters to et
x! - y!
ext# e state the su of cu$es forula.
% x! + y! = (x + y)(x2 - xy + y2)
Exercise
ro'e the su of cu$es equation (quation *)
Using the Special Product Forulas for Factoring
Exaples:
/actor the folloin
1. !0x2 - %y2 = (0x - 2y) (0x + 2y) otice that there only to ters.
2. !x! - 12x2 + 12x = !x (x2 - %x + %) Ree$er to pull the / out first.
= !x(x -2)2
!. x0 - 0% = (x! - 3) (x! + 3)
= (x - 2) (x2 + 2x + %) (x + 2) (x2 - 2x + %)
Exercises:
/actor the folloin
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4. %*a! $ - 25a$!
6. 0%x0 - 10x! + 1
. x2 + 2xy + y2 - 31
D. x12 - y12 (hallene ro$le)
Factoring Strategies
• 4lays pull out the / first
• 7oo, for special products. 8f there are only to ters then loo, for su of
cu$es or difference of squares or cu$es. 8f there are three ters# loo, for
squares of a difference or a su.
• 8f there are three ters and the first coefficient is 1 then use siple trinoial
factorin.
• 8f there are three ters and the first coefficient is not 1 then use the 4 ethod.
• 8f there are four ters then try factorin $y roupin.
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Exercises
4. 45a3b - 20ab3
6. 0%x0 - 10x! + 1
. x2 + 2xy + y2 - 31
D. x12 - y12 (hallene ro$le)
Factoring Strategies
• 4lays pull out the / first
• 7oo, for special products. 8f there are only to ters then loo, for su of
cu$es or difference of squares or cu$es. 8f there are three ters# loo, for
squares of a difference or a su.
• 8f there are three ters and the first coefficient is 1 then use siple trinoial
factorin.
•8f there are three ters and the first coefficient is not 1 then use the 4 ethod.
• 8f there are four ters then try factorin $y roupin.
Exercises
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4. x! - x
6. x2
- 9x - !5
. 0a2 $ - %3a$ - 92a + !0
D. %x2 - !0xy + 31y2
. *a% $! +
1535a
/. 2x2 + *x - 12
. *x
!
+ %5
;. x! + !x2 - %x - 12
Factoring in Algebra
Factors
u$ers ha'e factors:
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4nd expressions (li,e x!"#x"$) also ha'e factors:
Factoring
/actorin (called <Factorising< in the >) is the process of finding the factors:
/actorin: /indin hat to ultiply toether to et an expression.
8t is li,e <splittin< an expression into a ultiplication of sipler expressions.
xaple: factor 2y+66oth 2y and 0 ha'e a coon factor of 2:
•
2y is 2 × y• 6 is 2 × 3
So you can factor the hole expression into:
2y+6 = 2(y+3)So# 2y+0 has $een <factored into< 2 and y+!
/actorin is also the opposite of xpandin:
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Common Factor
8n the pre'ious exaple e sa that 2y and 0 had a coon factor of !
6ut to do the ?o$ properly a,e sure you ha'e the highest coon factor# includin any 'aria$les
xaple: factor 3y2+12y/irstly# ! and 12 ha'e a coon factor of 3.
So you could ha'e:
3y2+12y = 3(y2+4y)6ut e can do $etter@
3y2 and 12y also share the 'aria$le y.
Aoether that a,es 3y:
• 3y2 is 3y × y
• 12y is 3y × 4
So you can factor the hole expression into:
3y2+12y = 3y(y+4)
hec,: $%&%"#' ( $% ) % " $% ) # ( $%!"*!%
More Complicated Factoring
Factoring Can e !ard "
Ahe exaples ha'e $een siple so far# $ut factorin can $e 'ery tric,y.
6ecause you ha'e to fiure what got ultiplied to produce the expression you are i'en@
8t can $e li,e tryin to find out hat inredients ent
into a ca,e to a,e it so delicious. 8t is soeties not
o$'ious at all@
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#$perience !elps
6ut the ore experience you et# the easier it $ecoes.
Example: Factor 4x2 - 9;... 8 canBt see any coon factors.
6ut if you ,no your Special 6inoial roducts you iht see it as the +difference of s,uares+:
6ecause #x! is &!x'!# and - is &$'!#
so e ha'e:
4$2 % & = (2$)2 % (3)2
4nd that can $e produced $y the difference of squares forula:
(a+b)(a%b) = a2 % b2
&here a is 2x# and b is !.
So let us try doin that:
(2$+3)(2$%3) = (2$)2 % (3)2 = 4$2 % &Ces@
So the factors of #x! . - are &!x"$' and &!x.$':
Ans'er 4$2 % & = (2$+3)(2$%3)
;o can you learn to do that 6y ettin lots of practice# and ,noin <8dentities<@
emember t*ese dentities
;ere is a list of coon <8dentities< (includin the +difference of s,uares+ used a$o'e).
8t is orth ree$erin these# as they can a,e factorin easier.
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a2 % b2 = (a+b)(a%b)
a2 + 2ab + b2 = (a+b)(a+b)
a2 % 2ab + b2 = (a%b)(a%b)
a3 + b3 = (a+b)(a2%ab+b2)
a3 % b3 = (a%b)(a2+ab+b2)
a3
+3a2
b+3ab2
+b3
= (a+b)3
a3%3a2b+3ab2%b3 = (a%b)3
Ahere are any ore li,e those# $ut those are the siplest ones.
Ad,ice
Ahe factored for is usually $est.
&hen tryin to factor# follo these steps:
• </actor out< any coon ters
• See if it fits any of the identities# plus any ore you ay ,no
• >eep oin till you canBt factor any ore
Cou can also use coputers@ Ahere are oputer 4le$ra Systes (called <4S<) such as Axiom,
Derive, Macsyma, Maple, Mathematica, MuPAD, Reduce and any ore that are ood at factorin.
More #$amples
8 said that experience helps# so here are ore exaples to help you on the ay:
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Example: w4 - 164n exponent of % Eay$e e could try an exponent of 2:
'4 % 16 = ('2)2 % 42
Ces# it is the difference of squares
'4
% 16 = ('2
+ 4)('2
% 4)4nd <(2 - %)< is another difference of squares
'4 % 16 = ('2 + 4)(' + 2)(' % 2)Ahat is as far as 8 can o (unless 8 use iainary nu$ers)
Example: 3u4 - 24uv3
Reo'e coon factor <!u<:
3-4 % 24-,3 = 3-(-3 % .,3)Ahen a difference of cu$es:
3-4 % 24-,3 = 3-(-3 % (2,)3)
= 3-(-%2,)(-2+2-,+4,2)Ahat is as far as 8 can o.
Example: z3 - z2 - 9z + 9
/ry 0actoring t*e 0irst t'o and second t'o separately
2(%1) % &(%1)o' (%1) is on bot* so let -s -se t*at
(2%&)(%1)And 2%& is a di00erence o0 s-ares
(%3)(+3)(%1)