Solving Quadratic Equations (finding roots) Example f(x) = x 2 - 4 By Graphing Identifying Solutions...
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Transcript of Solving Quadratic Equations (finding roots) Example f(x) = x 2 - 4 By Graphing Identifying Solutions...
Solving Quadratic Equations
(finding roots)
Example f(x) = x2 - 4
By GraphingIdentifying Solutions
4
2
-2
-4
-5 5
Solutions are -2 and 2.
EXAMPLE 3 Solve a quadratic equation in standard form
Solve 2x2 + 20x – 8 = 0 by completing the square.
SOLUTION
Write original equation.2x2 + 20x – 8 = 0
Add 8 to each side.2x2 + 20x = 8
Divide each side by 2.x2 + 10x = 4
Add 10 2
2, or 52, to each side.x2 + 10x + 52 = 4 + 52
Write left side as the square of a binomial.
(x + 5)2 = 29
Solving Quadratic Equations by Factoring
Solve by using he zero product property.
1) 2) 3) 20 48 16t t 42 x 10133 2 xx
To solve a quadratic equation if you can’t factor the equation:
• Make sure the equation is in the general form.
• Identify a, b, and c.
• Substitute a, b, and c into the quadratic formula:
• Simplify.
• Solve a previous problem using the quadratic formula.
Descriminants can give us hints…
For the equation . . . 0742 xx
. . . the discriminant
acb 42 12
There are no real roots as the function is never equal to zero
2816
The Discriminant of a Quadratic Function
If we try to solve , we get0742 xx
2
124 x
The square of any real number is positive so there are no real solutions to 12
742 xxy0
Roots, Surds and Discriminant
Complex Conjugates and Division
Complex conjugates-a pair of complex numbers of the form a + bi and a – bi where a and b are real numbers.
( a + bi )( a – bi )
a 2 – abi + abi – b 2 i 2
a 2 – b 2( -1 )
a 2 + b 2
The product of a complex conjugate pair is a positive real number.
• Ex. Find the real and non-real roots of
154)( 2 xxxf