Solving equations ok1296542729
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Transcript of Solving equations ok1296542729
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Solving Equations
Overview
Boddu S Rao
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A linear or First degree Equation• Eg. 2y+1 = 13
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1.Solving linear equations by using inverse operations
• x – 7 = -3• + 7 = +7 (adding 7 on each side)• --------------• X = 4
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3x = 21
• 3x / 3 = 21 /3 ( dividing each by 3)• X = 7
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Solving Equations with parentheses
Solve 3(b+2) +2b = 21
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3(b+2) +2b = 21
• 3b+6 +2b = 21• 5b+6 = 21• 5b+6-6 = 21-6• 5b = 15• 5b/5 = 15/ 5• Therefore b = 3
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Solving equation contains fractions
m/3 – m/4 = 2
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m/3 – m/4 = 2
• 12(m/3) – 12(m/4) = 12(2) [ L.C.M. of 3 &4 is 12)
• 4m – 3m = 24• So, m= 24
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Solving Equations by cross multiplying• If x / 3 = (x + 4)/5 , what is the value of x?
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If x / 3 = (x + 4)/5 , what is the value of x?• 5(x) = 3(x+4)• 5x = 3x +12• 2x = 12 • x = 12 / 2• Therefore x= 6
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Using A root of an equation to answer a question
• If 3y – 2 = 4 , what is the value of y – 2 ?
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If 3y – 2 = 4 , what is the value of y – 2 ?
• If 3y – 2 = 4 ,then 3y = 6 • Therefore y = 2• The value of y-2 = 2 – 2 = 0
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The END
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Thank you for viewing ….
• Presented by Boddu S Rao