Solving Absolute Value Inequalities Part 1 Honors Math – Grade 8.
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Transcript of Solving Absolute Value Inequalities Part 1 Honors Math – Grade 8.
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Solving Absolute Value Inequalities Part 1Honors Math – Grade 8
![Page 2: Solving Absolute Value Inequalities Part 1 Honors Math – Grade 8.](https://reader036.fdocuments.in/reader036/viewer/2022083009/5697bf7b1a28abf838c8367e/html5/thumbnails/2.jpg)
Absolute Value Inequalities with <
When solving an inequality of the form |x|<n, consider the following cases:
1. The expression inside the absolute value symbols is positive.
2. The expression inside the absolute value symbols is negative.
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5xThis means the distance from zero is less than 5 units.
5 units 5 units
This shows an intersection. Write an inequality for each situation. x > -5 x < 5KEY CONCEPT Absolute Value Inequalities with <
ax + b > -candax + b < cmeans|ax + b|<c
ax + b > -candax + b < cmeans|ax + b|<c
![Page 4: Solving Absolute Value Inequalities Part 1 Honors Math – Grade 8.](https://reader036.fdocuments.in/reader036/viewer/2022083009/5697bf7b1a28abf838c8367e/html5/thumbnails/4.jpg)
Solve the open sentence. Then graph the solution set. 45 g
Write the inequality as a compound inequality using “and.”
g + 5 < 4 g + 5 > -4
Solve each inequality.
-5 -5 -5 -5
g < -1 g > -9
Therefore, g < -1 and g > -9.
Graph the solution set.The solution set represents an intersection.
The solution set is: -9 < g < -1
![Page 5: Solving Absolute Value Inequalities Part 1 Honors Math – Grade 8.](https://reader036.fdocuments.in/reader036/viewer/2022083009/5697bf7b1a28abf838c8367e/html5/thumbnails/5.jpg)
Solve the open sentence. Then graph the solution set. 28 n
Write the inequality as a compound inequality using “and.”
n – 8 < 2 n - 8 > -2
Solve each inequality.
+8 +8 +8 +8
n < 10 n > 6
Therefore, n < 10 and n > 6
Graph the solution set.The solution set represents an intersection.
The solution set is: 6 < n < 10
![Page 6: Solving Absolute Value Inequalities Part 1 Honors Math – Grade 8.](https://reader036.fdocuments.in/reader036/viewer/2022083009/5697bf7b1a28abf838c8367e/html5/thumbnails/6.jpg)
Solve the open sentence. Then graph the solution set. 352 c
Write the inequality as a compound inequality using “and.”
2c + 5 < 3 2c + 5 > -3
Solve each inequality.
-5 -5 -5 -5
2c < -2 c < -1
2c > -8 c > -4
Therefore, c < -1 and c > -4.
Graph the solution set.The solution set represents an intersection.
The solution set is: -4 < g < -1
![Page 7: Solving Absolute Value Inequalities Part 1 Honors Math – Grade 8.](https://reader036.fdocuments.in/reader036/viewer/2022083009/5697bf7b1a28abf838c8367e/html5/thumbnails/7.jpg)
75 cSolve
Recall that the absolute value of a number is the distance from zero. This means that the absolute value of a number is always positive!
Since l x + 2 l cannot be negative, l x + 2 l cannot be less than -7. So the solution is
This is the symbol for the empty set.
It means there is NO SOLUTION!