Soil analysis
Transcript of Soil analysis
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ESPEK RESEARCH & ADVISORY
SERVICES (ERAS)
PRESENT BY:NOOR SYAFIQAH
BINTI HABDUL LATIF
SOIL ANALYSIS
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INTERNSHIP REPORTWeeks Report
Week 1 - 2 : Fertilizer analysis [compound – CHB, baja kilang – R3Z, AJIB CRF, R1(WSP), R4, BOE analysis]
: Particles size, moisture: Washing
Week 3 - 5 : Soil analysis [soil registration, sample preparation, bases, pH, total P, available P, dry moisture, trace element, preparation of standard & reagents, UV-VIS spectrometry]
: Soil analysis[cation exchange capacity (CEC), bases, wet moisture, soil sample preparation, total P, available P, UV-VIS spectrometry]
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• Soil analysis is a set of various chemical processes that determine the amount of available plant nutrients in the soil, but also the chemical, physical and biological soil properties important for plant nutrition, or "soil health".
What is soil analysis?
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To determine the level of
availability of nutrients
To predict the fertility of the
soil
To evaluate the status of each nutrient
element
Purpose of soil analysis
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13 elements that being analyzed in soil laboratory
Potassium(K)Magnesium
(Mg)
Sodium
(Na)pH
Calcium (Ca)
Moisture
Available phosphorus(Ap)
Ferum
(Fe)
Zinc
(Zn)
Total phosphorus(Tp)
Copper (Cu)
Nitrogen (N)
Cation exchange capacity
(CEC)
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Analysis of soil1. Sampling/preparation
2. Determine the pH3. Determine the moisture sample
4. Leaching & Cation Exchange Capacity(CEC)5. Total phosphorus
6. Available phosphorus7. Total nitrogen,organic carbon & sulphur
8. Mechanical analysis9. Trace element analysis
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METHODOLOGY
1) Registratio
n
2) Drying
3) Crushing
and sieving
4)Weighing
5) Analyzing
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Registration• The soil samples
received.
• The quantity of samples were checked.
• The soil samples were
registered and put on the labelled box to dry
it out.
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Drying
• After being registered, the soil samples were dried out at a well air-ventilation.
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Crushing and sieving
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Weighing
Trace element:10 g of
sample (100 mL plastic
vial) pH:20 g of
sample (100 mL plastic
vial)
Moisture:10 g of sample
(petri dish)
Available P:2 g of
sample (50 mL plastic
vial)
Total P:1 g of
sample (digestion
tube)
Bases:10 g of
sample (50 mL plastic
vial)
Mechanical analysis:10 g of
sample & 6 g sodium
hemametaphosphate
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Analyzing-total phosphorus(TP)
Preparation of standard (KH2PO4):• How to prepare 1000ppm?
1) 10 g of KH2PO4 was put into an oven at 105°C and left overnight.
2) KH2PO4 was cooled down in dessicator.
3) Weighing(to prepare 1000ppm in 1 L volumetric flask) .
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• Atomic weight of KH2PO4=30.9738• Molecular weight of KH2PO4=136.09g/mol• 30.9738 =136.09• 1 =(1/30.9738)x136.09
=14.3937 g (1000 ppm)
• From 1000 ppm is diluted to 100 ppm & from 100 ppm is diluted to 10 ppm
• From 10 ppm are diluted to 0.0, 0.2, 0.4, 0.6, 0.8 & 1.0 ppm in 100 mL volumetric flask:
• M1V1 = M2V2• (10)V1 = (1.0)(100) = 10 mL
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Preparation of reagents:a) Digestion mixture:
Add to known volume of 60% perchloric acid an equal volume concentrated sulphuric acid. Cool the mixture to room temperature.
b) Reagent A:Dissolve 12 g ammonium molybdate in water and add 148 mL conc. Sulphuric acid (H2SO4).Dissolve 0.2908 g potassium antimony in water and add to the above solution.
c) Reagent B:Dissolve 1.32 g ascorbic acid to every 250 mL reagent A used.
• Ammonium molybdate and potassium antimony react in acid medium with othophosphate to form a heteropoly acid (phosphomolybdic acid) that is reduced to in tensely colored molybdanum blue by ascorbic acid.
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1 g of sample was weighed
The samples were digested
6 mL of HClO4 + H2SO4 was
added
The sample was transferred into a
digestion tube
Procedures
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Distilled water was added
The sample solution was
shook
The tube was mark up with distilled
water
The samples were filtrated
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Distilled water was added
8 mL reagent B was added
The samples were run by UV-VIS spectrometer
Mark up with distilled water
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0 0.2 0.4 0.6 0.8 1 1.20
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
f(x) = 0.247999999999999 x + 0.543000000000001
Linear regression of standard P
Concentration (ppm)
Abso
rban
ce
Data and calculation
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• y = mx+ c• y = 0.248x +
0.543• X = (y-c)/m
• Eg: BLK TP• X = (0.5373-
0.543)/0.248• X = -0.02298
1st dilution = 100/1 =1002nd dilution = 50/5 = 53rd dilution = 1Concentration of TP = concentration(ppm) x 1st dilut. X 2nd dilut. X 3rd dilut.
= -0.023 x 100 x 10 x 1 = -23
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• Soil analysis is very important in order to determine whether
the soil is in well condition which is in a very good fertility
for plantation.• From this analysis, element consists by soil can be identify
and future planning can be well plan.
Conclusion