Perinatal Drug Testing Using Umbilical Cord Tissue - NMS Labs
soft-tissue-mechanics-labs Documentation
Transcript of soft-tissue-mechanics-labs Documentation
soft-tissue-mechanics-labsDocumentation
Release 3.0
Martyn Nash, Hugh Sorby, Thiranja Prasad Babarenda Gamage
Mar 19, 2021
Contents
1 Introduction 3
2 Using OpenCMISS 52.1 Installing OpenCMISS . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52.2 Starting OpenCMISS . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52.3 Running models in OpenCMISS . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6
3 Lab 1: Analysing deformation in isotropic materials 73.1 Section 1: Solving mechanics models . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 73.2 Section 2: Strain analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8
4 Lab 2: Stress transformations 134.1 Revision . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 134.2 Section 1: Transforming from 2nd Piola-Kirchhoff to Cauchy stress tensor components . . . . . . . . 134.3 Section 2: Transforming stresses between rotated coordinate systems . . . . . . . . . . . . . . . . . 14
5 Lab 3: Analysing stresses in anisotropic materials 215.1 Revision . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 215.2 Section 1: Deriving components of the stress tensor . . . . . . . . . . . . . . . . . . . . . . . . . . 215.3 Section 2: Analysing stresses during equi-biaxial deformation . . . . . . . . . . . . . . . . . . . . . 22
6 Indices and tables 25
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Contents:
Contents 1
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2 Contents
CHAPTER 1
Introduction
Welcome to the soft tissue mechanics labs, which will take you through the following topics:
β’ Lab 1: Analysing deformation in isotropic materials
β’ Lab 2: Stress transformations
β’ Lab 3: Analysing stresses in anisotropic materials
These labs make use of the OpenCMISS computational modelling software that will be outlined in the next section.
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4 Chapter 1. Introduction
CHAPTER 2
Using OpenCMISS
This lab will make use of the OpenCMISS computational modelling software being developed at the Auckland Bio-engineering Institute. This software includes a computational back-end named Iron that runs simulations, and a font-end graphical user interface (GUI) named Neon that is used to visualise the results. For the purpose of these labs,we will only be interacting with the Neon GUI that has been set up with a series of simple computational models foranalysing stresses and strains in isotropic and anisotropic materials.
2.1 Installing OpenCMISS
An OpenCMISS installer for Windows 10 (64-bit) can be downloaded from this link.
2.2 Starting OpenCMISS
Once installed, OpenCMISS can be run from the start menu. When the program starts, you will be prompted to selecta project as shown in the screenshot below.
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Select a project and click ok. A drop down menu will appear listing a series of models that will be analysed during thecourse of the lab.
2.3 Running models in OpenCMISS
Select a model from the drop down menu and click βRunβ as shown in the screenshot below.
To run another model, select βProblemβ from the menu bar.
To open another project, select the new project button on the left hand side of the menu bar.
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CHAPTER 3
Lab 1: Analysing deformation in isotropic materials
The objective of this lab is to analyse large deformation kinematics with respect to reference coordinates in isotropicmaterials, for with the stiffness properties are the same in all directions. The deformations you will be analysinginclude:
β’ Model 1 (Uniaxial extension of unit cube)
β’ Model 2 (Equibiaxial extension of unit cube)
β’ Model 3 (Simple shear of unit cube)
β’ Model 4 (Shear of unit cube)
β’ Model 5 (Extension and shear of unit cube)
Before starting this lab, please read the Using OpenCMISS section to familiarise yourself with the software used inthis lab.
3.1 Section 1: Solving mechanics models
1. Start OpenCMISS and load the βKinematics analysisβ project (described in the Starting OpenCMISS section).
2. Select βModel 1 (uniaxial extension of unit cube)β from the drop down menu and click the βRunβ button (screen-shots of this procedure are shown in the Running models in OpenCMISS section).
3. After a short time, the model should have solved and the simulation results pane will open, as shown in thescreenshot below.
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The simulation results are shown in the 3D graphics window. In this graphical window:
β’ the undeformed (reference) configuration of the unit cube is shown in red; and
β’ the deformed (current) configuration is shown in green (π₯1, π₯2, π₯3 components of the deformedcoordinates are shown at the corners of the model).
The model in the 3D graphics window can be rotated (click-drag-left-mouse button), translated (click-drag-middle-mouse button), or zoomed (click-drag-right-mouse button).
3.2 Section 2: Strain analysis
4. Write down the coordinate equations that describe this deformation in the form π₯ = π(π), i.e.:
π₯1 = ππ1 + ππ2 + ππ3
π₯2 = ππ1 + ππ2 + ππ3
π₯3 = ππ1 + βπ2 + ππ3
where the constants π to π need to be identified from the undeformed and deformed coordinates of themodel shown in the graphics window.
Note: The undeformed (reference) configuration is the unit cube shown in red.
5. Determine the deformation gradient tensor (πΉ = ππ₯ππ ).
6. Evaluate the determinant of πΉ to see whether the material is incompressible (i.e. maintains constant volume).
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7. Determine:
β’ right Cauchy-Green deformation tensor (πΆ),
β’ πΌ1 = π‘ππππ(πΆ),
β’ πΌ3 = πππ‘(πΆ), and the
β’ Green-Lagrange strain tensor (πΈ).
8. Check your answers to 5-7 against the simulation results.
Note: Click and drag on the right hand boundary of the 3D graphics window to view the simulationresults as shown in the screenshots below:
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Note: In some cases, an apparent zero may be preceded by a negative sign. This value should still betreated as zero (i.e. ignore the negative sign).
9. Select βProblemβ from the menu bar and repeat steps 2-8 for the remaining models in the kinematics analysisproject:
β’ Model 2 (Equibiaxial extension of unit cube)
β’ Model 3 (Simple shear of unit cube)
β’ Model 4 (Shear of unit cube)
β’ Model 5 (Extension and shear of unit cube)
3.2.1 Questions to consider
After you have completed the above exercises, consider the following questions:
a. What do the off-diagonal components of πΉ represent?
b. In Model 1, why are πΈ22 and πΈ33 negative? What does this represent?
c. In Model 4, what does the equality of πΉ11 and πΉ33 represent? Why is πΉ22 less than 1.
Note: By the end of this lab you should be able to:
β’ analyse large deformation kinematics with respect to reference coordinates, i.e. by determining πΉ , πΆ, invariantsof πΆ, and πΈ.
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β’ relate the components of the deformation gradient tensor to the underlying deformation.
β’ determine if a deformation is incompressible.
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CHAPTER 4
Lab 2: Stress transformations
The objective of this lab is to:
1. transform 2nd Piola-Kirchhoff stresses to Cauchy stresses.
2. transform stresses and strains between reference and material (fibre) coordinates.
The deformations that will be considered in this lab include uniaxial and equi-biaxial extension of a unit cube.
4.1 Revision
Before starting this lab, please be sure to have completed Lab 1: Analysing deformation in isotropic materials.
4.2 Section 1: Transforming from 2nd Piola-Kirchhoff to Cauchystress tensor components
1. Start OpenCMISS and load the βKinematics analysisβ project. Select βModel 1 (Uniaxial extension of unitcube)β from the drop down menu and click the βRunβ button.
2. Open the simulation results pane and use the components of the 2nd Piola-Kirchhoff stress tensor (π ) and thedeformation gradient tensor (πΉ ) to determine the Cauchy components of the stress tensor (Ξ£) (Donβt forget theJacobian (π½)). See this link for an example on how to open the simulation results pane.
Note: Hint: See equations in Section 3.1 of Nash and Hunter (2007).
3. Select βProblemβ from the menu bar and repeat step 1-2 for the remaining models in the kinematics analysisproject.
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Note: By the end of this section you should be able to:
β’ derive the Cauchy stress tensor components from the second Piola-Kirchhoff stress tensor components using thedeformation gradient tensor.
4.3 Section 2: Transforming stresses between rotated coordinatesystems
4.3.1 Uniaxial extension of a unit cube
1. Consider the uniaxial deformation shown in the figure below, where a set of material axes are aligned with thespatial reference axes. In the following figure, the gold arrows represent the first material axis (for example, thismight be a the orientation of a collagen fibre within tissue):
In the screenshot:
β’ the undeformed (reference) configuration of the object (a unit cube) is shown in red;
β’ the deformed (current) configuration of the object is shown in green; and
β’ the gold arrows indicate the direction of the first material (fibre) axis in the object. In general,the microstructural fibres are not necessarily parallel to the direction of stretch or load.
This deformation is described by the following equations:
π₯1 =3
2π1 π₯2 =
βοΈ2
3π2 π₯3 =
βοΈ2
3π3
In all figures, π₯ represents π1 and π₯1, π¦ represents π2 and π₯2, and π§ represents π3 and π₯3.
2. Write down (see Lab 1):
β’ the deformation gradient tensor, πΉ = ππ₯ππ
β’ the right Cauchy-Green deformation tensor, πΆ and
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β’ the Green-Lagrange strain tensor. Label this as πΈπππ (to indicate that it is defined with respect tothe reference spatial coordinates).
Note: This is the same deformation used in Model 1 in Lab 1, so you should not need to re-do thesecalculations.
For this particular model, the second Piola-Kirchhoff stress tensors with respect to both the referencespatial, and material fibre axes, are:
ππππ = ππππ =
β‘β£440.5 0 00 0 00 0 0
β€β¦(Note: While the uniaxial deformation in Model 1 of Lab 1 is the same as that considered here, the stresstensors are different between thse two labs because different stress-strain constitutive relations havebeen used - this difference will be covered in Lab 3).
Uniaxial deformation with respect to rotated material axes
3. Now consider the same deformation, except that the material fibre axes are no longer aligned with the referencespatial axes. They are now rotated anti-clockwise by an angle of π = 30 degrees from the π1 axis (in the π1-π2
plane), as shown in the figure below.
For the following exercises, you are asked to transform strain and stress tensors between the referencespatial coordinates and the material fibre coordinate systems using the generalised rotational transformgiven by:
πΈπππ = πππΈππππ
where πΈπππ and πΈπππ are Green-Lagrange strain tensors defined with respect to the reference spatial andmaterial fibre axes, respectively, and π is the orthogonal rotation matrix, which for this example is defined
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by:
π =
β‘β£cos(π) β sin(π) 0sin(π) cos(π) 0
0 0 1
β€β¦
4. Calculate the components of the Green-Lagrange strain tensor with respect to the material fibre axes (πΈπππ) viathe appropriate tensor transformation (see Step 3).
5. Explain similarities/differences between πΈπππ and πΈπππ for this model.
6. The relationship between second Piola-Kirchhoff stress tensors defined with respect to reference spatial andmaterial fibre coordinates is (note the similarity to Step 3):
π πππ = πππ ππππ
Invert this equation, and then calculate the second Piola-Kirchhoff stress components with respect to thereference spatial axes (π πππ ) from the following components of the second Piola-Kirchhoff stress tensorwith respect to the material fibre axes (π πππ):
ππππ =
β‘β£ 330.345 β190.725 0β190.725 110.115 0
0 0 0
β€β¦
7. Explain similarities/differences between π πππ and π πππ for this model.
8. What would you expect from the analysis in steps 4-7 if the fibre angle was changed from π = 30 degrees toπ = 45 degrees, or to π = 90 degrees for this model? Explain the differences/similarities of the stress tensorsπ πππ and π πππ for this uniaxial deformation model.
Note: You should not need to do any calculations to answer this questions, but if you would like the extrapractice, perform steps 4-7 using:
π = 45 degrees, where the second Piola-Kirchhoff stress tensor with respect to the material fibre axes is:
ππππ =
β‘β£ 220.2 β220.2 0β220.2 220.2 0
0 0 0
β€β¦and/or π = 90 degrees, where the second Piola-Kirchhoff stress tensor with respect to the material fibreaxes is:
ππππ =
β‘β£0 0 00 440.5 00 0 0
β€β¦
Here are the solutions to Steps 1-8.
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4.3.2 Equi-biaxial extension of a unit cube
9. Start OpenCMISS and load the stress analysis project (described in the Starting OpenCMISS section).
10. Select βModel 1 (Equi-biaxial extension of unit cube, 0 degree fibre rotation)β from the drop down menu andclick the βRunβ button (screenshots of this procedure are shown in the Running models in OpenCMISS section).
11. After a short time, the model should have solved and the simulation results will appear in the 3D graphicswindow as shown in the screenshot below.
In this graphical window:
β’ the undeformed (reference) configuration of the unit cube is shown in red, and
β’ the deformed (current) configuration is shown in green (π₯1, π₯2, π₯3 components of the deformedcoordinates are shown at the corners of the model.
β’ ignore the gold arrows for now - these will be needed later.
The model in the 3D graphics window can be rotated (click-drag-left-mouse button), translated (click-drag-middle-mouse button), or zoomed (click-drag-middle-mouse button).
12. This equi-biaxial deformation is incompressible (i.e. maintains constant volume) described by the equations:
π₯1 =5
4π1 π₯2 =
5
4π2 π₯3 =
16
25π3
13. Write down:
β’ the deformation gradient tensor (πΉ = ππ₯ππ ),
β’ the right Cauchy-Green deformation tensor (πΆ), and
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β’ Green-Lagrange strain tensor (πΈ) (label this πΈπππ ).
Note: This is the same deformation used in Model 2 of Lab 1, so you should not need to re-do thesecalculations.
Equi-biaxial deformation with respect to rotated material fibre axes
14. Return to the model selection drop down menu and select/run βModel 3 (Equi-biaxial extension of unit cube, 30degree fibre rotation)β. This model is similar to the previous models, except that the material fibre axes are nolonger aligned with the reference (spatial) axes. For this model, the material fibre axis is rotated anti-clockwiseby an angle of π = 30 degrees from the π1 axis (in the π1-π2 plane). When visualising these models, the goldarrows in the graphics window indicate the direction of the first material fibre axis (along which the first materialcoordinate is defined), and the second material fibre axis (not shown) is perpendicular to the gold arrow but lieswithin π1-π2 plane.
15. Determine the Green-Lagrange strain tensor components with respect to the material fibre axes (πΈπππ) using theapproach in Section 2.
16. Check your answers to Step 15 against the simulation results from OpenCMISS.
Note: Drag the right edge of the 3D graphics window to reveal the stress and strain tensor componentsassociated with the simulation in material fibre and reference spatial coordinates. See this link for anexample on how to open this pane.
17. Explain similarities/differences between πΈπππ and πΈπππ for this model.
18. From the solution output, write down π πππ (the second Piola-Kirchhoff stress tensor with respect to the materialfibre axes). Use this to determine the second Piola-Kirchhoff stress components with respect to the referencespatial coordinate axes (π πππ ) via the approach Section 2.
19. Check your answers to Step 18 against the simulation results.
20. Explain similarities/differences between π πππ and π πππ for this model.
21. What would you expect from the analysis in steps 15-20 if the fibre angle was changed from π = 30 de-grees to π = 45 degrees, or to π = 90 degrees for this equi-biaxial deformation model? Explain the dif-ferences/similarities between the two strain tensors for this model. Then explain the differences/similaritiesbetween the two stress tensors for this model.
Note: You should not need to do any calculations to answer this questions. It is fine to do so if you wouldlike some extra practice - just perform steps 15-20 with π = 45 degrees by selecting the Model 4 thenModel 6 from the βRunβ menu.
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Here are the solutions to Step 21.
4.3.3 Questions to think about:
After you have completed the exercises above, consider the following questions:
a. How do changes in πΈπππ for different fibre angles (π) in the equi-biaxial deformation compare with the changesseen in the uniaxial deformation.
b. How do changes in πΈπππ for different fibre angles (π) in the equi-biaxial deformation compare with the changesseen in the uniaxial deformation.
c. How do changes in π πππ for different fibre angles (π) in the equi-biaxial deformation compare with the changesseen in the uniaxial deformation.
d. How do changes in π πππ for different fibre angles (π) in the equi-biaxial deformation compare with the changesseen in the uniaxial deformation.
e. Will the invariants of πΆ be the same or different when calculated with respect to reference spatial or materialfibre coordinates?
Note: By completing this lab, you should be able to:
β’ convert between 2nd Piola-Kirchhoff and Cauchy stress tensors.
β’ analyse large deformation kinematics with respect to reference spatial or rotated material fibre coordinates, andconvert between them.
β’ analyse stress tensors with respect to reference spatial or rotated material fibre coordinates, and convert betweenthem.
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CHAPTER 5
Lab 3: Analysing stresses in anisotropic materials
The objective of this lab is to learn how to analyse anisotropic constitutive equations and stresses defined with respectto a material coordinate system.
5.1 Revision
Before starting this lab, please be sure to have completed:
a. Lab 1: Analysing deformation in isotropic materials, and
b. Lab 2: Stress transformations.
Section 2 of Lab 2 demonstrated how rotating the material-fibre axis with respect to the reference axes influences thecomponents of the stress tensor. For the model in Section 2 of Lab 2, which considers an isotropic cube subject toequi-biaxial deformation, remind yourself:
β’ What happened to the components of the stress tensor as the material-fibre axis was rotated? Why?
All of the analyses in the present lab will be based on the equi-biaxial deformation described in Section 2 of Lab 2.The difference here is that we will now consider anisotropic mechanical properties that describe different stress-strainresponse alonf the different material axes.
5.2 Section 1: Deriving components of the stress tensor
1. Consider the following exponential constitutive relation, which is used to describe the distortional mechanicalresponse of the cube considered in this lab:
ππΌ =π12(ππ β 1)
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where
π =ππππΈ2ππ + ππ π πΈ
2π π + ππππΈ
2ππ+
2πππ (1
2(πΈππ + πΈπ π ))
2 + 2πππ(1
2(πΈππ + πΈππ ))
2 + 2πππ (1
2(πΈππ + πΈπ π))
2
Differentiate this strain energy density function with respect to each of the nine Green-Lagrange strain components(πΈπΌπ½), where πΌ and π½ each represent one of the microstructural material coordinates, (π, π , π). Thus, derive generalisedanalytical expressions for the nine distortional components of the second Piola-Kirchhoff stress tensor in terms ofthe strain components and the material constants: π1, πππ , ππ π , πππ, πππ , πππ, πππ .
Note:
β’ At this stage, do not substitute any values for the strain components nor constants.
β’ Recognising the similarity of terms should simplify this task.
β’ Donβt forget the chain rule when differentiating the exponential.
5.3 Section 2: Analysing stresses during equi-biaxial deformation
5.3.1 Analysing stresses with respect to the reference coordinates
2. Using OpenCMISS, load the stress analysis project and run Model 1. (The procedure for running this simulationin OpenCMISS is outlined in steps 1-3 in Section 2 of Lab 2). See this link for an example on how to open thesimulation results pane.
3. The Model 1 simulation uses the above constitutive equation with the following material constants:
π1 = 0.0475 πππ
πππ = ππ π = πππ = πππ = πππ = πππ = 15.25
Substitute the Green-Lagrange strain components (πΈπππ ) for this equi-biaxial deformation into your an-alytical expressions from Step 1 of this lab to determine values for the distortional components of thesecond Piola-Kirchhoff stress tensor. Verify that these distortional stresses are:
π ππ_πππ π‘πππ = π π π _πππ π‘
πππ = 8.59 πππ
Note:
β’ Hint: in the steps below, you will use your your analytical equations from step 1 repeatedly to donumber of calculations (with different parameters), so you might consider encoding your equationsusing a high level programming language (python, C, Matlab, etc) or a spreadsheet.
β’ Hint: π = 3.74.
β’ Your calculations for π ππ_πππ π‘πππ and π π π _πππ π‘
πππ could be within Β±0.02 πππ of the solution stated abovedue to round off errors.
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β’ These distortional components of the second Piola-Kirchhoff stress tensor (e.g. π ππ_πππ π‘πππ ) do
not match the stress values shown in the OpenCMISS results panel because the OpenCMISS resultsshow only the total stress components, which will be considered in the following steps.
4. Now assume that the material is incompressible, and write down analytical expressions for the total stresscomponents with respect to the reference coordinates: π ππ
πππ and π π π πππ (these are shown as π ππ and π π π in Eqn
38 of Nash and Hunter (2007), or Eqn 15 of Nash and Hunter (2000)).
5. Calculate the total stress components with respect to the reference coordinates: π πππππ and π π π
πππ using the ex-pressions you wrote down in Step 4 above. This requires addition of a dilatational component of stress calledthe hydrostatic pressure, π, which is a scalar variable with a value that is provided in the simulation results.Check your total stress values against those in the simulation results.
Note:
β’ {πΆππ} is the inverse of {πΆππ}. (They are different tensors)
β’ It is straightforward to invert a diagonal tensor. Check that {πΆππ}β1{πΆππ} = πΌ .
6. Using this analysis, what can you infer about the material symmetry of Model 1? Explain your observation.
7. Now run Model 2, which is similar to Model 1 except that the material constants are set to:
π1 = 0.0475 πππ
πππ = 15.25 ππ π
= 6.8 πππ = 8.9
πππ = 6.95 πππ
= 6.05 πππ = 4.93
Re-use your analytical expressions from Step 1 above, now with these new material constants, to calculatedistortional components of the second Piola-Kirchhoff stress tensor: π ππ_πππ π‘
πππ and π π π _πππ π‘πππ with respect
to the reference axes.
8. Re-use your analytical expressions from Step 4 above to calculate, for Model 2, the total stress components:π πππππ and π π π
πππ (use the new hydrostatic pressure value, π, from the simulation results). Check your answersagainst the simulation results.
9. Explain the similarities and differences in the total second Piola-Kirchhoff stress components from Steps 5 and8. What can you infer about the mechanical responses (material symmetries) of the two models?
5.3.2 Stresses with respect to rotated material-fibre axes
10. Now run Model 5, which uses the same (anisotropic) material constants as in Step 7 above. In this simulation,the material-fibre axis is oriented at π = 45 degrees with respect to the π1-axis (in the π1-π2 plane).
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11. Substitute the fibre strain components (πΈπππ) from the simulation results, and the material constants from Step7, into your expressions from Section 2 to determine the components of the total second Piola-Kirchhoff stresstensor with respect to the material-fibre coordinates, π πππ (use the hydrostatic pressure, π, from the simulationresults).
12. Determine the second Piola-Kirchhoff stress components with respect to the reference coordinate axes (π πππ )via an appropriate tensor transformation (see Step 3 of Section 2 of Lab 2a). Check your answers against thesimulation results.
13. How do the stress components of π πππ and π πππ for this model compare to the components of π πππ for theprevious model in Step 5 above? Explain the similarities and differences.
14. Now run Model 6, for which the material-fibre axis is oriented at π = 90 degrees with respect to the π1-axis (inthe π1-π2 plane). Repeat the analyses in Steps 11-12.
15. How do the stress components of π πππ and π πππ for this model compare to the components of π πππ for theprevious model in Step 5 above? Explain the similarities and differences.
5.3.3 Extra discussion points for experts
If you have completed the exercises above, you may like to consider the following questions:
a. What do you notice about the stress tensors, π πππ and π πππ , from the above analyses for the isotropic (Model1) and anisotropic (Models 2,5,6) materials subject to equi-biaxial deformations? Explain this observation.
b. Model 1 considers equi-biaxial deformation, and there were similarities in some of the stress components. If,instead, a uniaxial stretch was applied along the π1 direction, predict what would happed to the components ofstress.
c. What would you expect if you compared the maximum principal stresses for each of the anisotropic cases(Models 2,5,6)? Justify your amswer.
Note: By completing this lab, you should be able to:
β’ derive expressions for the components of the second Piola-Kirchhoff stress tensor.
β’ evaluate components of the second Piola-Kirchhoff stress tensor with respect to spatial or material-fibre coordi-nates.
β’ infer the material symmetry of a material described by a specific constitutive equation and a particular set ofmaterial constants by analysing the stress components.
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CHAPTER 6
Indices and tables
β’ genindex
β’ modindex
β’ search
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