Slab Design

13
No Liability is accepted by the Developer of this software for any direct

description

SLAB DESIGN

Transcript of Slab Design

Page 1: Slab Design

No Liability is accepted by the Developer of this software for any direct, indirect, consequential or accidental loss or damage

Page 2: Slab Design

No Liability is accepted by the Developer of this software for any direct, indirect, consequential or accidental loss or damage

DESIGN SLAB ->

Page 3: Slab Design

SLAB DESCRIPTION: DAANISH SCHOOL VEHARI (HOSTEL) F.F.S PANEL No.: S4

SLAB DIMENSIONS Mu(-ve) =-9.46 k-ft/ft

Short Span (la) 16 ft As = 0.41 sq.in/ft

Long Span (lb) 24 ft #4 @ 5.5 in c/c (T)

SLAB THICKNESS

Thickness Required 5.82 in Mua+ =5.61k-ft/ft

Thikness Provided 6.5 in As = 0.23 sq.in/ft

Clear Cover (Top & Bottom) 0.75 in #3 @ 5.5 in c/c (B)

Mu (-ve)=-0.65 k-ft/ft Two Way Slab Mu (-ve) =-0.65 k-ft/ft

IMPOSED LOADS Asmin = 0.14 sq.in/ft Mub+ =1.96 k-ft/ft Asmin = 0.14 sq.in/ft

Superimposed Dead Load (unfactd) 200 psf #3 @ 9 in c/c (T) Asmin = 0.14 sq.in/ft #3 @ 9 in c/c (T)

Superimposed Live Load (unfactd) 40 psf #3 @ 9 in c/c (B)

MATERIAL STRENGTH

Concrete Strength f'c 3 ksi Mu(-ve) =-1.87 k-ft/ft

Steel Yeild Strength 60 ksi Asmin = 0.14 sq.in/ft

#3 @ 9 in c/c (T)

Two Way Slab Loads

Slab Self wt 81.25 psf

Ultimate Dead Load 337.50 psf

Ultimate Live Load 64.00 psf

Total Ultimate Load 401.50 psf

COEFFICIENTS TO BE USED ACI

CALC-SHEET >>CALC-SHEET >>

ABOUTABOUT

DRAWING >>DRAWING >>

Continuous Edge

Continuous Edge

Continuous EdgeContinuous Edge

D10
shafiq ur Rehman: If the cell is in red color your section is failing in shear so increase thickness
Page 4: Slab Design

DESIGN OF TWO-WAY SLAB BY ACI-COEFFICIENTS

DAANISH SCHOOL VEHARI (HOSTEL) F.F.S

PANEL No : S4

Input Data:

Slab DimensionsShort Span = 16 ftLong Span = 24 ftSpan Ratio = 16 / 24 = 0.67Slab Thickness (reqd) = 2 x (16+24) x 12 / 165 = 5.82 inSlab Thickness (prvd) = 6.5 in

Edge ConditionsShort Span Edge Condition = One Edge ContinuousLong Span Edge Condition = Both Edges Discontinuous

Applied LoadsSlab self wt = 81.25 psfService Dead Load = 200 psfService Live Load = 40 psf

Material StrengthsConcrete Strength = 3 ksiSteel Yield Strength = 60 ksi

Design Moments

LoadsTotal Ultimate DL = 1.2(81.25 + 200) = 337.5 psfTotal Ultimate LL = 1.6(40) = 64 psfTotal Ultimate Load = 337.5 + 64 = 401.5 psf

Short Span MomentsPositive Moment DL Mua(dl)+ = 0.053 x 337.5 x 16^2 = 4.579 k-ft/ftPositive Moment LL Muall+ = 0.063 x 64 x 16^2 = 1.032 k-ft/ftTotal Postive Short Span Moment Mua+ = ---------------------------------> = 5.611 k-ft/ft

Negative Moment on Discontinuous Edge = 1/3 x 5.611 = 1.870 k-ft/ftNegative Moment on Continuous Edge = 0.092 x 401.5 x 16^2 = 9.456 k-ft/ft

Long Span MomentsPositive Moment DL Mubdl+ = 0.008 x 337.5 x 24^2 = 1.555 k-ft/ftPositive Moment LL Mubll+ = 0.011 x 64 x 24^2 = 0.406 k-ft/ftTotal Postive Long Span Moment Mub+ = ---------------------------------> = 1.961 k-ft/ft

Negative Moment on Discontinuous Edge = 1/3 x 1.961 = 0.654 k-ft/ftNegative Moment on Discontinuous Edge = 1/3 x 1.961 = 0.654 k-ft/ft

<< DESIGN DATA<< DESIGN DATA

DRAWING >>DRAWING >>

Page 5: Slab Design

DESIGN OF TWO-WAY SLAB BY ACI-COEFFICIENTSDAANISH SCHOOL VEHARI (HOSTEL) F.F.SPANEL No : S4

Reinforcement Calculations

Along Short SpanPositive SteelMu=5.61 k-ft ; b=12 in ; d=5.563 in ; fc'=3ksi ; fy= 60 ksiAs+ = 0.85 x 3 / 60 x [1 - [1-2 x 12 x5.611/(0.9x0.85x3x12x5.563^2) ]^0.5 ] x 12 x 5.563

= 0.234 sq.in.Asmin = 0.0018 x 12 x 6.5 = 0.140 sq inuse As+ = 0.234 sq.in. (#3 @ 5.5 in ) Negative SteelMu=1.87 k-ft ; b=12 in ; d=5.563 in ; fc'=3ksi ; fy= 60 ksiAs- = 0.85 x 3 / 60 x [1 - [1-2 x 12 x1.87/(0.9x0.85x3x12x5.563^2) ]^0.5 ] x 12 x 5.563

= 0.076 sq.in.Asmin = 0.0018 x 12 x 6.5 = 0.140 sq inuse As- = 0.140 sq.in. (#3 @ 9 in ) Negative SteelMu=9.46 k-ft ; b=12 in ; d=5.5 in ; fc'=3ksi ; fy= 60 ksiAs- = 0.85 x 3 / 60 x [1 - [1-2 x 12 x9.456/(0.9x0.85x3x12x5.5^2) ]^0.5 ] x 12 x 5.5

= 0.412 sq.in.Asmin = 0.0018 x 12 x 6.5 = 0.140 sq inuse As- = 0.412 sq.in. (#4 @ 5.5 in )

Along Long SpanPositive SteelMu=1.96 k-ft ; b=12 in ; d=5.188 in ; fc'=3ksi ; fy= 60 ksiAs+ = 0.85 x 3 / 60 x [1 - [1-2 x 12 x1.961/(0.9x0.85x3x12x5.188^2) ]^0.5 ] x 12 x 5.188

= 0.085 sq.inAsmin = 0.0018 x 12 x 6.5 = 0.140 sq inuse As+ = 0.140 sq.in. (#3 @ 9 in ) Negative SteelMu=0.65 k-ft ; b=12 in ; d=5.563 in ; fc'=3ksi ; fy= 60 ksiAs- = 0.85 x 3 / 60 x [1 - [1-2 x 12 x0.654/(0.9x0.85x3x12x5.563^2) ]^0.5 ] x 12 x 5.563

= 0.026 sq.inAsmin = 0.0018 x 12 x 6.5 = 0.140 sq inuse As- = 0.140 sq.in. (#3 @ 9 in ) Negative SteelMu=0.65 k-ft ; b=12 in ; d=5.563 in ; fc'=3ksi ; fy= 60 ksiAs- = 0.85 x 3 / 60 x [1 - [1-2 x 12 x0.654/(0.9x0.85x3x12x5.563^2) ]^0.5 ] x 12 x 5.563

= 0.026 sq.inAsmin = 0.0018 x 12 x 6.5 = 0.140 sq inuse As- = 0.140 sq.in. (#3 @ 9 in )

Shear Check (aci-coefficient)Total load on the panel = 16 x 24 x 401.5 = 154.1 kips

= 0.85 x 2 x ( 3000 )^½ x 12 x 5.5 / 1000 = 6.14 k/ft

Shear along short side Vua = ( 0.08 x 154.1 ) / (2 x 16 ) = 0.38 k/ft <6.14 k/ft…. (O.K.) ( 0.08 x 154.1 ) / (2 x 16 ) = 0.38 k/ft <6.14 k/ft…. (O.K.)

Shear Capacity of the section fVc

Page 6: Slab Design

DESIGN OF TWO-WAY SLAB BY ACI-COEFFICIENTS

DAANISH SCHOOL VEHARI (HOSTEL) F.F.S

PANEL No : S4

Input Data:

Slab DimensionsShort Span = 4.88 mLong Span = 7.31 mSpan Ratio = 0.666667Slab Thickness (reqd) = 148 mmSlab Thickness (prvd) = 163 mm s

Edge ConditionsShort Span Edge Condition = One Edge ContinuousLong Span Edge Condition = Both Edges Discontinuous

Applied Loads

Slab self wt = 3.89

Service Dead Load = 9.58

Service Live Load = 1.92

Material StrengthsConcrete Strength = 21 MPaSteel Yield Strength = 420 MPa

Design Moments

LoadsTotal Ultimate DL = 1.2(3.89025 + 9.576) = 337.5 KN/m2Total Ultimate LL = 1.6(1.9152) = 64 KN/m2Total Ultimate Load = 337.5 + 64 = 401.5 KN/m2

Short Span MomentsPositive Moment DL Mua(dl)+ = 20.36929 KN-m/mPositive Moment LL Muall+ = 4.591417 KN-m/mTotal Postive Short Span Moment Mua+ = ---------------------------------> = 24.961 k-m/m

Negative Moment on Discontinuous Edge = 8.320235 KN-m/mNegative Moment on Continuous Edge = 42.06294 KN-m/m

Long Span MomentsPositive Moment DL Mubdl+ = 6.917872 KN-m/mPositive Moment LL Mubll+ = 1.803771 KN-m/mTotal Postive Long Span Moment Mub+ = ---------------------------------> = 8.722 KN-m/m

Negative Moment on Discontinuous Edge = 2.907214 KN-m/mNegative Moment on Discontinuous Edge = 2.907214 KN-m/m

DESIGN OF TWO-WAY SLAB BY ACI-COEFFICIENTSDAANISH SCHOOL VEHARI (HOSTEL) F.F.SPANEL No : S4

Reinforcement Calculations

Along Short SpanPositive Steeluse As+ = 150.845 sq.mm. (#3 @ 137.5 mm ) Negative Steeluse As- = 90.580 sq.mm. (#3 @ 225 mm )

Along Long SpanPositive Steeluse As+ = 90.580 sq.mm. (#3 @ 225 mm ) Negative Steel

KN/m2

KN/m2

KN/m2

<< DESIGN DATA<< DESIGN DATA

DRAWING >>DRAWING >>

Page 7: Slab Design

use As- = 90.580 sq.mm. (#3 @ 225 mm )

Page 8: Slab Design

#####################################################################################################

5'-

6''

# 4 @ 5.5 in

# 3 @ 5.5 in

6'-0''

16 ft

6'-0''

@ 9

in

@ 9

in

@ 9

in

# 3

# 3

# 3

4'-

0'' # 3 @ 9.0 in

24 ft

SCHEMATIC DIAGRAM OF REINFORCED SLABDAANISH SCHOOL VEHARI (HOSTEL) F.F.SPANEL NO: S4

<< DESIGN DATA<< DESIGN DATA

Page 9: Slab Design
Page 10: Slab Design
Page 11: Slab Design

<< DESIGN DATA<< DESIGN DATA

Page 12: Slab Design