MODUL GCAKNA 2014 KERTAS 2 SET 2

SKEMA

Question Mark Scheme Marks

1 (a)

(b)

(c) (i)

(ii)

Ratchet

To prevent too much pressure being exerted on the object.

Positive Zero Error

2.80 – 0.02 = 2.78 mm

1

1

1

1

Total 4

Question Mark Scheme Marks

2 (a) (b) (i) (ii) (iii) (c)

Unstable isotope β- particle Geiger- Muller tube Area where Geiger-Muller show the maximum reading Have a short half life// change to a nucleus stable in short time

1

1

1

1

1

Total 5

Question

Mark Scheme Marks

4 (a) (b) (i) (ii) (iii) (c)

Displacement per time // rate of change of displacement Constant velocity // zero acceleration Increasing velocity // constant acceleration V = 100 10 = 10 ms-1

1

1

1

2

2

Total 7

3 (a) (i) Diode

1

(b) (i) (ii)

Forward bias

2

1

(c) (i) (ii)

Lights up

The arrangements is still in forward bias when terminal

positive connected to P

1

1

Total 6

Question Mark Scheme Marks

5 (a) Force of gravity acting on the object //

Mass x acceleration due to gravity // mg (explain symbol) 1

(b) (i) The weight of Cargo ship B bigger than Cargo ship B / vice

versa 1

(ii) The volume of water displaced in Diagram 5.2 higher than

Diagram 5.2 / vice versa 1

(c) (i) Buoyant force 1

(ii) The increases the volume of water displaced, the increases

the Buoyant force 1

(d) Archimedes ‘ Principle 1

(e) - Sinks

- Sea denser than river

2

Total 8

Question Mark Scheme Marks

6 (a) Rate of charge flow through a conductor 1

(b) Size of current flow in circuit in Diagram 6.1 is smaller than in

Diagram 6.2. 1

(c) (i) R = 8 Ω 1

(ii) R= 2 Ω 1

(d) (i) When the effective resistance increase the current is

decreases 1

(ii) Size of current inversely proportional to the resistance when

the voltage is constant 1

(e) (i) R = 4/3 = 1.33 1

(ii) I = 1.48 A 1

Total 8

Question Mark Scheme Marks

7 (a) (b) (c) (i) (ii) (d) (e) (i) (ii)

Image that can be formed on screen Normal adjustment is = 80 cm // 60 +20 1.Parallel line with arrow 2.Parallel dot line Virtual image// magnified// inverted M = 3 Increase focal length of objective lens and reduce the focal length of eyepiece. Magnification is the ratio of fo / fe

Use objective lens with large diameter More light enters

1

1

2

1

1

1

1

1

1

Total 10

Question Mark Scheme

Marks

8. (a) (i) Longitudinal wave / mechanical wave 1

(b) (i) Resonance 1

(ii) Same frequency // energy transferred 1

(c)

(Amplitude of the wave drawn is bigger)

1

(c) (i) P – Infrared Q - Ultraviolet

1 1

(ii) Gamma ray / ultraviolet / x-Ray 1

(iii) Can kills the life cell / skin burn or skin cancer /

1

(iv) Radio wave / microwave 1

(v) High frequency / high energy / high penetrating power / less diffracted

1

(vi) Gamma Ray 1

(vii) high energy / high penetrating power 1

Total 12

Question Mark scheme Marks

9 (a) (b) (i) (ii) (iii) (iv) (v) (c) (i) (ii) (d)

Pressure is the force acting normally per surface area of an object.// Force over surface area where direction of force is perpendicular to the surface area of an object. The speed of air flow between two sheets of paper in Diagram 9.1 is lower than in Diagram 9.2 The distance between two sheets of paper, x in Diagram 9.1 is longer than in Diagram 9.2 When the speed of air between two sheets of paper increase, the distance between two sheets of paper,x is decreases. Bernoulli’s Principle When the speed of air flow high , the pressure of air is low Aerofoil When the aeroplane moves the speed of air flows obove the wing is higher than below the wing The air pressure above the wing is low while the pressure Below the wing is higher. Difference in pressure between above and below the wing causes the aeroplane moving up as the lifting force produce.

suggestion Discription

Large length/ size of pump Small hole of at the end of pump nozzle Small hole of at the end of bottle nozzle Big size of bottle Pump is made by strong material and light

Much more volume of air blows out

So that air blows out when its pumped is high velocity, and the air pressure is low

Rate of quantity of liquid out is small

It can filled with large quantity poison .

It can withstand the high pressure as the air in pump is Compress.

1

1

1

1

1

1

1

1

1

1

2

2

2

2

Total 20

Question Mark Scheme Marks

10. (a) Decay is the process where heavy nucleus emits radioactive rays

and energy to be a stable nucleus

1

(b) 1. Initial activity is the same

2. time interval in Diagram 10.1 is longer

3. rate of decay in Diagram 10.1 is lower 4. The higher the rate of decay the shorter the time interval 5. The higher the rate of decay the shorter the half life

5

(c) Sheets of papers is palced on a moving conveyer belt

Radioactive source is placed under the conveyer belt

A detector is palced on top of the paper

Similar reading on the scale of the detector show the sheets has the same thickness // if nthe reading is more / less the sheet of paper is thinner/thicker

4

(d) Aspect Reasoning

Fuel rod used is Uranium to produce fission process for production of nuclear energy

Control rod is Boron or cadmium

to absorb neutron to control the reaction

Moderator is graphite to slow down the fast moving electron

Thick concrete wall Prevent escape of harmful radiation // to prevent leakage

Coolant used is heavy water To take away heat from the reactor out

2

2

2

2

2

Total

20

Question Mark Scheme Mark

11 (a)

(b)

(c)

(d) (i)

(ii)

(iii)

Temperature is the degree of hotness

- The thermometer is put under the touge

- The heat is transferred from the body to the

thermometer

- Mercury expand until it reaches a state of

thermal equilibrium

- The temperature of the thermometer is the

same as the body

Aspect Reasoning

Liquid used is Mercury

Expands uniformly // sensitive to changes in temperature

Thin glass walled bulb

More sensitive to heat

Small diameter of capillary

tube

get a wider range // More sensitive to heat

Glass-bore stem and cross

section - Thick and Curved

not easily to break // easy to

read

C most suitable

Mercury, Thin, Small and

Thick and Curved

( l -l0) x 100

( l100 - l0)

( 12 - 5 ) x 100

( 25 - 5 )

= 35 C

( 273 + 35 ) K = 308K

Volume expand with temperature

1

1

1

1

1

2

2

2

2

2

1

1

1

1

1

Total 20

Question Mark Scheme

Marks

12. (a) (i) A device to increase or decrease voltage 1

(ii) 1. When an a.c. voltage is supplied to the primary coil, an

alternating current flows through coil.

2. The soft -iron core is magnetized.

3. The magnet produced varies in magnitude and direction.

4. This causes a changing magnetic flux to pass through the

secondary coil.As a result ,an induced e.m.f across the

secondary coil is produced.

4

(b) (i) No of turns = 12 x 1500 240 = 75 turns

1

1

(ii) Efficiecy = Po x100 Pi 85 = Po x 100 (0.1) (240) Po = 0.1 x 2.4 x 85 = 20.4 W

1

1

1

(c) Aspects Reasoning

P step up Q step down

P increase voltage Q decrease voltage

Big diameter Reduce resistance

High voltage Small current// reduce heat loss

Cable on pylon Stiff / strong

L is chosen P step up and Q step down, big diameter, high voltage, cable on pylon

2

2

2

2

2

Total 20