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Signal Fitness-For-Service Report

Input Data

Assessment Information:Assessment Type: General Metal Loss

Design Code: ASME Section VIII Div 1

FFS Code: June 2007 API 579-1/ASME FFS-1

Units: lbs - in - psiRSFa: 0.9

Analysis By: MZW

Project Information: D-8133

Equipment Inputs:Equipment: Pressure Vessel

Nominal Thickness: 0.785 in

Inside Radius: 9.21 in

Circumferential Weld Joint Factor: 1

Longitudinal Weld Joint Factor: 1

Minimum Thickness

Minimum thickness = 0.397

Material Properties:

Material: ASME Section VIII Div 1Design Temperature: 200 F

Operating Condition Inputs:Pressure Type: Internal Pressure

Pressure: 1350 psi

Internal Uniform Metal Loss: 0.388 in

External Uniform Metal Loss: 0 in

Internal Future Corrosion Allowance: 0 in

External Future Corrosion Allowance: 0 in

Results Summary

Part 4 Level 1MAWPr must be greater than Design Pressure.

Does not satisfy June 2007 API 579-1/ASME FFS-1 Level 1 assessment.(Refer To: June 2007 API 579-1/ASME FFS-1 )

Part 4 Level 2MAWPr must be greater than Design Pressure.

Does not satisfy June 2007 API 579-1/ASME FFS-1 Level 2 Assessment.

(Refer To: June 2007 API 579-1/ASME FFS-1 )

Step By Step Results

Part 4 Level 1MAWPr must be greater than Design Pressure.

Does not satisfy June 2007 API 579-1/ASME FFS-1 Level 1 assessment.

(Refer To: June 2007 API 579-1/ASME FFS-1 )

Analysis done according to June 2007 API 579-1/ASME FFS-1

Step 1: Determine the minimum required thickness.

TminL = 0.320 in

TminC = 0.675 in

Tsl = 0.000 in

Tmin = 0.675 in

Step 2: Evaluate the thickness data.

Tmm = 0.397 in

Step 3: Determine the wall thickness to be used.

Tc = 0.397 in

Step 4: Determine the remaining thickness ratio.

Rt = 1.000 in

Step 5: Determine the length for thickness averaging.

Q = 50.000

L = 138.029 in

Step 6: Determine thickness averages.

Date:1/22/2015

Genera ted By : Signal Fitness-For-Service Standard Edition, Version 2014.0902

S igna l FFS is wr i t t en and main ta ined b y Ques t In tegr i t y Group, a Team Indus t r i a l Serv i ces compan y

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TamC = 0.397 in

TamS = 0.397 in

Step 7: Determine the acceptability for continued operation.

TamS - FCA >= TminC ? No: 0.397 < 0.675

Averaged longitudinal thickness must be greater than t_minC.

TamC - FCA >= TminL ? Yes: 0.397 >= 0.320

Tmm - FCA >= 0.338 ? Yes: 0.397 >= 0.338

MAWPr = 807.222 psi

MAWPr >= MAWP ? No: 807.222 < 1350.000

MAWPr must be greater than Design Pressure.

Part 4 Level 2MAWPr must be greater than Design Pressure.

Does not satisfy June 2007 API 579-1/ASME FFS-1 Level 2 Assessment.

(Refer To: June 2007 API 579-1/ASME FFS-1 )

Analysis done according to June 2007 API 579-1/ASME FFS-1

Step 1: Determine the minimum required thickness.

TminL = 0.320 in

TminC = 0.675 in

Tsl = 0.000 in

Tmin = 0.675 in

Step 2: Evaluate the thickness data.

Tmm = 0.397 in

Step 3: Determine the wall thickness to be used.

Tc = 0.397 in

Step 4: Determine the remaining thickness ratio.

Rt = 1.000 in

Step 5: Determine the length for thickness averaging.

Q = 50.000

L = 138.029 in

Step 6: Determine thickness averages.

TamC = 0.397 in

TamS = 0.397 in

Step 7: Determine the acceptability for continued operation.

TamS - FCA >= TminC*RSFa ? No: 0.397 < 0.608

Averaged longitudinal thickness must be greater than t_minC*RSFa.

TamC - FCA >= TminL*RSFa ? Yes: 0.397 >= 0.288

Tmm - FCA >= 0.338 ? Yes: 0.397 >= 0.338

MAWPr = 894.507 psi

MAWPr >= MAWP ? No: 894.507 < 1350.000

MAWPr must be greater than Design Pressure.

Figures

Date:1/22/2015

Genera ted By : Signal Fitness-For-Service Standard Edition, Version 2014.0902

S igna l FFS is wr i t t en and main ta ined b y Ques t In tegr i t y Group, a Team Indus t r i a l Serv i ces compan y

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