Settlement: Consolidation of Soil
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Transcript of Settlement: Consolidation of Soil
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COMPRESSIBILITY OF SOIL
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TERMS AND DEFINITIONS
Settlement Total vertical deformation at soil
surface resulting from the load
Consolidation (volume change velocity) Rate of decrease in volume with respect to time
Compressibility (volume change flexibility) Volume decrease due to a unit load
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TERMS AND DEFINITIONS
Shrinkage Volume contraction of soil due to reduction in
water content
Swelling Volume expansion of soil due to increase in
water content
Contraction (temperature expansion) Change in volume of soil due to a change in
temperature
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Causes of compression:
Expulsion of water or air from the void spaces Relocations of soil particles Deformation of soil particles
When stressed, soil deforms Stressed released, deformation remains Soil deformation: Distortion (change in shape)
Compression (change in volume) Both
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Components of Settlement: Immediate Settlement, Si
caused by the elastic deformation of dry, moist, and saturated soils, without any change in moisture content
Primary Consolidation Settlement, Sc caused by a volume change in saturated
cohesive soils due to expulsion of water that occupies the void spaces
Secondary Consolidation Settlement, Ss Caused by plastic adjustment of soil fabrics. It
is an additional form of compression that occurs at constant effective stress
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Total Settlement, StSt = Si + Sc + Ss Soil Movement:
Downward: load increase or lowering water table
Upward: temporary or permanent excavation Points of Interest: HOW MUCH SETTLEMENT OCCURS?o depends on the rigidity of soil skeletono compression of sand occurs instantlyo consolidation of cohesive soil is time
dependent
HOW FAST SETTLEMENT OCCURS?o depends on permeability of soil
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Compressibility of Soil Assumption in settlement:
100 % saturated and 1D (vertical) soil deformation When soil is loaded it will compress because
of: Deformation of soil grains (small ~ negligible) Compression of air and water in the voids Squeezing out of water and air from the voids Compressible soil mostly found below the water table ~ considered fully saturated
As pore fluid squeezed out: Soil grain rearrange themselves ~
stable/denser configuration Decrease in volume ~ surface settlement
resulted
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CONSOLIDATION OF CLAY
System is analog to soil layer at equilibrium with weight of all soil layer (overburden) above it.
Valve is closed. Piston is loaded,
compresses a spring in chamber.
Hydrostatic pressure = uo
At equilibrium: time, t=0
Spring ~ soil skeleton Water ~ water in pores Valve ~ pore sizes in
soil/permeability
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Soil is loaded by increment Δp.
Valve initially closed. Pressure(Δp) is transferred to
the water. As water is incompressible
and valve still closed, no water is out, no deformation of piston.
Pressure gauge read: Δu = Δp where Δu is excess hydrostatic pressure.
To simulate a fine-grained cohesive soil, where permeability is low, valve can be opened.
Water slowly leave chamber.
Under load Δp (0<t<∞)
Spring ~ soil skeleton Water ~ water in pores Valve ~ pore sizes in soil/ permeability
uo+Δu
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To simulate a fine-grained cohesive soil, where permeability is low, valve can be opened.
Water slowly leave chamber. As water flows out, load (Δp)
is transferred to the spring. At equilibrium, no further
water squeezed out, pore water pressure back to its hydrostatic condition.
Spring is in equilibrium with load po + Δp.
Settlement “s” exist.
At equilibrium (t=∞)
Spring ~ soil skeleton Water ~ water in pores Valve ~ pore sizes in soil/ permeability
po+Δp
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SETTLEMENT PROCESS: Initially all external load is transferred into excess
pore water (excess hydrostatic pressure) No change in the effective stress in the soil
Gradually, as water squeezed out under pressure gradient, the soil skeleton compress, take up the load, and the effective stress increase.
Eventually, excess hydrostatic pressure becomes zero and the pore water pressure is the same as hydrostatics pressure prior to loading.
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NORMALLY CONSOLIDATED AND OVERCONSOLIDATED CLAYS
When soil is loaded to a stress level greater than it ever experienced in the past, the soil structure is no longer able to sustain the increased load, and start to breakdown.
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Preconsolidation Pressure, Pc: Maximum pressure experienced by soil in the
past Normally Consolidated: OCR = 1 When the preconsolidation pressure is equal to
the existing effective vertical overburden pressure, Pc = P’o
Present effective overburden pressure is the maximum pressure that soil has been subjected in the past
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Preconsolidation Pressure, Pc: Maximum pressure experienced by soil in the
past Overconsolidated: OCR > 1 When the preconsolidation pressure is greater
than the existing effective vertical overburden pressure Pc > P’o
Present effective overburden pressure is less than that which the soil has been subjected in the past
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Preconsolidation Pressure, Pc: Maximum pressure experienced by soil in the
past Underconsolidated: OCR < 1 When the preconsolidation pressure is less than
the existing effective vertical overburden pressure Pc < P’o
e.g. recently deposited soil geologically or manually.
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Mechanism causing preconsolidation: Change in total stress due to:
Removal of overburden Past structures Glaciation
Environmental changes such as pH, temperature, and salt concentration
Change in pore water pressure: Change in water table elevation Artesian pressure Deep pumping, flow into tunnel Desiccation due to surface drying and plant life
Chemical alteration due to weathering, precipitation, cementing agents, ion exchange
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Consolidation Test Data Plots
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How to determine Pc?
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SETTLEMENT CALCULATIONNORMALLY CONSOLIDATED CLAY
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SETTLEMENT CALCULATION
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Example From the given soil profile shown, the ground surface is
subjected to a uniform increase in vertical pressure of 12 N/cm2. Compute the buoyant unit weight of clay. Compute the overburden pressure Po of mid-height of the
compressible clay layer. Compute the total settlement due to primary
consolidation.Sand ydry = 17.6 kN/m3
y’ = 10.4 kN/m3
Clay LL = 45w = 40 %ys = 27.8 kN/m3
ΔP = 12 N/cm2 4.6 m
5.86 m
7.6 m
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Example From the given soil profile shown, given B = 1.5 m, and L =
2.5 m. The footing carries a load of 120 kN. Compute the average effective pressure at mid-height of
clay layer. Compute the average increase of effective pressure in
the clay layer using 2:1 method. Compute the primary consolidation settlement of the
foundation.
Sand ysat = 15 kN/m3
ysat = 18 kN/m3
Clay LL = 38w = 35 %Gs = 2.7
1.5 m
1.5 m
2.5 m
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Example Prior to placement of a fill covering a large area at a site, the
thickness of a compressible soil layer was 10 m. Its original in situ void ratio was 1.0. Some time after the fill was constructed, measurements indicated that the average void ratio was 0.8. Estimate the settlement of the soil layer.
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Example
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Example The laboratory consolidation data for an undisturbed clay
specimen are as follows: e1 = 1.12 P1 = 90 kPa e2 = 0.90 P2 = 460 kPa
Compute the compression index. Find the void ratio for a pressure of 600 kPa. Determine the coefficient of compressibility.
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Example In a laboratory consolidation test on a clay sample the
following results were obtained: e1 = 0.92 P1 = 50 kPa e2 = 0.78 P2 = 120 kPa Thickness of the sample of clay = 25 mm Time for 50 % consolidation = 2.5 min Tv = 0.197
Find the coefficient of volume compressibility Determine the coefficient of consolidation if sample of
clay was drained on both sides. Compute the hydraulic conductivity of the clay.