Sequences Higher 2
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Transcript of Sequences Higher 2
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SequencesBy the end of this lesson you will:
- find the nth term for linear sequences- use the nth term to find any term in a sequence
Tracking BGrade C / B
Key words: sequences, nth term, linear, difference
Write down the first 4 terms foreach sequence...
a)2nb)2n + 1
c)2n + 5d)2n 3e)- 2nf)4 2n
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Can you suggest why they are called linear sequences?
1 2 3 40 5
2
4
6
8
10
tn= 2n + 1
tn= 3n - 4
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5
811
14
17
?
A linear number sequence is a sequence of numbers that has aconstant difference between adjacent terms. Consider the first fiveterms of the number sequence shown:
5, 8, 11, 14, 17,..?1st 2nd 3rd 4th 5th ................................nth
Can you see how the numbers of thissequence are related to those in the 3 timestable?
n 3n
1 3
2 63 9
4 12
5 15
3n + 2
Adjacent numbers in the 3 times table alsodiffer by 3. The terms in this sequence are 2bigger than the numbers in the 3 times table.
tn= 3n + 2
+ 2
terms
position
3 3 3 3difference
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Question 1
For each of the number sequences below, find a rule for the nth term (tn) and work out the value of t100 .
8, 13, 18, 23, 28,
tn= 5n + 3 t100 = 5 x 100 + 3 = 503
Question2
1, 4, 7, 10, 13, tn= 3n - 2 t100 = 3 x 100 - 2 = 298
Question
3
2, 9, 16, 23, 30, tn= 7n - 5 t100 = 7 x 100 - 5 = 695
Question4
9, 15, 21, 27, 33,
tn= 6n + 3 t100 = 6 x 100 + 3 = 603
Question
5
-1, 4, 9, 14, 19, tn= 5n - 6 t100 = 5 x 100 - 6 = 494
Question6
-3, 1, 5, 9, 13, tn= 4n - 7 t100 = 4 x 100 - 7 = 393
Question7
6, 18, 30, 42, 54,
tn= 12n - 6 t100 = 12 x 100 - 6 = 1194
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Number sequences can beused to solve problemsinvolving patterns indiagrams.
How manysquares of
chocolate (S) will
the 10th
diagram(D) contain?1
2
3
4
1 3 5 7
S = 2D - 1 S10 = 2 x 10 - 1 = 19
How many wooden braces (B) will there be, in the 20th panel (P)?
1 2 3
B = 3P + 1 B20 = 3 x 20 +1= 61
4 7 10
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How many stoneslabs (S) will the15th diagram (D)
contain?
1
2
3
1 5 9
S = 4D - 3 S15 = 4 x 15 3 = 57How many steel braces (B) will there be, in the 28th panel (P)?
1 2 3
6 11 16
B = 5P + 1 B28 = 5 x 28 + 1 = 141