Sept 2, 2008CVEN 4838/5838Slide #1 Lecture 3 Flood Control and Operating Criteria.

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Sept 2, 2008 Sept 2, 2008 CVEN 4838/5838 CVEN 4838/5838 Slide # Slide #1 Lecture 3 Lecture 3 Flood Control and Operating Flood Control and Operating Criteria Criteria

Transcript of Sept 2, 2008CVEN 4838/5838Slide #1 Lecture 3 Flood Control and Operating Criteria.

Page 1: Sept 2, 2008CVEN 4838/5838Slide #1 Lecture 3 Flood Control and Operating Criteria.

Sept 2, 2008Sept 2, 2008 CVEN 4838/5838 CVEN 4838/5838 Slide #Slide #11

Lecture 3Lecture 3

Flood Control and Operating CriteriaFlood Control and Operating Criteria

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Purpose of a ReservoirPurpose of a ReservoirTo smooth out the variability of surface water flow through control and regulation To smooth out the variability of surface water flow through control and regulation

and make water available when and where it is needed. The dis-benefits of and make water available when and where it is needed. The dis-benefits of evaporation and seepage are offset by the benefits of water supply, evaporation and seepage are offset by the benefits of water supply, hydropower, recreation and flood control.hydropower, recreation and flood control.

Two Main Operational Purposes:Two Main Operational Purposes:1.1. ConservationConservation – includes – includes

water supply (M&I and irrigation),water supply (M&I and irrigation),low-flow augmentation for water quality and ecological habitat, low-flow augmentation for water quality and ecological habitat, recreation, recreation, navigation, navigation, hydropowerhydropower

2.2. Flood ControlFlood Control – retention of water during flood events for the purpose of – retention of water during flood events for the purpose of reducing downstream flooding.reducing downstream flooding.

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Reservoirs have 3 Reservoirs have 3 primary storage zonesprimary storage zones

Flood Control StorageFlood Control Storagereserved for storing excessive flood reserved for storing excessive flood volume to reduce potential downstream volume to reduce potential downstream flood damage.flood damage.

Active StorageActive Storagefor conservation purposesfor conservation purposes

Dead StorageDead Storagefor sediment collection, hydropower for sediment collection, hydropower head.head.

From Mays and Tung Hydrosystems Engineering and Management, 1992. p. 271

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Design of Dead Storage CapacityDesign of Dead Storage CapacityConsiders estimates of sediment load (a future topic)Considers estimates of sediment load (a future topic)

Design of Active Storage CapacityDesign of Active Storage CapacityScreening methods for yield as discussed last weekScreening methods for yield as discussed last week

Multi-objective reservoirs designed with consideration ofMulti-objective reservoirs designed with consideration of Reliability of hydrology (chance-constrained optimization models; transition Reliability of hydrology (chance-constrained optimization models; transition

probability matrix; DP)probability matrix; DP) Hydropower firm energy commitments; B/C of powerHydropower firm energy commitments; B/C of power Buffer zone design for low flow augmentation in droughtBuffer zone design for low flow augmentation in drought Trade-off among objectives based on economic or other criteriaTrade-off among objectives based on economic or other criteria

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Multi-objective Tradeoff AnalysisMulti-objective Tradeoff AnalysisAn Example: A reservoir has 2 purposes – recreation (boating) and irrigation. These An Example: A reservoir has 2 purposes – recreation (boating) and irrigation. These objectives conflict because boating requires high reservoir levels in the summer, objectives conflict because boating requires high reservoir levels in the summer, whereas irrigation requires water to be released for downstream use. If X is total whereas irrigation requires water to be released for downstream use. If X is total units of water delivered and Y is visitor-days in the season, the possible solution is:units of water delivered and Y is visitor-days in the season, the possible solution is:

Best solution is on boundary where any Best solution is on boundary where any improvement in one objective will result in improvement in one objective will result in harm to the other. harm to the other.

Use unit cost or value to find solution:Use unit cost or value to find solution:

Income = Px X + Py YIncome = Px X + Py Ywhere Px is unit price of waterwhere Px is unit price of water and Py is unit price of visitor-day and Py is unit price of visitor-day

Find X ,Y values for constant IFind X ,Y values for constant I

where I where I11 < I < I22 < I < I33

II33 will provide the highest income and will will provide the highest income and will

be feasible for a single X,Y solutionbe feasible for a single X,Y solution

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Multi-objective Tradeoff AnalysisMulti-objective Tradeoff AnalysisIn reality, it is not easy to find a solution for multi-objective tradeoff problems becauseIn reality, it is not easy to find a solution for multi-objective tradeoff problems because

•There may not be quantifiable and commensurate values for objectives There may not be quantifiable and commensurate values for objectives (environmental, social objectives; also legally mandated objectives).(environmental, social objectives; also legally mandated objectives).

•The market values may not reflect social valuesThe market values may not reflect social values

The results of rigorous benefit–cost analyses seldom dictate which of competing water resources projects and plans should be implemented. This is in part because ofthe multi-objective nature of the decisions. One must consider environmental impacts, income redistribution effects and a host of other local, regional and national goals, many of which may be non-quantifiable.

Other important considerations are the financial, technical and political feasibilities of alternative plans. Particularly important when a plan is undertaken by government agencies is the relative political and legal clout of those who support the plan and those who oppose it. Still, a plan’s economic efficiency is an important measure of its value to society and often serves as an indicator of whether it should be considered at all.

Loucks and van Beek, 2005

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Sizing of Flood PoolSizing of Flood Pool

A flood wave passing through a reservoir is delayed A flood wave passing through a reservoir is delayed and attenuated in order to lessen damage downstream.and attenuated in order to lessen damage downstream.

Translation of INFLOW hydrograph to OUTFLOW Translation of INFLOW hydrograph to OUTFLOW hydrograph depends on the hydrograph depends on the geometric and hydraulicgeometric and hydraulic featuresfeatures of the pool and of the pool and reservoir operationreservoir operation..

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A flood pool with an uncontrolled spillway stores water as it is released according to the weir flow equation. The hydrograph is delayed and attenuated. The outflow hydrograph depends on the area of the reservoir and the length of the spillway.

A gated structure can more efficiently control the release. Less storage space is needed for the same outflow peak Q.However, the gates add significant cost to the project.

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Flood Pool SizingFlood Pool SizingTo size the pool, need to knowTo size the pool, need to know

1.1. Upstream hydrograph – Upstream hydrograph – based on analysis of recordbased on analysis of record

2.2. Downstream hydrograph – Downstream hydrograph – based on flood damage analysisbased on flood damage analysis

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Flood Pool Sizing – determination of Flood Pool Sizing – determination of downstream hydrographdownstream hydrograph

Calculation of the expected annual flood

damage without the reservoir is shown as the shaded area in quadrant (D) derived from: A - the expected stage-damage function,

B - the expected stage-flow relation, andC - the expected

probability of exceeding an annual peak flow.

(Loucks and van Beek, 2005)

P(Q) = 1/TP is exceedence probability; T is return period

Example Q(P=.25) = 5000

Elev = 275 m

Damage = $3M

Damage(P=.25) = $3M

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Flood Pool Sizing – determination of Flood Pool Sizing – determination of downstream hydrographdownstream hydrograph

Calculation of the expected annual flood

damage without the reservoir is shown as the shaded area in quadrant (D) derived from: A - the expected stage-damage function,

B - the expected stage-flow relation, andC - the expected

probability of exceeding an annual peak flow.

(Loucks and van Beek, 2005)

Example Q(P=.25) = 5000 without reservoir;

Q(P=.25) = 3500 with Storage = 50

Elev = 275 m

Damage = $3M

Damage = $2M

Damage(P=.25) = $3M

Elev = 200

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Design Decisions are based on cost of Design Decisions are based on cost of protecting downstream. protecting downstream.

Cost of protection is based on storage Cost of protection is based on storage (height of dam and area of reservoir) and (height of dam and area of reservoir) and

operational capabilities (gates)operational capabilities (gates)

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What are storage/operations requirements What are storage/operations requirements for meeting Q(P) downstream?for meeting Q(P) downstream?

First: Develop the Elevation-Area-Storage relationships based on topography of the reservoir site

Mays and Tung, 1992 p.281

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What are storage/operations requirements What are storage/operations requirements for meeting Q(P) downstream?for meeting Q(P) downstream?

Use storage routing to simulate the outflow hydrograph, given Q(P), using different outlet capabilities:

• Uncontrolled spillway length

• Regulated outflow (gates)

(See reading assignment: Engineering Hydrology, Principles and Practices, Chp 8,

Victor Miguel Ponce, 1989)

Outflow BAdd reg gates

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What range of Q(P) upstream need to be What range of Q(P) upstream need to be considered?considered?

Standard methods of fitting historical data to flood frequency curves provide a means of getting Q(P) for a range of return flows that have been obseved.

What about very large flows (T = 1000 or greater)?

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What range of Q(P) upstream need to be What range of Q(P) upstream need to be considered?considered?

Portion of peak flow probability of exceedence function showing contours containing 90% of the uncertainty associated with this distribution. To be 90% certain of protection from a peak flow of PQT, protection is needed from the higher peak flow, PQTΔ expected once every T Δ years, i.e. with an annual probability of 1/(T δ) or (1/T) δ of being equalled or exceeded.

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What range of Q(P) upstream need to be What range of Q(P) upstream need to be considered?considered?

As the return period increases, the value becomes more uncertain.

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What range of Q(P) upstream need to be What range of Q(P) upstream need to be considered?considered?

This revision of the T=1250 flow was based on two new values in the period of record.

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Why are low exceedance values so Why are low exceedance values so difficult to determine?difficult to determine?

Hydrologic record is not long enoughHydrologic record is not long enough

Many factors determine Q: rainfall volume, intensity, Many factors determine Q: rainfall volume, intensity, spatial pattern of precip, rain on snow, antecedent spatial pattern of precip, rain on snow, antecedent moisture conditions, temperature, changing runoff moisture conditions, temperature, changing runoff characteristics, characteristics,

Low-probability combinations of conditions are Low-probability combinations of conditions are numerousnumerous

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Probable Maximum FloodProbable Maximum Flood

PMF is variously defined as T=1000, T=10,000PMF is variously defined as T=1000, T=10,000

It can be derived statistically or by physical process It can be derived statistically or by physical process modeling using an estimate of the Probable modeling using an estimate of the Probable Maximum Precipiation (PMP)Maximum Precipiation (PMP)

Dam design policies require that the dam can pass the Dam design policies require that the dam can pass the PMF, i.e., that the PMF, i.e., that the dam does not faildam does not fail..

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Example: Canyon Lake Dam, SD June 9, 1972Example: Canyon Lake Dam, SD June 9, 1972

Forecast Forecast “partly cloudy, scattered t-storms, some possibly “partly cloudy, scattered t-storms, some possibly reaching severe proportions”reaching severe proportions”

That evening,10 in. fell in a small, steep watershed that That evening,10 in. fell in a small, steep watershed that averages 14 in. annually; 6 in fell in 2 hours.averages 14 in. annually; 6 in fell in 2 hours.

Rapid creek delivered 31,000cfs into Canyon Lake, a Rapid creek delivered 31,000cfs into Canyon Lake, a 40 ac-ft reservoir behind a 20-ft high earthen dam. 40 ac-ft reservoir behind a 20-ft high earthen dam. The previous record flow in 20 years was 2600cfsThe previous record flow in 20 years was 2600cfs

The dam washed out, destroyed over half of Rapid The dam washed out, destroyed over half of Rapid City (pop 43,000). 237 fatalities, 5000 homeless. City (pop 43,000). 237 fatalities, 5000 homeless. Pactola, 15 miles u.s. of Canyon Lake was Pactola, 15 miles u.s. of Canyon Lake was unaffected.unaffected.

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The small spillway (background) on Canyon Lake dam became clogged with debris, and the dam was over-topped. Rapid Creek flows through the dam in a large cut where the dam failed.

Erosion on the downstream face of Canyon Lake dam ultimately lead to its failure.

Close-up view of destroyed houses. The concrete silo houses a U.S. Geological Survey gage which had recorded a maximum of 2600 cubic feet per second in its 20 year history. On June 9, 1972, the discharge at this point was 31,200 cubic feet per second.

Flood-swept cars, pointing upstream (except for the Volkswagon bug), would stack on top of one another

People were moving into these new houses in western Rapid City the night of the flood.

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Flood Release PoliciesFlood Release PoliciesIn the Surcharge pool, all water is

released as quickly as possible, without regard to d.s. damage.

In the Induced Surcharge pool, release as quickly as possible without regard to d.s. damage, but regulation has the opportunity to take flatten the peak.

In the Flood Pool, regulated discharges evacuate the flood pool as quickly as possible, but constrained by d.s. maximum allowable channel flows and rate of change constraints.

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Operating Policies (Rules)Operating Policies (Rules)

Rules to achieve demands, flood control policies, low flow Rules to achieve demands, flood control policies, low flow requirements and other objectives by specifying:requirements and other objectives by specifying:

Rule curves (reservoir storage over time)Rule curves (reservoir storage over time)

Release rules – how to release water when the storage Release rules – how to release water when the storage is in specified pools.is in specified pools.

The rules are developed to vary seasonally and to The rules are developed to vary seasonally and to account for uncertainties in inflow and demands.account for uncertainties in inflow and demands.

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Rule Curves Rule Curves Release as quickly as possible,

without regard to d.s. damage.

Release down to bottom of flood pool as quickly as possible, but constrained by d.s. maximum allowable channel flows and rate of change constraints.

Meet demands and other objectives, but conserve water as possbile to keep level as close as possible to top of conservation pool.

No water for other objectives, but release as needed and as possible for d.s. low flow augmentation

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Design of Outlet works must Design of Outlet works must accomodate the operating policies, accomodate the operating policies, release requirements and storage release requirements and storage

requirementsrequirements