Section 4.1 Solving Linear Inequalities Using the Addition-Subtraction Principle.
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Transcript of Section 4.1 Solving Linear Inequalities Using the Addition-Subtraction Principle.
Section 4.1
Solving Linear Inequalities Using the Addition-Subtraction Principle
4.1 Lecture Guide: Solving Linear Inequalities Using the Addition-Subtraction Principle
Objective 1: Identify linear inequalities and check a possible solution of an inequality.
Verbally Algebraically Algebraic Examples
Graphically
A linear inequality in one variable is an inequality that is ____________ degree in that variable.
For real constants A, B, and C, with .0A
.
2x (2
[2
)2]2
CAx B
Ax B C
Ax B C
Ax B C
2x
2x
2x
Linear Inequalities
1. Which of the following choices is a linear inequality in one variable?
(a) (b) (c) (d) 23 1 10x 3 1 10x 3 1x 3 1 10x
• A conditional inequality contains a variable and is true for ____________, but not all, real values of the variable.
• The solution of a linear inequality consists of all values that ____________ the inequality. The solution of a conditional linear inequality will be an interval that contains an infinite set of values.
Conditional Inequality
2. Determine whether x = 5 satisfies each inequality.
(a) (b) (c) (d)
5x 5x 5x 5x
3. Determine whether either 4 or – 4 satisfies the inequality .6 2 5 4x x
Objective 2: Solve linear inequalities in one variable using the addition-subtraction principle for inequalities.
Verbally Algebraically Numerical Example
If the same number is ____________ to or subtracted from ____________ sides of an inequality, the result is an ___________inequality.
If a, b, and c, are real numbers then a < b is equivalent to
and to
is equivalent to
and to .
2 5x
2 22 5x 7x
a c b c
a c b c
Addition-Subtraction Principle for Inequalities
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
4. 5. 4 11x 3 3 x
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
6. 7. 3 2 7y y 7 6 1a a
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
8. 9. 3 1 2 6x x 7 6d d
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
10. 11. 8 2 7 12x x 5 3 6 4x x
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
12. 6 2 4 11 8x x
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
13. 7 2 2 13 1x x
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
14. 3 2 1 5 1 5m m
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
15. 3 2 2 2 5x x
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
16. 6 2 4 3 5x x x
Each inequality in problems 4-17 is a conditional inequality. Use the addition-subtraction principle of equality to solve each inequality. Give your answer in interval notation.
17. 3 7 5
4 5 5 4y y
18. The graph below displays the monthly cost y of two phone plans based on x minutes of use. The graph of represents the monthly cost of plan A and the graph of 2yrepresents the monthly cost of plan B.
$0
$20
$40
$60
0 100 200 300 400 500 600 700 800
y
x
Minutes
Co
st
2y
1y
(a) Approximate the monthly cost of plan A with 400 minutes of use.
(b) Approximate the monthly cost of plan B with 400 minutes of use.
Objective 3: Use tables and graphs to solve linear inequalities in one variable.
1y
(c) Approximate the monthly cost of plan A with 800 minutes of use.
(d) Approximate the monthly cost of plan B with 800 minutes of use.
18. The graph below displays the monthly cost y of two phone plans based on x minutes of use. The graph of 1y
represents the monthly cost of plan A and the graph of 2y
represents the monthly cost of plan B.
$0
$20
$40
$60
0 100 200 300 400 500 600 700 800
y
x
Minutes
Co
st
2y
1y
(e) For how many minutes of use will both plans have the same monthly cost?
(f) What is that monthly cost?
18. The graph below displays the monthly cost y of two phone plans based on x minutes of use. The graph of 1y
represents the monthly cost of plan A and the graph of 2y
represents the monthly cost of plan B.
$0
$20
$40
$60
0 100 200 300 400 500 600 700 800
y
x
Minutes
Co
st
2y
1y
(g) Explain the circumstances under which you would choose plan A.
(h) Explain the circumstances under which you would choose plan B.
18. The graph below displays the monthly cost y of two phone plans based on x minutes of use. The graph of 1y
represents the monthly cost of plan A and the graph of 2y
represents the monthly cost of plan B.
$0
$20
$40
$60
0 100 200 300 400 500 600 700 800
y
x
Minutes
Co
st
2y
1y
-5
5
-5 5
x
y
2y
19.(a)
(b)
(c)
1y
Use the graph to solve each equation or inequality.
1 2y y
1 2y y
1 2y y
-5
5
-5 5
x
y
2y
20.
1y
Use the graph to solve each equation or inequality.
(a)
(b)
(c)
1 2y y
1 2y y
1 2y y
21.
Use the table to solve each equation or inequality.
1 2, , or
4 1 2
3 2 0
2 3 2
1 4 4
0 5 6
1 6 8
2 7 10
x y y
(a)
(b)
(c)
1 2y y
1 2y y
1 2y y
22.
Use the table to solve each equation or inequality.
1 2, , or
4 2 2
5 1 4
6 4 6
7 7 8
8 10 10
9 13 12
10 16 14
x y y
(a)
(b)
(c)
1 2y y
1 2y y
1 2y y
(a) Use your calculator to create a graph of 1Y and 2Yusing a viewing window of 2, 6, 1 by 5, 10, 1 . Use theIntersect feature to find the point where these two lines intersect. Draw a rough sketch below. The values in the table will help.
is above for x-values to the ____________ of ______.
-5
10
-2 6
y
x
23. Solve the inequality by letting
and .
(b)
4 5 3 2x x 1 4 5Y x 2 3 2Y x
1Y2Y
(c) Create a table on your calculator with the table settings: TblStart = 0; . Complete the table below.
0
1
2
3
4
5
6
for x-values ______ than ______.
23. Solve the inequality by letting
and .
4 5 3 2x x 1 4 5Y x 2 3 2Y x
Tbl 1
1 2Y Y2Y1Y , , or x
(d)
(e) Do your solutions all match?
Solve the inequality algebraically.
23. Solve the inequality by letting
and .
4 5 3 2x x 1 4 5Y x 2 3 2Y x
4 5 3 2x x
Solve each inequality algebraically or graphically.
24. 0.5 3 0.5 5x x
25. 2 3 3 5 2x x x Solve each inequality algebraically or graphically.
Service Ax
Milesy
$ Cost
0.50 2.60
1.00 2.90
1.50 3.20
2.00 3.50
2.50 3.80
3.00 4.10
Service Bx
Milesy
$ Cost
0.50 2.40
1.00 2.80
1.50 3.20
2.00 3.60
2.50 4.00
3.00 4.40
26. The tables below display the charges for two taxi services based upon the number of miles driven. Service A has an initial charge of $2.30 and $0.15 for each quarter mile, while Service B has an initial charge of $2.00 and $0.20 for each quarter mile.
(a)
Use these tables to solve
(b)
(c)
(d) Interpret the meaning of the solution in parts (a) – (c).
1 2y y
1 2y y
1 2y y
27. Complete the following table. Can you give a verbal meaning for each case?
Phrase Inequality Notation
Interval Notation
Graphical Notation
“x is at least 5”
“x is at most 2”
“x exceeds
“x is smaller than
3 ”
1 ”
28. Write an algebraic inequality for the following statement, using the variable x to represent the number, and then solve for x.
Verbal Statement: Five less than three times a number is at least two times the sum of the number and three.
Algebraic Inequality:
Solve this inequality:
a cm 8 cm
8 cm
29. The perimeter of the triangle shown must be less than 26 cm.
Find the possible values for a.