Search for new physics at B factories
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Transcript of Search for new physics at B factories
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A.I. SandaNagoya University
Nagoya Japan
FPCP2004Daegu, KOREA
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A partial list of things that interested me
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1
1
sin 2 0.728 0.056 0.023 Belle
sin 2 0.722 0.040 0.023 Babar
Very impressiveIt will get even better!
ψKS asymmetry
KM mechanism is correct description of CP violation at low energies!
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Dramatic sign flip in sin2Φ1 with new VD at Belle. While ΨKS value for sin2Φ1 is stable with bo
th VD, Monte-Carlo studies supports that there nothing wrong, it is hard for me to understand. ( I look forward to Hazumi’s talk. I hope we can be convinced.)
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Φ KS asymmetry
Belle( ) ( )
cos sin( ) ( )
t t
A Mt S Mtt t
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Milky Way
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Why are these different?
Very useful for NP searches
As for CPV, my gut feeling is that it must be there!
( 0.13 0.60 0.56)% Belle
N NN N
Same sign dilepton CP asymmetry
Belle+Babar
( ) ( )0.113 0.019
( ) ( )
B K B K
B K B K
0 0
0 0
( ) ( )0.04 0.04
( ) ( )
B K B K
B K B K
B→Kπ CP asymmetries
obviously Belle data must come within the circle
ππ CP asymmetries
pQCD predicted itWith correct sign! Keum, Li, AIS
Babar New!
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Lyra
Altair
July 7
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0.170.160.43 0.51 BelleAsym
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Good news for isospin analysis
CP violation should be here too!
Looks promising!
Ways to unfold 4 fold ambiguities.
0 0 -6
0 0 0.44 0.22 -60.48 0.18
( ) (1.17 0.32 0.10) 10 Babar
( ) (2.32 ) 10 Belle
Br B
Br B
Observation of B→π0 π0
3*
0
+
*+
0
i
cb us
ub cs
B D K K
B D K K e
V V
V V
Observation of B→DK
Φ3
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B→VV polarization measurmentsMust for the new physics searches
0 0 0 0
Naive prediction
+10% K KC A
*B K
B→π0KS CP asymmetry
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Indication of things to expect in the future!
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Belle
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Not just limits. A quest for the discovery!
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Foreword: kaons again?In spite of a long history the K system is still a laboratory for the flavour physics, an interferometry system, a repository of all kinds of CP violation and can be a sensitive probe for NP.. Then:
YES, kaons again!
Vincenzo Patera*LNF/INFN
1030.189.0 1047.1)(
KBr
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He does not need to apologizeIt is a good sign for FP thatK physics continues after 57 years!
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KL0@E391a:Run I (2004)Expected
sensitivity
by Run I:
4÷9x10-10
Results from Run I in fall 2004
Requesting Run II in 2005
*11
2
4
3.2
110 10)5.06.2(10
Im
166
)(1048.1)(
ttt
SML GeV
mmKBR
A dream for a theorist, a
nightmare for an experimentalist. All
neutral, 2/3 invisible final state:
“Nothing to nothing”
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( , )
*
*ud ub
ucd cb
V VV V
132
*
*td tb
tcd cb
V VV V
(1,0)
SLAC notationIn honor of Bjorken
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Fermilab workshop 1988
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Correct a mistake in the CKM fitter figure
This solution is not allowed by ΨKS asymmetry!
AIS WIN2002, I.I. Bigi and AIS, to appear
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Notation
0 01
0 02
B p B q B
B p B q B
Mass eigenstates
1 1 11 11 12 12
2 2 11 11 12 12
2 2 2
2 2 2
i i q iM M M
p
i i q iM M M
p
Mass eigenvalues
2 1 12 122Re2
q iM M M M
p
Mass difference
* *2 12 12
12 12
* *12 12
12 12
2
2
2
2
iMq
ip M
iMq
ip M
Coefficients1 2 B B
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1
1
1
2*212 12
212 12
i
ii
M M eqe
p M M e
112 12
iM M e
1 12 22 1 12 122Re 2i iM M M e M e M
1212sin Im ( ) sin 2 Im ( )
iqMt f M t e f
p
112 122Resign MM M
This way -π/2< φ1 < π/2
± cancel but we need to know the sign
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*122
sin Im ( ) sin Im ( )
MqMt f Mt f
p M
2. Define △M>0 H LM M M
*122
sin Im ( ) sin Im ( )Mq
Mt f Mt fp M
1. Method which cancels △M dependence
*122Mq
p M
3. Try to cancel q/p dependence
12sin Im ( ) sin Re Im ( )q q q
Mt f M t fp p p
Discussions on the marketSign of ΔM cancel but you need to know the sign
ΔM>0, but you need to know the sign
Sign of q/p cancel but you need to know the sign
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2 2( ) ((1 ) )sign M sign
-
++
-
( )sign M
1 2 2
2 (1 )sin 2
(1 )
-
+
+
-
1sin 2
-+
+-
+
+ -
- 1sin sin 2M
These are allowed region for ψKS asym>0
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1 1sin 2 0, cos2 0
1 1sin 2 0, cos2 0
Excluded
.)(27.0.)(72.2)cos(2β 50.079.0 syststat
CL 86.6%at excluded
68.0
)β2(sin1)cos(2β 2
Babar
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Lets assume that ΔM contains NP.ε and ΔM constraints are removed as they may contain effects of new physics
Constraint from ψKS asymmetryassume sin2φis given by exp.
ubV
c
t
u 132
KM parameters are not directly related to ψKS asymmetry
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u c experimentally known
1Given all others are fixed
12iSMR e
2 ie
2iNPR e
12 212 12 12 2
iSM NP i
SM NPM
M M M R e R e
2
2
iMe
c
t
u 132
12 2 2 i i iSM NPR e R e e
1212 2SM i
SMM
M R e
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12i
SMR e
2 ie2iNPR e
c
t1
2
u
12 2 2 i i iSM NPR e R e e
If Φ1 <0, RNP gets bigger
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( 0.13 0.60 0.56)%
N NN N
1.0006 0.0030 0.0028qp
Belle hep-ex/0408012
4
4
1
1
SL
pqN N
AN N p
q
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12
2
2
2 21
2
8
3 (1Im
)SLc
b
mA
M m
*12
c
* *12
In the limit 0,
=
u
ud u
td b
c cb
t
b d
m m
V
M
V
V
V V
V
1
12*
* *2Im Im
td tb
ud ub cd cbSL
V V V VA
M V V NP
NP will get in the way ofcancellation
1* *
*2
12
I n the limit 0,
is realtbt
ub cbud c
d
d
c u
V
m
M
V
V
V
m
V
V
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1)ΨKS asymmetry sinφ
2) Φ 3 determination
230
( ) ( )1 2 cos cos
2 ( )CP CP
CP B B B
B D K B D KR r r
B D K
3
( ) ( )2 sin sin /
( ) ( )CP CP
CP B B CPCP CP
B D K B D KA r R
B D K B D K
Four fold ambiguity in Determining φ 3
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Large φ3 solutionIs almost excluded
4 fold degeneracy
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*
*
ub us
Ttb ts
T V Vr
P V V EW
TP
rP
T P EWP
Leave it to Yoshikawa to talk aboutThe importance of EW penguinsAnd other general analysis
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2 2
32 22 sin sin
K K TCP T
K K
A AA r
A A
2 20 00
32 20 0\
32 sin sin2 sin sinK K T
CP
K
CT
K
C
A AA r r
A A
2 200 0000
2 200 0032 sin sinC
CK K
CP
K K
A AA
A Ar
0 0 0( ) ( ) ( ) 0Asym K Asym K Asym K
+- 00
00
CP aymmetry A - A
A +10%
CP CP
CP
CP violation in the decay amplitude
( ) ( )0.113 0.019
( ) ( )
B K B K
B K B K
Belle+Babar
0 0
0 0
( ) ( )0.04 0.04
( ) ( )
B K B K
B K B K
See Yoshikawa’s talk for details
A naïve analysisNeglect all r2
terms and annihilation just to illustrate a point
Cancellation?
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0 0The role of C in B
2
2
2
2
0 0 0
0
0
( ) ( )
( ) (1 )
( ) (1 )
id
i
i
i
w
d
e
ew
P Ce
T TPC
eT
PA B T e
T
A B T
PA B T
T
eT
pi pi data => C/T = 0.70 e^{i 63^o}Substituting the above C/T into the K pi data, we obtain T/P = 0.16 e^{-25^o i}, P^{ew}/P = 0.26 e^{-70 ^o i} So, it is possible to accommodate all data by increasing only C.
See Yoshikawa’s talk for details
Charng and Li
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ΦKS asymmetry
2 2
* * *
4
0
tb ts cb cs ub usV V V V V V
( ) ( ) S SK K
* tb tsV V
0B
d
b c
csd
SK
*cb csV V
Standard model predicts equal CP violation for these decay modes
Im( ( ))qp f
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I believe that some new physics effect might be there.
But not at the level of 50%.It is probably at 1% level.
So, precision experiments are needed!
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Naïve factorizationWe expect |A00 |>> |A-- |>> |A++
|
New physics must show up in B→ ΦK*
asymmetry
f A A
fL should dominate
|f00|>>|f--|>> |f++| 1
f
f
Φ
b s
s s
A. Kagan
3 possibilities
BΦ K*0 0 No spin flip
Spin filp of s quark
Spin flip of both s quarks
00LA A
A
ACP + 00LA A
A A A+
A A A-
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This is a naïve argument! Non factorizable diagrams ect.
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If there is NPit should appear here
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I am not surprised if so called new physics effects went away! Continued search is absolutely necessary.
Don’t say 1035 , it is not enough! SUPERB with 1043 is strongly
encouraged! Many interesting physics to do for many
years to come! Lets have fun!