SAMPLE TEST PAPER - Resonanceresostart.in/.../STaRT_2015_Sample_Test_Paper_Clsss_11_bio.pdf ·...

Write your Name and STaRT-2015 Student Registration No. in the space provided below.

Name Reg. No.

GENERAL INSTRUCTIONS IN EXAMINATION HALL

Please read the instructions carefully. You are allotted additional 5 minutes specifically for this purpose.

Duration : 90 Minutes Max. Marks : 200

SAMPLE TEST PAPERCLASS : XI STREAM : SCIENCE - BIOLOGY

Best of Luck

1 5

A. General :

1. This Question Paper contains 50 questions. Please check before

starting to attempt. The question paper consists of 4 parts (Physics,

Chemistry, Biology & Mental Ability).2. Space is provided within question paper for rough work hence no

additional sheets will be provided.3. Blank paper, clipboard, log tables, slide rules, calculators, cellular

phones, pagers and electronic gadgets in any form are not allowedinside the examinaiton hall.

4. The answer sheet, a machine-gradable Objective ResponseSheet (ORS), is provided separately.

5. Do not Tamper / mutilate the ORS or this booklet.6. Do not break the seals of the question-paper booklet before

instructed to do so by the invigilators.7. SUBMIT the ORS to the invigilator after completing the test &

take away the test paper with you.8. Any student found/reported using unfair means to improve

his/her performance in the test, shall be disqualified fromSTaRT-2015.

B. How to fill Objective Response Sheet (ORS) for filling detailsmarking answers:

9. Use only HB Pencil/Blue or Black ball point pen for filling the ORS.Do not use Gel/Ink/Felt pen as it might smudge the ORS.

10. Write your STaRT-2015 Student Registration No. in the boxes givenat the top left corner of your ORS with blue/black ball point pen.Also, darken the corresponding bubbles with HB Pencil/Blue orBlack ball point pen only.

11. If any student does not fill his/her STaRT-2015 Student RegistrationNo. correctly and properly, then his/her ORS will not be checked/evaluated.

12. Since it is not possible to erase and correct pen filled bubble, youare advised to be extremely careful while darken the bubblecorresponding to your answer.

13. Neither try to erase / rub / scratch the option nor make the Cross(X) mark on the option once filled. Do not scribble, smudge, cut,tear, or wrinkle the ORS. Do not put any stray marks or whiteneranywhere on the ORS.

14. If there is any discrepancy between the written data and thebubbled data in your ORS, the bubbled data will be taken as final.

C. Question paper format and Marking scheme :15. For each right answer you will be awarded 4 marks if you

darken the bubble corresponding to the correct answer and zeromarks if no bubble is darkened. In case of bubbling of incorrectanswer, minus one (�1) mark will be awarded.

v- lkekU; %

1- bl iz'u&i= esa 50 iz'u gSaA Ñi;k ijh{kk 'kq: djus ls igys tk¡p

ys aA bl iz'u&i=k es a 4 Hkkx bl izdkj gS a & Hk k S frd foKku]

jlk;u foKku ] tho foKku ,o a e ku fld ;k s X;r k

2- jQ dk;Z djus ds fy, iz'u&i= esa gh LFkku fn;k x;k gS vr% vfrfjDr :i

ls dksbZ 'khV ;k isij ugha fn;k tk,xkA

3- [kkyh dkxt] r[rh] y?kqx.kd lkj.kh] LykbM :y] dsYdqysVj] lsy

Qksu] istj ,oa fdlh Hkh izdkj ds bysDVªkWfud xStsV ijh{kk gkWy esa

ykuk oftZr gSA

4- mÙkj iqfLrdk] vkWCtsfDVo jsLikWUl 'khV ¼vks-vkj-,l-½ tks fd e'khu }kjk

tk¡ph tk,xh] vyx ls iznku dh xbZ gSA

5- vks-vkj-,l- ;k iz'u&i= dks fdlh Hkh izdkj ls dkaVs&NkaVs ;k eksM+s ughaA

6- iz'u&i= dh lhy rc rd ugha [kksysa tc rd fd fujh{kd }kjk funsZ'k ugha

fn, tk,saA

7- ijh{kk lekIr gksus ds ckn vks-vkj-,l- 'khV fujh{kd dks lkSais rFkk iz'u&i=

vius lkFk ys tk,saA

8- ;fn dksbZ fo|kFkhZ ijh{kk esa vad c<+kus ds fy, vuqfpr lk/kuksa dk iz;ksx

djrk ik;k x;k ;k ,slk lwfpr fd;k x;k rks og STaRT-2015 ds fy,

v;ksX; gksxkA

c - vk W Ct sfDVo j sLik W Ul 'khV ¼vk s -vkj-,l-½ e s a fMV sYl rF kk mÙkj

vafdr djus ds fy, fuEu izdkj Hkjs a %

9- vks-vkj-,l- Hkjus ds fy, dsoy HB isafly@uhyk ;k dkyk ckWy isu gh

iz;ksx djsaA tsy@L;kgh@QsYV isu iz;ksx ugha djsaA

10- viuk STaRT-2015 fo|kFkhZ jftLVªs'ku Øekad vks-vkj-,l- 'khV ds ck;sa

dksus esa fn, x, LFkku esa uhys ;k dkys ckWy isu ls HkjsaA lkFk gh Øekad ds

vuqlkj uhps fn, x;s xksyksa dks Hkh HB isafly@uhys ;k dkys ckWy isu ls

xgjk djsaA

11- ;fn dksbZ fo|kFkhZ viuk STaRT-2015 fo|kFkhZ jftLVªs'ku Øekad lgh ,oa

Bhd <ax ls ugha Hkjrk gS rks mldh vks-vkj-,l- dks pSd@ewY;kafdr ugha

fd;k tk,xkA

12- vks-vkj-,l- esa fn, x, xksyksa dks ;fn ,d ckj ckWy isu ls xgjk fd;k tkrk

gS rks mls feVkuk laHko ugha] blfy, fo|kFkhZ iwjh lrdZrk ls gh xksyksa dks

xgjk djsaA

13- ,d ckj fdlh fodYi ds xksys dks xgjk djus ds ckn feVkus ;k [kqjpus dk

iz;Ru ugha djsaA vks-vkj-,l- 'khV ij fdlh izdkj ds /kCcs] xUnxh ;k

flyoV u yxus nsa vkSj u gh bls eksM+sa ;k dkVsaA

14- ;fn fdlh lanHkZ esa fyf[kr ,oa xksyksa esa vafdr tkudkjh esa varj ik;k x;k

rks xksyksa esa vafdr tkudkjh dks gh izekf.kd ekuk tk,xkA

l - iz'u&i= izk:i ,oa vad iznku fu;e %

15- izR;sd mÙkj ds fy, 4 vad fn, tk,xsa ;fn lgh xksys dks xgjk fd;k x;kA

;fn xyr xksys dks xgjk fd;k x;k rks ¼&1½ vad dkVk tk,xkA ;fn fdlh

xksys dks Hkh xgjk ugha fd;k x;k rks 'kwU; vad fn;k tk,xkA

(SPACE FOR ROUGH WORK)

RESONANCE STaRT2015 XI_(BIO) - 3

PART-I (PHYSICS)

Straight Objective Type

This section contains (1-15) questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out ofwhich ONLY ONE is correct.

lh/ks oLrqfu"B izdkj

bl [k.M esa (1-15) cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (A), (B), (C) rFkk (D) gSa] ftuesa ls flQZ ,d lgh

gSA

1. Arc AB is half section of ellipse (with AB as the major axis). An ideal gasis taken from A to B as shown in diagram. The work done by gas for A toB process is : [use = 22/7]pki AB nh?kZoÙk dk v/kZ&Hkkx (AB nh?kZ v{k) gS A ,d vkn'kZ xSl dks fp=kkuqlkj Als B rd ys tk;k x;k gSA bl çfØ;k esa xSl }kjk A ls B rd fd;k x;k dk;Z gS:[ = 22/7]

A B

2×103 9×10

3

3×10�3

5×10�3

V(m )3

P(N/m )2

0

(A) 11 J (B) 22 J (C) �11 J (D) �22 J

2. A ball is thrown at different angles with same speed u and from the same point. It has the same range in boththe cases. If y1 and y2 be the maximum heights attained in the two cases, then y1 + y2 is :,d xsan vyx&vyx dks.k ls ijUrq leky pky u ls ,d gh fcUnq ls Qsadh tkrh gSA nksauks fLFkfr;ksa esa xsan dh ijkl leku gSA ;fny1 rFkk y2 nksauks fLFkfr;ksa esa xsan }kjk çkIr vf/kd re Å pk¡bZ;ka gks rks y1 + y2 gksxk

(A) gu2

(B) gu2 2

(C) g2u2

(D) g4u2

3. A simple pendulum is suspended from the ceiling of a car. Find the horizontal acceleration of the car in termsof the angle which the pendulum makes with the vertical.

,d d kj d h Nr ls ,d ljy yksyd yVd k gqvk gSA Å /okZ/kj ls yksyd }kjk cuk;s x;s d ks.k d s inksa esa d kj d k {kSfrtRoj.k Kkr d hft,A(A) g tan (B) g sin (C) g cos (D) g cot

4. A car is moving on a plane inclined at 30º to the horizontal with an acceleration of 9.8 m/s2 parallel to the planeupward. A bob is suspended by a string from the roof. The angle in degrees which the string makes with the verticalis : (Assume that the bob does not move relative to car) [g = 9.8 m/s2]30º dks.k okys ,d ur ry ij ,d dkj ur ry ds lekUrj Å ij dh vksj 9.8 m/s2 ds Roj.k ls xfr dj jgh gSA dkj dh Nrls Mksjh }kjk ,d yksyd (bob) yVdk gqvk gSA Mksjh }kjk m/okZ/kj ds lkFk cuk;k x;k dks.k gS% (ekuk yksyd (bob)] dkj ds lkis{kxfr ugha djrk gS½ [g = 9.8 m/s2](A) 20º (B) 30º (C) 45º (D) 60º



5. Value of is increased gradually from = 0. At = tan�1

2

1 both the blocks just start slipping. Then value of

2 is:

(g = 10 m/s2)

= 0 ls dk eku yxkrkj c<+ jgk gSA = tan�1

21

ij nksauks CykWd xfr djuk çkjEHk djrs

gSA rc 2 dk eku gS : (g = 10 m/s2)

(A) 0.5 (B) 0.4 (C) 0.6 (D) 0.3

6. A particle of mass 5 kg is moving on rough fixed inclined plane (making an angle 30° with horizontal) with

constant velocity of 5 m/s as shown in the figure. Find the friction force acting on the body by the inclineplane. ( take g = 10m/s2)5 kg nzO;eku dk ,d d.k ,d fLFkj [kqjnjs ur ry ¼tks {kSfrt ls 30° dk dks.k cukrk gS½ ij fn[kk;sfp=kkuqlkj 5 m/s ds fu;r osx ls xfr djrk gSA ur ry }kjk d.k ij yxus okyk ?k"kZ.k cy Kkrdhft,A ( g = 10m/s2)

(A) 25 N (B) 20 N (C) 30 N (D) none of these buesa ls dksbZ ugh

7. The potential energy for a force field F

is given by U (x,y) = cos (x + y). The force acting on a particle at

position given by coordinates

4,0 is

,d cy {ks=k Fdh fLFkfrt Å tkZ U (x,y) = cos (x + y) gS] rks funsZ'kkad

4,0 fLFkfr ij d.k ij yxus okyk cy gS

(A) � 2

1)j�i�( (B)

2

1)j�i�( (C)

j�

23

i�21

(D)

j�

23

i�21

8. The potential energy (in S units) of a particle of mass 2 kg in a conservative field is U = 6x � 8y. If the initial velocity

of the particle is u

= � 1.5 i� + 2 j� then the total distance travelled by the particle in first two seconds is -

,d 2 kg nzO;eku okys d.k dh laj{kh {ks=k esa fLFkfrt Å tkZ (in S units) U = 6x � 8y gSA ;fn d.k dk izkjfEHkd osx

u

= � 1.5 i� + 2 j� gS rks d.k }kjk igys nks lSd.M esa r; dh xbZ dqy nwjh gksxh &

(A) 10 m (B) 12 m (C) 15 m (D) 18 m




9. An insect of mass m = 3 kg is inside a vertical drum of radius 2 m that is rotating with anangular velocity of 5 rad/sec. If the insect does not fall off, then the minimum co-efficientof friction required is (g = 10m/s2) :,d 3 kg nzO;eku dk dhM+k 2 eh- f=kT;k ds m/okZ/kj Mªe ds vUnj gS rFkk Mªe 5 rad/sec ds dks.kh; osxls ?kwe jgk gSA ;fn dhM+k uhps ugh fxjrk rks U;wure vko';d ?k"kZ.k xq.kkad gS (g = 10m/s2) :

(A) 0.5 (B) 0.4 (C) 0.2 (D) none of these buesa ls dksbZ ugha

10. A mass M hangs stationary at the end of a light string that passes through a smoothfixed tube to a small mass m that moves around in a horizontal circular path. If isthe length of the string from m to the top end of the tube and is angle between thispart and vertical part of the string as shown in the figure, then time taken by m tocomplete one circle is equal to,d nzO;eku M gYdh jLlh ls fLFkj :i ls yVd jgk gS rFkk jLlh dk nwljk fljk fpduh tM+or~V~;wc ls xqtkjus ds ckn NksVs nzO;eku m ls ca/kk gSA tks {kSfrt oÙkh; iFk esa ?kwe jgk gSA ;fn m ls V~;wcds Å ijh fljs rd jLlh dh yEckbZ vkSj jLlh ds bl Hkkx rFkk jLlh ds Å /okZ/kj Hkkx ds chp dks.k gS rks m }kjk ,d pDdj yxkus esa oÙk iwjk djus esa fy;s x;s le; dk eku gksxk M

m

(A)

sing

2

(B)

cosg

2

(C)

sinMg

m2

(D) Mg

m2

11. A uniform thin rod of mass �m� and length L is held horizontally by two vertical strings attached to the two ends. One

of the string is cut. Find the angular acceleration soon after it is cut :

,d m nzO;eku rFkk L yEckbZ dh NM+ dks nks yEcor~ Mksjh;ksa }kjk {kSfrt yVdk;k x;k gS Mksjh fdukjksa ls ca/kh gSA ;fn ,d Mksjh dks

rksM+ fn;k tk;s rks Mksjh VwVus ds rqjUr ckn dks.kh; Roj.k gksxk :

(A) L2g

(B) Lg

(C) L2g3

(D) Lg2

12. A uniform cylinder of mass m can rotate freely about its own axis which is horizontal. A particle of mass m0

hangs from the end of a light string wound round the cylinder which does not slip over it. When the system isallowed to move, the acceleration of the descending mass m

0 will be:

m nzO;eku dk ,d le:i csyu mldh Loa; v{k tks {kSfrt gS ds lkis{k ?kw.kZu ds fy, LorU=k gSA mo nzO;eku dk ,d d.k ,d

Mksjh ds fljs ls yVdk gqvk gS rFkk Mksjh csyu ij fyiVh gqbZ gS tks bl ij fQlyrh ugha gSA tc fudk; dks xfr ds fy, NksM+k tkrkgS] nzO;eku m

0 dk uhps dh vksj Roj.k gksxk &

(A) 2

2

m g

m mo

o(B)

m g

m mo

o(C)

2m g

m mo

o(D)

m g

m mo

o2



13. In the figure shown the initial velocity of boat (30 kg) + person (15 kg )is 2 m/s. Find velocity v of person with respect to boat so that velocity ofboat will be 1 m/s towards right (Neglect friction between boat and water)fp=kkuqlkj "uko + euq";" dk izkjfEHkd osx 2 eh0@lS0 gSA euq"; dk osx v uko ds lkis{kKkr djks ftlls uko dk osx 1 eh0@ls0 nk;ha vksj gks tk;s ¼uko vkSj ikuh ds chp ?k"kZ.kux.; gS½

(A) 3 m/s towards right nkW;h vkSj 3 m/s ls(B) 3 m/s towards left ck¡;h vkSj 3 m/s ls(C) 4 m/s towards right nk¡;h vkSj 4 m/s ls(D) 4 m/s towards left ck¡;h vkSj 4 m/s ls

14. The spacecraft of mass M moving with a velocity v in free space explodes and breaks up into two pieces. If afterexplosion a piece of mass m comes to rest, the other piece of spacecraft will have velocity.M nzO;eku dk vUrfj{k;ku eqDr {ks=k esa v osx ls xfr'khy gS rFkk foLQksV ds dkj.k nks Hkkxksa esa VwV tkrk gSA ;fn foLQksV ds i'pkr~m nzO;eku dk ,d VqdM+k fojkekoLFkk esa vk tkrk gS] vUrfj{k;ku ds vU; VqdM+s dk osx gksxk &

(A) mMMv

(B) mMMv

(C) mv / (M�m) (D) mMmv

15. A projectile is launched at an angle with the horizontal from point A, and finally falls at point B. A and B areon a horizontal line. During the course of the motion from point A to point B, for the projectile :,d iz{ksI; fcUnq A ls {kSfrt ds lkFk dks.k ij NksM+k tkrk gS] var esa ;g /kjkry ds fdlh fcUnq B ij igq¡prk gSA A o B ,d gh{ksfrt js[kk ij fLFkr gSaA fcUnq A ls B rd xfr ds nkSjku iz{ksI; ds fy;s :

A B(A) magnitude of normal acceleration first increases then decreases.(B) magnitude of tangential acceleration first increases then decreases.(C) radius of curvature first increases then decreases.(D) external force acting on it first increases then decreases.

(A) vfHkyEcor~ ¼vfHkdsUnzh;½ Roj.k dk ifjek.k igys c<+rk gS fQj ?kVrk gS(B) Li'kZjs[kh; Roj.k dk ifjek.k igys c<+rk gS fQj ?kVrk gS(C) oØrk f=kT;k igys c<+rh gS vkSj fQj ?kVrh gSA(D) vkjksfir cká cy igys c<+rk gS vkSj fQj ?kVrk gSA




PART-II (CHEMISTRY)


This section contains ( 16-25) questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out ofwhich ONLY ONE is correct.



gSA

16. 7.5 ml of a gaseous hydrocarbon was exploded with 36 ml of oxygen. The volume of gases on cooling was found

to be 28.5 ml, 15 ml of which was absorbed by KOH and the rest was absorbed in a solution of alkaline pyro-

gallol. If all volumes are measured under same conditions, the formula of hydrocarbon is

,d xSlh; gkbMªksdkcZu ds 7.5 ml dks vkWDlhtu ds 36 ml ds lkFk foLQksfVr fd;k x;kA B.Mk djus ij xSl dk vk;ru 28.5 ml

ik;k x;k] ftlesa ls 15 ml dks KOH ds }kjk vo'kksf"kr fd;k x;k rFkk cps gq, vk;ru dks {kkjh; ik;jksxSyksy ds foy;u esa vo'kksf"krfd;k x;kA ;fn lHkh vk;ru leku ifjfLFkfr ij ekis x;s rks gkbMªksdkcZu dk lw=k gS\(A) C

3H

4(B) C

2H

4(C) C

2H

6(D) C

3H

6

17. The correct set of four quantum numbers for the valence electron of Rubidium (Z = 37) is ::fcfM;e (Z = 37) ds la;ksth bysDVªkWu ds fy, pkj Dok.Ve la[;k dk lgh leqPp; crkvks

(A) n = 5, = 0, m = 0, s = + 21

(B) n = 5, = 1, m = 0, s = + 21

(C) n = 5, = 1, m = 1, s = + 21

(D) n = 6, = 0, m = 0, s = + 21

18. Fluorine has the highest electronegativity among the ns2 np5 group on the Pauling scale, but the electron affinity offluorine is less than that of chlorine because :(A) the atomic number of fluorine is less than that of chlorine.(B) fluorine being the first member of the family behaves in an unusual manner.(C) chlorine can accommodate an electron better than fluorine by utilising its vacant 3d�orbital.

(D) small size, high electron density and an increased electron repulsion makes addition of an electron to fluorineless favourable than that in the case of chlorine in isolated stage.

ikWfyx ekiØe ds vuqlkj ns2 np5 oxZ esa ¶Ykksjhu lcls T;knk fo|qr_ .kh gSaA ysfdu ¶Ykksjhu dh bysDVªkWu ca/kqrk] Dyksjhu ls degksrh gSa] D;ksafd %(A) ¶yksjhu dk ijek.kq Øekad Dyksjhu ls de gksrk gSaA(B) ¶yksjhu oxZ dk igyk lnL; gSa] blfy;s ;s vyx O;ogkj djrk gSaA(C) Dyksjhu fjDr 3d�d{kd dk mi;ksx ¶yksjhu ls vPNh rjg djds ,d bysDVªkWu j[k ldrk gSaA(D) NksVk vkdkj mPp bysDVªkWu ?kuRo vkSj bysDVªkWu çfrd"kZ.k esa of) ds dkj.k foyfxr voLFkk esa Dyksjhu dh rqyuk es ¶yksjhu

esa ,d e� tksM+uk de vuqdqy gksrk gSA



19. S1 : Always cyclic part is main chain and acyclic is substituent in alicyclic molecules.S1 : ,fylkbfDyd v.kq esa ges'kk pØh; Hkkx eq[; Ja[kyk gksrk gS rFkk vpØh; Hkkx izfrLFkkihAS2 : Correct IUPAC name of the following is 3-Bromo-2-Chlorohepta-2,4-diene.S2 : fuEu dk lgh IUPAC uke 3-czkseks-2-DyksjksgsIVk-2,4-MkbZbZu

S3 : DU of the following compounds is 6.S3 : fuEu ;kSfxd dk DU = 6 gSA

S4 : Di, tri., tetra of complex radical are considered for alphabetization.S4 : ladqy ewyd dk MkbZ] VªkbZ] VsVªk vxzsth o.kZekyk esa lfEefyr fd;k tkrk gSA(A) F T T F (B) F T F T (C) F F T T (D) T T F F

20. A 5.2 molal aqueous solution of methyl alcohol (CH3OH), is supplied. What is the mole fraction of methyl alcohol inthe solution ?esfFky ,sYdksgkWy] CH3OH dk ,d 5.2 eksyy tyh; foy;u fn;k tkrk gSA bl foy;u esa esfFky ,sYdksgkWy dk eksy izHkka'k D;kgS\(A) 0.100 (B) 0.190 (C) 0.086 (D) 0.050

21. 2K + 2 + 22 HNO

3 2HO

3 + 2KO

3 + 22NO

2 + 10H

2O

If 3 moles of K & 2 moles 2 are reacted with excess of HNO

3. Volume of NO

2 gas evolved at NTP is

;fn K ds 3 eksy rFkk 2 ds 2 eksy HNO

3 ds vkf/kD; ls fØ;k djrs gSA ekud rki o nkc ij NO

2 dk izkIr vk;ru gSµ

(A) 739.2 Lt (B) 1075.2 Lt (C) 44.8 Lt (D) 67.2 Lt

22. Identify the incorrect statement(A) Formal charge do not indicate real charge separation with in the molecule.(B) A pair of +1 and �1 formal charges on the adjacent atoms is considered as coordinate bond in lewis dot

structures.(C) The lowest energy lewis dot structure is the one with minimum formal charge on the atoms.(D) Formal charge is the factor based upon electronegativity of bonded atom.vlR; dFku dks igpkfu;sA(A) ,d v.kq esa vkSipkfjd vkos'k (formal charge) okLrfod vkos'k iFkDdj.k dks ugh n'kkZrkA(B) ysfol fcUnq lajpuk esa fudVorhZ (adjacent) ijek.kq ij +1 rFkk � 1 vkSipkfjd vkos'k dks milgla;kstd ca/k ds :i esa ekurs

gSaA(C) U;wure Å tkZ okyh ysfol fcUnq lajpuk esa ijek.kqvksa ij U;wure vkSipkfjd vkos'k gksrk gSA(D) vkSipkfjd vkos'k ,d ,slk dkjd gS tks cfU/kr ijek.kqvksa dh fo|qr _ .krk ij vk/kkfjr gSA



23. Decreasing �I effect of given groups is :

fn;s x;s lewgks ds �I izHkko dk ?kVrk gqvk Øe gSA(i) CN (ii) NO

2(iii) NH

2(iv) F

(A) iii > ii > i > iv (B) ii > iii > iv > i (C) iii > ii > iv > i (D) ii > i > iv > iii

24. Which of the following compound will not give positive iodoform test.fuEu esa ls dkSulk ;kSfxd /kukRed vkW;ksMksQkWeZ ijh{k.k ugha nsrk gSA

(A) (B) (C) (D) CH3 � CHO

25. The most stable anion is :lcls vf/kd LFkk;h ,uk;u ¼_ .kk;u½ gS %

(A) (B) (C) (D)

PART - III (BIOLOGY)





gSA

26. On stimulation, the parasympathetic nerve fibres secrete a chemical called(A) acetylecholine (B) Lysin (C) ADH (D) vasopressin

mRizsj.k feyus ij ijkuqdEih rfU=kdk rU=k }kjk ,d jlk;u dk lzo.k fd;k tkrk gS ftls dgk tkrk gS

(A) ,lhVkbZydksfyu (B) ykbflu (C) ADH (D) oklksizsflu

27. Which proteolytic enzyme induces lysis of fibrin during fibrinolysis ?(A) fibrin (B) plasmin (C) thrombin (D) All of these

dkSulk izksVh;ksykbfVd ,Utkbe Qkbfczuksykbfll ds nkSjku Qkbfczu ds VqVus ¼ykbfll½ dks izsfjr djrk gS

(A) Qkbfczu (B) IykfTeu (C) FkzksfEcu (D) mijksDr lHkh



28. Which of the following digestive juices have the maximum pH ?(A) gastric juice (B) pancreatic juice (C) bile (D) Saliva

fuEu esa ls dkSuls ikpd ,Utkbe dh pH lokZf/kd gS

(A) tBj jl (B) vXuk'k;h jl (C) fiRr (D) ykj

29. The cranial capacity was least among the(A) Neanderthal man (B) Java apeman (C) African man (D) Peking man

fuEu esa ls fdlesa lcls de dikyh; lkeF;Zrk ik;h tkrh gS

(A) fu,UMjFky ekuo (B) tkok ,iekuo (C) vÝhdu ekuo (D) iSfdax ekuo

30. Last molars in human being are called(A) milk teeth (B) wisdom teeth (C) thecodont (D) none of these

ekuo esa ik, tkus okys vfUre eksyj nkar dks D;k dgk tkrk gS

(A) nw/k ds nkar (B) vDdy nk<+ (C) xrZnUr (D) buesa ls dksbZ ugh

31. Which of the following organelle is associated with synthesis of lipid and lipid like steroidal hormones?(A) Mitochondria (B) Lysosomes (C) SER (D) ChloroplastfuEu esa dkSu lk dksf'kdkax fyfiM o fyfiM dh rjg LVhjkW;My gkWeksZu ds la'ys"k.k ls lacaf/kr gS -(A) ekbVksdkWf.Mª;k (B) ykblkslksEl (C) SER (D) gfjryod

32. Malpighian tubules are present in(A) rabbit and are excretory organs (B) cockroach and are respiratory organs(C) frog and are part of circulatory system (D) cockroach and are excretory organs

eSYih?kh;u ufydk,¡ fdlesa ik;h tkrh gS

(A) [kjxks'k esa rFkk ;s mRlthZ vax gksrh gS (B) dkWdjksp esa rFkk 'olu vax gksrh gS

(C) esa<+d esa rFkk ifjlapj.k rU=k dk ,d Hkkx gksrh gS (D) dkWdjksp esa rFkk mRlthZ vax gksrh gS

33. Universal pigments present in all the algae are(A) Chl a, Chl b (B) Chl a, b, c (C) Chl a, carotenoid (D) Chl a, b carotenoid,slk lkoZf=kd o.kZd tks lHkh 'kSokyksa esa ik;k tkrk gS -(A) DyksjksfQy a, b (B) DyksjksfQy a, b, c

(C) DyksjksfQy a, dSjksfVukW;M (D) DyksjksfQy a, b, dSjksfVukW;M

34. Which hormone is responsible in delaying senesence(A) GA (B) ABA (C) Cytokinin (D) EthylenefuEu esa dkSu lk gkWeksZu th.kZrk dks foyEc djrk gS -(A) GA (B) ABA (C) lkbVksdkbfuu (D) bFkkbZyhu



35. In EMP pathway which occurs in both aerobic and anaerobic cell, non enzymatic step is(A) Glucose glucose 6 phosphate (B) Fructose 1.6 diphosphate 3 PGA(C) 3 PGAL 1,3di PGAL (D) PEP PA

EMP ikFkos tks vkWDlhdkjh o vukWDlhdkjh nksuksa izdkj dh dksf'kdkvksa esa ik;k tkrk gS] esa ,Utkbe jfgr in gS -

(A) Xywdkst Xywdkst 6 QkWLQsV (B) ÝDVkst 1.6 MkbQkWLQsV 3 PGA

(C) 3 PGAL 1,3di PGAL (D) PEP PA

36. In chromosome when centromere is subterminal in position, it is said to be(A) Metacentric (B) Acrocentric (C) Sub-metacentric (D) Telocentric

xq.klw=k esa tc lSUVªksfe;j dh fLFkfr mifljh; gksrh gS rks bls dgrs gSa -

(A) eSVklSfUVªd (B) ,ØkslSfUVªd (C) lc&eSVklSfUVªd (D) VhykslSfUVªd

37. In photosynthetic carbon oxidative (PCO) cycle which organelle is involved releasing of ammonia and CO2?

(A) Chloroplast (B) Peroxisome (C) Mitochondria (D) All of these

izdk'kla'ys"kh vkWDlhdkjh (PCO) pØ esa dkSulk dksf'kdkax veksfu;k o CO2 eqDr djus ds fy;s mÙkjnk;h gS

?

(A) gfjryod (B) ijvkWDlhlkse (C) ekbVksdkWf.Mª;k (D) lHkh

38. Peristomes for spore dispersal are present in(A) Riccia (B) Marchantia (C) Equisetum (D) Funaria

chtk.kqvksa ds izdh.kZu gsrq iSfjLVkse fdlesa ik;k tkrk gS -

(A) fjfDl;k (B) ekdsZfU'k;k (C) bDohlhVe (D) ¶;wusfj;k39. Microsporophyll of Cycas has the same nature as

(A) Sepal (B) Stamen (C) Petal (D) Carpel

lkbdl ds y?kqchtk.kq dh izÑfr fuEu esa fdlds leku gS\

(A) cká ny (B) iqadslj (C) ny (D) v.Mi

40. When filament is attached to the back of the anther and the anther can freely swing is called(A) Dorsifixed (B) Basifixed (C) Adnate (D) Versatile

;fn ijkxdks"k ds i"B Hkkx ls iqrUrq bl izdkj layXu gks fd ijkxdks"k eqDr:i ls iqrUrq ij nksyu dj lds og iqadslj

dgykrk gS

(A) i"ByXu (B) vk/kkj yXu (C) layXu (D) eqDrnksyh




PART-IV (MENTAL ABILITY)Straight Objective Type




gSA

Direction (41 to 43) : Find the missing terms �funsZ'k ¼41 ls 43½’vKkr in Kkr djksA

41. 94, 166, 258, ?, 4912(A) 3610 (B) 1644 (C) 1026 (D) 516

42. AD 17 39 CFBP 258 108 HJGN ? ? LM(A) 203, 181 (B) 179, 239 (C) 18, 210 (D) 9, 29

43.

(A) 38 (B) 64 (C) 4 (D) 16

44. If AJAY is written as 1117, then in same code NAMA would be written as :;fn AJAY dks 1117 fy[kk tk;s rks] mlh dksM+ esa NAMA dks D;k fy[kk tk;sxk \(A) 5114 (B) 5411 (C) 5141 (D) 4511

45. Arrange the following group such that when arranged in a specific order, meaningful word is formed.fuEu v{kjks ds lewg dks bl izdkj O;ofLFkr djks rkfd buls ,d vFkZ iw.kZ 'kCn cu tk;s \V A H Y E1 2 3 4 5(A) 2, 3, 4, 5, 1 (B) 3, 2, 5, 1, 4 (C) 3, 5, 2, 1, 4 (D) 1, 5, 2, 3, 4

46. If + is x,� is +, x is and is �, then what is the value of given equation

;fn + dk eryc ×] � dk eryc +, × dk eryc ÷ rFkk ÷ dk eryc � ekus rks bl lwpuk ds vk/kkj ij fuEu lehdj.k dkeku gksxkA21 ÷ 8 + 2 � 12 × 3 = ?

(A) 14 (B) 9 (C) 13.5 (D) 11

47. What is the product of all the numbers in the dial of a telephone ?VsfyQksu ds Mk;y ij fLFkr vadksa dk xq.kuQy D;k gksxk ?(A) 1,58,480 (B) 1,59,450 (C) 1,59,480 (D) None of these



Directions (48) : In the following questions, there is a diagram marked (X), with one or more dots placed in it. Thediagram is followed by four other figures, marked (A), (B), (C) and (D) only one of which is such as to makepossible the placement of the alternative in each case.

funsZ'k (48) : fuEufyf[kr iz'u esa] ,d vkd fr (X) nh xbZ gS ftlls ,d ;k vf/kd fcUnq yxs gq, gSA ;g vkd fr vU; pkj vkd fr;ksad k vuqlj.k djrh gS ftudks fd (A), (B), (C) rFkk (D) esa fpfUgr fd;k x;k gSA buesa ls flQZ ,d vkd fr esa bu fcUnqvksa dslgh fpfUgr dh lEHkkouk gSA ml fodYi dks pqfu;s ?

48.

(X)

(A) (B) (C) (D)

Directions : (49) Figures 1 and 2 are related in a particular manner. Establish the same relationship between figures 3 and4 by choosing a figure from amongst the four alternatives, which would replace the question mark in figure (4).

funsZ'k : (49) iz'u vkd fr d s izFke Hkkx esa fn;s x;s nwljs fp=k dk ftl izdkj igys fp=k ls lEcU/k gS ogh lEcU/k nwljs Hkkx ds rhljsfp=k d k mÙkj vkd fr esa fn;s x;s pkj fodYiksa esa ls fdlls lEcU/k gksxkA

49. Problem Figures ¼iz'u vkÑfr½

........... ......... ....... ............ ............ .......... ........ .. .......

.

.

.... ?........... ......... ........ ............ .

.... ....

.......... .......... .. ...

...: :: :

Answer Figures ¼mÙkj vkÑfr½

..

......

....

......... . ..... ......... ...

. ...

.. ... .

....

..

.... . ..... ..... .... ........

............ .. ...

.. ......... .

.....

...

....

........ . ..... ..

....... ...

(A) (B) (C) (D)

Directions : (50) Out of the four figures (A), (B), (C) and (D), given in each problem, three are similar in a certain way.However, one figure is not like the other four. Choose the figure which is different from the rest.

funsZ'k : (50) uhps fn;s x;s 4 fp=kksa (A), (B), (C) rFkk (D) esa rhu fd lh rjhd s ls leku gS vkSj ,d mu rhuksa ls vyx gS vFkkZr~lewg esa ls rhu fp=k leku izÑfr ij vk/kkfjr gS ml fp=k d ks crkb, ft ld h izd fr ckfd rhuksa ls vyx gSaA

50.

(A) (B) (C) (D)

ANSWER KEY

CLASS : XI | STREAM : SCIENCE-BIOLOGY1. (C) 2. (C) 3. (A) 4. (B) 5. (C)6. (A) 7. (B) 8. (C) 9. (C) 10. (D)11. (C) 12. (A) 13. (A) 14. (A) 15. (A)

16. (B) 17. (A) 18. (D) 19. (B) 20. (C)21. (A) 22. (D) 23. (D) 24. (C) 25. (A)

26. (A) 27. (B) 28. (C) 29. (C) 30. (B)31. (C) 32. (D) 33. (C) 34. (C) 35. (C)36. (B) 37. (C) 38. (D) 39. (B) 40. (D)

41. (A) 42. (A) 43. (C) 44. (C) 45. (C)46. (B) 47. (D) 48. (A) 49. (B) 50. (B)

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