Sample Question Paper Asstt Manager S&T E02

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APTITUDE 1. Who became the first Indian to win three medals in successive ISSF shooting world cup held recently? (1) Abhinav Bindra (2) Gagan Narang (3) Jitu Rai (4) Vijay Kumar 1. vHkh gky gh esa vk;ksftr ISSF “kwfVax fo”o di esa yxkrkj rhu esMy thrus okyk igyk Hkkjrh; f[kykM+h dkSu cuk\ (1) vfHkuo fcUæk (2) xxu ukjax (3) ftrw jkW; (4) fot; dqekj 2. Recently, the plan to build the world most powerful and largest telescope ‘ATLAST’ to analyse the environment of other planets and to track the existence of aliens life, was unveiled. This is planned by: (1) FKA & RKA (2) ESA (3) ISRO (4) NASA 2. vHkh gky gh esa fo”o dk lokZf/kd “kfä”kkyh ,oa lcls cM+k VsyhLdksi ^ATLAST* ds fuekZ.k djus dh ;kstuk] ftlds }kjk nwljs xzgksa ds okrkoj.k ,oa nwljs xzgksa ds çk.kh dh thou dh fo|ekurk [kkstus ,oa fo”ys’k.k djuk gS] dk vukoj.k fd;k x;kA ;g fdldh ;kstuk gS% (1) FKA & RKA (2) ESA (3) ISRO (4) NASA 3. Who bagged the FIDE World Rapid Chess Championship title recently held in Dubai? (1) Fabiani Caruana (2) Vishwanathan Anand (3) Magnus Carlsen (4) Vladimir Kramnik 3. vHkh gky gh esa fdlus nqcbZ esa vk;ksftr FIDE fo”o jSfiM “krjat pSfEi;uf”ki dh mikf/k thrh\ (1) QSch;kuh d:vkuk (2) fo”oukFku vkuUn (3) eSXul dkyZlu (4) Oyknehj Økefud 4. Who won the world food prize for the year 2014? (1) Dr. Sanjaya Rajaram (2) Dr. Aditi Mukherji (3) Dr. Charity Kawira Mutegi (4) Dr. Norman Borlaug 4. o’kZ 2014 ds fy, fo”o [kk| iqjLdkj fdlus thrk\ (1) MkW- lat;k jktkjke (2) MkW- vfnrh eq[ktÊ (3) MkW- pSfjVh dohjk eqVsxh (4) MkW- ukjeSu oksjykWx 5. India’s first ‘one stop crisis centre’ for women who are victims of violence named ‘Gauravi’ was launched recently by ......... in ........? (1) Film Actor Amir Khan, Bhopal (2) Film Actor Shahrukh Khan, Mumbai (3) Film Actor Amitabh Bachhan, Allhabad (4) Film Actress Hema Malini, Agra 5. efgyk,a tks fgalk dh f”kdkj gSa] muds fy, Hkkjr dk igyk ^ou LVkWi ØkbZfll lsUVj* ftldk uke ^xkSjoh* gS] dks vHkh gky gh esa --------- }kjk --------- esa “kqHkkjEHk fd;k x;k% (1) fQYe vfHkusrk vkfej [kku] Hkksiky (2) fQYe vfHkusrk “kkg:[k [kku] eqEcbZ (3) fQYe vfHkusrk vferkHk cPpu] bykgkckn (4) fQYe vfHkus=h gsek ekfyuh] vkxjk 6. The world first electric plane named E-Fan first flight was carried successfully recently in: (1) U.S.A. (2) U.K. (3) Germany (4) France 6. fo”o dk igyk fo|qr gokbZ tgkt ftldk uke ^E-Fan* gS] dh igyh mM+ku vHkh gky gh esa lQyrk iwoZd dgk¡ lapkfyr gqbZ% (1) ;w-,l-,- (2) ;w-ds- (3) teZuh (4) Ýk¡l 7. Which one of the following plants yield bio diesel or bio fuels? (1) Hevea brasiliensis (2) Jatropha Curcas (3) Juniperus Verginiana (4) Parthenium orgenatum 7. fuEufyf[kr esa ls dkSu&lk ikS/kk ck;ksMht+y ;k ck;ks b±/ku iSnk djrk gS% (1) ghoh;k czSUlhfyUlhl (2) tSVªksQk dSjdsl (3) twuhisjl otÊfu;kuk (4) ikFksZfu;e vtsZukVe 8. The Argumentative Indian’ is a book written by (1) Amartya Sen (2) Chetan Bhagat (3) Vikram Seth (4) Arundhati Roy 8. ^n vkWX;wZesaVsfVo bafM;u* iqLrd fdlds }kjk fy[kh xbZ gS\ (1) veR;Z lsu (2) psru Hkxr (3) foØe lsB (4) v#a/kfr jkW; 9. Nanda Devi Biosphere Reserve is located in which Indian state? (1) Arunachal Pradesh (2) Assam (3) Manipur (4) Uttarakhand 9. uUnk nsoh tho&eaMy fjtoZ Hkkjr ds fdl jkT; esa fLFkr gS% (1) v:.kkpy çns”k (2) vle (3) ef.kiqj (4) mÙkjk[k.M 10. Who has recently won 2014 Pultizer prize in the poetry category: (1) Gobind Beharilal (2) Jhumpa Lahiri (3) Vijay Seshadri (4) Siddharath Mukherjee 10. vHkh gky gh esa dfork Js.kh esa 2014 iqfyRt+j iqjLdkj fdlus thrk% (1) xksfcUn fcgkjhyky (2) >qEik ygjh (3) fot; “ks’kkfæ (4) fl)kFkZ eq[ktÊ 11. Clean water would have BOD value of less than: (1) 5 ppm (2) 19 ppm (3) 25 ppm (4) 50 ppm 11. LoPN ty esa BOD eku fdlls de gksxk% (1) 5 ppm (2) 19 ppm (3) 25 ppm (4) 50 ppm [Legal Asstt. ] [A–1]

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Question Paper Asstt Manager S&T E02

Transcript of Sample Question Paper Asstt Manager S&T E02

APTITUDE1.WhobecamethefirstIndiantowinthreemedalsin successive ISSF shooting world cup held recently? (1)Abhinav Bindra(2)Gagan Narang (3)J itu Rai(4)Vijay Kumar 1... r.a r. + ..=+ ISSF .: ++ =| + a.+. +.= +:a =.+= +.a. |ra. ..+. c.a.:. =.= +=. (1).=+ +-a.(2)= =. (3)=+ .(4)+= =+. 2.Recently, the plan to build the world most powerful and largesttelescopeATLASTtoanalysetheenvironment of other planets and to track the existence of aliens life, was unveiled. This is planned by: (1)FKA & RKA(2)ESA (3)ISRO(4)NASA 2... r.a r. + ++ =. =+..= .+..a. |+ =+= +:. :a.-=.| ATLAST==+..===..==.,===o..=r.= +.+.+. |+ = r. = a... =. =.+= =. ++.=+. c..== |+ +a.. ==. r, =. =.+. =. .i r ===. .==. r (1)FKA & RKA(2)ESA (3)ISRO(4)NASA 3.Who bagged the FIDE World Rapid Chess Championship title recently held in Dubai? (1)Fabiani Caruana(2)Vishwanathan Anand (3)Magnus Carlsen(4)Vladimir Kramnik 3... r.a r. + === +; + ..=+ FIDE ++ |: .+= |=.| =. !|.. =.+. (1)=+..=. ==.=.(2)++=..= .=- (3)+== =.a==(4)a.+. =.+== 4.Who won the world food prize for the year 2014? (1)Dr. Sanjaya Rajaram(2)Dr. Aditi Mukherji (3)Dr. Charity Kawira Mutegi(4)Dr. Norman Borlaug 4.+. 2014 = a| ++ c.. |-=. === =.+. (1):.. ==. .=..+(2):.. +. +c.=' (3):.. :. =+.. +:.(4):.. =.+= +.a. 5.Indiasfirstonestopcrisiscentreforwomenwhoare victimsofviolencenamedGauraviwaslaunched recently by ......... in ........? (1)Film Actor Amir Khan, Bhopal (2)Film Actor Shahrukh Khan, Mumbai (3)Film Actor Amitabh Bachhan, Allhabad (4)Film Actress Hema Malini, Agra 5.+ra.| =. r=. =. .=. r, !== a| ..+ =. |ra. += -:.| =.;== =-: ===. =.+ .+. r, =. .. r.a r. + ......... o.. ......... + .... =. . (1)=-+ .=+. .+ c..=, ..|.a (2)=-+ .=+. ..r=c. c..=, ++; (3)=-+ .=+. ++.. +=, ;a.r.+.(4)=-+ .=+. r+. +.a=., .. 6.TheworldfirstelectricplanenamedE-Fanfirstflight was carried successfully recently in: (1)U.S.A.(2)U.K. (3)Germany(4)France 6.++ =. |ra. ++ r+.; =r.= ===. =.+ E-Fan r, =. |ra. !:.= .. r.a r. + ==a+. |+= =r. =.a+ r; (1).|=.|.(2).=. (3)=+=.(4)=.= 7.Which one of the following plants yield bio diesel or bio fuels? (1)Hevea brasiliensis(2)J atropha Curcas (3)J uniperus Verginiana(4)Parthenium orgenatum 7.==ac.+ + = =.=-=. |... +..:.=a . +.. ;.= |. =+. r (1)r.+.. +-=.a-=.=(2)=:.=. === (3)==.|= +='=.=.(4)|..=+ ==.:+ 8.The Argumentative Indian is a book written by (1)Amartya Sen(2)Chetan Bhagat (3)Vikram Seth(4)Arundhati Roy 8. .+::+ ;:= |-+= === o.. ac.. ; r (1)+ ==(2)+= .+ (3)+=+ =(4)=.+ . 9.NandaDeviBiosphereReserveislocatedinwhich Indian state? (1)Arunachal Pradesh(2)Assam (3)Manipur(4)Uttarakhand 9.=-. +. =.+-+:a =+ ..+ = == .- + -.+ r (1)=..a a.(2)=+ (3)+.|(4)!-..c.: 10.Whohasrecentlywon2014Pultizerprizeinthepoetry category: (1)Gobind Beharilal (2)J humpa Lahiri (3)Vijay Seshadri (4)Siddharath Mukherjee 10... r.a r. + =++. =.. + 2014 |a= |-=. === =.+. (1).+- +r..a.a (2)n|. ar. (3)+= ...a (4)=o.. +c.=' 11.Clean water would have BOD value of less than: (1)5 ppm(2)19 ppm (3)25 ppm(4)50 ppm 11.-+= =a + BOD +.= === =+ r.. (1)5 ppm(2)19 ppm (3)25 ppm(4)50 ppm [L e g a l A s s t t . ] [A1] 12.IdentifytheShakespeareanplayinwhichwehavea death by poisoning: (1)As You Like It(2)Hamlet (3)The Merchant of Venice(4)None of these 12..+=|. = != =.:= =. |r.= ==+ =r = = = =.. + r; .. (1)|= a.;= ;:(2)r+a: (3) +-: .= +==(4);=+ = =.; =r. 13.Whowillhaveitsleader elected as leader of opposition andgiventhestatus&facilitiestotherankofcabinet ministers? (1)The opposition party with the largest number of MPs (2)TheoppositionpartywiththelargestnumberofMPsand whose number is at least 1/10 of the total house (3)TheoppositionpartywiththelargestnumberofMPsand whose number is at least 1/5 of the total house (4)None of the above is correct 13.==ac.+ + = == +|. =. =+. =. =.|. |+ != =+=: ++. =. =. |+ =+..| a.= =. =.. (1)+|.. a ==+ =+= -.. =c. + =.= r (2)+|.. a ==+ =+= -.. =c. + =.= r |+ ===. =c. == = =a =c. =. =+ = =+ 1/10 r (3)+|.. a ==+ =+= -.. =c. + =.= r |+ ===. =c. == = =a =c. =. =+ = =+ 1/5 r (4)!|+ + =.; .. =r. =r. r 14.Which one of the following is most likely to occur if the Reserve bank of India lowers the Cash Reserve Ratio? (1)An Increase in aggregate savings (2)A rise in Budget Deficit (3)A rise in aggregate money supply (4)A rise in the use of credit cards 14...+.=++====+=|.+=.=+=+.r+. ==ac.+ + = === .:+ r.= =. =..+=. r (1)=a ++ + +o (2)+=: ..: + +.-.. (3)=a +.a= .|+ + +.-.. (4)=:: =.: = a. + +.-.. 15.TheReportsofthecomptrollerandauditorGeneralof IndiarelatingtotheaccountsoftheUnionshallbe submitted to: (1)The President of India(2)The Prime minister of India (3)The Speaker of the Lok Sabha (4)The Finance Minister of India 15.=. = ac... = =+-. + ..+ = =+= . +r.ac.. |..= =. |.: == =. a-++ =. =.|. (1)..+ = .:|+ (2)..+ = a..=++. (3)a.==.. = . (4)..+ = +-.-++. 16.OnestarisgoingawayfromtheEarth.Thenthe observer on the Earth will experience: (1)Decrease in wave length (2)Increase in wave length (3)No change in wave length (4)None of these 16.=.; +.. |+. = =. r. r |+. | +. =..= +. = a.-+ a=.-. = =+. + +. =.+ =. (1)+ + =+. (2)+ + +o (3)+ + =.; |++= =r. (4);=+ = =.; =r. 17.WhoamongtheBritishGeneralsdefeatedPeshwaBaji Rao II: (1)Autram(2)Malcom (3)Elphinstone(4)Kitchner 17.== +:. ==a = |.+. +.=..+ o+. =. |.-+ =. .. (1).:+(2)+a=+ (3)|a==-:.=(4)== 18.Which one is not written by Munshi Prem Chand: (1)Rangbhoomi(2)Prem Pachisi (3)Vishkanya(4)Kayakalp 18.==ac.+ + = =.= +.. a+- o.. + =r. r (1).+(2)a+ |.=. (3)+.=-.(4)=..=-| 19.A B is a tangent to the circle. The radius of the circle is 2 cm. Then the area of the shaded portion is: (1) 2 2(2)2 2 (3) 2 4(4)None of these 19.+-.||=-|.c..ABri+-.=.+-.2=+..ri+. =..=+ .. =. .+=a r.. (1) 2 2(2)2 2 (3) 2 4(4);=+ = =.; =r. [L e g a l A s s t t . ] [A2] 20.Two cylinders have the same volume. The heights are in the ratio of 1 : 2, then the ratio of the radii will be: (1)2 : 1(2)1 : 2 (3)1 :2 (4)2: 1 20.. =a-:. =. .+= =+.= ri !== =.; =. =|.+ 1:2 r +. !== +-.. =. =|.+ r.. (1)2 : 1(2)1 : 2 (3)1 :2 (4)2: 1 21.If the ath part of 49 is 7 and bth part of 63 is 9 and cth part of 112 is 16. Then which of the following is true: (1)abc =71(2)abc =a3(3)abc =491(4)None of these 21. 49 =. a+. r-=. 7 r, 63 =. b+. r-=. 9 r +.. 112 =. c+. r-=. 16 r+.== + ==. = =. = r(1)abc =71(2)abc =a3(3)abc =491(4);=+ = =.; =r. 22.Fivepersonsarestandinginaqueue.Oneofthetwo persons at the extreme end is a professor and the other is abusinessman.Anadvocateisstandingtotherightof thestudent.Anauthoristotheleftofthebusinessman. Thestudentisstandingbetweentheprofessorandthe advocate.Countingfromthelefttheauthorisatwhich place: (1)1st (2)2nd

(3)3rd (4)4th22.|. + |= =+. + c.: ri . +. + |= -++ =. | |= + |= a.== +.. =. |= +=.. ri +... = .r= |= |:+.=: c.:. ri +=.. = +.| |= ac.= ri +... a.== |+ |:+.=: = + + c.:. ri +.| = =+ r| ac.= == -..= | r (1)a.+(2)o+. (3)++. (4)+. 23.PisstandingtotheeastofQatadistanceof4Km.P standsstillwhileQgoesnorthfor4Km.Inwhich direction must Q now look to see P: (1)East (2)South East (3)South (4)South West 23.Q = |+ + P4 =.+.. =. . | c.:. ri P +r. c.:. r =+= Q 4 =.+.. !-. =. . a+. ri P =. c.= = a| Q =. == .. =. . c.=. .r| (1)|+ (2).. |+ (3).. (4).. |+ 24.If AM=3, ARE=4, and NEVER=8, then INDIA IS A GREAT NATION=: (1)32(2)29 (3)28(4)None of these 24. AM=3, ARE=4, |+ NEVER=8, +. INDIA IS A GREAT NATION= (1)32(2)29 (3)28(4);=+ = =.; =r. DIRECTIONS: Complete the following series. 25.A Z B Z _ A B A _ A _ B _ B A (1)A Z B Z(2)B Z A Z (3)B Z Z Z(4)Z A Z Z =. ==ac.+ =c.a. =. |. =i 25.A Z B Z _ A B A _ A _ B _ B A (1)A Z B Z(2)B Z A Z (3)B Z Z Z(4)Z A Z Z 26.If one side and one diagonal of a rhombus are 5 cm and 8 cm respectively, then its area (in cm2) is: (1)22(2)20 (3)24 (4)25 26. +.= =. |= .=. |+ |= +=. =+. 5 |+ 8 =+.. r, +. !==. .+=a (=+..2 +, r (1)22(2)20 (3)24 (4)25 27.Oneacuteangleofarightangledtriangleis double the other.Ifthelengthofitshypotenuseis10cm,thenits area is: (1) 275cm2 (2)25 cm2(3)3225cm2 (4)None of these27.|= =+=.. +.= =. -==.. = =. =. ri ;== +=. =. a+.; 10 =+.. r +. ;==. .+=a r.. (1) 275cm2 (2)25 cm2(3)3225cm2 (4);=+ = =.; =r. 28.The average age of the boys in a class of 30 boys is 14.5 years. What will be the average age if 10 new boys come whose average is 15.2 years, and joins them? (1)15.5 years(2)14.68 years(3)16.25 years(4)None of these 28.30 a:=. =. |= =.. + .=+ . 14.5 +. ri .=+ . +. r.. 10 = a:= . .+ |+ ..+a r.+ r ===. .=+ . 15.2 +. r.+. r (1)15.5 +.(2)14.68 +. (3)16.25 +.(4);=+ = =.; =r. [L e g a l A s s t t . ] [A3] 29.InacertaincodelanguagePROPORTIONiswrittenas PORPRONOIT.HowisCONVERSIONwritteninthat code language? (1)VNOCERONIS (2)VNCORENOIS (3)VNOCRENOIS (4)VNOCREIONS 29.|==+=.:PROPORTION=.PORPRONOITac.. =.+. r +. !=. =.: .... + CONVERSION =. == ac. (1)VNOCERONIS (2)VNCORENOIS (3)VNOCRENOIS (4)VNOCREIONS 30.Threemenoreightboyscandoapieceofworkin17 days.Howmanydayswilltwomenandsixboys together take to finish the same work? (1)11 days (2)17 days (3)12 days (4)None of these 30.+.= + . . a:= ==. =. =. 17 = + = ==+ ri . + |+ = a:= |= =.. !=. =. =. |. == + =+=. = a (1)11 = (2)17 = (3)12 = (4);=+ = =.; =r. 31.Twelvesolidspheresofthesamesizearemadeby meltingasolidmetalliccylinderofbasediameter2cm and height 16 cm. The diameter of each sphere is: (1)2 cm(2)3 cm (3)4 cm(4)6 cm 31.|= .= ..+= =a:, ===. ... .= 2 =+.. |+ =.; 16 =+.. r, =. a.= |= r. .=. = 12 .= .a +=.| =.+ ri a= .a =. .= r.. (1)2 =+..(2)3 =+.. (3)4 =+..(4)6 =+.. 32.Therearesomegirlsandbuffalosataplace.Iftotal numberofheadsis15andtotalnumberoflegsis46, then how many girls and how many buffalos are there? (1)8 girls and 7 buffalos (2)9 girls and 6 buffalos (3)7 girls and 8 buffalos (4)6 girls and 9 buffalos 32.|= -..= | = = a: =. |+. = ri =. =. = a = c. 15 |+| . =. = a = c. 46 r.+.=+=. a: =. |+=+=. .= r (1)8 a:=. |+ 7 .= (2)9 a:=. |+ 6 .= (3)7 a:=. |+ 8 .= (4)6 a:=. |+ 9 .= 33.Given two positions of the dice as being. When 2 is at the bottom which number is at the top: (1)5(2)4 (3)1(4)6 33.|.= =. . -.+. ;= a=. . ; ri =+ 2 +a + r.. +. =.=-=. =c. ... | r.. (1)5(2)4 (3)1(4)6 34.Simplify: 265270 297238 (1)1(2)0 (3)1(4)None of these 34.=a = 265270 297238 (1)1(2)0 (3)1(4);=+ = =.; =r. 35.The average of 5 consecutive numbers A, B, C, D and E is 48. What is the product of A and D? (1)2300 (2)2204 (3)2208 (4)2254 35.5 =+= =c.. A, B, C, D |+ E =. .=+ 48 ri A |+ D =. .==a +. r.. (1)2300 (2)2204 (3)2208 (4)2254 36.Among five friendsBrijesh, Feroz, Jai, Kamal and Vinod eachhavingadifferentweight.Ferozisheavierthan only Jai. Brijesh is heavier than Feroj and Vinod but not asheavyasKamal.Whoisthethirdheaviestamong them? (1)Kamal (2)Brijesh (3)Vinod (4)Data inadequate 36.|. ++. + = - +=., =.=, =, =+a |+ +=. + a= =. .. .x ri =.= =+a = = ... ri +=. =.= |+ +=.= ... r a== =+a = ... =r. ri !=+ +.=. =+= ... =.= r(1)=+a (2)+=. (3)+=. (4)|.-+ .=: [L e g a l A s s t t . ] [A4] 37.Select the suitable alternative to complete the series. 2401, 49, 7; __ , 36, 6: (1)1296(2)216 (3)7776(4)1378 37.==ac.+ a= + != +=-| =. = =. =.. =. |. =+. ri 2401, 49, 7; __ , 36, 6: (1)1296(2)216 (3)7776(4)1378 38.IfinacertaincodelanguageBALEiswrittenas + & and SKIP is written as @ %. How is LIFE written in that code? (1)@ + (2) % T & (3) & % $(4)@ & + 38.==. =+ =.: .... +BALE =. + & |+ SKIP =. @ % ac.. =.+. ri LIFE =.!=. =. : + == ac. (1)@ + (2) % T & (3) & % $(4)@ & + DIRECTIONS:(QuestionNo.39&40)Inacertaincode language i.Cod dex nom stands for banana is sweet ii.Zip dex nux stands for apple is good iii.Cod nux elp stands for banana and apple andiv.pa reb nom stands for oranges are sweet. 39.Which word in that language stands for apple. (1)Elp(2)Nux (3)Zip(4)None of these =. (a= =c. 39 |+ 40, |= =+ =.: .... +- i.Cod dex nom =. +.| r banana is sweet ii.Zip dex nux =. +.| r apple is good iii.Cod nux elp =. +.| r banana and apple |+ iv.pa reb nom =. +.| r oranges are sweet 39.!= .... + =.=-=. . apple = a a+ =. . r (1)Elp(2)Nux (3)Zip(4);=+ = =.; =r. 40.What does Zip stand for? (1)Apple (2)And (3)Good (4)None of these 40.Zip === a a+ =. . r (1)Apple (2)And (3)Good (4);=+ = =.; =r. 41.Youhavecomeacrossacasewhereinyourretired colleagueisunabletosubmithislifecertificateand claim pension to meet his treatment expenses. You will (1)Go strictly as per the procedures (2)Takeinitiativetohelphimandaskforarrangingfor alternative documents (3)Assist colleague with some money on your own but do not compromise on procedures. (4)Avoid some procedural steps since you understand the necessity of the colleague 41..|= =.+= |= |=. +.+a. |. r. r ==+ .|=. |= =+.=++ =r=+. |=. =.+= |+..-|+ |-++ == . |= ;a.= = c. = a| |.= =. .+. == + =+. ri .| (1)|=+ =.+.. = ==. =.+.r. = (2)!==. + == +.. +=-|= =.=.+ +. == =. +-.. == = a| != =r= =. .. + |ra = (3)=r=+. = a| -+ == |= =. =r.+. = a== =.+.. = =.. =+n.+. =r. = (4)=+| =.+.= =.+.;. =. :.a +.= .| =r=+. =. ==+ =. =+n+ ri 42.Youalongwithyourbrothersfamilyhaveplannedfora vacation tour to a place where you are likely to meet your familymembersandyourailingmother.Youhavegot permittedleavefromtheofficeforthistrip.Whileatthe time of going to station for the trip, you receive a message fromyouroneofthesubordinatestaffthatManaging Directorofthecompanyneedsyouinthemeetingwitha foreign customer who landed without program: (1)Youwillignorethemessageofyoursubordinateand ask him to tell a lie that you were in train . (2)You will speak to your immediate boss and tell him that your mother is ailing and you are with your family, hence can not come (3)You will explain the situation to your brothers family and getyourticketcancelledandshallgototheoffice, attend the meeting (4)You will speak to your immediate boss and say that you have advance permitted leave and it is urgent to see the ailing mother, hence can not come immediately 42..|=|=..;=|+.==..|=|=-..==a| +=..-. =. .==. +=.; r =r. .|= |= |+. = =-. +..+.+.+.+.=+a==.=..+=.ri.|=.;=.=a| =..a==::.+==.;ri.=a|-:.==.+=+ .|=. |= ..=-. -:.= = ;= .. =. =. |.-+ r.+. r = =|=. = |+. =.= =. |= +.. .r= = =.. += = ..=, =. ==. =.=+ = +=. |.. . r, .|=. ==+ r (1).| |= ..=-. = =. =. =c.. = . != =r = +r n +.a = .| a.:. + + = r (2).||=.=-=.=..=+.+ = . != ++.| = .|=.+.+.+.+.r..||=|+.==..r.== =.. =r. . ==+ (3).| |= ..; = |+. =. -.+ -|: = . |=. :=: =.|, =..a =.|, += + .. a (4).| |= .=-= .=.. = +.+ = . ++.| = .|= + -+.=+ =::. a. r +.. +.+. +.+. =. c.=. ==. r, ;=a| +=.a =r. . ==+i [L e g a l A s s t t . ] [A5] 43.YouareworkingasastorespurchaseofficerofIndian railways.Thereisasuddendemandofsomesafety itemsduetoemergency.Youhavefloatedalimited tender with a short notice. After opening the tender, you sensethatthereisacartelamongthebiddersdueto emergentsituationandallofthemhavequotednearly five time more than the last purchase price. You will (1)Awardtheordertothelowestbidderasthisisan emergent situation (2)Immediatelyreportthemattertothehigherauthorities explaining the factual situation and wait for their further orders. (3)Negotiatewithanybidderandbringdowntheratesas low as possible and award it to that bidder (4)Submit your report to your bosses and request them to float open tender instead of limited tender 43..| ..+. a + |= .:. c.. .=.. = =| + =.+ = r ri .|.+=.a = =.. == =.. +. =. .=+= +. |. r. ; ri .|= -| ==. =r+ |= =.++ :: =.. = . ri :: c..a=|.|=.|=.a+.r=.|.+=-.+==.. +.a..+.. = +. |= =. += . r . =.. = |=a =+- = a. |. =. = .= ..+ +. ri .| (1)-=++ +.a..+. =. .: +.= r |= .|.+= -.+ r (2)+.-++=-.+-|:=+r|+=.a+.+a=+.+ !..=.. =. =+ = . !== a ... =. |+... = (3)==. +.a..+. = =.. =.+.=. = . != ..=.+ -=++ ..+. = a| .=. = . != +.a..+. =. .: (4)|=!..=..=.|=.|.:|-++=.!== =.++ :: =. =r +++ :: =.. == =. =.. =i 44.You come to know of some clandestine bogus and fake purchaseactivitiesgoingonintheoffice.Theculprits areyourcolleaguesandtheyensurethatnoovertor directsignsofsuchactivitiesarevisible.Fromamong the following alternatives, which one you will choose: (1)Leave things as they are (2)Organize an immediate raid on the suspected (3)Ask the colleagues to immediately stop it (4)Begin collecting evidence and after collecting evidence bring the matter to the higher authorities submitting evidences 44..|=.=.==..+r.+.r=+++==-++.=. =.a. c.. =.=a.| a r ri ... ++ .|= =r=+. r . + r ==+ =+ r = ;= +r = =.=a.|. =. =.; +.r. .+.|.==+=c..;i=.||+=-|.+=.| =.==. +=-| = (1)== +r = r.a.+ r, !-r += r. =.: (2)=. ++. | +=.a =.|. +.= =. ..== = (3)=r=+. = +=.a |=. + == =. =r (4)=. ;=:. ==. .= = . =. ;=:. == =+. =. |-++ =+ r| +.+a=. !+ .=..= =+. | -++ =i 45.Youarethesanctioningauthorityforthetravellingand conveyance bills of your department. You find that there is a dedicated staff who stays long hours in the office to disposeoffhisdaytodaybacklogwork.Youfindhim submittinghugeconveyanceclaimsforlatehoursto youwhichotherwiseisnotpermissiblewithoutpre approvalofstaybyhigherauthoritiesasperCompany policy. What would you do under such a situation: (1)You will pass his claims considering his dedication and sincerity. (2)You will strictly go by rules and do not pass his claims. (3)You will ask him and say that he should take back the conveyance bills submitted and submit a fresh bill of the same amount for normal working hours (4)Youwillcallhimandaskhimtofinishtheworkwithin office time and if there is extra work load , you will ask him to get a preapproval of stay for processing of such bills and ask him to withdraw the bills submitted 45..| |= +.. = .+. . =+.. +a. = a| +=. .=.. ri .| c.+ r = |= |=. =+|+ -:.= r =. |= = = |=a +=.. =.+ =. =|:.= = a| =..a + .+ += ==+. ri .| c.+ r = !== .|= =+. .+ = a| +:-+: =+.. +a |-++ =| r =.= =|=. =. =.+ = ==. !+ .=.. o.. =..a + r= =. |+ =++ = +=. =+ =r. ri |=. -.+ + .| +. = (1).| !== =+|. . ==|:+. =. c.+ r| !== .+ += = (2).| =+.=. =:.; = |.a= = . !== .+ += =r. = (3).| != =r = +r |. =| | +a +.|= a a . =|=. =. =.+ = ==. !=. .. =. =.+.- =. .: = =+ =. |= =. +a +=.|(4).| != +a.| . =r = =..a =. =.+ =..a =+ =..+|.=.=.+=.+++..r+.|= +a. | =.+.r. = a| r= = +.-+ |+ =++ |.-+ = +.. =+. =.| | +a +.|= a ai [L e g a l A s s t t . ] [A6] 46.The equivalent resistance of the circuit is: (1)200 (2)400 (3)600 (4)1600 46.||. =. =+=. a+.. r (1)200 (2)400 (3)600 (4)1600 47.Decimal43inHexadecimalandBCDnumbersystem, respectively is: (1)B2, 0100 0011 (2)2B, 0100 0011 (3)2B, 0011 0100 (4)B2, 0100 0100 47.r+=.:=.+a+..+.=.:.=c.|..a.+:=.+a43=+. ==.==. r (1)B2, 0100 0011 (2)2B, 0100 0011 (3)2B, 0011 0100 (4)B2, 0100 0100 48.A bus connected between the CPU and main memory thatpermitstransferofinformationbetweenmain memory and the CPU is known as: (1)Memory bus (2)DMA bus (3)Address bus (4)Control bus 48.=.|. +.. += ++.. = +. =.=+ +=, =. += ++.. . =.|. = +. =.==.. = +. =. =++ +. r, =ra.+. r (1)++.. += (2):.|+| += (3)|:= += (4)=:.a += 49.TheLaplacetransformofi(t)isgivenbyI(s)= 2/(s(1+s)). As t , the value of i(t) tends to: (1)0 (2)1 (3)2 (4) 49.i(t) =. a-a= =|.+. I(s) = 2/(s(1+s)) = |.-+ r.+. ri +.= t r +. i(t) =. +.= r (1)0 (2)1 (3)2 (4) 50.Whatisthetimetakenbybinarysearchalgorithmto search a key in a sorted array to n elements?: (1)O (log2n) (2)O (n) (3)O (n log2n) (4)O (n2) 50.o.... -+.. |a.+ o.. n |a.+:= = |+ =.:: =.. + |= ==. = + =+=. =+ a+. r (1)O (log2n) (2)O (n) (3)O (n log2n) (4)O (n2) 51.Ntype silicon is obtained by doping silicon with: (1)Germanium (2)Aluminum (3)Boron (4)Phosphorus 51.=a=.= =. == = =.. :.| o.. N-:.;| =a=.= |.. =.+. r (1)=+=+ (2)|-+.=+ (3)+.= (4)=.-=.= 52.Voltageseriesfeedback(alsocalledseries-shunt feedback) results in: (1)increase in both the input and output impedances. (2)decrease in both the input and output impedances. (3)increaseintheinputimpedanceanddecreaseinthe output impedance. (4)decreaseintheinputimpedanceandincreaseinthe output impedance. 52.+.-:+.=..=.:+=(===..-.:=.:+=..=r+r,=. |..+ r.+. r (1);-|: +.. .!:|: .=. |++.... + +o (2);-|: +.. .!:|: .=. |++.... + .+: (3);-|: |++... + +o +.. .!:|: |++... + .+: (4);-|: |++... + .+: +.. .!:|: |++... + +o [S i g n a l & T e l . ] [A7] 53.In a uniformly doped BJT, assume that NE, NB and NC aretheemitter,baseandcollectordopingsin atoms/cm3,respectively.Iftheemitterinjection efficiencyoftheBJTiscloseunity,whichoneofthe following conditions is TRUE?: (1)NE= NB = NC(2)NE >> NB and NB>>NC(3)NE = NB and NB < NC(4)NE < NB < NC53.|==+.==|=+.+BJT++.=a.=|=|+...cm3 + NE,NB+..NC =+.|+.:,+=+..=.r.+.=ri BJT=. |+.: ;=+.= |..++. ==: =:. r +. == + = =.==. -.+ = r (1)NE= NB = NC(2)NE >> NB and NB>>NC(3)NE = NB and NB < NC(4)NE < NB < NC54.Ifforasiliconn-p-ntransistor,thebaseto-emitter voltage (VBE) is 0.7V and the collector-to-voltage (VCB) is 0.2V, then the transistor is operating in the.: (1)normal active mode. (2)saturation mode. (3)inverse active mode. (4)cut-off mode. 54. =a=.= n-p-n :.=-: = a| +=-:-|+.: +.-:+. (VBE) 0.7Vr +.. =.r.-=-+.-:+. (VCB)0.2V r +. :.=-: == | a r. r (1)=.+.- == +. (2)=+-+ +. (3)|+a.+ == +. (4)+=. +. 55.ACEamplifierwitharesistorconnectedbetween collector and base forms a case of negative feedback amplifier using: (1)Voltage series feedback (2)Current series feedback (3)Current shunt feedback (4)Voltage shunt feedback 55.=.r..+==+.=.=+|+..==++|=CE |-a.=.=..+==.:+==.-.+|.=+.r==+ |-a.=. == =. |. = r. r.+. r (1)+.-:+. =.. =.:+= (2)... =.. =.:+= (3)... .: =.:+= (4)+.-:+. .: =.:+= 56.Choosethecorrectmatchforinputresistanceof various amplifier configurations shown below.: ConfigurationInput resistance CB :Common BaseLO :Low CC :Common CollectorMO :Moderate CE :Common EmitterHI :High (1)CB LO, CC MO, CE HI (2)CB LO, CC HI, CE MO (3)CB MO, CC HI, CE LO (4)CB HI, CC LO, CE MO 56.=. ..| | +.-= |-a.=. +-.=. = ;-|: |+.. = a| =r. +a =. = = +-.=;-|: |+.. CB =.+.- ...LO -= CC =.+.- =.r.MO +.:: CE =.+.- |+.:HI ! (1)CB LO, CC MO, CE HI (2)CB LO, CC HI, CE MO (3)CB MO, CC HI, CE LO (4)CB HI, CC LO, CE MO 57.The circuit shown in the figure is best described as a: (1)Bridge rectifier (2)Ring modulator (3)Frequency discriminatory (4)Voltage doubler 57.=. ... . ||. =+.++ =| = == =ra.+. r (1)=+ :=.. (2)=+ +.:a= (3).++ +.. (4)+.-:+. o.= 58.Generally,thegainofatransistoramplifierfallsat high frequencies due to the: (1)internal capacitances of the device. (2)coupling capacitor at the input. (3)skin effect. (4)coupling capacitor at the output. 58..++. | :.=-: |-a.=. =. a. ! .++. | == =.. = =.+. r (1)!|=. =. .+= ..+.| (2);-|: | += ..+. (3)!|-+ |..+ (4).!:|: | += ..+ [S i g n a l & T e l . ] [A8] 59.Ifthedifferentialvoltagegainandthecommonmode voltage gain of a differential amplifier are 48 dB and 2 dB respectively, then its common mode rejection ratio is: (1)23 dB.(2)25 dB. (3)46 dB.(4)50 dB. 59. ==. +.. |-a.=. =. +.. +.-:+. a. . =.+.- +.+.-:+.a.=+.48dB+..2dBr+.;==.=.+.- +. -+.=. =|.+ r (1)23 dB.(2)25 dB. (3)46 dB.(4)50 dB. 60.Half wave rectifier has maximum theoretical efficiency of: (1)40.6% (2)50% (3)78.5% (4)81.2% 60.o+ :=.. + .=++ =o.+= .+. ==.==. r.+. r (1)40.6% (2)50% (3)78.5% (4)81.2% 61.ThenumberofdistinctBooleanexpressionof4 variables is: (1)16(2)256 (3)1024(4)65536 61.4 . = =-|: +a. .++. =. =c. r (1)16(2)256 (3)1024(4)65536 62.The following switching function is to be implemented using a decoder: =) 14 , 10 , 8 , 4 , 2 , 1 ( mThe minimum configuration of the decoder should be (1)24(2)38 (3)416(4)532 62.|= :.=.: =. |. =+ r| == -+ |=. =..-++ =. =.=. r =) 14 , 10 , 8 , 4 , 2 , 1 ( m:.=.: =. -=++ +-.= r.=. .r| (1)24(2)38 (3)416(4)532 63.The 8-bit 2s complement representation of42 is: (1)000101010(2)111010110 (3)111010101(4)100101010 63.42 =. 8-+: 2 |= .++ r (1)000101010(2)111010110 (3)111010101(4)100101010 64.Withoutanyadditionalcircuitry,an8:1MUXcanbe used to obtain: (1)some but not all Boolean functions of 3 variables (2)all function of 3 variables but none of 4 variables (3)allfunctionof3variablesandsomebutnotallof4 variables (4)all functions of 4 variables 64.==. +++ ||.=. = +=. 8:1 MUX =. |. == |.-+ == = a| =. =. ==+. r (1)3 . = == =+ =.. +a. =a= =r. (2)3 . = =.. =a= =+ 4 . =. =.; .. =r. (3)3 . = =.. =a= . 4 . = == =+ =.. =r. (4)4 . = =.. =a=65.A0to6counterconsistsof3flipflopsanda combinationcircuitof2inputgate(s).The combination circuit consists of: (1)One AND gate. (2)One OR gate. (3)One AND gate and one OR gate. (4)Two AND gates. 65.0 = 6 += = |= =.!: + 3 +a| +a.| +.. 2 ;-|: : =. |= =.== ||. ri =.== ||. + == ..+a r (1)|= AND : (2)|= OR : (3)|= AND +.. |= OR : (4). AND : 66.The Fourier transform of unit step function u(t) is: (1)1/j(2)j (3)1/(1+j)(4) ()+1/j 66.=: -:| =a= u(t) =. = =|.+ r (1)1/j(2)j (3)1/(1+j)(4) ()+1/j 67.Let x (t) be the input to a linear, time-invariant system. The required output is 4x(t-2). The transfer function of the system should be: (1)4 ej4f (2)2 e j8f (3)4 e j4f (4)2 e j8f67.+.= a.=| = x(t) |= c.= =.a |..a. =. ;-|: ri |.+ .!:|: 4x(t-2) ri |..a. =. =|.+ =a= r.=. .r| (1)4 ej4f (2)2 e j8f (3)4 e j4f (4)2 e j8f[S i g n a l & T e l . ] [A9] 68.Thephasevelocityofanelectromagneticwave propagatinginahollowmetallicrectangular waveguide in the TE10 mode is: (1)Equal to its group velocity (2)Less than the velocity of light in free space (3)Equal to the velocity of light in free space (4)Greater than the velocity of light in free space 68.TE10 +. + |= c..c.a ..+= .+.=. + |.= + =+ |= ++ +=. + =. |.+-.. + r.+. r (1);== =+r + = +.+ (2)+++ +. + |=.. = + = =+ (3)+++ +. + |=.. = + = +.+ (4)+++ +. + |=.. = + = .= 69.Consider the following statements S1 and S2: S1 : At the resonant frequency the impedance of a series R-L-C circuit is zero. S2 : In a parallel G-L-C circuit, increasing the conductance G results in increase in its Q factor. Which one of the following is correct? (1)S1 is FLASE and S2 is TRUE (2)Both S1 and S2 are TRUE (3)S1 is TRUE and S2 is FALSE (4)Both S1 and S2 are FLASE 69.== S1 . S2 =.=. | +. = S1:==.=.++|=..R-L-C||.=.|++....- r.+. r S2:|= =+.=.+ G-L-C||. + .a=+ G+ +o == = !== Q-..= + +o r. =.+. r == + = =.= =r. r (1)S1 a+ r . S2 =r. r (2)S1 +.. S2 - .=. =r. r (3)S1 =r. r . S2 a+ r (4)S1 +.. S2 - .=. a+ r 70.APDcontrollerisusedtocompensateasystem. Comparedtotheuncompensatedsystem,the compensated system has: (1)A higher type number. (2)Reduced damping. (3)Higher noise amplification. (4)Larger transient overshoot. 70.==. |..a. = |+=. = a| |= PD=+= =. |. =. =.+. ri -|+=.+ |..a. =. +a=. +, |+=.+ |..a. + r (1)|= ! =.: =c. (2).:. r. ++= (3)! += |+.= (4)+..a ..= +=+. 71.The use of non-uniform quantizationleads to: (1)Reduction in transmission bandwidth. (2)Increase in maximum SNR. (3)Increase in SNR for signal levels. (4)Simplification of quantization process. 71.=+.= ++.:.=. = |. = =a-+=| r.+. r (1)=. +:+:. + .+: (2).=++ SNR + +o (3)==a -+. = a| SNR + +o (4)++.:.=. |=. =. =a.=. 72.Thepowerspectraldensity(psd)ofadeterministic signalisgivenby[sin(f)/f2 ]wherefisfrequency.The autocorrelationfunctionofthissignalinthetime domain is: (1)A rectangular pulse (2)A delta function (3)A sine pulse (4)A triangular pulse 72.=....+= ==a =. .++ -|+:+. .=+ (psd) [sin(f)/f2 ] = |+.a+.r=r.f.++ri=.a.++;===a=. -+-=r=+. =a= r (1)|= .+.=. |-= (2)|= :-:. =a= (3)|= =.;= |-= (4)|= +=... |-= 73.At a given probability of error, binary coherent FSK is inferior to binary coherent PSK by: (1)6 dB (2)3 dB (3)2 dB (4)0 dB 73.+: =. |= . r; |.=+. | o-.... =+o FSK o-.... =+o PSK =. +a=. + ==.==. .:. r (1)6 dB (2)3 dB (3)2 dB (4)0 dB 74.InamplitudemodulationAM,ifmodulationindexis more than 100% then: (1)Power of the wave increases. (2)Efficiency of transmission increases. (3)The wave gets distorted. (4)Bandwidth increases 74...+ +.:a= AM+, +.:a= ==.= 100%= .= r +. (1)+ =. .++ + =.+. r (2)=. =. |..++. + =.+. r (3)+ +=|+ r. =.+. r (4)+:+:. + =.+. r [S i g n a l & T e l . ] [A10] 75.The depth of penetration of electromagnetic wave in a medium having conductivity at a frequency of 1 MHz is 25 cm. The depth of penetration at a frequency of 4 MHz will be: (1)6.25 cm (2)12.50 cm (3)50.00 cm (4)100.00 cm 75.1 MHz =. .++ | .a=+ = ++ +.+ + ++ +=. + = |+. =. r.; 25 cm ri 4 MHz =. .++ | |+. =. r.; r.. (1)6.25 cm (2)12.50 cm (3)50.00 cm (4)100.00 cm 76.Twelve1resistancesareusedasedgestoforma cube. The resistance between two diagonally opposite corners of the cube is: (1)(5/6) (2)1 (3)(6/5) (4)(3/2) 76.|=.==.=+..===a| ==.. = =| + +.r 1 |+... =. |. =. =.+. ri .= = . +=.+ +... =.=. = +. |+.. r (1)(5/6) (2)1 (3)(6/5) (4)(3/2) 77.TheHammingdistancebetweentwocodewordscan be calculated : (1)By XORing the code-words bit-by-bit and counting the number of 1s in the result. (2)By XORing the code-words bit-by-bit and counting the number of 0s in the result. (3)ByORingthecode-wordsbit-by-bitandcountingthe number of 1s in the result. (4)ByORingthecode-wordsbit-by-bitandcountingthe number of 0s in the result. 77.. =: .. = +. r+ . =. .=. ;= |=. =. =. ==+. r (1)=: .. =. +:-+.;-+: XORing == . |..+ + 1s =. =c. == =(2)=: .. =. +:-+.;-+: XORing == . |..+ + 0s =. =c. == = |..+ + (3)=: .. =. +:-+.;-+: ORing== . |..+ + 1s =. =c. == =(4)=: .. =. +:-+.;-+: ORing== . |..+ + 0s =. =c. == =78.Lighttravelswithinacladdingfasterthanitdoes within a core because: (1)Refractiveindexofcladdingismorethanrefractive index of core (2)Refractive index of cladding and core are same (3)refractiveindexofcladdingislessthanrefractive index of core (4)None of above 78.|=.. |= |=..= + |= =. = ..+ = .= +=. = =+ r.+. r +.= (1)|=..= =. |++=.= =. = |++=.= = .= r.+. r (2)|=..= . =. =. |++=.= |==+.= r.+. r (3)|=..= =. |++=.= =. = |++=.= =. +a=. + =+ r.+. r (4)!|++ + = =.; =r. 79.The impedance parameters Z11 and Z12 of the two-port network in the figure are: (1)Z11 = 2.75 and Z12 = 0.25 (2)Z11 = 3 and Z12 = 0.5 (3)Z11 = 3 and Z12 = 0.25 (4)Z11 = 2. 25 and Z12 = 0.5 79.=. | | + + .-=o. =:+= = |++... |.a Z11 +.. Z12 r (1)Z11 = 2.75 and Z12 = 0.25 (2)Z11 = 3 and Z12 = 0.5 (3)Z11 = 3 and Z12 = 0.25 (4)Z11 = 2. 25 and Z12 = 0.5 80.Which one of the following modes of transmission will not be supported by a rectangular wave guide?: (1)TE10 (2)TE11(3)TM11 (4)TM1080.=. =. == + = =.==. +. |= .+.=. + |.= o.. =+.+ =r. r.. (1)TE10 (2)TE11(3)TM11 (4)TM10[S i g n a l & T e l . ] [A11] 81.An ideal op-amp is an ideal: (1)Voltage controlled current source (2)Voltage controlled voltage source (3)Current controlled current source (4)Current controlled voltage source 81.|= .. op-amp r.+. r |= .. (1)+.-:+. =++ ... =.+ (2)+.-:+. =++ +.-:+. =.+ (3)... =++ ... =.+ (4)... =++ +.-:+. =.+ 82.Match items in Group 1 with items in Group 2,: Group 1Group 2 P.LED1.Heavy doping Q.Avalanche photodiode2.Coherent radiation R.Tunnel diode3.Spontaneous emission S.LASER4.Current gain (1)P -1, Q-2, R -4, S-3 (2)P -2, Q-3, R -1, S-4 (3)P -3, Q-4, R -1, S-2 (4)P -2, Q-1, R -4, S-3 82.=+r 1 =. +. =. =+r 2 =. +. = =.. =+a+ = =+r 1 =+r 2P. |a;:.1. .= +.= Q. +..+ =.:.:..:2. =a. =+o +=. R. :=a :..:3. -++ -=+ !=== S. a=4. ... a. (1)P -1, Q-2, R -4, S-3 (2)P -2, Q-3, R -1, S-4 (3)P -3, Q-4, R -1, S-2 (4)P -2, Q-1, R -4, S-3 83.Inanairfilledrectangularwaveguide,thecutoff frequencyofaTE10modeis5GHzwhereasthatof TE01 mode is 12 GHz, the dimensions of the guide are: (1)3 cm and 1.25 cm (2)1.25 cm and 3 cm (3)6 cm and 2.5cm (4)2.5 cm and 6 cm 83.+.=.r||=+|.=+TE10+.:=.+=.++ 5GHzr =+= TE01 +.: =. 12GHzr, |.= =. a+.;-.:.; r (1)3 =:.+.: +.. 1.25 =:.+.: (2)1.25 =:.+.: +.. 3 =:.+.: (3)6 =:.+.: +.. 2.5 =:.+.: (4)2.5 =:.+.: +.. 6 =:.+.: 84.IfPisPassivation,Qisn-wellimplant,Ris metallization and S is source/drain diffusion, then the orderinwhichtheyarecarriedoutinastandardn-well SMOS fabrication process, is: (1)P-Q-R-S (2)Q-S-R-P (3)R-P-S-Q (4)S-R-Q-P 84. P =:=. r, Q n-well .|. r, R ..+.=. r +.. S =.+.|+.r +=. r +. |= +.== n-well SMOS =+=.= +, == =+ = + =..-++ =| =.|, +r r (1)P-Q-R-S (2)Q-S-R-P (3)R-P-S-Q (4)S-R-Q-P 85.Anamplifierwithoutfeedbackhasavoltagegainof 50,inputresistance1kandoutputresistanceof 2.5k.Theinputresistanceofthecurrent-shunt negative feedback amplifier using the above amplifier with a feedback factor of 0.2 would be: (1)1/11 k(2)1/5 k (3)5 k(4)11 k 85.=.:+=-+r.= |= |-a.=. =. +.-:+. a. 50, ;-|: |+.. 1k..!:|:|+..2.5kri!|++|-a.=.=. 0.2=.:+= ..= =r+ |. == +.a |= ...-.: =..+= =.:+= |-a.=. =. ;-|: |+.. r.. (1)1/11 k(2)1/5 k (3)5 k(4)11 k 86.TheactionofaJFETinitsequivalentcircuitcanbe represented as a: (1)Current controlled current source (2)Current controlled voltage source (3)Voltage controlled voltage source (4)Voltage controlled current source 86.JFET = |= =++- ||. + !==. =. == =| + ++ =. =. ==+. r (1)... =++ ... =.+ (2)... =++ +.-:+. =.+ (3)+.-:+. =++ +.-:+. =.+ (4)+.-:+. =++ ... =.+ 87.Threeidenticalamplifierswitheachonehavinga voltage gain of 50, input resistance of 1 k and output resistanceof250,arecascaded.Theopencircuit voltage gain of the combined amplifier would be: (1)49 dB (2)51 dB (3)98 dB (4)102 dB 87.+.= |= = |-a.=.. =., ==+ = |= + +.-:+. a. 50, ;-|: |+.. 1 k +.. .!:|: |+.. 250r =.|.=+ =. =.+. ri +=+ |-a.=. =. c.a. ||. +.-:+. a. r.. (1)49 dB (2)51 dB (3)98 dB (4)102 dB [S i g n a l & T e l . ] [A12] 88.If the op-amp in the figure is ideal, the output voltage Vout will be equal to: (1)1 V (2)6 V (3)14 V (4)17 V 88. =. | | + + op-amp .. r +. .!:|: +.-:+. Vout == = +.+ r.. (1)1 V (2)6 V (3)14 V (4)17 V 89.An ideal sawtooth voltage waveform of frequency 500 Hz andamplitude3Visgeneratedbychargingacapacitor of 2F in every cycle. The charging requires: (1)constant voltage source of 3 V for 1 ms (2)constant voltage source of 3 V for 2 ms (3)constant current source of 3 mA for 1 ms (4)constant current source of 3 mA for 2 ms 89.2F = |= =..+ =. |= = + .+.+ == = 500 Hz .++ +.. 3V ..+ =. |= .. ...+. +.-:+. + =| !|-= r.+. ri .+.= = a| ==+ r (1)1 ms = a| 3V =. =++ +.-:+. =.+ (2)2 ms = a| 3V =. =++ +.-:+. =.+ (3)1 ms = a| 3mA =. =++ ... =.+ (4)2 ms = a| 3mA =. =++ ... =.+ 90.Thecircuitshowninthefigurehas4boxeseach described by inputs P,Q,R and outputs Y, Z with: Y = PQR, Z= RQ +P Q R P+The circuit acts as a (1)4 bit adder giving P + Q (2)4 bit subtractor giving P Q (3)4 bit subtractor giving Q P (4)4 bit adder giving P +Q+ R 90.=. ..| | ||. + . ++= r ==+ = |= ;-|: P, Q, R +.. .!:|: Y, Z o.. +.+ r =+= Y = PQR, Z= RQ +P Q R P+||. == =| + =.+ =+. r (1)4 +: .== === P+Q |.-+ r.+. r (2)4 +: .:.= +.a. === P-Q |.-+ r.+. r (3)4 +: .:.= +.a. === Q-P |.-+ r.+. r (4)4 +: .== === P+Q+R |.-+ r.+. r 91.Forthelogiccircuitgivenbelow,therequiredinput condition (A,B,C) to make the output, X = 1 is: (1)1,0,1 (2)0, 0, 1 (3)1, 1, 1 (4)0 , 1,1 91.=.||a.==||.=a|,.!:|:+=.==a| |.+ ;-|: -.+ (A,B,C), X = 1 r (1)1,0,1 (2)0, 0, 1 (3)1, 1, 1 (4)0 , 1,1 [S i g n a l & T e l . ] [A13] 92.A 4 bit ripple counter and a 4 bit synchronous counter aremadeusingflipflopshavingapropagationdelay of10nseach.Iftheworstcasedelayintheripple counterandthesynchronouscounterbeRandS respectively, then: (1)R = 10 ns, S = 40 ns (2)R = 40 ns, S = 10 ns (3)R = 10 ns, S = 30 ns (4)R = 30 ns, S = 10 ns 92.+a|-+a.| =. |. == +=.| | 4 +: = |a =.!: +.. 4 +: +-=.a= =.!: + = |= + 10=. =. . ri |a =.!: +.. +-=.a= =.!: + +.+a =. =+..= . =+. R +.. S r +. (1)R = 10 ns, S = 40 ns (2)R = 40 ns, S = 10 ns (3)R = 10 ns, S = 30 ns (4)R = 30 ns, S = 10 ns 93.TheDTL,TTL,ECLandCMOSfamiliesofdigitalICs are compared in the following 4 columns: (P)(Q)(R) (S) Fanout is minimumDTLDTLTTLCMOS PowerConsumption is minimum TTLCOMSECLDTL Propagation delay is minimum COMSECLTTLTTL The correct column is (1)P(2)Q (3)R(4)S 93.:=:a ICs= DTL, TTL, ECL +.. CMOS |+.. =. == . =.a+. + +a=. =. =.+. r (P)(Q)(R) (S) +r+.= -=++ r DTLDTLTTLCMOS +=a. =. c.|+ -=++ TTLCOMSECLDTL =. . -=++ COMSECLTTLTTL =r. =.a+ r (1)P(2)Q (3)R(4)S 94.The circuit shown in the figure is a 4 bit DAC: Theinputbits0and1arerepresentedby0and5V respectively. The OP AMP is ideal, but all the resistances andthe5Vinputshaveatoleranceof10%.The specification(roundedtothenearestmultipleof5%)for the tolerance of the DAC is (1)35%(2)20% (3)10%(4)5% 94.+ + c... . ||. 4 +: :.|=. r ;-|: +:0+.. 1=+. 0+.. 5Vo.. |a.+ r.+ ri OP AMP..r=+=..|+..+..5V;-|:.+10% =. =r=.++.riDAC=a|=r=.+++.:+.(5%= ==:++ .= += |. =. ;, r (1)35%(2)20% (3)10%(4)5% 95.In an 8085 microprocessor, the instruction CMP B has been executed while the content of the accumulator is less than of register B. As a result: (1)carry flag will be set but Zero flag will be reset (2)carry flag will be reset but Zero flag will be set (3)both carry flag and Zero flag will be reset (4)both Carry flag and Zero flag will be set 95.|= 8085+.;=.|.== + CMPB=. =|.+ =. . r =+= =.= =. ++-+ =-: B=. +a=. + =+ r === =a-+=| (1)=. +a =: =. =.|. . .- +a |= =: =. =.|. (2)=. +a |= =: =. =.|. . .- +a =: =. =.|. (3)=. +a +.. .- +a .=. |= =: =| =.| (4)=. +a +.. .- +a .=. =: =| =.| 96.LetXandYbetwostatisticallyindependentrandom variablesuniformlydistributedintheranges(1,1) and(2,1),respectively.LetZ=X+Y.Thenthe probability that [Z 2] is: (1)Zero (2)1/6 (3)1/3 (4)1/12 96.+.= a.=| X +.. Y .=. =.c= : = -+++ .== =+.(1,1,+..(2,1,+=+.==|=+++ri+.= a.=| Z = X+Y r ++ [Z 2] =. |.=+. r (1).-(2)1/6 (3)1/3 (4)1/12 [S i g n a l & T e l . ] [A14] 97.Let P be linearity, Q be time-invariance, R be causality andSbestability.Adiscrete-timesystemhasthe input-output relationship,: =+=1 n0 n1 n), 1 n ( x, 0), n ( x) n ( ywherex(n)istheinputandy(n)istheoutput.Theabove system has the properties (1)P, S but not Q, R (2)P, Q, S but not R (3)P, Q, R, S (4)Q, R, S but not P 97.+.= a.=| P c.=+., Q =.a |+++. . S -.+. ri |= ++++-=.a |..a. + ;-|:-.!:|: =+. r =+=1 n0 n1 n), 1 n ( x, 0), n ( x) n ( y=r. x(n) ;-|: . y(n) .!:|: ri !++ |..a. = . r (1)P, S a== Q, R =r. (2)P, Q, S a== R =r. (3)PQRS (4)QRS a== P =r. 98.In an end-fire array: (1)the directional pattern is bi-directional (2)the directional pattern is unidirectional (3)maximumtransmissionorreceptionisinadirection perpendicular to the axis. (4)maximumtransmissionorreceptionisalongtheaxis of the antenna 98.= r + (1)..+= |o+ o-..+= r (2)..+= |o+ |=-..+= r (3).=++ =. .+. |.-+ . =. a+++ .. + r (4).=++ =. .+. |.-+ |:.=. = . = =..-=.. r 99.LetXbetheGaussianrandomvariableobtainedby sampling the process at t = ti and let: dy e21) ( Q2x2= The probability that [x 1] is (1)1 Q (0.5) (2)Q (0.5) (3)Q (1/(22)) (4)1 Q (1/(22)) 99.+.= a.=| |=. =. t = ti| |+= == | |.-+ .!=. .== X r . +.= a.=| dy e21) ( Q2x2= [x 1] =. |.=+. r (1)1 Q (0.5) (2)Q (0.5) (3)Q (1/(22)) (4)1 Q (1/(22)) 100.Forthe8085assemblylanguageprogramgiven below,thecontentoftheaccumulatorafterthe execution of the program is: 3000MVIA45H 3002MOVBA 3003STC 3004CMC 3005RAR 3006XRAB (1)00H(2)45H (3)67H(4)E7H 100.=. | | 8085=+a. a|= =.=+ = a| =.=+ = =|.= = +. =.= =. ++-+ r 3000MVIA45H 3002MOVBA 3003STC 3004CMC 3005RAR 3006XRAB (1)00H(2)45H (3)67H(4)E7H 101.IfthetotalpowertoanantennaisWt,theradiated powerisWr,andtheradiationintensityis.Match list-Iwithlist-IIandselectthecorrectanswerusing the code given below the lists: List-IList-II A.Power gain B.Directive gain C.Average power radiated D.Efficiency of the antenna. 1.Wr/Wt2.Wr/4 3.4 /wt4.4 /wr Code (1)A3, B4, C2, D1 (2)A4, B3, C2, D1 (3)A3, B4, C1, D2 (4)A4, B3, C1, D2 101.|:.=.=.=a.++Wt,+=..++.Wr+..+=. r=+. ri =. I =. =. II = =.. =+a+ = . =. = =. | | =.: =. |. =+ r| =r. !+ =. = = =. I=. II A..++ a. B..= a. C..=+ +=. .++ D.|:.=. =. |..++. 1.Wr/Wt2.Wr/4 3.4 /wt4.4 /wr=.: (1)A3, B4, C2, D1 (2)A4, B3, C2, D1 (3)A3, B4, C1, D2 (4)A4, B3, C1, D2 [S i g n a l & T e l . ] [A15] 102.IfthenumberofbitspersampleinaPulseCoded Modulation (PCM) system is increased from 5 bits to 6 bits,theimprovementinsignaltoquantizationnoise ratio will be: (1)3 dB (2)6 dB (3)2 dB (4)0 dB 102. ==. |-= =.:: +.:a= (|.=.|+, |..a. + |= =+= + +:. =. =c. 5 = +.= 6 +: = . =.+. r, +. ++.:.=. += =|.+ = |+ ==a + =.. r.. (1)3 dB (2)6 dB (3)2 dB (4)0 dB 103.What are the minimum numbers of 2 to 1 multiplexers required to generate a 2 input AND gate and a 2 input Ex-OR gate, respectively?: (1)1 and 2 (2)1 and 3 (3)1 and 1 (4)2 and 2 103.=+. 2 ;-|: AND : +.. 2 ;-|: Ex-OR gate +=.= = a| |.+ 2 = 1 += = +r==+=. =. -=++ =c. +. r.. (1)1 +.. 2 (2)1 +.. 3 (3)1 +.. 1 (4)2 +.. 2 104.AcommunicationchannelwithAWGNoperatingata signaltonoiseratioSNR>>1andbandwidthBhas capacityC1.IftheSNRisdoubledkeepingB constant, the resulting capacity C2 is given by: (1)C2 2C1+B (2)C2 C1+B (3)C2 C1+2B (4)C2 C1+0.3B 104.==+==+=|.+SNR>>1||.a+AWGN+..B +:+:. = ++ |= =. =a =. .++. C1 ri B =. -. c.+ r| SNR =. = . =.+. r +. |..+. .++. C2 == o.. |.-+ r.. (1)C2 2C1+B (2)C2 C1+B (3)C2 C1+2B (4)C2 C1+0.3B 105.Aneventhas6possibleoutcomeswithprobabilities p1=1/2,p2=1/4,p3=1/8,p4=1/16,p5=1/32,p6=1/32.Find therateofinformationifthereare16outcomesper second: (1)15 bits/second (2)16 bits/second (3)31 bits/second (4)32 bits/ second 105.|=.:=.=.p1=1/2,p2=1/4,p3=1/8,p4=1/16,p5=1/32, p6=1/32|.=+..=r+6=..++ |..+ r. ==+ ri |+ ==: 16 |..+ r +. ==. =. |+. a.| (1)15 +:.==: (2)16 +:.==: (3)31 +:.==: (4)32 +:.==: DIRECTIONS:DataforQuestionno.106107isgivenbelow. Letm(t)=cos[(4x103 )t]bethemessagesignalandc(t)=5 cos [(2x106 )t] be the carrier. 106.C(t)andm(t)areusedtogenerateanAMsignal.The modulationindexofthegeneratedAMsignalis0.5. Thenthequantity(Totalsidebandpower)/(Carrier power) is: (1)1/2(2)1/4 (3)1/3(4)1/8 =.a==c.106|+107=.=:=.|ri+.==m(t) = cos [(4x103 )t] =. ==+ r |+ c(t) = 5 cos [(2x106 )t] +.r= ri 106.AM==a = =+.. = a| C(t) +.. m(t) =. |. =. =.+. ri =++ AM ==a =. +.: a= ==.= 0.5 r, +. +.+. (=a |.+ +: .++,.(= .++, r (1)1/2(2)1/4 (3)1/3(4)1/8 107.C(t) and m(t)are used to generate an FM signal. If the peakfrequencydeviationofthegeneratedFMsignal isthreetimesthetransmissionbandwidthoftheAM signal,thenthecoefficientoftheterm[2(1008x103 t)]intheFMsignal(intermsoftheBessel coefficients) is: (1)5 J4(3) (2)(5/2) J8(3) (3)(5/2) J8(4) (4)5 J4(6) 107.FM ==a = =+.. = a| C(t) +.. m(t) =. |. =. =.+. ri =++ FM ==a =. !++ .++ +a= AM ==a = =. +:+:. = +=. r +. FM==a (+=a ..=. = .. +, + | [2 (1008x103 t)] =. ..= r (1)5 J4(3) (2)(5/2) J8(3) (3)(5/2) J8(4) (4)5 J4(6) [S i g n a l & T e l . ] [A16] 108.MatchitemsinGroup1withthemostappropriate item in Group 2,Group 1Group 2 PRing modulator1Clock recovery QVCO2Demodulation of FM RFoster-Seely discriminator3Frequency conversion SMixer4Summing the two inputs 5Generation of FM 6Generationof DSB-Sc (1)P-1 Q-3 R-2 S-4(2)P-6 Q-5 R-2 S-3 (3)P-6 Q-1 R-3 S-2(4)P-5 Q-6 R-1 S-3 108.=+r1=.+.=.=+r2+=+..=!|+++.==.. =+a+ = =+r 1 =+r 2 P +.:a: 1 +a.= =+. Q +.=.. 2 |=|+ =. :.+.:a.= R =.-:-=.a. +.= 3 .++ =|.+. S ++= 4 . ;-|:. =. =.:=. 5 |=|+ =. =+.. 6 DSB-Sc =. =+.. (1)P-1 Q-3 R-2 S-4(2)P-6 Q-5 R-2 S-3 (3)P-6 Q-1 R-3 S-2(4)P-5 Q-6 R-1 S-3 109.Asuperheterodynereceiveristooperateinthe frequencyrange550kHz1650kHz,withthe intermediatefrequencyof450kHz.LetR=(Cmax)/ (Cmin)denotetherequiredcapacitanceratioofthe localoscillatorandIdenotetheimagefrequency(in kHz) of the incoming signal. If the receiver is tuned to 700 kHz, then: (1)R = 4.41, I = 1600 (2)R = 2.10, I = 1150 (3)R = 3.0, I = 1600 (4)R = 9.0, I = 1150 109.|= =|r:.:.;= ..r. =. 450kHz=. + .+ + =r+ 550 kHz 1650 kHz =. .++ =c.a. + =.+ ==. ri +.= a.=| = R = (Cmax)/ (Cmin) -..=. .a+ =. |.+ ..+. +.. I .+= ==a =. |+++ .++ (kHz +, |a.+ =+. ri ..r. =. 700 kHz | := =. =.+. r +. (1)R = 4.41, I = 1600 (2)R = 2.10, I = 1150 (3)R = 3.0, I = 1600 (4)R = 9.0, I = 1150 110.Alosslesstransmissionlineisterminatedinaload whichreflectsapartoftheincidentpower.The measuredVSWRis2.Thepercentageofthepower that is reflected back is: (1)57. 73(2)33.33 (3)0.11(4)11.11 110.|= .+r.= =. a.;= .. + =+.-+ r. =.+. r =. .|++ .++ =. |= r-=. |a.+ =+. ri +.|+ VSWR 2 ri +.|= |a.+ r.= +.a. .++ =. |+.+ r (1)57. 73(2)33.33 (3)0.11(4)11.11 111.Three analog signals, having bandwidths 1200 Hz, 600 Hzand600Hz,aresampledattheirrespective Nyquistrates,encodedwith12bitwords,andtime divisionmultiplexed.Thebitrateforthemultiplexed signal is: (1)115.2 kbps (2)28.8 kbps (3)57.6 kbps (4)38.4 kbps 111.+.= ==| ==a ===. +:+:. 1200 Hz, 600 Hz +.. 600 Hzr !-r !== |=.-|=. =.;++-: . | |+=+ =. =.+. r, 12+: .. = =.:+ =. =.+. r . =.a +.. +r==++ =. =.+. ri +r==++ ==a =. +: r (1)115.2 kbps (2)28.8 kbps (3)57.6 kbps (4)38.4 kbps 112.InanimpedanceSmithchart,aclockwisemovement along a constant resistance circle gives rise to: (1)decrease in the value of reactance (2)an increase in the value of reactance (3)no change in the reactance value (4)no change in the impedance value 112.|= |++... -+. .: + |= =++ |+.. ++ = =..-=.. |= ..++ =a= == =. =-+ +. r (1)|+..+ = +.= + =+. (2)|+..+ = +.= + +o (3)|+..+ = +.= + =.; +a.+ =r. (4)|++... +.= + =.; +a.+ =r. 113.IfSrepresentsthecarriersynchronizationatthe receiverandrepresentsthebandwidthefficiency, thenthecorrectstatementforthecoherentbinary PSK is: (1)= 0.5, S is required (2)= 1.0, S is required (3)= 0.5, S is not required (4)= 1.0, S is not required 113. S ..r. | = +-=.a= . +:+:. |..++. =. |a.+ =+. r +. =+o o-.... PSK = =+. + =r. =.= r (1)= 0.5, S |.+ r (2)= 1.0, S |.+ r (3)= 0.5, S |.+ =r. r (4)= 1.0, S |.+ =r. r [S i g n a l & T e l . ] [A17] 114.MatchitemsinGroup1withthemostappropriate item in Group 2. Group 1Group 2 1FMPSlope overload 2DMQ -law 3PSKREnvelop detector4PCMSCapture effect THibert transform UMatched filter (1)1T,2P,3U,4S(2)1S,2U,3P,4T (3)1S,2P,3U,4Q(4)1U,2R,3S,4Q 114.=+r1=.+.=.=+r2=.=+..=!|+++.==.. =+a+ = =+r 1 =+r 2 1FMP -a.| .+a.: 2DMQ-+. 3PSKR |-+a| ::+: 4PCMS =- |..+ T r.;+: =|.+ U =+a+ =-: (1)1T,2P,3U,4S(2)1S,2U,3P,4T (3)1S,2P,3U,4Q(4)1U,2R,3S,4Q 115.1kHzsinusoidalsignalisideallysampledat1500 samples/secandthesampledsignalispassed through an ideal low-pass filter with cut off frequency 800 Hz. The output signal has the frequency: (1)Zero Hz (2)0.75 kHz (3)0.5 kHz (4)0.25 kHz 115.1kHz-.+=.==a1500=+=..==:|..+|+ =+ =. . r . =+ =+= =. += .+-. 800 Hz =r+ |= .. == |.= =-: + = =.. =.+. ri .!:|: ==a =. .++ r (1)Zero Hz (2)0.75 kHz (3)0.5 kHz (4)0.25 kHz 116.The directive gain of an antenna: (1)is less than or equal to 1 (2)is greater than or equal to 1 (3)lies between 0 and directivity of antenna (4)is greater than directivity of antenna 116.|= |:.=. =. ..+= a. (1)1 = =+ .+. !== +.+ r (2)1 = .= .+. !== +.+ r (3)0 . |:.=. =. ..+=+. = +. =. r (4)|:.=. =. ..+=+. = .= r 117.ThefollowingICisusedforprioritizinginterruptsin the microprocessor based system: (1)8251(2)8255 (3)8259(4)8279 117.+.;=.|.==...+|..a.++.=.=.|..+=+.== a| == IC =. |. =. =.+. r (1)8251(2)8255 (3)8259(4)8279 118.Inamicrowavetestbench,whyisthemicrowave signal amplitude modulated at 1 kHz?: (1)To increase the sensitivity of measurement (2)To transmit the signal to a far-off place (3)To study amplitude modulation (4)Becausecrystaldetectorfailsatmicrowave frequencies 118.+.;=.++ |... + + +. =.. r = +.;=.++ ==a ..+ =. 1 kHz | +.:a.=+ =. =.+. r (1)+.|= =. =++. +.= = a| (2)==a =. = -.a =. =+ == = a| (3)..+ +.:a= =. = == = a| (4)+.==-:a::+:+.;=.++ .++. | ==a r+. r 119.The line of sight communication requires the transmit andreceiveantennastofaceeachother.Ifthe transmitantennaisverticallypolarized,forbest reception the receive antenna should be: (1)Horizontally polarized (2)Vertically polarized (3)At 45 degrees with respect to horizontal polarization (4)At 45 degrees with respect to vertical polarization 119.. =. =. c.. |=. ==. =+n+. r = =. . |.|. |:.=.|=-==.+=-=.+=r.i=.|:.=.=+.. =| = .+.=+ r +. =+.++ =-.= = a| |.|= |:.=. (1).+= =| = .+.=+ r.=. .r| (2)=+.. =| = .+.=+ r.=. .r| (3).+= .+.=. =. 45 | (4)=+.. .+.=. =. 45 | 120.A rectangular metal wave guide filled with a dielectric materialofrelativepermittivityr=4hastheinside dimensions 3.0 cm 1.2 cm. The cut-off frequency for the dominant mode is: (1)2.5 GHz(2)5.0 GHz (3)10.0 GHz(4)12.5 GHz 120.|.++ =.+. = . r| |= .+.=. ..+= |.= =. =.|.= |+:+.:. r=4 r, ===. - =. ++.| r 3=:.+.: 1.2 =:.+.:i |..+. +. = a| += .++ r (1)2.5 GHz(2)5.0 GHz (3)10.0 GHz(4)12.5 GHz [S i g n a l & T e l . ] [A18]