Rube-Goldberg Catapult Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig.
-
Upload
darcy-gregory -
Category
Documents
-
view
218 -
download
0
Transcript of Rube-Goldberg Catapult Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig.
![Page 1: Rube-Goldberg Catapult Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig.](https://reader036.fdocuments.in/reader036/viewer/2022082422/5697c00e1a28abf838cc9f54/html5/thumbnails/1.jpg)
Rube-Goldberg Catapult
Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig
![Page 2: Rube-Goldberg Catapult Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig.](https://reader036.fdocuments.in/reader036/viewer/2022082422/5697c00e1a28abf838cc9f54/html5/thumbnails/2.jpg)
Overview
A three step Rube-Goldberg device with the purpose of shooting a ball via catapult
The first step involves a ball traveling down a PVC pipe triggering a mouse trap upon landing
In the next step, the mouse trap pulls the firing pin out of the catapult
The last step involves the firing of the catapult
![Page 3: Rube-Goldberg Catapult Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig.](https://reader036.fdocuments.in/reader036/viewer/2022082422/5697c00e1a28abf838cc9f54/html5/thumbnails/3.jpg)
The Rube-Goldberg Catapult
![Page 4: Rube-Goldberg Catapult Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig.](https://reader036.fdocuments.in/reader036/viewer/2022082422/5697c00e1a28abf838cc9f54/html5/thumbnails/4.jpg)
Energy Conversions
The first step involves a ball with gravitational potential energy ( Ugrav =
mgh ) which gives us (0.25 kg)(9.81 m/s/s)(0.1588 m) = 0.0389 Joules to trigger the mouse trap.
The mouse trap exerts elastic potential energy ( Fd = E ) which gives us (136 N)(0.08m) = 10.88 Joules which then converted to kinetic energy. The force required to pull the catapult pin is 1.5 N.
Since the catapult uses springs, the energy requires a spring constant. The spring constant, K, can be calculated by measuring the force per length deflection from the neutral position. A force of 34.5 N is required to obtain a deflection of .292 M. K is then equal to (34.5 N)/(.292 M)= 118 N/M for each spring. The elastic potential energy can be derived from this using ( ½ Kx2 ) multiplied by two (springs) which gives us 118N/M(.292M)2=10.06 Joules.
All potential energy used in this device converts to kinetic energy.
![Page 5: Rube-Goldberg Catapult Team members: Rob Burgin Craig Bowers Aaron Shannon James Hartsig.](https://reader036.fdocuments.in/reader036/viewer/2022082422/5697c00e1a28abf838cc9f54/html5/thumbnails/5.jpg)
Conclusion
The device is very simple and reliable The most difficult part was accounting for
energy lost during the process The calculations were very straight forward
when nonconservative forces are emitted We feel that no changes are necessary