Rev_3.pdf
-
Upload
choon-yong-loh -
Category
Documents
-
view
214 -
download
0
Transcript of Rev_3.pdf
![Page 1: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/1.jpg)
Normal stress varies linearly with distance from neutral axis
Elastic flexure formula for maximum normal stress,
I = moment of inertia of cross section
Normal stress at any distance y distance from neutral axis
S = elastic section modulus
section rectanglefor 3
121 bhI
section rectanglefor 2
61 bhI
![Page 2: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/2.jpg)
curvature of the member
S= elastic section modulus
![Page 3: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/3.jpg)
4 - 3
Sample Problem 4.2SOLUTION:
Based on the cross section geometry, calculate
the location of the section centroid ( 𝑌) and
moment of inertia (I).
mm 383000
10114 3
A
AyY
3
3
3
32
101143000
104220120030402
109050180090201
mm ,mm ,mm Area,
AyA
Ayy
49-3
2312123
121
23
1212
m10868 mm10868
18120040301218002090
I
dAbhdAIIx
![Page 4: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/4.jpg)
Find I and 𝑌1. (Ans: I = 301.3 × 10−6 𝑚4 , Y = 170mm 2. Ans: I = 79.7 × 10−6 𝑚4 , Y = 75mm
3. Ans: I = 13.8694 × 10−6 𝑚4 , X = 44.25mm
Y
X
![Page 5: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/5.jpg)
• A 56N.m coupled is applied to the steel bar shown. (a) Assuming that the couple is applied about the z-axis as shown, determine the maximum stress and the radius of curvature of the bar. Use E= 200GPa.[ans: (a) 94.3 MPa, 19.1m]
![Page 6: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/6.jpg)
![Page 7: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/7.jpg)
Analysis and Design of Beam for Bending
• Sign conventions for shear forces V and V’
and bending couples M and M’
![Page 8: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/8.jpg)
• Sign conventions for shear
forces V and V’ and bending
couples M and M’
![Page 9: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/9.jpg)
Sample Problem 5.3
5 - 9
Draw the shear and bending-
moment diagrams for the beam
and loading shown.
SOLUTION:
• Taking the entire beam as a free body,
determine the reactions at A and D.
• Apply the relationship between shear and
load to develop the shear diagram.
• Apply the relationship between bending
moment and shear to develop the bending-
moment diagram.
![Page 10: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/10.jpg)
Sample Problem 5.3
5 - 10
SOLUTION:
• Taking the entire beam as a free body, determine the
reactions at A and D.
• Apply the relationship between shear and load to
develop the shear diagram.
dxwdVwdx
dV
zero slope between concentrated loads
linear variation over uniform load segment
![Page 11: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/11.jpg)
Sample Problem 5.3
5 - 11
• Apply the relationship between bending
moment and shear to develop the bending-
moment diagram.
dxVdMVdx
dM
bending moment at A and E is zero
total of all bending-moment changes across
the beam should be zero
net change in bending moment is equal to
areas under shear distribution segments
bending moment variation between D
and E is quadratic
bending moment variation between A, B,
C, and D is linear
![Page 12: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/12.jpg)
• Normal stress is often the critical design criteria
S
M
I
cM
I
Mymx
Requires determination of the location and
magnitude of largest bending moment.
![Page 13: Rev_3.pdf](https://reader035.fdocuments.in/reader035/viewer/2022062520/5695d14f1a28ab9b0295ff14/html5/thumbnails/13.jpg)
Sample Problem 5.1
5 - 13
• Identify the maximum shear and bending
moment from plots of their distributions.
mkN50kN26 Bmm MMV
• Apply the elastic flexure formulas to
determine the corresponding
maximum normal stress.
36
3
36
2
612
61
m1033.833
mN1050
m1033.833
m250.0m080.0
S
M
hbS
Bm
Pa100.60 6m