Resistance of columns and beam- columns - IV - · PDF fileResistance of columns and...
Transcript of Resistance of columns and beam- columns - IV - · PDF fileResistance of columns and...
Resistance of columns and beam-columns
TMR41205 Buckling and ultimate load analysis of marine structures Jørgen Amdahl
Dept. Marine structures
Eaxmple of column buckling due to excessive jacking during installation.
Element
STRUCTURE
Beam Column
M
l
Idealized
effl
N
Idealisering av stavelementer i et rammeverk til en isolert bjelkesøyle
CM
Column buckling
The characteristic axial compressive resistance based Johnson-Ostenfeldt expression with 10% reduction :
c2
y
f 0.9 for 1.34f
λλ
= >
21.0 0.28 for 1.34c
y
ff
λ λ= − ≤
( )2
2,y EE
f EIff k A
πλ = =l
If local buckling strength fcl < fy replace fy by fcl
0.0
0.2
0.4
0.6
0.8
1.0
1.2
0.0 0.5 1.0 1.5 2.0 2.5
Euler
ISO (1-0.28 l², 0.9/l²)
Chen & Ross - fabricated
Smith, Somerville & Swan - fabricated
Smith, Somerville & Swan - seamless
Steinmann & Vojta - ERW
Yeomans - ERW
Yeomans - seamless
λ = (Fyc/Fe)0.5
fc/Fyc
Bias 1.057 COV = 0.041 n = 84
Figure A.13.2-1 Comparison of Test Data with Column Buckling Design Equation forFabricated Cylinders Subjected to Axial Compression
ISO column buckling curve Comparison with test data
Effect of axial local buckling
2
1 0 0 412
1 047 0 274 0 412 1 382
1 382
cl
y
cl
y
cl ce
f . .ff . . . .f
f f .
= λ ≤
= − λ ≤ λ ≤
= ≤ λ
λ =
f y
fxe
λ2 =f xef y
fcl
f y
= 1.0 λ ≤ 0.412
fcl
f y
= 1.047 − 0.274λ2 0.412 ≤ λ ≤1.382
fcl = fce 1.382 ≤ λ
fxe = 0.3E
tr
Elastic buckling
If fcl < fy replace fy by fcl in column buckling check
Yield stress D/t local buckling limit 235 91 355 60 420 51
Local buckling strength versus D/t-ratio
0"
0.2"
0.4"
0.6"
0.8"
1"
1.2"
0" 20" 40" 60" 80" 100" 120" 140"
Norm
alise
d"local"buckling"stress"
Diameter/thickness"ra=o"
Cri=cal""local"buckling"stress"
Yield stress achieved for D/t < 60
Capacity in bending
Typical normalized moment-rotation curves for cylinders for various D/t-ratios (MPS is plastic bending moment)
Capacity in bending m
y
f Zf W
= 0.0517yf DEt
≤
1 13 2 58 ym
y
f Df Z. .f Et W
⎛ ⎞⎛ ⎞ ⎛ ⎞= −⎜ ⎟ ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠⎝ ⎠0.0517 0.1034yf D
Et< ≤
0 94 0 76 ym
y
f Df Z. .f Et W
⎛ ⎞⎛ ⎞ ⎛ ⎞= −⎜ ⎟ ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠⎝ ⎠0.1034 120y yf D f
Et E< ≤
4 4( 2 )32
D D tD
π ⎡ ⎤− −⎣ ⎦
3 31 ( 2 )6D D t⎡ ⎤− −⎣ ⎦
W = elastic section modulus
Z = plastic section modulus
Allowable bending stress for tubular members ISO/DIS 19902/NNORSOK N_004
Plastic thin-walled
Yield
Yield stress D/t plas>c limit D/t "Elas>c" 235 46 92 355 31 61 420 26 52
Allowable bending stress versus D/t-ratio (yield stress 355 MPa)
• Fully plastic bending moment achieved only for D/t < 30
0"
0.2"
0.4"
0.6"
0.8"
1"
1.2"
1.4"
1.6"
0" 20" 40" 60" 80" 100" 120"
Allowab
le(ben
ding(stress(fm
/fY%
Diameter/thickness(ra6o(D/t(
Interaction equation for tubular beam-columns subjected to axial force and
bending moment (ISO, NORSOK)
0.1
NN1
MC
NN1
MCM1
NN
5.02
Ez
Sd
Sdz,mz
2
Ey
Sd
Sdy,my
RdRdc,
Sd ≤
⎪⎪⎭
⎪⎪⎬
⎫
⎪⎪⎩
⎪⎪⎨
⎧
⎥⎥⎥⎥
⎦
⎤
⎢⎢⎢⎢
⎣
⎡
−+
⎥⎥⎥⎥
⎦
⎤
⎢⎢⎢⎢
⎣
⎡
−+
Table 6-2 Effective length and moment reduction factors for member strengthcheckingStructural element k Cm
(1)
Superstructure legs - Braced 1.0 (a) - Portal (unbraced) k(2) (a)Jacket legs and piling - Grouted composite section 1.0 (c) - Ungrouted jacket legs 1.0 (c) - Ungrouted piling between shim points 1.0 (b)Jacket braces - Primary diagonals and horizontals 0.7 (b) or (c) - K-braces(3) 0.7 (c) - Longer segment length of X-braces(3) 0.8 (c)Secondary horizontals 0.7 (c)
Notes:1. Cm values for the cases defined in Table 6-2 are as follows:
(a) 0.85(b) for members with no transverse loading,Cm = 0.6 - 0.4 M1,Sd/M2,Sdwhere M1,Sd/M2,Sd is the ratio of smaller to larger moments at the ends of that portion of the memberunbraced in the plane of bending under consideration. M1,Sd/M2,Sd is positive when the number is bentin reverse curvature, negative when bent in single curvature.(c) for members with transverse loading,Cm = 1.0 - 0.4 Nc,Sd/NE, or 0.85, whichever is less, and NE = NEy or NEz as appropriate.
2. Use Effective Length Alignment Chart in Commentary.
3. At least one pair of members framing into the a K- or X-joint must be in tension if the joint is notbraced out-of-plane. For X-braces, when all members are in compression, the k-factor should bedetermined using the procedures given in the Commentary.
4. The effective length and Cm factors given in Table 6-2 do not apply to cantilever members and themember ends are assumed to be rotationally restrained in both planes of bending.
Buckling coefficient for X-braces dependeing on force condition and rotational end support
Capacity checks of deep water tubular members
Stresses in circular cross-sections for external hydrostatic pressure
Hoop stress from external hydrostatic pressure
h=pr/2t h Axial stress from capped end forces x=0.5 h q,Sd
p
Hoop buckling • General formula
– see buckling of cylindrical shells
Hoop buckling strength of fabricated cylinders subjected to hydrostatic pressure- test data compared with design equation (from ISO19902)
y
he
ff
λ =
fhe = 2ChEtD
⎛⎝⎜
⎞⎠⎟
0,0
0,2
0,4
0,6
0,8
1,0
1,2
1,4
0 1 2 3 4 5 6 7
ISO
Miller & Kinra - fabr.+ rings
Miller, Kinra & Marlow - fabr.+rings
Miller, Kinra & Marlow - fabr. unstif.
Eder et al - fabr.+ rings
Eder et al- ERW + rings
Kiziltug et al - ERW unstif.
Steinmann & Vojta - ERW unstif.
Fy/Fhe
fh/Fy
Hoop buckling resistance versus D/t-ratio
• Notice the rapid decrease of buckling strength with increasing D/t-ratio • For D/t > 30 buckling is predominantly elastic (yield stress 355 MPa)
0"
0.2"
0.4"
0.6"
0.8"
1"
0" 20" 40" 60" 80" 100" 120" 140"
Norm
alise
d+ho
pp+buckling+s
tress+
Diameter6thickness+ra7o+
Hoop+buckling+stress+versus+diameter6thickness+ra7o+
Elas-c"buckling"stress"f_he/f_Y"
Cri-cal"buckling"stress"f_h/f_Y"
Interaction between column buckling,local buckling and hydrostatic pressure
fch
fcl
⎛
⎝⎜⎞
⎠⎟
2
−fc
fcl
−2σ x
fcl
⎛
⎝⎜⎞
⎠⎟fch
fcl
+σ x
fcl
σ x
fcl
−1⎛
⎝⎜⎞
⎠⎟= 0, λ < 1.34 (1−
2σ x
fcl
)⎡
⎣⎢
⎤
⎦⎥
−1
fch
fcl
= 12
[ξ −2σ x
fcl
+ ξ 2 +1.12λ 2 σ x
fcl
], λ <1.34 (1−2σ x
fcl
)⎡
⎣⎢
⎤
⎦⎥
−1
Interaction local buckling –hydrostatic pressure
0
50
100
150
200
250
300
350
400
450
500
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
0 0.2 0.4 0.6 0.8 1
Wat
er d
epth
[m]
f_ch
/f_cl
Sigma_x/f_cl
Interaction between hydrostatic pressure and column buckling
lamda=0.5
lamda=0.7
lamda=0.9
lamda=1.1
lamda=1.3
lamda=1.5
D/t = 30
D/t = 40
D/t = 50
D/t = 60
Interaction equations 1) Combined tension and hydrostatic pressure 2) Combined bending and hydrostatic pressure (shown below)
Characteristic bending stress modified for hydrostatic pressure
Bending resistance with no external hydrostatic pressure
Design hoop buckling resistance
fmh
fm
= 1+ 0.09σh
fh
⎛
⎝⎜⎞
⎠⎟
2
−σh
fh
⎛
⎝⎜⎞
⎠⎟
2η
− 0.3σh
fh
⎛
⎝⎜⎞
⎠⎟
fmhfm
⎛
⎝⎜⎞
⎠⎟
2
+ 2vfmhfm
⎛
⎝⎜⎞
⎠⎟σhfh
⎛
⎝⎜⎞
⎠⎟+
σhfh
⎛
⎝⎜⎞
⎠⎟
2η
= 0 η = 5 − 4fhf y
Interaction between bending and hydrostatic pressure
0
0.2
0.4
0.6
0.8
1
1.2
0 0.2 0.4 0.6 0.8 1 1.2
f_m
h/f_
m
Sigma_x/f_h
f_h/f_y =0.2
f_h/f_y =0.4
f_h/f_y =0.6
f_h/f_y =0.8
f_h/f_y =1.0
fmh
fm
⎛
⎝⎜⎞
⎠⎟
2
+ 2vfmh
fm
⎛
⎝⎜⎞
⎠⎟σh
fh
⎛
⎝⎜⎞
⎠⎟+
σh
fh
⎛
⎝⎜⎞
⎠⎟
2η
= 0 η = 5 − 4fh
f y
fmh
fm
= 1+ 0.09σh
fh
⎛
⎝⎜⎞
⎠⎟
2
−σh
fh
⎛
⎝⎜⎞
⎠⎟
2η
− 0.3σh
fh
⎛
⎝⎜⎞
⎠⎟
Reduction of characteristic bending stress versus water depth
0
50
100
150
200
250
300
20 30 40 50 60 70 80 90 100
Diameter/thickness
Wat
erde
pth
(m)
100 %10 %5 %
2 %
Reduction in bending strength as a function of water depth and D/t-ratio
Interaction equation for beam-columns with external hydrostatic
pressure
• Two formulations given, depending on capped end forces included or not
• Here, only the formulations for capped end forces NOT included are shown
σ a
fch+ 1fmh
Cmyσmy
1− σ a
fEy
⎛
⎝
⎜⎜⎜⎜
⎞
⎠
⎟⎟⎟⎟
2
+ Cmzσmz
1− σ a
fEz
⎛
⎝
⎜⎜⎜
⎞
⎠
⎟⎟⎟
2⎡
⎣
⎢⎢⎢⎢⎢
⎤
⎦
⎥⎥⎥⎥⎥
0.5
≤1.0
Interaction equation for tubular beam-columns subjected to axial compression, bending moment and external hydrostatic pressure
(capped end forces NOT included).
Axial compressive strength in the presence of external hydrostatic pressure
Bending resistance in the presence of external hydrostatic pressure
Yield check for tubular beam-columns subjected to axial compression, bending moment
and external hydrostatic pressure (capped end forces NOT included).
σ a +σ x
fcl+
σ my2 +σ mz
2
fmh≤1.0
Local buckling strength not affected by external hydrostatic pressure
Bending resistance in the presence of external hydrostatic pressure
Yield check for tubular beam-columns subjected to axial tension, bending moment and
external hydrostatic pressure (capped end forces NOT included).
σ a −σ x
fth+
σmy2 +σmz,
2
fmh≤1.0
Axial tensile resistance in the presence of external hydrostatic pressure
Bending resistance in the presence of external hydrostatic pressure
σ ac ≥σ x (net axial tension)
Capacity check for tubular beam-columns subjected to axial tension, bending moment and external hydrostatic pressure
(capped end forces NOT included).
σ a −σ x
fcl+
σ my2 +σ mz
2
fmh≤1.0
Local buckling resistance
Bending resistance in the presence of external hydrostatic pressure
σ a,Sd <σ q,Sd (net axial compression)
The material factor for beam-column checks depends on the utilisation wrt local buckling and
hoop buckling
0.1λfor1.45γ
1.0λ0.5forλ0.600.85γ
0.5λfor 1.15γ
sM
ssM
sM
>=
≤≤+=
<=
NORSOK standard N-004 Rev. 3, February 2013
NORSOK standard Page 19 of 264
0.1Ȝfor1.45Ȗ
1.0Ȝ0.5forȜ0.600.85Ȗ
0.5Ȝfor 1.15Ȗ
sM
ssM
sM
!
dd�
�
( 6.22)
where
h
2
h
Sdp,c
c
Sdc,s Ȝ
fı
Ȝf
ıȜ �¸
¸¹
·¨¨©
§��
l
( 6.23)
where fcl is calculated from Equation ( 6.6) or Equation ( 6.7) whichever is appropriate and fh from Equation ( 6.17), Equation ( 6.18), or Equation ( 6.19) whichever is appropriate.
ec
yc f
fȜ
l
, and he
yh f
fȜ
( 6.24)
fcle and fhe is obtained from Equation ( 6.8), and Equation ( 6.20) respectively. Vp,Sd is obtained from Equation ( 6.16) and
W
MM
ANı
2Sdz,
2Sdy,Sd
Sdc,
��
( 6.25)
NSd is negative if in tension.
6.3.8 Tubular members subjected to combined loads without hydrostatic pressure
6.3.8.1 Axial tension and bending Tubular members subjected to combined axial tension and bending loads should be designed to satisfy the following condition at all cross sections along their length:
0.1M
MM
NN
Rd
2Sdz,
2Sdy,
75.1
Rdt,
Sd d�
�¸¸¹
·¨¨©
§
( 6.26)
where
My,Sd = design bending moment about member y-axis (in-plane) Mz,Sd = design bending moment about member z-axis (out-of-plane) NSd = design axial tensile force
If shear or torsion is of importance, the bending capacity MRd needs to be substituted with MRed,Rd calculated according to subclause 6.3.8.3 or 6.3.8.4.
6.3.8.2 Axial compression and bending
Tubular members subjected to combined axial compression and bending should be designed to satisfy the following condition accounting for possible variations in cross-section, axial load and bending moment according to appropriate engineering principles:
0.1
NN
1
MC
NN
1
MC
M1
NN
5.02
Ez
Sd
Sdz,mz
2
Ey
Sd
Sdy,my
RdRdc,
Sd d
°°
¿
°°
¾
½
°°
¯
°°
®
»»»»
¼
º
««««
¬
ª
��
»»»»
¼
º
««««
¬
ª
��
( 6.27)
and at all cross sections along their length:
NORSOK standard N-004 Rev. 3, February 2013
NORSOK standard Page 19 of 264
0.1Ȝfor1.45Ȗ
1.0Ȝ0.5forȜ0.600.85Ȗ
0.5Ȝfor 1.15Ȗ
sM
ssM
sM
!
dd�
�
( 6.22)
where
h
2
h
Sdp,c
c
Sdc,s Ȝ
fı
Ȝf
ıȜ �¸
¸¹
·¨¨©
§��
l
( 6.23)
where fcl is calculated from Equation ( 6.6) or Equation ( 6.7) whichever is appropriate and fh from Equation ( 6.17), Equation ( 6.18), or Equation ( 6.19) whichever is appropriate.
ec
yc f
fȜ
l
, and he
yh f
fȜ
( 6.24)
fcle and fhe is obtained from Equation ( 6.8), and Equation ( 6.20) respectively. Vp,Sd is obtained from Equation ( 6.16) and
W
MM
ANı
2Sdz,
2Sdy,Sd
Sdc,
��
( 6.25)
NSd is negative if in tension.
6.3.8 Tubular members subjected to combined loads without hydrostatic pressure
6.3.8.1 Axial tension and bending Tubular members subjected to combined axial tension and bending loads should be designed to satisfy the following condition at all cross sections along their length:
0.1M
MM
NN
Rd
2Sdz,
2Sdy,
75.1
Rdt,
Sd d�
�¸¸¹
·¨¨©
§
( 6.26)
where
My,Sd = design bending moment about member y-axis (in-plane) Mz,Sd = design bending moment about member z-axis (out-of-plane) NSd = design axial tensile force
If shear or torsion is of importance, the bending capacity MRd needs to be substituted with MRed,Rd calculated according to subclause 6.3.8.3 or 6.3.8.4.
6.3.8.2 Axial compression and bending
Tubular members subjected to combined axial compression and bending should be designed to satisfy the following condition accounting for possible variations in cross-section, axial load and bending moment according to appropriate engineering principles:
0.1
NN
1
MC
NN
1
MC
M1
NN
5.02
Ez
Sd
Sdz,mz
2
Ey
Sd
Sdy,my
RdRdc,
Sd d
°°
¿
°°
¾
½
°°
¯
°°
®
»»»»
¼
º
««««
¬
ª
��
»»»»
¼
º
««««
¬
ª
��
( 6.27)
and at all cross sections along their length:
NORSOK standard N-004 Rev. 3, February 2013
NORSOK standard Page 19 of 264
0.1Ȝfor1.45Ȗ
1.0Ȝ0.5forȜ0.600.85Ȗ
0.5Ȝfor 1.15Ȗ
sM
ssM
sM
!
dd�
�
( 6.22)
where
h
2
h
Sdp,c
c
Sdc,s Ȝ
fı
Ȝf
ıȜ �¸
¸¹
·¨¨©
§��
l
( 6.23)
where fcl is calculated from Equation ( 6.6) or Equation ( 6.7) whichever is appropriate and fh from Equation ( 6.17), Equation ( 6.18), or Equation ( 6.19) whichever is appropriate.
ec
yc f
fȜ
l
, and he
yh f
fȜ
( 6.24)
fcle and fhe is obtained from Equation ( 6.8), and Equation ( 6.20) respectively. Vp,Sd is obtained from Equation ( 6.16) and
W
MM
ANı
2Sdz,
2Sdy,Sd
Sdc,
��
( 6.25)
NSd is negative if in tension.
6.3.8 Tubular members subjected to combined loads without hydrostatic pressure
6.3.8.1 Axial tension and bending Tubular members subjected to combined axial tension and bending loads should be designed to satisfy the following condition at all cross sections along their length:
0.1M
MM
NN
Rd
2Sdz,
2Sdy,
75.1
Rdt,
Sd d�
�¸¸¹
·¨¨©
§
( 6.26)
where
My,Sd = design bending moment about member y-axis (in-plane) Mz,Sd = design bending moment about member z-axis (out-of-plane) NSd = design axial tensile force
If shear or torsion is of importance, the bending capacity MRd needs to be substituted with MRed,Rd calculated according to subclause 6.3.8.3 or 6.3.8.4.
6.3.8.2 Axial compression and bending
Tubular members subjected to combined axial compression and bending should be designed to satisfy the following condition accounting for possible variations in cross-section, axial load and bending moment according to appropriate engineering principles:
0.1
NN
1
MC
NN
1
MC
M1
NN
5.02
Ez
Sd
Sdz,mz
2
Ey
Sd
Sdy,my
RdRdc,
Sd d
°°
¿
°°
¾
½
°°
¯
°°
®
»»»»
¼
º
««««
¬
ª
��
»»»»
¼
º
««««
¬
ª
��
( 6.27)
and at all cross sections along their length:
NORSOK standard N-004 Rev. 3, February 2013
NORSOK standard Page 19 of 264
0.1Ȝfor1.45Ȗ
1.0Ȝ0.5forȜ0.600.85Ȗ
0.5Ȝfor 1.15Ȗ
sM
ssM
sM
!
dd�
�
( 6.22)
where
h
2
h
Sdp,c
c
Sdc,s Ȝ
fı
Ȝf
ıȜ �¸
¸¹
·¨¨©
§��
l
( 6.23)
where fcl is calculated from Equation ( 6.6) or Equation ( 6.7) whichever is appropriate and fh from Equation ( 6.17), Equation ( 6.18), or Equation ( 6.19) whichever is appropriate.
ec
yc f
fȜ
l
, and he
yh f
fȜ
( 6.24)
fcle and fhe is obtained from Equation ( 6.8), and Equation ( 6.20) respectively. Vp,Sd is obtained from Equation ( 6.16) and
W
MM
ANı
2Sdz,
2Sdy,Sd
Sdc,
��
( 6.25)
NSd is negative if in tension.
6.3.8 Tubular members subjected to combined loads without hydrostatic pressure
6.3.8.1 Axial tension and bending Tubular members subjected to combined axial tension and bending loads should be designed to satisfy the following condition at all cross sections along their length:
0.1M
MM
NN
Rd
2Sdz,
2Sdy,
75.1
Rdt,
Sd d�
�¸¸¹
·¨¨©
§
( 6.26)
where
My,Sd = design bending moment about member y-axis (in-plane) Mz,Sd = design bending moment about member z-axis (out-of-plane) NSd = design axial tensile force
If shear or torsion is of importance, the bending capacity MRd needs to be substituted with MRed,Rd calculated according to subclause 6.3.8.3 or 6.3.8.4.
6.3.8.2 Axial compression and bending
Tubular members subjected to combined axial compression and bending should be designed to satisfy the following condition accounting for possible variations in cross-section, axial load and bending moment according to appropriate engineering principles:
0.1
NN
1
MC
NN
1
MC
M1
NN
5.02
Ez
Sd
Sdz,mz
2
Ey
Sd
Sdy,my
RdRdc,
Sd d
°°
¿
°°
¾
½
°°
¯
°°
®
»»»»
¼
º
««««
¬
ª
��
»»»»
¼
º
««««
¬
ª
��
( 6.27)
and at all cross sections along their length:
Local buckling Hoop buckling
NORSOK standard N-004 Rev. 3, February 2013
NORSOK standard Page 17 of 264
M
yRdSd
32
fAVV
J d
( 6.13)
where VSd = design shear force fy = yield strength A = cross sectional area JM = 1.15
Tubular members subjected to shear from torsional moment should be designed to satisfy the following condition:
M
ypRdT,SdT,
3D
f2IMM
J d
( 6.14)
where MT,Sd = design torsional moment
Ip = polar moment of inertia = > @44 )t2D(D32
��S
6.3.6 Hydrostatic pressure
6.3.6.1 Hoop buckling Tubular members subjected to external pressure should be designed to satisfy the following condition:
M
hRdh,Sdp,
ff
JV d
( 6.15)
t2DpSd
Sdp, V
( 6.16)
where fh = characteristic hoop buckling strength Vp,Sd = design hoop stress due to hydrostatic pressure (compression positive) pSd = design hydrostatic pressure JM = see 6.3.7
If out-of-roundness tolerances do not meet the requirements given in NORSOK M-101, guidance on calculating reduced strength is given in Clause 12.
,ff yh yhe f44.2ffor ! ( 6.17)
4.0
y
heh f
ff7.0f
»»¼
º
««¬
ª y for yhey f55.0f2.44f !t
( 6.18)
,ff heh yhe f55.0ffor d ( 6.19)
The elastic hoop buckling strength, fhe, is determined from the following equation:
DtEC2f hhe
( 6.20)
where Ch = 0.44 t/D for P t 1.6D/t = 0.44 t/D + 0.21 (D/t)3/P4 for 0.825D/t d P < 1.6D/t = 0.737/(P - 0.579) for 1.5 d P < 0.825D/t