Report1
4
Prob # 36 E= 200 GPa = 200* 10^9 Pa D= 15 mm = 0.015 m ∆T = 0 Solution 0 x< 0.3 0.3< x < 1 From Bcs -------------------------------- -------------------------------- So From Compatibility -------------------------------------- 1 From macro-equilibrium Rl Rr -------------------------2
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Transcript of Report1
Prob # 36 E= 200 GPa = 200* 10^9 Pa D= 15 mm = 0.015 m
∆T = 0
Solution
0 x< 0.3
0.3< x < 1
From Bcs
--------------------------------
--------------------------------
So
From Compatibility
-------------------------------------- 1
From macro-equilibrium
Rl Rr
-------------------------2
From 1 &2
Prob # 79 ∆T = 10
0< x < 0.3
0.3< x <0.6
From Bcs
--------------------------------
--------------------------------
From Compatibility
------------------------------------ 1
At joining point
------------------------------- 2
From 1 & 2
Prob # 80
– ------------ I
0.053 < x < 0.293
---------------------------------
0 < x < 0.3
---------------------------------