Repetition of the CalculationsRepetition of the Calculations Dr. István HULLÁR associate professorDr. István HULLÁR associate professor

Calculation 1

Calculate the organic matter (OM) and the N-free Extract (NFE) content of the following wheat sample!

Calculation 1Calculation 1

organic matter (OM), N-free Extract (NFE)

DM: 900 g/kg,

CP: 120 g/kg,

CF: 30 g/kg,

Ash: 25 g/kg,

EE: 20 g/kg,

NEm: 9.6 MJ/kg.

SolutionSolution

1. OM: DM – Ash = 900-25 = 875 g/kg;

2. NFE: OM – CP – CF – EE = 875 – 120 – 30 – 20 = 705 g/kg.

Calculation 2Calculation 2

Calculate the protein:energy (P:E) ratio of the following turkey diet by using the necessary data!

CP: 29.00%, DCP: 25.00%,

MPE: 12.00%, MPN: 14.00%,

DE: 15.42 MJ/kg, ME: 12.13 MJ/kg,

NEm: 9.00 MJ/kg, NEl: 8.50 MJ/kg,

NEg: 7.00 MJ/kg.

SolutionSolution

P:E ratio: protein (g/kg)/energy (MJ/kg).

But what type of protein and energy are used?

Type of protein and energy used in the given species.

Turkey: CP/ME

CP = 29%, ME = 12.13 MJ/kg;

CP/ME = 290 (g/kg)/12.13 (MJ/kg) = 23.91 g/MJ.

Calculation Calculation 33

Calculate the CP digestibility of corn according to the necessary data of an experiment carried out by pigs!

Feed intake: 6000 g,CP content of the feed: 9%,Faeces output: 2500 g,CP content of faeces: 4%,CP content of urine: 14%.

SolutionSolution

Apparent Digestibility: nutrient intake nutrient output =

nutrient intake (6000*0.09) (2500*0.04) =

(6000*0.09)

540 100 440 = = 0.8148 540 5400.8148*100 = 81.48%.

Feed intake: 6000 g,CP content of the feed: 9%,Faeces output: 2500 g,CP content of faeces: 4%,

Calculation Calculation 44

Calculate the TDN content of the corn silage by using the necessary data!

Calculation Calculation 44

DM: 32.90%, Corn Silage

Nutrients on DM basis (%)

CP: 9.20 EE: 4.20

CF: 20.10 NFE: 61.20

Nutrients’ Digestibility (%)

CP: 55.00 EE: 80.00

CF: 64.00 NFE: 74.00.

SolutionSolution

TDN (g/kg DM): DCP + 2.25*DEE + DCF + DNFECalculation of the TDN

Nutrients g/kg DM Dig. factor TDNCP 92 *0.55 - 50.6EE 42 *0.80 *2.25 75.6 CF 201 *0.64 - 128.6NFE 612 *0.74 - 452.9

707.7 g/kg DM

Calculation Calculation 55

UFPHow many grams of urea can be added to the daily

ration of a beef cattle when 25 kg of corn silage is fed as an only feed?

DM: 32.90%,TDN: 707.7 g/kg DM (if it is not given, the basic data

are required for the calculation of TDN);dg: 69% (on DM basis).

SolutionSolution

UFP (g/kg DM):(1.044*TDN) – dg (g/kg DM)

2.8(1.044*707.7) – 690 = 17.44

2.8g urea/1 kg DM of corn silage;DM content of 25 kg of corn silage = 25*0.329 = 8.225 kg;Amount of urea can be added to 25 kg of corn silage: 8.225*17.44 = 143.5 g.

Calculation Calculation 66

Check the following ration based on its energy content only whether it is sufficient for a limusine bull having 350 kg of body weight and 1300 g/day body weight gain. (Do not calculate with the CF, CP, Ca and P content of the ration!)

Ration: 11 kg corn silage (predough stage),15 kg sugar beet silage, 1.5 kg corn 0.6 kg sunflower extr., average;

Requirements (you will get them)NEm: 31.30 MJ/day; NEg: 19.70 MJ/day.

SolutionSolution

RationFeeds DM, kg NEm, MJ NEg, MJ11 kg corn silage 3.84 26.03 16.2815 kg sugar beet 2.16 16.76 11.04 1,5 kg corn 1.37 12.53 8.63 0,6 kg sunflower 0.54 3.52 2.17Total 7.91 58.84 38.12

Requirements: 31.30 19.70

SolutionSolution

Evaluation

Tolerable level of Energy: 10% of the requirement;

a) NEm

7.91 kg DM contains 58.84 MJ

x kg DM contains 31.30 MJ (requirement)

x = 31.30/58.84*7.91 = 4.21 kg DM contains the energy level for maintenance;

DM remained for gain: 7.91-4.21 = 3.7 kg.

SolutionSolution

b) NEg 7.91 kg DM contains 38.12 MJ

3.70 kg DM contains x MJ

x = 3.70/7.91*38.12 = 17.83 MJ (requirement: 19.70 MJ);

Difference: 19.70-17.83 = 1.87 MJ;

How many % is the difference of the requirement?

1.87/19.70*100 = 9.49% (the tolerable level is 10%, O.K.);

the ration can cover the energy requirement of the bull.

Calculation Calculation 77

1. How many kg of milking concentrate is required for producing 1 kg of milk when the milk fat is 3.7%, the milk protein is 3.4%?

Do not calculate with the Ca and P content of the concentrate!The components of the milking concentrate are as follows.

0.4 kg sunflower meal, extr. (average),0.6 kg corn.

SolutionSolution

Milking concentrateFeeds DM, kg NEl, MJ MPE, g MPN, g

0.4 kg sunflower 0.358 2.27 51 93

0.6 kg corn 0.547 4.66 61 39

1.0 kg 0.905 6.93 112 132

Which MP value is valid?

.

SolutionSolution

1. How many kg of milking concentrate is required for producing 1 kg of milk when the milk fat is 3.7%, the milk protein is 3.4%?

1. Calculation on energy basisNEl requirement of 1 kg milk: 1.471 + 0.4032*milk fat (%) = 1.471 + 0.4032*3.7 = 2.96 MJ;,

1 kg milking concentrate contains 6.93 MJ NEl x kg milking concentrate contains 2.96 MJ NEl x = 2.96/6.93 = 0.427 kg milking concentrate is required for producing 1 kg milk.

SolutionSolution

1. How many kg of milking concentrate is required for producing 1 kg of milk when the milk fat is 3.7%, the milk protein is 3.4%?

2. Calculation on protein basisMP requirement of 1 kg milk: Milk protein (g/kg)/0.65 = 34/0.65 = 52 g;

1 kg milking concentrate contains 112 g MP x kg milking concentrate contains 52 g MP x = 52/112 = 0.464 kg milking concentrate is required for producing 1 kg milk.

On energy basis: 0.427 kg on protein basis: 0.464 kg???MP is the limiting factor;Answer 1: 0.464 kg of milking concentrate is required for

producing 1 kg of milk.

SolutionSolution

2. Supplement the milking concentrate with 0.5% of premix and 0.5% of salt! Which component of the milking concentrate (sunflower or corn?) must be reduced by 1% owning to the supplementation?

Answer 2: MP is the limiting factor, supplementation is made in account of the energy rich compound (corn).

3. As the final solution, write down the new receipt of the milking concentrate!

Answer 3: 40% sunflower meal 59% corn 0.5% premix 0.5% salt100%.

Calculation Calculation 88

Check the following TMR whether it can cower the Ca and P requirement of the following dairy cow! (Do not calculate with the other nutrients!);

In case of Ca or P deficiency please correct the TMR by using the adequate mineral supplements.

Calculation Calculation 88

1. Data Sheet

- TMR

meadow hay (average): 5.0 kg,

corn silage (predough stage): 15.5 kg

sunflower meal extr. (average): 2.6 kg,

CCM (Corn Cob Mix): 8.4 kg;

- Data regarding the dairy cow

W: 580 kg, milk production: 25 kg/day,

2nd lactation.

SolutionSolution

2. Nutrient RequirementsMaintenanceCa requirement: 44*0.001*W = 25.52 g/day;P requirement: 34*0.001*W = 19.72 g/day;Correction2nd lactation: +10% of the total maintenance req. (see

later).

SolutionSolution

2. Nutrient RequirementsMilk ProductionCa requirement: 2.8 g/kg milk;

25 kg milk = 25*2.8 = 70.00 g/day;P requirement: 1.7 g/kg milk;

25 kg milk: 25*1.7 = 42.50 g/day.

SolutionSolution

Sum of the RequirementsCa P (g) (g)

Maintenance 25.52 19.72+10% 2.55 1.9725 kg milk 70.00 42.50TOTAL 98.07 64.19

SolutionSolution

DM, Ca, and P Content of the TMR DM Ca P

Feeds (kg) (g) (g) 5.0 kg hay 4.37 20.98 12.2415.5 kg silage 5.41 17.85 13.52 2.6 kg sunfl. 2.33 7.22 17.47 8.4 kg CCM 5.28 3.17 13.20TOTAL 17.39 49.22 56.43

SolutionSolution

Ca (g)Requirement: 98.07TMR: 49.22Difference: - 48.85Tolerable level: 2.8*2 = 5.6Evaluation: insufficient

P (g)Requirement: 64.19TMR: 56.43Difference: - 7.76Tolerable level: 1.7*2 = 3.4Evaluation: insufficient.

SolutionSolution

CorrectionsTypes of Ca and P supplementsName Ca (g) P (g)Limestone 380 -AP-17 210 170AP-18 190 180Phylafor 40 125AP-IV 17 170

SolutionSolution

Corrections1. Correction of the P deficiency by AP-IV:

1000 g AP-IV contains 170 g P x g AP-IV contains 7.76 g Px = 7.76/170*1000 = 45.65 g AP-IV

2. Calculation of the amount of Ca given by AP-IV:1000 g AP-IV contains 17 g Ca 45.65 g AP-IV contains x g Cax = 45.65/1000*17 = 0.78 g Ca.

SolutionSolution

Corrections3. Calculation of the Ca deficiency remained:

48.85 – 0.78 = 48.07 g;4. Correction of the Ca deficiency by limestone:

1000 g limestone contains 380 g Ca x g limestone contains 48.07 g Cax = 48.07/380*1000 = 126.50 g limestone.

SolutionSolution

Final Evaluation

- 45.65 g AP-IV and 126.50 g limestone supplementations are required.