Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices,...

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Remark: Commutation of Operators Since operators are matrices, they do not necessarily commute We define the commutator of the operators A and B as The properties of most physically important operators (e.g. X, P, L, S,…) can generally be deduced solely from their commutation relations BA AB ! [ ] BA AB B A ! = ,

Transcript of Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices,...

Page 1: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Remark: Commutation of Operators

• Since operators are matrices, they do not

necessarily commute

• We define the commutator of the operators A

and B as

• The properties of most physically important

operators (e.g. X, P, L, S,…) can generally be

deduced solely from their commutation

relations

BAAB !

[ ] BAABBA !=,

Page 2: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Lecture 5: Postulates of QM

MOTIVATION TO STUDY QM:

• Quantum mechanics underlies Nuclear,Particle, Condensed Matter, and Atomicphysics (and is thus very important forAstronomy and Astrophysics)

• Quantum mechanics explains the periodictable and Chemistry

• When tested, Quantum Mechanics has alwaysbeen found to be correct

– Some predictions of QM tested to ten decimalplaces of precision

• Quantum Mechanics is self-consistent, thereare no ‘paradoxes’

– So called ‘paradoxes of QM’ are merely pointswhere its predictions conflict with ‘classical’intuition about the nature of reality

• The ‘meaning’ of Quantum Mechanics is not‘understood’

– The key difficulty is the origin of the randomnessinherent in QM

– Is true randomness logically tenable?

– Very different interpretations are equally valid

• Many-worlds, Bohmian mechanics,…

Page 3: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Question #1

• Suppose a particle has the wavefunction:

• If the position of the particle is measured, what

will the result of the measurement be?

220 2)(

4 2

1)(

!

"!# xx

ex$$

=

Statement of the Postulates

1. At a fixed time t0, the state of a physical system is

defined by specifying a ket |!(t0)" belonging to the

state space of the system

2. Every measureable physical quantity is describedby a Hermitian operator A acting in the state spaceof the system. This operator is called an‘observable’

3. The only possible result of the measurement of thephysical property associated with the observable Ais one of the eigenvalues of A.

4. When the observable A is measured on a system inthe normalized state |!" , the probability of obtainingeigenvalue a is:*

5. If the measurement of the observable A on thesystem in stqte |!" gives the result a the state of thesystem immediately after the measurement is

6. The time evolution of the state vector is governedby Schrödinger's equation:

where H is the operator associated with the totalenergy of the system

aIaP =)(

!! Ht

i ="

"h

!!

!!

a

a

I

I' =

Page 4: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #1

At a fixed time t0, the state of an isolated physicalsystem is defined by specifying a ket |!(t0)"belonging to the state space of the system

Postulate #2

Every measureable physical quantity is described

by a Hermitian operator A acting in the state

space of the system. This operator is called an

‘observable’

Page 5: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #3

The only possible result of the measurement of

the physical property associated with the

observable A is one of the eigenvalues of A.

mmA

A

maamaA

aaaA

nnn

nnn

,,

,,

!!!

!!!

=

=

=

=

Postulate #4

• When an observable is measured, the

probability of obtaining a particular eigenvalue

is given by the expectation value of the

projector onto the subspace associated with

that eigenvalue.

subspace

Page 6: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #4a

For the case of a discrete non-degenerate

eigenvalue:

When the observable A is measured on a systemin the normalized state |!" , the probability of

obtaining eigenvalue an is

2

2

)(

n

n

nn

an

c

a

aa

IaPn

=

=

=

=

!

!!

Projector onto

eigenvector |an"

!nn

nna

nnn

ac

aaI

aaaA

n

=

=

=

Postulate #4b

For the case of a discrete eigenvalue with a

discrete degeneracy:

When the observable A is measured on a systemin the normalized state |!" , the probability of

obtaining eigenvalue an is

!

!

!

=

=

=

=

=

=

=

n

n

n

n

d

m

mn

d

m

n

d

m

nn

an

c

ma

mama

IaP

1

2

,

1

2

1

,

,,

)(

"

""

Here dn is the degree of degeneracy of

the eigenvalue an

Projector onto

degenerate

subspace

associated

with eigenvaluea

n!mac

mamaI

maamaA

nmn

M

m

nna

nnn

n

n

,

,,

,,

,

1

=

=

=

"=

Page 7: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #4c

For the case of a continuous non-degenerate

eigenvalue:

When the observable A is measured on a systemin the normalized state |!" , the differential

probability dP(#) of obtaining a result between #and # + d# is:

!!"

!"!

!"!!"

!!!

d

d

d

dIdP

2

2

)(

)()(

=

=

=

=

Projector

onto

eigenstate|#"!""!

"""

"""

=

=

=

)(

)(I

A

Postulate #4d

For the case of a continuous eigenvalue with a

discrete degeneracy:

When the observable A is measured on a systemin the normalized state |!" , the probability dP(#)

of obtaining a result between # and # + d# is:

!!"

!"!

!"!!"

!!

!

!

!

d

dm

dmm

IdP

M

m

m

M

m

M

m

#

#

#

=

=

=

=

=

=

=

)(

1

2

)(

1

2

)(

1

)(

,

,,

)()(

Projector

onto

degenerate

subspace

associated

with

eigenvalue#

!""!

"""

"""

"

m

mmI

mmA

m

M

m

,)(

,,)(

,,

)(

1

=

=

=

#=

Page 8: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #4e

• Additional cases:]

– A discrete eigenvalue with a continuous

degeneracy

– A continuous eigenvalue with a continuous

degeneracy

• Additional topics

– Imperfect measurements

– Strong versus weak measurements

– Single measurements of ensembles of identical

systems

• These topics will be covered in the homework

Postulate #5

• Once the measurement is complete and the

result is obtained, the state of the system after

the measurements is given by the projection of

the state before the measurement onto the

subspace associated with the resulting

eigenvalue.

– The new state should be re-normalized to unity.

Page 9: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #5a

The case of a discrete non-degenerate spectrum

•The spectrum of an operator is a list of its eigenvalues and

associated degeneracies

If the measurement of the observable A on the systemin state |!" gives the result an, the state of the system

immediately after the measurement is the normalized

projection onto the subspace associated with an :

!!

!!

!!

n

n

a

a

I

I="

"#

na=!"

!!

!!

nn

nn

aa

aa="

!

!!

n

n

n

a

aa="

Just a global

phase factor

Postulate #5b

The case of a discrete spectrum with a discrete

degeneracy

If the measurement of the observable A on thesystem in state |!" gives a result between #1 and

#2, the state of the system immediately after he

measurement is:

!=

=

="

"#

n

n

n

d

m

nna

a

mamaI

I

I

1

,,

2

1$$

$$

$$

%%

Page 10: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #5c

The case of a continuous non-degenerate spectrum

If the measurement of the observable A on thesystem in state |!" gives a result between #1 and #2,

the state of the system immediately after he

measurement is:

– The interval (#1, #

2) would correspond to the

resolution of the detector

!=

="

"#

2

1

2

1

2

1

2

1

$

$

$$

$$

$$

$$$

%%

%%

%%

dI

I

I

Postulate #5d

• Additional cases:

– Discrete spectrum with continuous degeneracy

– Continuous spectrum with discrete degeneracy

– Continuous spectrum with continuous

degeneracy

Page 11: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and

Postulate #6

The time evolution of the state vector |!(t)" isgoverned by the Schrödinger equation:

Where H is the observable associated with the

total energy of the system

– H is called the ‘Hamiltonian’

)()( tHtdt

di !! =h

How to evolve a state in time:

Page 12: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and
Page 13: Remark: Commutation of OperatorsRemark: Commutation of Operators •Since operators are matrices, they do not necessarily commute •We define the commutator of the operators A and