Relational Algebra continues…
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Transcript of Relational Algebra continues…
ASETRename Operation
• Allows us to name, and therefore to refer to, the results of relational-algebra expressions.
• Allows us to refer to a relation by more than one name.• Example:
x (E)
returns the expression E under the name X• If a relational-algebra expression E has arity n, then
returns the result of expression E under the name X, and with theattributes renamed to A1 , A2 , …., An .
)(),...,,( 21E
nAAAx
ASETComposition of Operations
• Can build expressions using multiple operations• Example: A=C(r x s)
• r x s
• A=C(r x s)
A B
11112222
C D
1010201010102010
E
aabbaabb
A B C D E
122
101020
aab
ASET
Banking Examplebranch (branch_name, branch_city, assets)
customer (customer_name, customer_street, customer_city)
account (account_number, branch_name, balance)
loan (loan_number, branch_name, amount)
depositor (customer_name, account_number)
borrower (customer_name, loan_number)
ASETExample Queries
• Find all loans of over $1200
Find the loan number for each loan of an amount greater than $1200
amount > 1200 (loan)
loan_number (amount > 1200 (loan))
Find the names of all customers who have a loan, an account, or both, from the bank
customer_name (borrower) customer_name (depositor)
ASETExample Queries
• Find the names of all customers who have a loan at the Perryridge branch.
Find the names of all customers who have a loan at the Perryridge branch but do not have an account at any branch of the bank.customer_name (branch_name = “Perryridge”
(borrower.loan_number = loan.loan_number(borrower x loan))) –
customer_name(depositor)
customer_name (branch_name=“Perryridge”
(borrower.loan_number = loan.loan_number(borrower x loan)))
ASETAdditional Operations
• Additional Operations
– Set intersection– Natural join– Aggregation– Outer Join– Division
• All above, other than aggregation, can be expressed using basic operations we have seen earlier
ASETNatural Join Operation – Example• Relations r, s:
A B
12412
C D
aabab
B
13123
D
aaabb
E
r
A B
11112
C D
aaaab
E
s
r s
ASET
Notation: r s
Natural-Join Operation
• Let r and s be relations on schemas R and S respectively. Then, r s is a relation on schema R S obtained as follows:
– Consider each pair of tuples tr from r and ts from s.
– If tr and ts have the same value on each of the attributes in R S, add a tuple t to the result, where
• t has the same value as tr on r
• t has the same value as ts on s
• Example:R = (A, B, C, D)S = (E, B, D)– Result schema = (A, B, C, D, E)– r s is defined as:
r.A, r.B, r.C, r.D, s.E (r.B = s.B r.D = s.D (r x s))
ASETAggregate Functions and Operations• Aggregation function takes a collection of values and returns a single value as
a result.avg: average valuemin: minimum valuemax: maximum valuesum: sum of valuescount: number of values
• Aggregate operation in relational algebra
E is any relational-algebra expression– G1, G2 …, Gn is a list of attributes on which to group
– Each Fi is an aggregate function
– Each Ai is an attribute name
)()(,,(),(,,, 221121E
nnn AFAFAFGGG
ASETAggregate Operation – Example
• Relation account grouped by branch-name:
branch_name g sum(balance) (account)
branch_name account_number balance
PerryridgePerryridgeBrightonBrightonRedwood
A-102A-201A-217A-215A-222
400900750750700
branch_name sum(balance)
PerryridgeBrightonRedwood
13001500700
ASET
Aggregate Functions (Cont.)• Result of aggregation does not have a name
– Can use rename operation to give it a name– For convenience, we permit renaming as part of aggregate operation
branch_name g sum(balance) as sum_balance (account)
ASET
Q1. Consider the following relational database, where the primary keys are
underlined. Give an expression in the relational algebra to express each of the
following queries:
employee( person_name, street, city)
Works(person_name, company_name, salary)
company( company_name, city)
manages(person_name, manager_name)