Rakshk Wlc

RAKESH ASERY (09EC73)

EXPERIMENT NO:- {1}

Object:-

Design a microstrip rectangular patch with dielectric substrater=2.2&highth=0.1588cm.atresonancefrequencyfr=10GHz.

Solution:-Given:- Microstriprectangular patch

r=2.2,h=0.1588cm.&fr=10GHz

(a)Width:- =( )

where =Lightvelocity=3x10^10cm/sec.

w=^

^ ( . ) =1.1858cm.

(b)Effectivepermittivity:- eff = + ( )( / )

eff =2.2 + 1

2 +(2.2 1)

2 (1 + 12X0.1588/1.1858) = 1.97

(c)Incrementlength:- L =. ( . ) .

( . ) .

L =. . ( . . )( .. . )

( . . )( .. . )

L =0.083cm.

(d)Actuallength:- 2

=

= 3x10^1010^10 . =2.1365cm.

NowL=2.1365/2 2X0.083=0.9019cm.

(e)Effectivelength:- Leff=L+2 L

Leff =0.9019+2X0.083=1.068cm.


RESULT:- We have successfully microstrip rectangular patch antenna.


EXPERIMENT NO:- {2}

Object:-

Design a microstrip circular patch using dielectric substrate having &highth=0.1588cm.atresonancefrequency fr=10GHz.

Solution:-Given:- Microstripcircularpatch

Radius:- =( . )

Where F= . ^

F= . ^^ .

=0.5926cm.

Now = ..

. . (.

. . )=0.527cm.


RESULT:- We have successfully microstrip circular patch antenna.


EXPERIMENT NO:- {3}

OBJECT:-Plot the pattern of YAGI-UDA wire antenna-

Given :-

Frequency=1GhzandDipoleradius(r)isL/100

NumberofDirectorsare4.

Ans.:-

WeknowthatReflectorlength(L)is=0.48C/fand

FedElementlength(l)is=0.46C/f,

SpacingbetweenReflectorandFedElement(r1)is=0.25C/f.

SpacingbetweenDirectoraandDirectorbis(r2)=0.31C/f.(wherea,bare1,22,33,4).

LengthofDirectors(L1,L2,L3,L4)is0.44C/f,.043C/f,0.40C/frespectevelly.

SOthatBycalculation:-

L=14.4cm,r=0.144cm,l=13.8cm

L1=13.2cm,L2=13.2cm,L3=12.9cm,L4=12.0cm

r1=7.5cm,r=9.3cm.


Yagi Array Antenna (Rectangular Plot)


Polar Plot of Yagi Array Antenna


3-D Plot of Yagi Array Antenna

RESULT:- We have successfully design Yagi-Uda antenna.


EXPERIMENT NO:- {4}

OBJECT:-Plot the pattern of Half-wave Dipole antenna with frequency 900MHz.

Given:- Frequency f=900MHz

The length of Dipole antenna given as =( )

= = 15.88 cm.

The radius of Dipole antenna given as r= L/100

r =15.88/100 = 0.1588cm.


RESULT:- We have successfully design half-wave dipole antenna.


EXPERIMENT NO:- {5}

OBJECT:-Plot the pattern of DRCS (Dipole Radar Cross Section) with frequency 3GHz.

Given: - DRCS Antenna frequency f=3GHz

We now that length of DRCS antenna = 0.6x

Where (operating wavelength)=c/f

Wherec=lightvelocity(3x10^8m/sec.)Now =3x10^8/3x10^9=0. 1m.

And = 0.6x10 =6cm.

The Dipole radius r=0.0002x

r=0.0002x 10 =0.002cm.


RESULT: - We have successfully design DRCS (Dipole Radar Cross Section) antenna.


EXPERIMENT NO:- {6}

OBJECT:-Plot the pattern of Loop antenna (electrically larger) with frequency 1GHz.

Given: - Loop antenna frequency f=1GHz

We now that Loop radius for Loop antenna r= /2



Andr=30/2

Whenthewireradiusrw = 0.001x

rw =0.001x30 = 0.03cm.


Impedanceplot


PolarPatternPlot

RectangularPatternPlot


3DPatternPlot


Whenthewireradiusrw = r/100

rw =4.78/100 = 0.0478cm.

Impedanceplot


PolarPatternPlot

RectangularPatternPlot


3DPatternPlot

RESULT:- We have successfully design Loop antenna (electrically larger) .


EXPERIMENT NO:- {7}

OBJECT:-Plot the pattern of V-Dipole antenna with frequency 1GHz.

Given: - V-Dipole antenna frequency f=1GHz

We now that V-Dipole antenna length = 0.475x



And = 0.475x30/2 =7.125cm.

Wireradiusr = 2 /100

r =2x7.125/100

r = 0.1425cm.


V-DipoleantennaAnalysiswhenangleb/warms=75


V-Dipoleantenna 3Dpatternwhenangleb/warms=150

RESULT: - We have successfully design V- Dipole antenna.


EXPERIMENT NO:- {8}OBJECT:-To design a Long periodic dipole array (LPDA) antenna workingBetween frequency f1 = 0.060 GHz and f2 = 0.300 GHz.

Solution:-

Various calculations required for plotting the antenna pattern can be solved asGiven below Given Frequency f1 = 0.060 GHzFrequency f2 = 0.300 GHz

Log ( Or f2 or


Long periodic dipole array (LPDA) Antenna

Figure: Long periodic dipole array (LPDA) Antenna Design

Figure: Geometry of Long periodic dipole array (LPDA) Antenna


Figure: Long periodic dipole array (LPDA) Antenna analysis

Figure: Long periodic dipole array (LPDA) Antenna analysis, calculation of dipole dimensions


RESULT: - We have successfully design a Long periodic dipole array (LPDA) antenna working between frequency f1 = 0.060 GHz and f2 = 0.300 GHz.


EXPERIMENT NO:- {9}

OBJECT:-To Design A Finite Wire Dipole Array Antenna With Operating Frequency 3GHz.

Solution:-

Length of Antenna (L) = 0.05 = 0.5cm Radius of Antenna(R) = 0.00001 = 0.00001cm Spacing: X-axis = 0.05 cm = 0.5cm Y-axis = 0.1 cm = 1.0cm


Finite Wire Dipole Array (Rectangular plot)


Finite Wire Dipole Array (Polar plot)

Finite Wire Dipole Array (3-D plot)


Finite Wire Dipole Array (Wire Geometry)

RESULT: - We have successfully design A Finite Wire Dipole Array Antenna.


EXPERIMENT NO:- {11}

OBJECT:-To design a Uniform Linear Array with frequency 1GHz.

Solution:- Frequency = 1GHz Wavelength ( ) =30cm.

No. of element =5

Element spacing = ((N-1) / N) x ( /4)


RESULT: - We have successfully design a Uniform Linear Array.



OBJECT:-To Design A Uniform Circular Array Having Operating Frequency 3GHz. And Also Find Their Directivity in Following Case

An Array Having Isotropic Element. An Array Having Rectangular Patch Element.



Case 1:Element spacing =0.6 =6cm. Outer Radius=1 =10cm.No. Of Element =9Directivity=11.6dB


Case 2:Element spacing =0.5 =5cm.

Outer Radius=5 =50cm. No. Of Element =31 Directivity=30.0dB


RESULT: - We have successfully design A Uniform Circular Array and also find their Directivity in given Cases.



OBJECT:-To Design An Infinite Printed Dipole Array Having Operating Frequency 3GHz.


E And H Plane Spacing=0.5 =5cm

Plane Spacing=0.5 =5cm.

Dipole Length=0.39 =3.9cm.

Width=0.02 =0.2cm.

Dielectric Constant (r) =2.55

Substrate Thickness=0.19 =1.9cm

Elevation Step Size=30


RESULT: - We have successfully design An Infinite Printed Dipole Array.



OBJECT:-To design a Uniform Rectangular Array having operating

frequency 3GHz and also find their directivity in following case

A 22 Broadside Array Having Isotropic Element For A 44 Planar Array Having X-Polarized Rectangular Patch Element For

A 84 Planar Array Having X-Polarized Rectangular Patch Element For

Solution:- Frequency = 3GHz

Wavelength ( ) =10cm.

Case 1:- Element spacing in Y-Direction (dy) = /2=5cm.

Element spacing in X-Direction 5cm.

No. Of Element in X-Direction=2

No. Of Element in Y-Direction=2


Uniform Planar Array Antenna (Rectangular Plot)


Uniform Planar Array Antenna (Polar Plot)

Uniform Planar Array Antenna (3-D Plot)


Case 2:Element spacing in Y-Direction (dy) = /2=5cm.

Element spacing in X- 0.5774( ) cm = 5.774cm


No. Of Element in Y-Direction=2 Uniform Planar Array Antenna (Rectangular Plot)



Case 3:Element spacing in Y-Direction (dy) = /2=5cm.

Element spacing in X- 2.887cm.


No. Of Element in Y-Direction=4


Uniform Planar Array Antenna (Rectangular Plot)




RESULT: - We have successfully design Uniform Rectangular Array having operating frequency 3GHz and also find their directivity in given cases.

Rakshk Wlc

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