Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w =...
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Transcript of Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w =...
![Page 1: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/1.jpg)
Questions about Sound in pipes
![Page 2: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/2.jpg)
Equations and facts needed to solve the subsequent problems
• vw = 331 +0.6t
• v = λf
Length of pipe between any two harmonics = ½ λ
• For an Open pipe: fundamental λ = 2L– Subsequent harmonics at 2f1, 3f1, 4f1…
• For Closed pipe: Fundamental λ = 4L– Subsequent harmonics at 3f1, 5f1,7f1…
![Page 3: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/3.jpg)
Q1
• A 440 Hz tuning fork is held above a closed pipe. Find the spacing between resonances when air temp is 20°C in centimeters and meters
![Page 4: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/4.jpg)
Q2
• 440 Hz tuning fork is used with a resonating column to determine the velocity of sound in Helium gas. If the spacing between resonances are 110 cm, what is the velocity of sound in helium gas?
![Page 5: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/5.jpg)
Q3
• The frequency of a tuning fork is unknown. A student uses an air column at 27°C and find resonances spaced by 20.2 cm. What is the frequency of the tuning fork?
![Page 6: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/6.jpg)
Q4
• A bugle can be thought of as an open pipe. If a bugle were straightened out, it would be 2.65 m long.
• A) If the speed of the sound was 343 m/s, find the lowest frequency that is resonant for the bugle.
• B) Find the next 2 resonant frequencies for the bugle.
![Page 7: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/7.jpg)
Q5
• The auditory canal leading to the eardrum is a closed pipe that is 3.0 cm long. Find the approximate value of the lowest resonance frequency.
![Page 8: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/8.jpg)
Q6
• If you hold a 1.2 m aluminum rod in the center and hit one end with a hammer, it will oscillate like a open pipe. The speed of sound in aluminum is 5150 m/s. What would be the bar’s lowest frequency of oscillation?
![Page 9: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/9.jpg)
Q7
• A flute acts as an open pipe. If a flute sounds a note with a 370 Hz pitch, what are the frequencies of the 2nd, 3rd, and fourth harmonics of this pitch
![Page 10: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/10.jpg)
Q8
• A clarinet sounds the same note with a 370 Hz pitch as the flute in the previous problem. The clarinet, however, is a closed pipe. What are the frequencies of the 2nd, 3rd, and 4th harmonics produced by this instrument?
![Page 11: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/11.jpg)
Q9
• A guitar string is 65.0 cm long and is tuned to produce a lowest frequency of 196 Hz.
• A) Is the guitar treated as a open or closed end resonator?
• B) what is the speed of the wave on the string?
![Page 12: Questions about Sound in pipes. Equations and facts needed to solve the subsequent problems v w = 331 +0.6t v = λf Length of pipe between any two harmonics.](https://reader036.fdocuments.in/reader036/viewer/2022071807/56649e2a5503460f94b18447/html5/thumbnails/12.jpg)
Q10
• The lowest note produced from a pipe organ is 16.4 Hz.
• A) What is the shortest open pipe that will resonate at this frequency?
• B) What is the pitch if the same organ pipe is closed?