Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation...

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Quantum ElectroDynamics III Dr.Farida Tahir Physics department CIIT, Islamabad Feynman diagram

Transcript of Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation...

Page 1: Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation of relevant Feynman diagram to determine the amplitude M for the process. Kinematical

Quantum ElectroDynamics III

Dr.Farida TahirPhysics department

CIIT, Islamabad

Feynman diagram

Page 2: Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation of relevant Feynman diagram to determine the amplitude M for the process. Kinematical

Human Instinct

What? Why?

How?

Feynman diagrams Feynman diagrams

Feynman diagrams

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What?Graphic way to represent exchange forces

Developed by Richard Feynmanwhen working on the development of

QED

Describing a variety of particle interactions

1942

Page 4: Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation of relevant Feynman diagram to determine the amplitude M for the process. Kinematical

Why ?

Decay rates and Scattering cross section

To calculate

Page 5: Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation of relevant Feynman diagram to determine the amplitude M for the process. Kinematical

Calculation of Decay rates and Scattering cross sections

Need two informationDynamical

Evaluation of relevant Feynman diagram todetermine the amplitude M for the process.

KinematicalThe phase space factor, it depends on the masses, energies, and momenta of the participants.

Page 6: Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation of relevant Feynman diagram to determine the amplitude M for the process. Kinematical

Ingredients (Rules)

Recipe (Structure)

How?

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Feynman rules:Electron (e-) & Positron (e+)(Dirac eq.)Photons(Maxwell eq.)

Dirac Equation in electromagnetic field(concept of gauge symmetry)

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The Feynman rules for

Electron (e-) Positron (e+)

021 =vv021 =uu Orthogonal

mcvv 2−=mcuu 2= Normalized

( )mcpvv s

s

s −=∑=

λλγ

2,1( )mcpuu

s

ss +=∑=

λλγ

2,1

Completeness

( ) 0=−mcPu λλγ ( ) 0=+mcPv λ

λγAdjoint

( ) 0=− umcPλλγ ( ) 0=+ vmcPλ

λγDirac

( ) ( ) ( )PuaeX sPXi .h

=ψ ( ) ( ) ( )PvaeXPXi .

h=ψFree

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The Feynman rules for (γ)

Photon (γ)

( ) ( ) ( )saeXAPXi

μμ ε.

h

=

Orthogonal

Normalized

( ) ( ) jiijs

jsis pp ˆˆ2,1

)()( −=∑=

δεε Completeness

Lorentz condition

Free

0=μμε P

0)2(*)1( =μ

μ εε

1* =μμ εε

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Complete Lagrangian for f & γ

Lagrangian density describing the fermionic field in the presence of an electromagnetic field is

( )[ ] λλ

λνλν

λλλγ AJFFXmqAiX −−Ψ−−∂Ψ=

41)()(L

[ ] ( ) λλλ

λνλν

λλ γγ AXXqJFFXmiX )()(

41)()( ΨΨ+−−Ψ−∂Ψ=L

Current produce by Dirac particle

Current coupled to Aλ, describe the interaction vertex.

Feynman diagram

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Structure of Feynman Diagrams

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Fermions represented by straight lines with arrows pointing in direction of time flow

Forward-facing arrows represent particles

Backward-facing arrows represent antiparticles

Photons and weak bosons, W- and W+ and Z0 are squiggly lines

Gluons are curly lines

Structure of Feynman Diagrams

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Line types

External lines• Enter and leave diagram• Represent real “observable” particles

real particles and must have E2 = p2 + m2

Referred to as particle being on “mass shell”

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Internal linesConnect vertices, called propagatorsRepresent “virtual” particles that cannotbe observedDo not have to obey relativistic mass,

energy, momentum relationship: (mc2)2= E2- (pc)2

Referred to as particle being off “mass shell”

Line types

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At the point of emission (or absorption) the vertices gives a contradiction with Einstein relation between energy and mass.

Virtual

VerticesConserve: energy, momentum, & charge for all

types of interactionsDetermine order of perturbation contributes to the particular calculationSame number of arrows enter as leave

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How to write currents by using F.D

For each QED vertex, write factor μγei

For each internal photon line having momentum k write factor

εαβ

αβ ikg

ikiD F += 2)(α β

For each internal lepton line having momentum p write factor

εε impmp

impipiS F +−

+=

+−= 22

1)(

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For each external (initial) fermions)(pur

For each external (final) fermions)(pur

For each external (initial) anti-fermions)(pvr

For each external (final) anti - fermions)(pvr

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αkFor each initial photon )(krαε

kαFor each final photon )(* krαε

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ExamplesBasic vertices

ElectromagneticCharge particle enters, emits (or absorbs) a

photon and exits.

- ieγμ137

12

==c

eh

α

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Current

)()( 22 puiepKuJ rr νν γ+=

+= μ

μ JJL

ε

μνμν

ikgikiD+

= 2)(

μ

ν

p'p

K

2p2pK +

)'()( pueipuJ rr μμ γ=

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)()()'()( 222 puiepKuiK

gipuiepuM rrrrfi ν

μν

μ γε

γ +−

=

)()()'()( 222

2

pupKupupuiK

ei rrrrμ

μ γγε

+−

−=

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Scattering

Elastic

Mott Møller

Bhabha

μμ ee → eeee →

+−+− → eeee

Inelastic

Compton

Pair production

Pair annihilation

Muon productionγγ→+−ee

+−+− → μμee

+−→ eeγγ

γγ ee →

Lowest Order Fundamental Processes

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+−+− +→+ eeee

γγ +→+ +− ee+− +→+ eeγγ

γγ +→+ −− ee

Scattering

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Møller scattering

Electron-electron scattering (Moller scattering)Two electron enters, a photon passes between them

eeee →

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Bahabha scattering +−+− → eeee

Twist into any topological configuration

Particle line running backward in time is interpreted as the corresponding antiparticle going forward

Rule:

e-e+ annihilate to form a photon which produces a new e-e+

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Bhabha & Moller scattering are related by cross symmetry

BADC

DBCA

DCBA

+→+

+→+

+→+

+−+− +→+ 4321 eeee

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Compton scattering

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Remember

Dominant contribution comes from tree level

Ignore higher order contribution

13712

==c

eh

α

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QED InteractionsHigher order diagrams

Charge screening

Page 30: Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation of relevant Feynman diagram to determine the amplitude M for the process. Kinematical
Page 31: Quantum ElectroDynamics III · Scattering cross sections Need two information Dynamical Evaluation of relevant Feynman diagram to determine the amplitude M for the process. Kinematical

Recall

Forces coupling Strength Range Particles

Strong αs 1 10-15 Gluons; m=0

Electromagnetic α 1/137

10-6

10-39

Weak αw

Photon; m=0∞

10-18 W &Z boson

∞ graviton; m=0Gravity αg