Q.1 Explain Newton law of viscosity ANS

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SHEKHAWATI INST. OF ENG.& TECHNOLOGY COLLEGE SIKAR , RAJASTHAN 1st MID TERM EXAMINATION 2017-18 (B.TECH 4 th year -CE) Subject Code & Name: 4MI2 FLUID MECHANICS MM: 20 Times: 1.5hrs MODEL ANSWER PAPER Q.1 Explain Newton law of viscosity ANS: Q. 2 A Plate 0.025 mm distant from a fixed plate, moves at 60 cm/s and require a force of 2N per unit area i.e 2N/m 2 to maintain the speed Determine the fluid viscosity between the plates.

Transcript of Q.1 Explain Newton law of viscosity ANS

Page 1: Q.1 Explain Newton law of viscosity ANS

SHEKHAWATI INST. OF ENG.& TECHNOLOGY COLLEGE

SIKAR , RAJASTHAN 1st MID TERM EXAMINATION 2017-18 (B.TECH 4th year -CE) Subject Code & Name: 4MI2 FLUID MECHANICS MM: 20 Times: 1.5hrs

MODEL ANSWER PAPER

Q.1 Explain Newton law of viscosity

ANS:

Q. 2 A Plate 0.025 mm distant from a fixed plate, moves at 60 cm/s and require a force of 2N per

unit area i.e 2N/m2 to maintain the speed Determine the fluid viscosity between the plates.

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Q.2 A differential manometer is connected a two point A and B of two pipes as shown in fig. The pipe A contain a liquid of sp.gr.= 1.5 While pipe B contains a liquid Sp.gr = 0.9. The pressure A and B are 1 Kgf/cm2 and 1.80 Kgs/cm2 respectively. Find the difference in mercury level in differential manometer (5)

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Q.3 Derive an expression for the depth of centre of pressure from free surface of liquid of an inclined plane surface sub-merged in the liquid (5)

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Q.4 a rectangular plane surface 2 m wide and 3 m deep lies in water in such a way that its plane makes an angle of 300 with the free surface of water. Determine the total pressure and position of centre of pressure when the upper edge is 1.5m below the free water surface (5)

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(5)Derive the continuity equation in three dimensional (5)

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