Psych 5500/6500
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Transcript of Psych 5500/6500
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Psych 5500/6500
t Test for Dependent Groups
(aka ‘Paired Samples’ Design)
Fall, 2008
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Experimental Designs
t test for dependent groups is used in the following two experimental designs:
1. Repeated measures (a.k.a. within-subjects) design.
2. Matched pairs design.
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Repeated Measures (Within-subjects) Design
Measure each participant twice, once in ‘Condition A’ and once in ‘Condition B’. The scores in the two groups are no longer independent as they come from the same participants.
I like to use ‘Condition A’ and ‘Condition B’ rather than ‘Group 1’ and ‘Group 2’ as the latter terms seem to imply (at least to me) that there are different subjects in each group.
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DesignSubject Condition A Condition B
1 S1 S1
2 S2 S2
3 S3 S3
etc. etc. etc.
Each subject’s two scores are dependent, but are independent of the other subjects’ scores.
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Matched Pairs
The two paired scores don’t have to come from the same person, there are other ways the scores within the pairs could be associated (dependent). For example, measuring marital satisfaction within married couples (a static group design).
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Design
Couple Wife Husband
1 S1.W S1.H
2 S2.W S2.H
3 S3.W S3.H
etc. etc. etc.
The scores within each couple are dependent, but each couple’s scores are independent of the other other couples’ scores
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Example: Repeated Measuresor Within-Subjects Design
You are interested in whether attending a mixed-race day camp affects children’s racial prejudice. Six children attending the day camp were given a test to measure racial prejudice (higher scores = more prejudice) when they first arrived at camp. The same six children were given the same test seven days later when they left the camp.
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DataSubject Before After
1 85 80
2 30 26
3 52 50
4 10 11
5 98 94
6 39 36
Mean= 52.33 49.5
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Getting Rid of the Nonindependence
Because we have two scores per person the scores are not all independent of each other, which means we can’t do a t test. The solution is simple, we will turn those two scores per person into just one score per person, a score which reflects the difference in each person’s score when they are in Condition A compared to when they are in Condition B.
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Difference ScoresSubject Before - After = Difference
1 85 - 80 = 5
2 30 - 26 = 4
3 52 - 50 = 2
4 10 - 11 = -1
5 98 - 94 = 4
6 39 - 36 = 3
For each subject we now have just one score, their ‘difference’ score. 1) The difference scores measure how much the subject’s score differed in the two conditions. 2) The difference scores are independent of each other, we can now perform the t test for a single group of scores on the difference scores.
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Difference ScoresSubject Before - After = D
1 85 - 80 = 5
2 30 - 26 = 4
3 52 - 50 = 2
4 10 - 11 = -1
5 98 - 94 = 4
6 39 - 36 = 3
To simply, let’s call the difference scores ‘d scores’. The mean of the d scores is a measure of the average difference between the scores in condition A and the scores in condition B.
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Difference ScoresSubject Before - After = D
1 85 - 80 = 5
2 30 - 26 = 4
3 52 - 50 = 2
4 10 - 11 = -1
5 98 - 94 = 4
6 39 - 36 = 3
In our sample, the prejudice scores were on average 2.83 higher before the day camp than they were after the day camp.2.83
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N
DD
17D
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Difference Scores
Subject D
1 5
2 4
3 2
4 -1
5 4
6 3
2.836
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N
DD
17D
Mean D is a statistic, it reflects what wefound in those six kids. Our hypotheseswill concern the larger population thesesix kids represent (2-tailed):
H0: μD=0 Ha: μD0
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Same Thing
What we are about to do is exactly the same thing as performing a t test for a single group of scores, we have simply relabeled our variable as ‘D’ (to stand for ‘difference scores’) rather then ‘Y’.
This is not really a third t test, it is just another context in which we can use the t test for a single group of scores.
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Sampling Distribution
All the results we could get for mean D assuming H0 were true.
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df and tc
516
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df
Ndf D
so tc=±2.571
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est. standard error
87.06
14.2..
14.257.4..
57.45
83.22
1.
83.226
1771
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2
2
2
2
D
DD
DD
D
DD
D
DD
N
estest
estest
N
SSest
SS
N
DDSS
(Compare to t test for a single group mean).
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tobt
You should be able to guess what this formula is.
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t(5)=3.24, p=.023
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Difference ScoresSubject Before - After = Difference
1 85 - 80 = 5
2 30 - 26 = 4
3 52 - 50 = 2
4 10 - 11 = -1
5 98 - 94 = 4
6 39 - 36 = 3
If we analyze the difference scores to see if the mean of their population differs from zero we get: t(5)=3.248, p=.023, we can conclude that their is a statistically significant difference in the before and after scores (i.e. μD0), if we have no serious confounding variables then we conclude that the day camp affected prejudice scores.
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One-Tail Tests
If we are testing a theory which predicts that prejudice should be less after the day camp then that would imply that the mean of the difference scores should be greater than zero (write Ha to express the prediction).H0: μD 0Ha: μD > 0
This is indeed the direction the results fell, so the p value would be p=.023/2=.012 So the results are t(5)=3.248, p=.012
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One-Tail Tests
If we are testing a theory which predicts that prejudice should be greater after the day camp then that would imply that the mean of the difference scores should be less than zero (write Ha to express the prediction).H0: μD 0Ha: μD < 0
This is opposite from the direction the results fell, so the p value would be p=1-.023/2=.988 So the results are t(5)=3.248, p=.988
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Matched Pairs DesignThis type of design is analyzed exactly the same
way as a repeated measures design, you analyze the difference scores.
Couple Wife - Husband = Difference
1 - =
2 - =
3 - =
4 - =
5 - =
6 - =
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Lowering Variance
Since the beginning of the semester I’ve been making the point that lowering the variance of the data is a good thing, it leads to more representative data and thus makes it easier to draw conclusions about the population from which the sample was drawn. Lowering variance increases power. I have been promising we would look at a way of accomplishing that other than simply sampling from a more homogeneous population, here it is...
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Look again at our original data, if these scores came from an independent groups design (e.g. random half of the kids measured before the day camp and the other half measured after the day camp) we would be in trouble, look at how much the scores vary within each group, the kids really differed in prejudice levels. This variance would kill the power of our experiment.
Subject Before After
1 85 80
2 30 26
3 52 50
4 10 11
5 98 94
6 39 36
Mean= 52.33 49.5
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But with a repeated measures design we are just looking at the effect of the independent variable (attending the camp) on each kid (how much they differed before and after rather than at how prejudiced they are). The independent variable had fairly similar effects on the kids (from –1 to 5), and thus the difference scores don’t have nearly as much variability as the prejudice levels of the various kids.
Subject Before - After = Difference
1 85 - 80 = 5
2 30 - 26 = 4
3 52 - 50 = 2
4 10 - 11 = -1
5 98 - 94 = 4
6 39 - 36 = 3
Mean 52.33 49.5 83.2D
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Subject Before - After = Difference
1 85 - 80 = 5
2 30 - 26 = 4
3 52 - 50 = 2
4 10 - 11 = -1
5 98 - 94 = 4
6 39 - 36 = 3
Mean 52.33 49.5 83.2D
Analyzed as t for independent groups
.884p0.15,t(10)
0.1518.93
2.83
18.93
0-49.5)-(52.33t
.023p3.25,t(5)
3.250.87
2.83t
Analyzed as t for dependent
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Variability and DesignsWhich t test you use is based upon how you run the study.
In deciding how to run the study:1. If you think the effect of the independent variable will
be rather similar for each subject and that the subjects’ actual scores will vary quite a bit then use a paired sample design (repeated measure or matched pairs design).
2. If you think the effect of the independent variable will vary quite a bit and that the subjects’ actual scores will be rather similar than use an independent groups design (true experiment, quasi-experiment, static group design).
A repeated measures design is usually more powerful than an independent groups design.
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Effect Size
The direct measure of effect size in this t test is simply the mean of the difference scores. This value represents the effect of the independent variable on the participants, and it also happens to equal the mean of the first group minus the mean of the second group (making it the same as the measure of effect size in the t test for independent groups).
D
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Standardized Effect Size
D
D
D
D
σ est.
D g sHedges'
sample, for the S
Dd sCohen'
,population for the σ
μ δ sCohen'
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2.144.57est.σest.σ
4.575
22.83
1N
SSest.σ
1.953.81SS
3.816
22.83
N
SSS
22.836
1771
N
DDSS
83.26
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N
DD
2DD
D
D2D
2D
D
D2D
2
D
2
2D
D
Manual Calculations
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From SPSSWhen doing a ‘Paired Samples t Test’ (what SPSS calls what I call‘t test for correlated groups’) the analysis will provide thefollowing under the title ‘Paired Samples Test’:
Mean = 2.83333 Std Deviation=2.13698
In our use of symbols these would be represented as:
Which is enough to compute Hedges’s g, for Cohen’s dwe need the standard deviation of the sample, which can befound by:
13698.2est. 2.83333D D
95.16
513698.2
1 est. S DD
D
D
N
N
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32.114.2
83.2
σ est.
D g sHedges'
45.11.95
2.83
S
Dd sCohen'
:SizeEffect edStandardiz
2.83D :DifferenceMean as SizeEffect
D
D
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Warning....There is some controversy about the correct calculations for standardized effect size. The shortcuts provided in the earlier lecture on a single group t test (repeated below) don’t work in this context:
df
2td
N
2tg
If we were to use those formulas we would get larger effect sizes:
91.2df
2td 2.65
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(2)(3.25)
N
2tg
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GPower 3.0In GPower this t test is called the t test for “Means: Difference between two dependent means (matched pairs)”. If you give it mean D and the standard deviation of D (‘SD’) it will compute Cohen’s d (big deal, as we have seen that is a simple formula). The ‘Total sample size’ is the number of pairs of scores (6 in our example). By the way, the post hoc analysis shows that this example had a power of 0.80! This was due to my having the mean D be rather large compared to the SD.
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Carry-Over Effect
Carry-Over Effect: A confounding variable that may arise due to measuring the same person more than once, thus can only happen in a repeated-measures design.
Practice effect: the general term for when a carry-over effect leads to an increase in performance over subsequent measures.
Fatigue effect: the general term for when a carry-over effect leads to a decrease in performance over subsequent measures.
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Options for Controlling Carry-Over Effects
1. If your independent variable is a carry-over effect (e.g. the effect of practice) then you do not need or want to control it. Otherwise....
2. If applicable, use different forms of the same test.
3. Minimize the carry-over effect (e.g. increase the time between first measure and second measure).
4. Counterbalance the order of conditions.
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Counterbalancing the Order of Conditions
Half the participants are in Condition A first and in Condition B second.
The other half of the participants are in Condition B first and Condition A second.
Subject Condition A Condition B
S1 1st 2nd
S2 2nd 1st
S3 1st 2nd
S4 2nd 1st