Prove Trig Identities

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Trigonometry Proving Trigonometric Identities Aim To demonstrate how to prove trigonometric identities. Learning Outcomes At the end of this section you will be able to: Distinguish between an equation and an identity, Solve trigonometric identities. An equation is an expression that is true for some value(s) of the unknown variable. An identity is an expression that is true for all values of the unknown variable. Some example of trigonometric identities are cos 2 θ + sin 2 θ = 1, tan θ = sin θ cos θ . Page 9 of the log tables can be very useful when proving trigonometric identities. We’ll now look at a two examples. Example 1 Prove cos 2 θ = 1 + cos2θ 2 . From the log tables we know that cos(A + B) = cos A cos B sin A sin B (let A = θ and B = θ), cos2θ = cos 2 θ sin 2 θ. (1) Also, cos 2 θ + sin 2 θ = 1, sin 2 θ = 1 cos 2 θ. (2) Substitute equation (2) into equation (1) and we get, cos2θ = cos 2 θ (1 cos 2 θ), = cos 2 θ 1 + cos 2 θ, cos2θ = 2cos 2 θ 1. 1

Transcript of Prove Trig Identities

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Trigonometry

Proving Trigonometric Identities

Aim

To demonstrate how to prove trigonometric identities.

Learning Outcomes

At the end of this section you will be able to:

• Distinguish between an equation and an identity,

• Solve trigonometric identities.

An equation is an expression that is true for some value(s) of the unknown variable.

An identity is an expression that is true for all values of the unknown variable. Some

example of trigonometric identities are

cos2 θ + sin2 θ = 1,

tan θ =sin θ

cos θ.

Page 9 of the log tables can be very useful when proving trigonometric identities.

We’ll now look at a two examples.

Example 1

Prove cos2 θ =1 + cos2θ

2.

From the log tables we know that

cos(A + B) = cosA cos B − sinA sinB (let A = θ and B = θ),

⇒ cos2θ = cos2 θ − sin2 θ. (1)

Also,

cos2 θ + sin2 θ = 1,

⇒ sin2 θ = 1− cos2 θ. (2)

Substitute equation (2) into equation (1) and we get,

cos2θ = cos2 θ − (1− cos2 θ),

= cos2 θ − 1 + cos2 θ,

⇒ cos2θ = 2 cos2 θ − 1.

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Trigonometry

2cos2 θ = cos 2θ + 1,

⇒ cos2 θ =1 + cos 2θ

2.

Example 2

Prove that tan2 θ + 1 = sec2 θ.

Recall that sec θ =1

cos θand tan θ =

sin θ

cos θ. Therefore,

tan2

θ + 1 = sec2

θ,sin2 θ

cos2 θ+ 1 =

1

cos2 θ,

sin2 θ + cos2 θ

cos2 θ=

1

cos2 θ,

⇒1

cos2 θ=

1

cos2 θ.

Related Reading

Croft, A., R. Davison. 2003.Foundation Mathematics 

. 3rd

Edition. Pearson EducationLimited.

Booth, D.J. 1998. Foundation Mathematics. 3rd Edition. Pearson Education Limited.

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