Protection Relay Discrimination Curve Analysis
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Transcript of Protection Relay Discrimination Curve Analysis
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Instruction on Use of this Spreadsheet 4,572 KVA
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5 C# %rimar! Current 03' . *0(0:5 C# %rimar! Current / (/2 *22:5 C# %rimar! Current '2 ('. *
@ A8ormal Inverse &.6' curve) ( 2 ('/5er! Inverse&'(.6' curve) '( '.(+
Btremel! Inverse 2( - (on ,#ime Inverse '( '2 (
Slope of the #ime6currentcurve set
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' * '3 *'(
' (
' (
' (
" ' 3 C% Consultants %te tdC% Consultants %te td reserves all ri hts to these3 dra in s3 desi nand6or an! other data contained her" ' 3 C% Consultants %te tdC% Consultants %te td reserves all ri hts to these3 dra in s3 desi nand6or an! other data contained her
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3 3C% Consultants %te #d other than the sole purpose for hich such dra in s3 desi ns and6or other dataas C% Consultants %te td ma! prescriEe("
3 3C% Consultants %te td other than the sole purpose for hich such dra in s3 desi ns and6or other data aas C% Consultants %te td ma! prescriEe("
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ID$# raphin ormula Ease on I C 0 2++,.%repared E! uke Feo
' 3 * ' 3
in( 8o %art of the said dra in s3 desi nsin( 8o %art of the said dra in s3 desi ns
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re provided to licensed users on such termsre provided to licensed users on such terms
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Instruction on Use of this Spreadsheet
2) Click on " Discrimination Curve" orksheet to anal!se the resultin curves
HT Incoming HT TransformeNormal Inverse (3/ ! curve" Normal Inverse (
# !$!2 #% !$ 4 %
#$S !$ ! #$S
%S &%rimar! current)&!$!& A
au urren u va en au urren
' ) Incoming ' ) outgVer Inverse( $3/ ! curve" Ver Inverse( $3
# #% 3$5 %
#$S !$ #$S
%S &%rimar! current) 2,25! A
'**) +oo u- ta.le '**) Incoming '**) utgoing
I6Ir 8S' 8S+
*mp( #rip 9atin2!! A
*mp( #rip 9atin$ t t #rip Current #rip #ime #rip Current'( + ' ( ' ( '20 * ' ( -/ *2( ' ( ' ( 2/ * ' ( '0 *.( .+( .+( .0 * .+( 2/ */( 2 ( 2 ( /- * 2 ( .2 *+( '2( '2( 0 * '2( / *0( ( ( 12 * ( /- *1( 0( 0( -/ * 0( +0 *-( +( +( 0 * +( 0/ *-( ( / ( / 0 * ( / 0/ *
( ( . ( . ' - * ( . 12 *' ( ( . ( . '2 * ( . - *2 ( ( 2 ( 2 2/ * ( 2 '0 *. ( ( ' ( ' .0 * ( ' 2/ */ ( ( ' ( ' /- * ( ' .2 *
&:5*)
') %lease amend the Cell ith 1 T T
%S &%rimar!current)
%S &%rimar!current)
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4,572 KVA 5 C# %rimar! Current 03' . *0(0:5 C# %rimar! Current / (/2 *22:5 C# %rimar! Current '2 ('. *
outgoing @ A
3/ ! curve" 8ormal Inverse &.6' curve) ( 2 ('/!$!2 5er! Inverse&'(.6' curve) '( '.(+!$ 4 Btremel! Inverse 2( - (!$ ! on ,#ime Inverse '( '2 (
52$5! A
oing/ ! curve"
3$5!$
2!!! A
0!! A#rip #ime' (
' (.+(2 ('2(
(0(+(
( /( .( .( 2( '( '
Slope of the #ime6currentcurve set
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' * '3 *'(
' (
' (
' (
" ' 3 C% Consultants %te tdC% Consultants %te td reserves all ri hts to these3 dra in s3 desi nand6or an! other data contained her
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3 3C% Consultants %te td other than the sole purpose for hich such dra in s3 desi ns and6or other data aas C% Consultants %te td ma! prescriEe("
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ID$# raphin ormula Ease on I C 0 2++,.%repared E! uke Feo
' 3 * ' 3
in( 8o %art of the said dra in s3 desi ns
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re provided to licensed users on such terms
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ID$# rela! al a!s ork ith a separate current transformer
Current #ransformer #urn 9atio3 &a6E) & . 6 +%lu Settin 3 %S ' ( G
#he rela! ill operate if line current is reater than . *mp
or ID$# 8ormal Inverse Curve3 ormula ma! Ee calculated as follo H. *mp
%lu settin $ultiplier3 $ ' (#ime $ultiplier Settin 3 #$S 'Operatin #ime3 t 2( 1 sec
In practice3 all C# at distriEution level are " 6+"( Onl! at ;53 C# are "BB6'"or eBample3 if C# is . 6+3 settin the %S to '+ G ill impl! the rela! ill o
;o lon the rela! operate depend on the #$S used(In practice3 rela!s must Ee set to ive discrimination at the maBimum fault le
#here are our standard ID$# Curves define in JS '/2(' 00 and I C 0 2+
8oeH If rela! operatin time is to Ee calculated usin the aEove formula3 hav
I is the current on the primar! side of the C#(
t = β
M α − 1
× TMS
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)
perate if line current is reater than /+ amp(
el a time difference of (/ second(
+,. and can Ee eBpressed as follo H
@ A
8ormal Inverse &.6' curve) ( 2 ('/5er! Inverse&'(.6' curve) '( '.(+
Btremel! Inverse 2( - (on ,#ime Inverse '( '2 (
to include . ms for additional filter and detection time(
Slope of the #ime6currentcurve set
t =0.14
M 0.02−1× TMS M =
I F
a × PS