Project Programming C

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UNIVERSITI TEKNOLOGI MALAYSIA

FACULTY

OF

MECHANICAL

ENGINEERING

SME 1013

PROGRAMMING FOR ENGINEER

PROJECT 1 C PROGRAMMING

NAME

:

MOHD

FIRDAUS

BIN

MOHD

NASIR

MATRIK : SXO81059MMJ04

SECTION : 1

LECTURE : DR YUSSOFF



Universiti Teknologi Malaysia'

Fakulti Kejuruteraan Mekanikal

SME/SKMM 1013 Programming for Engineers

2011-2012-02

Project -

C

Programming

Psychrometry deals with the properties of moist air. When the atmospheric pressure (total

pressure)

P

(kPa), the air dry bulb temperature

T

cae , and the relative humidity

RH (%)

are

known, the following properties can be calculated:

where

p . = 0.00008T

3

- 0.0007T2 + 0.0754T +

4 8 7 ~

(kPa)

P

v

=RH ) . . . .

(kPa)

w

0622

P

P,

. . . H • • • • • H • " " " .

1

/ L

= 100 P

[P - p ] .... .

..

.

..

.... .... ................. ....... (

)

p . P - P

v

h=

1.00ST +

w 2S00

+

1.88T .

.... ... .

... . ...... (kJlkgdryair

p.

= saturation pressure

of

water at dry bulb temperature

T

P

v

= partial pressure

of

water vapor

w

= humidity ratio

j.1

=

percentage saturation

h

=

specific enthalpy

of

air-vapor mixture

RH =

relative humidity

Write a C program to tabulate the following properties for 18°C

T

40°C

in

increment of

2°C,

and

40 RH 100

in increment

of

10

:

• w

• / L

• h

Tabulate for P = 101.325 kPa and P =

95

kPa.

Refer

http://www.fkm .

utm my/ myusofflw

.doc

for a sample of tabulated property .

Be creative when tabulating the proper ties

Your report submission must include the source code and the computer generated outputs.

Briefly discuss the results obtained and give your conclusions.

The report

is

due on

13

thoMay

2012.



SOLUTION

SOURCE CODE

1) P=101.325 Kpa

#include <stdio.h>

main(){

float t,h,p,ps[12],rh,pv[12][7],w[12][7],mu[12][7],temp[12];

int i,j;

p=101.325;

i=-1;{ for(t=18; t<=40; t=t+2)

i=i+1;

j=-1;

for(rh=40; rh<=100; rh=rh+2)

j=j+1;temp[i]=t;

ps [i]=(0.00008*pow(t,3)) + (0.0007*pow(t,2)) + (0.0754*t) + 0.4875;

pv[i][j] =((rh*ps[i])/100);

w[i][j] =0.622*pv[i][j]/(p-pv[i][j]);

mu[12][7] =(100*pv[i][j]/ps[i])*((p-ps[i])/(p-pv[i][j]));

h=(1.005*t) + (w[i][j]*(2500+(1.88*t)));

}

printf(" Relative Humidity(Percent) \n");

printf(" -----------------------------------------------------------------\n");

printf(" T(C) 40 50 60 70 80 90 100 \n");

printf(" -----------------------------------------------------------------\n");

for(i=0;i<=1;++i)for(j=0;j<=0;++j)

printf(" %.2d %.4f %.4f %.4f %.4f %.4f %.4f %.4f \n",pv[i][0], pv[i][1], pv[i][2],

pv[i][3], pv[i][4], pv[i][5], pv[i][6], pv[i][7]);

system("pause");

}



2) P=95 Kpa

#include <stdio.h>

main()

{

float t,h,p,ps[12],rh,pv[12][7],w[12][7],mu[12][7],temp[12];

int i,j; p=95;

i=-1;for(t=18; t<=40; t=t+2)

{ i=i+1;

j=-1;

for(rh=40; rh<=100; rh=rh+2)

j=j+1;temp[i]=t;

ps [i]=(0.00008*pow(t,3)) + (0.0007*pow(t,2)) + (0.0754*t) + 0.4875;

pv[i][j] =((rh*ps[i])/100);

w[i][j] =0.622*pv[i][j]/(p-pv[i][j]);

mu[12][7] =(100*pv[i][j]/ps[i])*((p-ps[i])/(p-pv[i][j]));h=(1.005*t) + (w[i][j]*(2500+(1.88*t)));

}

printf(" Relative Humidity(Percent) \n");

printf(" -----------------------------------------------------------------\n");

printf(" T(C) 40 50 60 70 80 90 100 \n");

printf(" -----------------------------------------------------------------\n");

for(i=0;i<=1;++i)

for(j=0;j<=0;++j)

printf(" %.2d %.4f %.4f %.4f %.4f %.4f %.4f %.4f \n",pv[i][0], pv[i][1], pv[i][2],

pv[i][3], pv[i][4], pv[i][5], pv[i][6], pv[i][7]);

system("pause");

}



3) Graf

Humi di t y Rat i o of Ai r( P = 101. 325 kPa)

Rel at i ve Humi di t y ( %)- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

T( C) 40 50 60 70 80 90 100- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -18. 0. 00516 0. 00646 0. 00777 0. 00909 0. 01041 0. 01173 0. 0130620. 0. 00584 0. 00731 0. 00880 0. 01029 0. 01179 0. 01329 0. 0148022. 0. 00660 0. 00827 0. 00995 0. 01164 0. 01334 0. 01505 0. 0167624. 0. 00745 0. 00935 0. 01125 0. 01316 0. 01509 0. 01703 0. 0189826. 0. 00841 0. 01055 0. 01271 0. 01487 0. 01706 0. 01926 0. 0214728. 0. 00949 0. 01191 0. 01434 0. 01680 0. 01927 0. 02176 0. 0242830. 0. 01069 0. 01342 0. 01617 0. 01895 0. 02175 0. 02458 0. 0274332. 0. 01203 0. 01511 0. 01822 0. 02136 0. 02453 0. 02773 0. 0309634. 0. 01351 0. 01698 0. 02049 0. 02404 0. 02763 0. 03125 0. 03492

36. 0. 01516 0. 01907 0. 02302 0. 02702 0. 03108 0. 03518 0. 0393438. 0. 01698 0. 02137 0. 02582 0. 03034 0. 03491 0. 03956 0. 0442640. 0. 01899 0. 02392 0. 02892 0. 03401 0. 03917 0. 04442 0. 04975- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Humi di t y Rat i o of Ai r( P = 95 kPa)

Rel at i ve Humi di t y ( %)- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

T( C) 40 50 60 70 80 90 100- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

18. 0. 00516 0. 00646 0. 00777 0. 00909 0. 01041 0. 01173 0. 0130620. 0. 00584 0. 00731 0. 00880 0. 01029 0. 01179 0. 01329 0. 0148022. 0. 00660 0. 00827 0. 00995 0. 01164 0. 01334 0. 01505 0. 0167624. 0. 00745 0. 00935 0. 01125 0. 01316 0. 01509 0. 01703 0. 0189826. 0. 00841 0. 01055 0. 01271 0. 01487 0. 01706 0. 01926 0. 0214728. 0. 00949 0. 01191 0. 01434 0. 01680 0. 01927 0. 02176 0. 0242830. 0. 01069 0. 01342 0. 01617 0. 01895 0. 02175 0. 02458 0. 0274332. 0. 01203 0. 01511 0. 01822 0. 02136 0. 02453 0. 02773 0. 0309634. 0. 01351 0. 01698 0. 02049 0. 02404 0. 02763 0. 03125 0. 0349236. 0. 01516 0. 01907 0. 02302 0. 02702 0. 03108 0. 03518 0. 0393438. 0. 01698 0. 02137 0. 02582 0. 03034 0. 03491 0. 03956 0. 0442640. 0. 01899 0. 02392 0. 02892 0. 03401 0. 03917 0. 04442 0. 04975- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -



4) Conclusion

From the above table we can see that the value slightly different when the pressure was change from

101.325 Kpa to 95 Kpa. Due to pressure drop the condensation was happen and resulted the relative

humidity become higher instead higher pressure apply.

Project Programming C

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