Processor Privilege-Levels

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Processor Privilege- Levels How the x86 processor accomplishes transitions among its four distinct privilege-levels

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Processor Privilege-Levels. How the x86 processor accomplishes transitions among its four distinct privilege-levels. Rationale. The usefulness of protected-mode derives from its ability to enforce restrictions upon software’s ability to perform certain actions - PowerPoint PPT Presentation

Transcript of Processor Privilege-Levels

Page 1: Processor Privilege-Levels

Processor Privilege-Levels

How the x86 processor accomplishes transitions among its four distinct privilege-levels

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Rationale

• The usefulness of protected-mode derives from its ability to enforce restrictions upon software’s ability to perform certain actions

• Four distinct privilege-levels are supported

• Organizing concept: concentric “rings”

• Innermost ring has greatest privileges, and privileges diminish as rings move outward

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Four Privilege Rings

Ring 3

Ring 2

Ring 1

Ring 0

Least-trusted level

Most-trusted level

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Suggested purposes

Ring0: operating system kernel

Ring1: operating system services

Rin2: custom extensions

Ring3: ordinary user applications

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Unix/Linux and Windows

Ring0: operating system

Ring1: unused

Ring2: unused

Ring3: application programs

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Legal Ring-Transitions

• A transition from an outer ring to an inner ring is only possible by using a special control-structure (known as a call gate)

• The ‘gate’ is defined by a data-structure located in a system memory-segment normally inaccessible to modifications

• A transition from an inner ring to an outer ring is not nearly so strictly controlled

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Data-sharing

• Procedure-calls typically require that two separate routines share some data-values (e.g., parameter-values get passed from the calling routine to the called routine)

• To support reentrancy and recursion, the processor’s stack is frequently used as a shared-access storage-area

• But among routines with different levels of privilege, this could create “security hole”

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An example senario

• Say a procedure that executes in ring 3 calls a procedure that executes in ring 2

• The ring 2 procedure uses a portion of its stack-area to create ‘automatic’ variables that it uses for temporary workspace

• Upon return, the ring 3 procedure would be able to examine whatever values are left behind in this ring 2 workspace

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Data Isolation

• To guard against unintentional sharing of privileged information, different stacks are provided at each distinct privilege-level

• Accordingly, any transition from one ring to another must necessarily be accompanied by a ‘stack-switch’ operation

• The CPU provides for automatic switching of stacks and copying of parameter-values

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Call-Gate Descriptors

offset[ 31..16 ]

code-selector offset[ 15..0 ]

gatetype

P 0DPL

parametercount

63 32

31 0

Legend:

P=present (1=yes, 0=no) DPL=Descriptor Prvilege Level (0,1,2,3)code-selector (specifies memory-segment containing procedure code)offset (specifies the procedure’s entry-point within its code-segment)parameter count (specifies how many parameter-values will be copied)gate-type (‘0x4’ means a 16-bit call-gate, ‘0xC’ means a 32-bit call-gate)

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An Interprivilege Call

• When a lesser privileged routine wants to invoke a more privileged routine, it does so by using a ‘far call’ machine-instruction

• In as86 assembly language:

callf #0, #callgate-selector

0x9A (ignored) callgate-selector

opcode offset-field segment-field

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What does the CPU do?

• When CPU fetches a far-call instruction, it looks up that instruction’s specified descriptor

• If it’s a call-gate descriptor, and if access is allowed (i.e., CPL DPL), then the CPU will perform a complex series of actions to accomplish a requested ring-transition

• CPL (Current Privilege Level) is based on least significant 2-bits in CS (also in SS)

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Series of CPU Actions

- pushes the current SS:SP register-values onto a new stack-segment

- copies the specified number of parameters from the old stack onto the new stack

- pushes the updated CS:IP register-values onto the new stack

- loads new values into registers CS:IP (from the callgate-descriptor) and into SS:SP

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The missing info?

• Where do the new values for SS:SP come from? (They’re not found in the callgate)

• They’re from a special system-segment, called the TSS (Task State Segment)

• The CPU locates its TSS by referring to the value in register TR (Task Register)

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Diagram of Relationships

TASKSTATE

SEGMENT

NEWSTACK

SEGMENT

stack-pointer

OLDSTACK

SEGMENT

params

params

SS:SP

Descriptor-Table

gate-descriptor

call-instruction

TSS-descriptor TR

CS:IP

GDTR

old code-segment new code-segment

called procedure

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Return to an Outer Ring

• Use the far-return instruction: retf – Restores CS:IP from current stack– Restores SS:SP from current stack

• Or use the far-return instruction: retf n– Restores CS:IP from current stack– Discards n bytes from stack (parameters)– Restores SS:IP from current stack

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Demo-program: ‘tryring1.s’

• We have created a short program to show how this ring-transition mechanism works

• It enters protected-mode (at ring0)

• It ‘returns’ to a procedure in ring1

• Procedure shows a confirmation-message

• The ring1 procedure then ‘calls’ to ring0

• The ring0 procedure exits protected-mode

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Data-structures needed

• Global Descriptor Table needs to contain the protected-mode segment-descriptors and the call-gate descriptor– Code-segments for Ring0 and Ring1– Stack-segments for Ring0 and Ring1– Data-segment (for Ring1 to write to VRAM)– Task-State Segment (for ring0 SS:SP)– Task-Gate and TSS Descriptors (for ‘callf’)

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In-class Exercise #1

• Modify the ‘tryring1.s’ demo so that it uses a 32-bit call-gate and a 32-bit TSS

TSS for 80286 (16-bits)

0

2

4SP1

SP2

SS2

6

8

10

12

SP0

SS0

SS1

ESP0

ESP1

ESP2

SS0

SS1

SS2

TSS for 80386 (32-bits)

0

4

8

12

16

20

24… …

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System Segment-Descriptors

Base[ 15..0 ] Limit[ 15..0 ]

Limit[19..16]

Base[ 31..24 ] Base[ 23..16 ]typeDPL

P 0

type 0 = reserved 1 = 16-bit TSS (available) 2 = LDT 3 = 16-bit TSS (busy)

type 8 = reserved 9 = 32-bit TSS (available) A = reserved B = 32-bit TSS (busy)

S-bit is zero

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In-class exercise #2

• Modify the ‘tryring1.s’ demo so that it first enters ring2, then calls to ring1 from ring2 (but returns to ring2), and then finally calls to ring0 in order to exit protected-mode

• How many stack-segments do you need?

• How many code-segment descriptors?

• How many VRAM-segment descriptors?