Process Dynamic and Control

8/2/2019 Process Dynamic and Control

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4/22

Malaviya Na tiona I Institute of Tech nology JaipurFint mid termProcess D. namic &Control CH-30

Max Time: 1Hr. Max arks: 20ote: Attempt any four questions.

Find Inverse of Laplace(I) l/{s ( S 2 _ 2s-5)}(_) d2q/dt2+ dq/dt=r+Zt

q(o)=4 & qior= .: 1


5/22

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6/22

0"''''\'I iMalaviyu National In titute of Technology JaipurFirst mid termProcess Dynamic & Control CH-306

Max Marks: 200[(': Auemj t all questions.

QI. Find the complete time -domain solution for the following differential equation usingL apla ce iran Corm :d ' x(3) -. +-I.\:= 'withcil',{.Y 6d, - -,(b) -, + - +__x =edt: II

:'\(0)=0. dx(O) _ 0 d2x(0) 0=r : =z:':with x( O = 0 dx (O) = 0dt

.A stirred tank bl nding system initially i full of water and is being fed pure water at aconstant now rate. q. At a particular time, an operator adds caustic olution at the samev lum tric flow rate q but concentration c , . I f the liquid volume V is constant, withc\ 0)= . \\ 'hat i the concentration response of the reactor effluen stream, c(t)? sketch itas fun tion of -50K: /m

< . . . ) 3 . A urge tank in fig l i designed with a slotted weir so that the outlet flov rate, \I .ISp r p rtional !O the liquid level to the 1.5 power; that is.

\\'= Ril l;\\-h r R is a COil tant. If a ingle stream enter the tank with flow rate v r ,find therransf r funcri n

H (5)rr ( )

Id mit"; the gain and all time ost ant . The cr -sectional area fthe tank i A. densityp ) constant.

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7/22

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8/22

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9/22

.\1I~lI1pt all question.

'I \1 \\ 1\ \ :\.\ no~ \l. I'ISTlTtITE OF TECHNOLOGY, ,J lPUR111 n. I'cch hcmical Eng;nccl"ing, 2010-11

'l'l"Ill!! ~~l1Il'StCl", 1 lid THill Evnm

I'imc t hour Max Marks 30(10 marks each)

til ,1 (\\,' r .ms, 1l1l:-'1Ili ; PI','': ss sl11\\1) in figur bel",. :-" varie from 0 Ibsal ft3 to 1 lbsaluft',l":"hitn.,! t" ,I'P function. -\t \\ har time til salt concentration in the tank 2 rea he U.6I",! lrt Th holdup \ o lum M ach tank is oft'.

I ~l \\ tat I:' the u . ..ms rcnt response \)C u ~irsl order ~yst rn to a inusoida! forcing function. shoII th >i It,ll le di.igram.

\

./ I ~~ C t- /T.!.l1. : T~~l .c2

Ar a= : r r

R.:= -

-:


10/22

Malaviya National Institute of Technology JaipurSecond mid termProcess Dynamic &Control CH-306

Max Time: IHr. Max Marks: 20Note: Attempt all questions.

Q I. Define overshoot & rise time. Derive the expression for over shoot.Q. The two tanks are connected in an interacting fashion. The systemis initially at steady state with q=J0 cfm. The following data applyto the tanks: Aj=Ift", A2=1.25ft2, Rl=lftlcfm,R2=O.8ft1cfm.(a)Ifthe flow changes from 10 toll cfrn according to a step change,Determine H2(s), i.e. the Laplace transform of H, (t), where H2is thedeviation in h2.

(b)Detennine H2(4) and H2(ro).Q3. For second order system fwd impulse response for ~


11/22

(5 marks)

Roll 0: .III B. Tech Chemical Engineer-ing, 2007-2008II :\lid Term Examubjecr: Process Dynamic- & Control

Time 1 hour Max Marks 20Attempt all questions.

1. -xplain th characteristic f a second order ystern underdarnped re pan es for astep and sine wave input and explain the vari us terminologies.

(7 marks)

3. For a Process healing ve sel with ontinuou inflow and outflow and fitted with aheating coil and a temperature controller. explain the experimental m thod andcal ulations to obtain the process tran fer func t i n r lati ng the vari lion in thepro ess \. sse] temperature with respect to disturbances in the i nf low tempe ra tu rand heat suppl y to the rank. (8 marks)


12/22

\1:119\ i~a ':lIionalln_titutt.' ofT hnolo .Iaipurvc nd mid termr cess D\ na 11, s : C ntrc I 1 1 .-306

I Hr. Max lark: 20

" t : .\ltcmpt all que lion.

l. D fin overshoot . rise time. D riv the expre ion for over shoot.The \\ ~ W11! s 3I conn . .; in an intern on,; fashion. The ysternis initiallya steady sta e with q=IO cfrn. The following data apply

l: e ~J...:. A,=lft: ..-\:=L~fi:. Rr=lft cfrn .Ry=O. ft, fm .{a If the flow change- from IOta 11cfm a cording to a step change.. ~(:). i.e. the La La e transform of H2 (t), where H~ is the

/Final controlelement

...-_._~M\ Recorder-vv controllerJ e c t r i c a r p o w e r _ _ ~or steam

ZD.1i----'

P r o c e s sTemperaturemeasur ingelement

I--- .....w, T'-----~

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I 1::(1L ime l l lra torc ing fu nc tion \\ hen thl valu e \It

I

(a \\ ill th e process xhibit overshoot r r a step hange in u? l x plain \\h) or ' \h~not

(b I \\'hat \\ ill ih approxrmat maximum \ al ul'n=3 '1tel Approximately when will th e maximum value ccur? (0)

.The tw o tank hearing process shown in Figlc : 'on-ist f two identical. well-stirredtanks in en s. At stead) stat. T.=Tt>=700F. At time 1=0. the temp rature ofeach

the a cording to(~WW,T I

to I. nd r',(b) Obtain an expre sian f r T12( ).I }Determine T{S)

,mDara:V, ,=\\ 2=4501b minH old up \ olume of each tank=20ft3Densir, of f lu id =501b/ft3H e at c ap ac ity oflluid=1 Btu/(Ib)(f)/ 10 : '.08 -- I.I

, r


14/22

J.\LAH\ AIII B. T ch Chemical Engineering, 010-11

prin erne ter, Il Mid Term E amCode: CH306

Max Marks 30(10 marks each)Tim 1 bour Attempt all questions." '!~F chang of magnitud 3 IS introdu ed iota the transf r f'.!. ~:on) ( ) X() = 10 I t _ ~1 - :- U .J +0.':)Det rmin 0, rshoot, D a) ratio. Rise tim and Fr CJu D ) of os illation

") The flow rate F of water passing through _ perfec tly m ixed tanks c onnec ted in series IS constant at50litres min. Tbe density of the water is 1gm/cc. and the heat capacity is O.96cal gmCC The volume ofth f IrS 1 ta nh i s 400 liter and the se ond tank is 500 l i ters. Th t m pe ratu re o f th wa te r en te ri n g th firstlank 1 T, and i - o o e ar initial steady state. Tem peratu res in the two tanks TI an d T~ are both equ al [096'"C a steady tate. A beating coil in the first tank use steam to heat the water and Q is the addition ofw trovertamperature dis ibution in the two tanks?

A \ mperarure onrroller i in tall d in order to maintain T2. If a propornonal ontroner of gam, and ontrol valve of K, = -OOOcalories.min 11l6mA and Transducer of !',,,=ioll" :OoC IS

u d. d \ elop III 0\ erall blo k diagr=m for til control yst m and in orporat th uan f r. . . . ., .unc 10ns.:~~.nc 0.0 t . : _ ' "

~ F plain brief ~ the re pon ses of a ~ pica I ontrol -) 'tern" ith Proportional. Pl and Pill modes :'If controlan d ih i r tr an f r fu n c uon -.


15/22

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MALAVIYA NATIONAL INSTITUTE OF TECHNOLOGY JAlP RDEI>ARTMENT OF CHEMICAL ENGINEERINGEnd Term Examination. May ~011 ~ubject: Proces Dynamic & ControlI Semester Sub. Code: CH306

Time: 2 hours Max Marks: 30

m

Attempt all questions. Graph papers, log-log, semi log papers will be pro\'ided

1 . D fine Ru th tabili ty c ri teria. W hat ar it lim itations,10f ir t o rder y tern has a transfer fun tion G p ( = = - - - and is onrr lied \Iith

fe dback PI ontroll r, o,( )=Kc (1 + _ 1 _ ) .TIS urne that the final ontr I Imen t haa fu n tion of Gr= _ and the rran fer func tion of the mea u ring I m nt i

I . . f d tl a ' of valu e f K an d IIth at w ill yi Id stablng R u t 1 cntena In 1 p ir .r po n e. (J+ )

3 Explain ran sportari n L g.lag. b) 1\ \ differ 11 1 m th d

4. I I ' , \ 1 1 pen \ L ) ) P \\\1\1"1"1'rur I y tern havinu the to \\ Il1g0\ c rtIr "\ till' uam 1 1 \ , 1 1\ !. In . u i IDetermine th e nO'so\c r ICQUt:1 1 .' 10' ~

th pha e margin r r r ab ili ry .


16/22

1\1alH"iya Naliolllli III~Wllk nf'l'IIIII.lc I i. ,. .. '~y. II pllrI' l id 1('1111 1 ' ; ' : 1 1 1 1Prot'l'SS I)YII:llllil' C ' ('(Hilm ('11-10(1

Noll': t\lklllpl all questions.(ll. : \11 \ 'thl' . 1 : ' 1 \ 1 1 1 illg till (;1cutial ..:quatl\llls h) I ,qll:ll:lll:OII~IIIIIII:, alit! 1IIIdII1Vl:rSC01 It. (ll)

(~iI' .J' l i t ; + .1' e- $111JI, riven that y = 0 w hcn r= O .42\1 r i p . dyJli) _'-, - 2~ +)' = e' : given that y = -2._ = -3 when 1=0.~- ~ ~

Q2. Invert the f llowing tran r 1'111.: ( 7 )

.com. ! ) : 5 . ' Obtain the transfer run lion f thc control y tern hewn in fig. I (8)

s-: For the control sy tern hown in fig 2, determine: (6)(a) qS)1 i < . . ~ ~ )(b) C(cn)(c) Orlset(d) ceO.S)(e) Whether the closed-loop response is oscillat I'yr - : Write the characteri tic equation for the control system shown in fig3(a) Use the Routh Test to determine if the sy. tern i stable for Kc=4 .(b) Determine the ultimate value of K , above which system is unstable

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20/22

ubjcct: PROCESS I)YNAMIC'S & CO THOLDate - 02-0S-20()8, Time 3 11I"s Suh.iccl ( 'ode: ( 'JBII(,M ax m ~ lrk \= ~ S

)\nswel' all queslions

I. m erc ury therm om eter having a t ime constant [2 0ec onds IS allowed to cometo eq u ilibrium in the room air at 70F . Then it is plac ed in the 3S0"F oil bath fO Talength of tim e less than ne sec nd and qu ic kly rem oved f rom the bath andreex posed to the 75F ambient ondi t ions. It may be estim ated that the heattransf er c oef f ic ient to the therm om eter in air is one-six th that I n the oil bath , If I()seconds af ter th therm om eter is rem oved from the bath it reads 96"F e stim ate th elength of tim e that the therm om eter was in the bath,

../ nV. A f irst order proc ess w ith dead lim e h as the tran fer fu nc tio nG ( = l_Qe '~o~ ~

Th i r- cess i b on rolled ith P I c nrolJeri. e the B ode diagram to f ind the valu es of K , s o that the system is stable As u me

th at Gm and G r= I and that the re et tim e for the PI contro ller is '1- 05 m in Obtainth e c ro sso ver f req ue nc y a nd g ai n m arg in .ii. O btain the c ontroller ertin gs f or a P I a nd P IO c ontrol (10)

/ . D raw the root loc u s of a c losed loop ystern w i th f o ll ow i ng c h ar ac t er i, ti c >1G (S=----

p (2s+ Ix s+ I)T ransf er fu nc tions for the P roportional c ontro ller G ,(s) = k c- F inal c ontr I elem ent has afu nc tion o f G r( s)= I, and the m easu ring elem ent is G m(s) = 1 .lnd ic ate \\ hat segm ent of therO OI l oc us (valu es of K ,) w ill y ie ldi. Overdampedi i. Cr it ic a ll y d am p ediii nderdarnped c l sed loop responses r

(10)

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k _ ! ! ) _r s+1'"f ind Ill, pair "r \ uluc- "I' k, and r,

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Process Dynamic and Control

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