Problem Solving (Geometry 1_6)

A Plan for Problem SolvingA Plan for Problem Solving

You will learn to solve problems that involve the perimetersand areas of rectangles and parallelograms.



Perimeter is the _____________________.

Perimeter is similar to ____________.



Perimeter is the _____________________.distance around an object

Perimeter is similar to ____________.a line segment





Area is the _______________________________________________.

Area is similar to ______.





Area is the _______________________________________________.number of square units needed to cover an object’s surface

Area is similar to ______.a plane


In this section you will learn to solve problems that involve the perimetersand areas of rectangles and parallelograms.

Perimeter is the ____________________.



Perimeter is the ____________________.distance around a figure




The perimeter is the ____ of the lengths of the sides of the figure.




The perimeter is the ____ of the lengths of the sides of the figure.sum





The perimeter of the room shown here is:





The perimeter of the room shown here is:

15 ft + 12 ft+ 18 ft + 6 ft + 6 ft + 9 ft

= 66 ft


Some figures have special characteristics. For example, the opposite sidesof a rectangle have the same length.

This allows us to use a formula to find the perimeter of a rectangle.(A formula is an equation that shows how certain quantities are related.)


Some figures have special characteristics. For example, the opposite sidesof a rectangle have the same length.

This allows us to use a formula to find the perimeter of a rectangle.(A formula is an equation that shows how certain quantities are related.)

Perimeter 2 2

2( )

l w

l w

(of a rectangle)


Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft.

17 ft

8 ft



17 ft

8 ft

= 2(17 ft) + 2(8 ft)

= 34 ft + 16 ft

= 50 ft

wl 2 2 Perimeter



17 ft

8 ft

= 2(17 ft) + 2(8 ft) = 2(17 ft + 8 ft)

= 34 ft + 16 ft

= 50 ft

= 2(25 ft)

= 50 ft

wl 2 2 Perimeter ) (2 or wl


Another important measure is area.

The area of a figure is ____________________________________________.



The area of a figure is ____________________________________________.the number of square units needed to cover its surface




The area of the rectangle below can be found by dividing it into 18 unit squares.

3

6




The area of the rectangle below can be found by dividing it into 18 unit squares.

3

6

The area of a rectangle can also be found by multiplying the length and the width.


The area “A” of a rectangle is the product of the length l and the width w.

l

w A lw

Find the area of the rectangle

14 in.

10 in.



l

w A lw


14 in.

10 in.A lw

(14 )(10 )A in in2140A in

The area of the rectangle is 140 square inches.



l

w A lw


14 in.

10 in.A lw

(14 )(10 )A in in2140A in

The area of the rectangle is 140 square inches.

NOTE: units indicate area is being calculated 2( )( )in in in

Plan for Problem SolvingPlan for Problem Solving

Because the opposite sides of a parallelogram have the same length,the area of a parallelogram is closely related to the area of a ________.


Because the opposite sides of a parallelogram have the same length,the area of a parallelogram is closely related to the area of a ________.rectangle



The area of a parallelogram is found by multiplying the ____ and the ______.

base

height



The area of a parallelogram is found by multiplying the ____ and the ______.base height

base

height



The area of a parallelogram is found by multiplying the ____ and the ______.base height

Base – the bottom of a geometric figure.Height – measured from top to bottom, perpendicular to the base.

base

height


Find the area of the parallelogram:

4 m

15

10m

4.3 m



4 m

15

10m

4.3 m

51 (4 )

10

A bh

m m



4 m

15

10m

4.3 m

51 (4 )

10

A bh

m m

2

2

204

10

220

5

m

m

§1.6 A Plan for Problem Solving§1.6 A Plan for Problem Solving

Problem Solving (Geometry 1_6)

Education

Transcript of Problem Solving (Geometry 1_6)