Probabilities and Proportions

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C4, L2, S1 Probabilities and Proportions Probabilities and proportions are numerically equivalent. (i.e. they convey the same information.) e.g. The proportion of U.S. citizens who are left handed is 0.1; a randomly selected U.S. citizen is left handed with a probability of approximately 0.1.

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Probabilities and Proportions. Probabilities and proportions are numerically equivalent. (i.e. they convey the same information.) e.g. The proportion of U.S. citizens who are left handed is 0.1; a randomly selected U.S. citizen is left handed with a probability - PowerPoint PPT Presentation

Transcript of Probabilities and Proportions

Page 1: Probabilities and Proportions

C4, L2, S1

Probabilities and ProportionsProbabilities and proportionsare numerically equivalent.(i.e. they convey the same information.)

e.g. The proportion of U.S. citizens who are left handed is 0.1; a randomly selected U.S. citizen isleft handed with a probabilityof approximately 0.1.

Page 2: Probabilities and Proportions

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2. Helmet Use and Head Injuries in Motorcycle Accidents (Wisconsin, 1991)

Brain Injury

No Brain Injury

Row Totals

No Helmet 97 1918 2015

Helmet Worn 17 977 994

ColumnTotals 114 2895 3009

BI = the event the motorcyclist sustains brain injury

NBI = no braininjury

H = the event themotorcyclist waswearing a helmet

NH = no helmet worn P(BI) = 114 / 3009 = .0379

What is the probability that a motorcyclist involved in a accident sustains brain injury?

Page 3: Probabilities and Proportions

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2. Helmet Use and Head Injuries in Motorcycle Accidents (Wisconsin, 1991)

Brain Injury

No Brain Injury

Row Totals

No Helmet 97 1918 2015

Helmet Worn 17 977 994

ColumnTotals 114 289 3009

BI = the event the motorcyclist sustains brain injury

NBI = no braininjury

H = the event themotorcyclist waswearing a helmet

NH = no helmet worn P(H) = 994 / 3009 = .3303

What is the probability that a motorcyclist involved in a accident was wearing a helmet?

Page 4: Probabilities and Proportions

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2. Helmet Use and Head Injuries in Motorcycle Accidents (Wisconsin, 1991)

Brain Injury

No Brain Injury

Row Totals

No Helmet 97 1918 2015

Helmet Worn 17 977 994

ColumnTotals 114 2895 3009

What is the probability that the cyclist sustained brain injury given they were wearing a helmet? P(BI|H) = 17 / 994 = .0171

BI = the event the motorcyclist sustains brain injury

NBI = no braininjury

H = the event themotorcyclist waswearing a helmet

NH = no helmet worn

Page 5: Probabilities and Proportions

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2. Helmet Use and Head Injuries in Motorcycle Accidents (Wisconsin, 1991)

Brain Injury

No Brain Injury

Row Totals

No Helmet 97 1918 2015

Helmet Worn 17 977 994

ColumnTotals 114 2895 3009

What is the probability that the cyclist not wearing a helmet sustained brain injury? P(BI|NH) = 97 / 2015

= .0481

BI = the event the motorcyclist sustains brain injury

NBI = no braininjury

H = the event themotorcyclist waswearing a helmet

NH = no helmet worn

Page 6: Probabilities and Proportions

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2. Helmet Use and Head Injuries in Motorcycle Accidents (Wisconsin, 1991)

Brain Injury

No Brain Injury

Row

Totals

No Helmet 97 1918 2015

Helmet Worn 17 977 994

Column

Totals 114 2895 3009

How many times more likely is a non-helmet wearer to sustain brain injury?

.0481 / .0171 = 2.81 times more likely. This is called the relative risk or risk ratio (denoted RR).

Page 7: Probabilities and Proportions

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Building a Contingency Table from a Story

3. HIV Example

A European study on the transmission of the HIV

virus involved 470 heterosexual couples.

Originally only one of the partners in each couple

was infected with the virus. There were 293

couples that always used condoms. From this

group, 3 of the non-infected partners became

infected with the virus. Of the 177 couples who

did not always use a condom, 20 of the non-

infected partners became infected with the virus.

Page 8: Probabilities and Proportions

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Let C be the event that the couple always used condoms. (NC be the complement)

Let I be the event that the non-infected partner became infected. (NI be the complement)

C NC

NI

I

3. HIV Example

Total

Total

Condom UsageInfectio

n Status

Page 9: Probabilities and Proportions

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A European study on the transmission of the HIV virus involved 470 heterosexual couples. Originally only one of the partners in each couple was infected with the virus. There were 293 couples that always used condoms. From this group, 3 of the non-infected partners became infected with the virus.

C NC

NI

I

3. HIV Example

Total

Total

Condom UsageInfectio

n Status

470293

3

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Of the 177 couples who did not always use a condom, 20 of the non-infected partners became infected with the virus.

C NC

NI

I

3. HIV Example

Total

Total

Condom UsageInfectio

n Status

470293

3 20

177

290 15723

447

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a) What proportion of the couples in this study always used condoms?

C NC

NI

I

Total

Total

Condom UsageInfection

Status

470293

3 20

177

290 15723

447

3. HIV Example

P(C )

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a) What proportion of the couples in this study always used condoms?

C C

I

I

Total

Total

Condom UsageInfection

Status

470293

3 20

177

290 15723

447

3. HIV Example

P(C ) = 293/470 (= 0.623)

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b) If a non-infected partner became infected, what is the probability that he/she was one of a couple that always used condoms?

3. HIV Example

C NC

NI

I

Total

Total

Condom UsageInfection

Status

470293

3 20

177

290 15723

447

P(C|I ) = 3/23 = 0.130

Page 14: Probabilities and Proportions

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Example 3 - Death Sentence Example

University of Florida sociologist, Michael Radelet, believed that if you killed a white person in Florida the chances of getting the death penalty were three times greater than if you had killed a black person. In a study Radelet classified 326 murderers by race of the victim and type of sentence given to the murderer. 36 of the convicted murderers received the death sentence. Of this group, 30 had murdered a white person whereas 184 of the group that did not receive the death

sentence had murdered a white person. (Gainesville

Sun, Oct 20 1986)

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Death Sentence Example

Let W be the event that the victim is white.

B be the event that the victim is black. D be the event that the sentence is death.

ND be the event that the sentence is not death.

ND

D

W

Victim’s Race

Sentence

Total

Total

B

Page 16: Probabilities and Proportions

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Death Sentence ExampleIn a study Radelet classified 326 murderers by race of the victim and type of sentence given to the murderer. 36 of the convicted murderers received the death sentence. Of this group, 30 had murdered a white person whereas 184 of the group that did not receive the death sentence had murdered a white person.

ND

D

W

Victim’s Race

Sentence

Total

Total

B

326

290

36 30 6

112214

106184

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Death Sentence Examplea) What proportion of the murderers in this study

received the death sentence?

P(D) =

ND

D

W

Victim’s Race

Sentence Total

Total

B

326

290

36 30 6

112214

106184

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Death Sentence Examplea) What proportion of the murderers in this study

received the death sentence?

ND

D

W

Victim’s Race

Sentence Total

Total

B

326

290

36 30 6

112214

106184

P(D) = 36/326 = 0.1104

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Death Sentence Exampleb) If a victim from this study was white, what is the

probability that the murderer of this victim received the death sentence?

ND

D

W

Victim’s Race

Sentence Total

Total

B

326

290

36 30 6

112214

106184

P(D|W ) =

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5. Death Sentence Exampleb) If a victim from this study was white, what is the

probability that the murderer of this victim received the death sentence?

ND

D

W

Victim’s Race

Sentence Total

Total

B

326

290

36 30 6

112214

106184

P(D|W ) =

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Death Sentence Exampleb) If a victim from this study was white, what is the

probability that the murderer of this victim received the death sentence?

ND

D

W

Victim’s Race

Sentence Total

Total

B

326

290

36 30 6

112214

106184

P(D|W ) = 30/214 = 0.1402

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Death Sentence Examplec) If a victim from this study was black, what is the

probability that the murderer of this victim received the death sentence?

P(D|B ) =

ND

D

W

Victim’s Race

Sentence Total

Total

B

326

290

36 30 6

112214

106184

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Death Sentence Examplec) If a victim from this study was black, what is the

probability that the murderer of this victim received the death sentence?

P(D|B ) =

ND

D

W

Victim’s Race

Sentence Total

Total

B

326

290

36 30 6

112214

106184

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Death Sentence Examplec) If a victim from this study was black, what is the

probability that the murderer of this victim received the death sentence?

P(D|B ) = 6/112 = 0.0536P(D|W) is approx. three times larger than P(D|B)

D

D

W

Victim’s RaceSentence Total

Total

B

326

290

36 30 6

112214

106184