Primitive Data Types and Operations Identifiers, Variables, and Constants Primitive Data Types Byte,...
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Transcript of Primitive Data Types and Operations Identifiers, Variables, and Constants Primitive Data Types Byte,...
Primitive Data Types and Operations
Identifiers, Variables, and ConstantsPrimitive Data Types
Byte, short, int, long, float, double, char, boolean
CastingExpressionsOperators, Precedence, Associativity, Operand Evaluation Order: ++, --, *, /, %, +=, -=, *=, /=, %=, ^, &, |, +, -, Style and Documentation
Identifiers An identifier must start with a letter, an underscore, or a
dollar sign. An identifier cannot contain operators, such as
+, -, and so on. An identifier cannot be a reserved word. (See Appendix
A, “Java Keywords,” for a list of reserved words). An identifier cannot be true, false, ornull.
An identifier can be of any length.
Numerical Data Types
byte 8 bits
short 16 bits
int 32 bits
long 64 bits
float 32 bits
double 64 bits
Number Literals int i = 34;
long l = 1000000;
float f = 100.2f; orfloat f = 100.2F;
double d = 100.2d ordouble d = 100.2D;
Declaring Variablesint x; // Declare x to be an // integer variable;
double radius; // Declare radius to // be a double variable;
char a; // Declare a to be a // character variable;
Assignment Statements
x = 1; // Assign 1 to x;
radius = 1.0; // Assign 1.0 to radius;
a = 'A'; // Assign 'A' to a;
Declaring and Initializingin One Step
int x = 1;
double d = 1.4;
float f = 1.4;
Is this statement correct?
Declaring and Initializingin One Step
int x = 1;
double d = 1.4;
float f = 1.4;
Is this statement correct?
float f = (float)1.4;
Constants
final datatype CONSTANTNAME = VALUE;
final double PI = 3.14159;
final int SIZE = 3;
Operators
+, -, *, /, and %
5/2 yields an integer 2.
5.0/2 yields a double value 2.5
5 % 2 yields 1 (the remainder of the division)
Shortcut Operators
Operator Example Equivalent
+= i+=8 i = i+8
-= f-=8.0 f = f-8.0
*= i*=8 i = i*8
/= i/=8 i = i/8
%= i%=8 i = i%8
Increment andDecrement Operators
x = 1;
y = 1 + x++;
y = 1 + ++x;
y = 1 + x--;
y = 1 + --x;
Using increment and decrement operators makes expressions short, but it also makes them complex and difficult to read. Avoid using these operators in expressions that modify multiple variables, or the same variable for multiple times such as this: int k = ++i + i.
Assignment Expressions and Assignment Statements
Prior to Java 2, all the expressions can be used as statements. Since Java 2, only the following types of expressions can be statements:
variable op= expression; // Where op is +, -, *, /, or %
++variable;
variable++;
--variable;
variable--;
Numeric Type Conversion
Consider the following statements:
byte i = 100;
long k = i*3+4;
double d = i*3.1+l/2;
int x = k; (Wrong)
long k = x;(fine,implicit casting)
Type Casting
doubledouble float long intint short byte
Automaticcasting, type widening
Do narrowing conversion!
Type Casting, cont.
Implicit casting
double d = 3; (type widening)
Explicit casting
int i = (int)3.0; (type narrowing)
float f = 3.12345f;
Type Casting, cont.
What is wrong?
1) int x = 5/2.0;
2) byte b = 50;
b = 2*b;
3) int x = 10;
float f = 2.0*x;
Type Casting, cont.
What is wrong?
1)int x = 5/2.0;-> int x= (int)(5/2.0);
2) byte b = 50;
b = 2*b; -> b = (byte)(2*b);
3) int x = 10;
float f = 2.0*x; ->
-> float f=(float)2.0*x
-> float f=(float)(2.0*x);
Type Casting in expressions If one of operands is long, type of the expression is long.
If one of operands is float, type of the expression is float.
If one of operands is doable, type of the expression is double
byte b = 42; char c = ‘a’;
short s = 1024; int i = 50000;
float f = 5.67f; double d = 0.1234;
double result = (f*b) + (i/c) - (d*s);
(float) (int) (double)
(float) (double)
(double)
Character Data Type
char letter = 'A'; (ASCII)
char numChar = '4'; (ASCII)
char letter = '\u000A'; (Unicode)
char letter = '\u000A'; (Unicode)
Special characters
char tab = ‘\t’;
Unicode Format
Description Escape Sequence Unicode
Backspace \b \u0008
Tab \t \u0009
Linefeed \n \u000a
Carriage return \r \u000d
The boolean Type and Operators
boolean lightsOn = true;
boolean lightsOn = false;
&& (and) (1 < x) && (x < 100) || (or) (lightsOn) || (isDayTime) ! (not) !(isStopped)
The & and | Operators
If x is 1, what is x after this expression?
(1 > x) & ( 1 > x++)
If x is 1, what is x after this expression?
(1 > x) && ( 1 > x++)
How about (1 = x) | (1 > x++)?(1 = x) || (1 > x++)?
Short logical operations
1) Logical operations
if (denom != 0) && (num/denom > 10)
Both operand, left and right ones, will be evaluated.
What is happened if denom is equal to zero
(denom==0)?
2) Short-circuit form of the logical operations
if (denom != 0) &&&& (num/denom > 10)
If the left operand is FALSE, because denom==0,
the total result will be FALSE and the right operand
will not evaluated.
Operator Precedence var++, var— ++var,--var Casting ! *, /, % +, - <, <=, >, >= ==, !=; & ^ | && || =, +=, -=, *=, /=, %=
Operator Associativity
When two operators with the same
precedence are evaluated, the associativity of
the operators determines the order of
evaluation. All binary operators except
assignment operators are left-associative.
a - b + c – d is equivalent to ((a – b) + c) – d
Assignment operators are right-associative.
Therefore, the expression
a = b += c = 5 is equivalent to a = (b += (c =
5))
Operand Evaluation Order
The precedence and associativity rules specify the
order of the operators, but do not specify the order in
which the operands of a binary operator are
evaluated. Operands are evaluated from left to right in
Java.
The left-hand operand of a binary operator is
evaluated before any part of the right-hand operand is
evaluated.
Operand Evaluation Order, cont.
If no operands have side effects that change the value of a variable, the order of operand evaluation is irrelevant. Interesting cases arise when operands do have a side effect. For example, x becomes 1 in the following code, because a is evaluated to 0 before ++a is evaluated to 1.
int a = 0;
int x = a + (++a);
But x becomes 2 in the following code, because ++a is evaluated to 1, then a is evaluated to 1.
int a = 0;
int x = ++a + a;
Programming Style and Documentation
Appropriate Comments Naming Conventions Proper Indentation and Spacing Lines Block Styles
Appropriate Comments
Include a summary at the beginning of the program to
explain what the program does, its key features, its
supporting data structures, and any unique techniques it
uses.
Include your name, class section, instruction, date, and a
brief description at the beginning of the program.
Naming Conventions
Choose meaning and descriptive names.
Variables and method names:
– Use lowercase. If the name consists of
several words, concatenate all in one, use
lowercase for the first word, and capitalize
the first letter of each subsequent word in
the name. For example, the variables
radius and area, and the method
computeArea.
Naming Conventions, cont.
Class names: – Capitalize the first letter of each
word in the name. For example, the class name ComputeArea.
Constants: – Capitalize all letters in constants.
For example, the constant PI.
Proper Indentation and Spacing
Indentation– Indent two spaces.
Spacing – Use blank line to separate segments of the code.
Block Styles
Use next-line style for braces.