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    PRE SPM QUICK REVISION

    CHAPTER 3

    1. Type of substances moving through the

    diff.parts of the plasma membrane.

    a) Phospoholipids bilayer small lipidsoluble molecules, charged ions,

    gases

    Process involved : simple diffusion

    b) Carrier protein large water solublemolecules e.g glucose, amino acids

    Process involved : facilitated diffusion

    c) Carrier protein ions

    Process involved: active transport

    (When explain any process, make sure

    to mention the

    diff. in concentration and end up the

    sentence with

    the process involved)

    (When discuss any process, do not

    write like this : e.g facilitated

    diffusion moves from high

    concentration area to low

    concentration area, but always write ,

    in facilitated diffusion substances

    move from high concentration area to

    low concentration area.)

    2. Metabolic / respiratory poison inhibitsthe production of ATP energy, therefore,

    inhibits active transport. Denaturing of

    protein can cause destruction to the carrier

    and pore protein, therefore, inhibits

    facilitated and active transport.

    3. 30% sucrose solution is hypertonic / Distilledwater is hypotonic towards the cell sap

    (plant cell) / cytoplasma (animal cell)

    4. Hypertonic / hypotonic:- Water moleculesdiffuses out / into the cell sap (plant cell) /

    cytoplasma (animal cell) through the plasma

    membrane by osmosis

    5. Hypertonic:- Plant cell becomes flaccid dueto plasmolysis / animal cell -crenates.

    Hypotonic:- Plant cell becomes turgid /

    animal cell burst (haemolysis)

    6. When you draw flaccid cell, make sure thecell still has two layers (cell wall), the

    vacuole is smaller, the plasma

    membraneis pulled away from the cell

    wall. Turgid cell the vacuole must be

    bigger than normal

    7. Movement of water into root hair cells:-Soil water is hypotonic towards . //

    Excess fertilizers causes soil water to

    become hypertonic towards

    CHAPTER 4

    1. DNA - Structure: Made up oftwopolynucleotides. Double helix.

    Function: Carries / stores all genetic

    information

    RNA Structure: Made up ofone

    polynucleotide. Single chain. Function:

    Carries genetic information on protein

    synthesis

    2. DNA /RNA :- Elements:- Carbon,

    Hydrogen, Oxygen, Phosphorus,Nitrogen. Components:- Phosphate

    group, pentose sugar, nitrogenous

    base. Basic Unit:- Nucleotide

    3.

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    4. Points to remember in explaining theformation ofextracellular enzymes:-

    a) DNA unwinds, exposing the codeson protein synthesis

    b) Protein from the ribosomes move tothe membrane of RER. The

    membrane buds off forming

    transport vesicles which moves

    towards Golgi Apparatus and fuses

    with the membrane of GA.

    c) GA modifies, sorts and packagesthe proteins and the membrane buds

    off forming secretory vescicleswhich moves towards Plasma

    membrane and fuses with the

    membrane to release the enzymes.

    5. Lock and Key Hypothesis:- Whenname of enzyme is given, make sure

    to specify the explanation. E.g If

    Lactase is given.

    a) Lactose binds at the active site ofLactase to form Lactose- lactase

    complex. Hydrolysis occurs which

    breaks lactose into glucose and

    galactose which later live the active

    site living lactase unchanged.

    6. Relating temp. and enzyme

    activity:-

    Any increase towards optimum more heat

    which increases kinetic energy of both

    enzyme and substrate molecules, increases

    the collision so more chances of the

    substrate molecules to come into

    contact with enzymes molecules.

    7. Relating pH and enzyme activity:-

    Changes in pH, changes the charges on

    the active site and surface of substrate.

    Active sites and subtrates must have diff.

    charges. Low pH causes more H+

    attach to the active sites. High pHcauses more OH- attach to the active

    site.

    CHAPTER 5

    1. Cell cycle:- the period from the timea cell is produced until the time the cell

    completes a division

    2. G1:- Proteins and new organellesproduce. S phase:- DNA

    undergoes replication forming identical

    sister chromatids. G2:- More proteins

    and organelles produced

    3. Chromosomal Behaviour

    Metaphase :-Align atequator /metaphaseplate

    Anaphase:-Move toopposite poles

    Mitosis

    Sisterchromatidsalign ..

    Centromeredivides.SisterchromatidsseparateDaughter

    First Class protein Second Classprotein

    Contain allessential a.a

    Does not contain allessential a.a

    Animal protein Plant protein

    Essential A.A Non essential A.A

    Cant besynthesized by bodycells

    Can be synthesized

    Saturated Fats Unsaturated FatsSolid in roomtemp.

    Liquid in roomtemp.

    No double bond

    btwn carbon atom.

    Double bond is

    still presence

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    chromosomesmove.

    Meiosis 1

    Bivalentalignrandomly

    Centromeredoes notdivideBivalentsseparate

    Sisterchromatidsmove .

    Meiosis 11

    Sisterchromatidsalign ..

    Centromeredivides.SisterchromatidsseparateDaughterchromosomesmove.

    4. Points to remember in explainingTissue Culture:

    a) Remove meristematic tissues(explants) from a desirable plant

    b) Place it in sterile cultures medium

    c) Incubate at 37 C for 3 weeks untilcallus is formed

    d) Cut callus into smaller pieces and putevery cut into sterile growth

    hormones to form embryo andlater plantlets

    e) Plantlets taken to soil

    5. Tissue Culture

    Advantage Disadvantage

    Inherit desirable

    characteristics

    Large quantity

    produced in shorter

    time

    No variation

    Having the sameresistance towards

    certain disease-

    shorter life span

    6. Points to remember in explaining

    animal cloning

    a) Somatic cells from desirable animal

    removed

    b) Unfertilised ovum from a donor isremoved and its nucleus is also

    removed

    c) Fusion between the somatic cell andthe ovum without nucleus

    d) The embryo is implanted to thesurrogate mother.

    CHAPTER 6

    1.Balanced diet:- a diet containing all

    the seven

    classes of food in the correct

    proportion

    2. Diet for different groups:-

    Pregnant ladies More protein-fetus

    tissue formation

    More caliums and

    phosphorus bone

    dev. Of fetus

    More folic acid

    and ferum more

    fetus RBC formationInfants and children More calcium and

    phosphorus- teeth

    and bone formation

    More protein

    enhance growthAtheletes More

    carbohydrates

    More protein-

    muscle formationMore sodium - to

    prevent muscle

    cramp

    More vitamins and

    minerals- maintain

    healthy

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    3. Symptoms ofkwashiorkor:-distended stomach due

    to water retention

    4. Explaining digestion, e.g:-

    In the mouth, starch is digested /

    hydrolysed into maltose by maltase in

    the presence of water molecules

    5. Digestion along the alimentary canal.

    Organ Digestion Enzyme

    Mouth Starch into

    maltose

    Salivary

    amylase

    Stomach Protein into

    polypeptide

    Pepsin

    Duodenu

    m

    Polypeptide into

    peptide

    Starch into

    maltose

    Tiny droplets of

    lipids into fatty

    acids and glycerol

    Trypsin

    Pancrea

    tic

    amylase

    Lipase

    Ileum Peptide into

    amino acids

    Maltose into

    glucose

    Sucrose into

    glucose

    Lactose into

    Glucose

    Erepsin

    Maltase

    Sucrase

    Lactase

    6. Bile produced by liver and stored ingall bladder. Is used to emulsify lipids

    into tiny droplets of lipids.

    7. No enzyme produced by duodenum.The enzymes

    in duodenum are produced by

    pancreas

    8. If any enzyme failed to be produced,remember

    that digestion still occurs but at

    slower rate//

    incompletely. So, dont write, no

    digestion takes

    place.

    9. Structural adaptation of ileum

    a) Long and forms folded structure-increase surface area for more

    absorption and digestion

    b) Contains numerous number of villi-increase surface area for amore

    absorption of nutrients

    10. Structural adaptation of villi

    a) Long projection- increase surface area-

    more absorption of nutrients

    b) Have numerous of microvilli ot the

    surface- increase surface area

    c) Wall thin-one cell thick- rapidabsorption of nutrients

    d) Contain (not covered) network ofblood capillaries more transport of

    glucose, a.a, water soluble vit. And

    minerals

    e) Contain a lacteal - transport of lipidsoluble vitamins and fatty acids and

    glycerol

    11. Glucose, a.a, water soluble vitamins andminerals are transported to liver

    through HEPATIC PORTAL VEIN.

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    REMEMBER:- Therefore, this vein

    contains higher concentration of those

    nutrients than other veins.

    12. Fatty acids , glycerol and lipid solublevitamins are transported out from the villi

    by lymphatic vessels to thoracic duct

    and is drained into left subclavian

    vein.

    13. Assimilation in the liver

    Glucose Excess converted by insulin

    into glycogenUsed by the liver cells for

    cellular respiration

    Amino

    acids

    Excess- converted into urea

    (deamination) to be

    transported to kidney for

    excretion.

    Used by liver cells to

    produce new protoplasm

    Synthesis plasma protein

    14. Assimilationin other body cells

    Glucose Excess converted by insulin

    into glycogen and stored in

    muscles

    Used by the cells for cellular

    respirationAmino

    acidsUsed by cells to produce new

    protoplasm

    , repair injured tissues,

    synthesize enzymes and

    hormones and plasma

    membraneLipids Phospholipids used by cells to

    produce plasma membrane

    15. Points to remember rin explainingdigestion in RUMINANTS

    a) Partially chewed food is taken torumen

    b) Cellulose is digested by cellulosewhich is produced by symbiotic

    microorganisms ( WHY SYMBIOTIC

    ????) - The microbes use a part

    of digested food.

    c) Partially digested food enters thereticulum for further digestion

    ( similar to the one in the rumen) and

    cud is formed

    d) The cud is regurgitated into themouth.

    e) The cud is reswallowed and taken tothe omasum where large particles

    of food is broken into smaller parts.

    Water from the food is removed here

    f) The food particles move to theabomasums true stomach .

    (WHY ???? - It contains gastric

    juices like our stomach to digest

    proteins and other substances.)

    g) The digested food then taken to smallintestine to be absorbed

    16. Points to remember rin explainingdigestion in RODENTS

    a) Cellulose is digested in its largecaecum

    b) Soft faeces are produced at nightand are eaten to enable the animal to

    absorb the products of digestion -

    causing the second faeces to

    become harder.

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    17. COMPARING THE DIGESTIVE SYSTEM OFHUMAN, RUMINANTS AND RODENTS

    Similarities

    All the three have stomach where

    digestion of protein occurs

    All the three cannot produce their own

    cellulase

    Human Rumina

    nt

    Rodent

    No.ofstomach

    chambers

    1 4 1

    Cellulase

    producing

    bacteria

    No Presenc

    e

    Presenc

    e

    Place for

    digestion

    of

    cellulose

    None Rumen

    &

    reticulu

    m

    Caecum

    Regurgitat

    ion

    None Occurs None

    Size of

    caecum

    Small Small Large

    18. Nutrient deficiency in plants

    NitrogenChlorosis - synthesized ofchlorophyll is inhibited

    Stunted growthMagnesiu

    m

    Chlorosis

    Phosphor

    us

    Poor growth

    Potassiu Reduce protein synthesis-

    m poor growth

    19. Structural adaptation of a LEAF for

    optimum rate of photosynthesis

    Waxy layer on top

    of epidermal

    tissues

    Prevent higher rate

    of transpiration

    Leaves are

    arranged in an

    arrangement called

    leaf mosaic

    Leaves are spread

    out for optimum

    exposure to sunlight

    Thin lamina Allows rapid

    diffusion of gases

    involved inphotosynthesis

    No chloroplast in

    epidermal tissue

    (transparent)

    Allow penetration of

    maximum sunlight

    Contains vascular

    tissues-xylem and

    phloem

    Transport of water

    and products of

    photosynthesis

    Pallisade

    mesophyll cellsare closely

    packed and

    contain abundant

    of chloroplasts

    Maximum amount

    of light receive

    Spongy

    mesophyll cells

    are loosely

    packed and

    contain abundant

    of chloroplast

    Allow the presence

    of large air space

    for exchange of

    gases to occur

    20. Adaptation of plants in different

    habitats

    Land plants More stomata at the

    lower epidermal

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    tissues- to

    prevent excessive

    lost of water

    Floating plants More stomata on

    the upper

    epidermis

    Aquatic plants Chloroplasts found

    all over the surface

    (therefore, the

    whole leaves and

    stem is green) as

    low intensity of light

    in water

    Desert plant Very few stomata

    and some are

    sunken stomata-

    embedded in the

    leaves to reduce

    water lost

    Chloroplasts found

    mostly on stems

    21. Points to remember in explaining

    light reaction

    a) Occurs in Grana

    b) Chlorophyll captures light energywhich excites the electron in the

    chlorophyll to leave the chlorophyll

    c) Light energy splits water moleculesinto H+ and OH- (photolysis)

    d) H+ receive electron to form H atoms

    e) OH- releases electron to form hydroxyl

    group

    f) Hydroxyl group binds with otherhydroxyl group to form water

    molecules and oxygen

    22. Points to remember in explaining

    dark reaction

    a) Occurs in stroma

    b) Hydrogen atom binds with carbondioxide to form glucose (reduction)

    23. Comparing light and dark reaction

    Light reaction Dark reaction

    Grana Stroma

    Requires light

    energy, waterRequires carbon

    dioxide

    Does not requirelight energy

    Produces water and

    oxygen

    Produces glucose

    and water

    Forms hydrogen

    atoms

    Uses hydrogen

    atoms

    Occurs only in the

    presence on light

    Occurs with and

    without light

    24. How Greenhouse aids in ensuring cropproduction takes place throughout the

    year

    Controlling Carbon

    dioxide

    concentration

    Burning paraffin

    to ensure

    continuous supply

    of CO2

    Light intensity The use of glass

    allows penetration

    of light. When light

    intensity is low- use

    artificial

    lighting.When light

    intensity is too high

    - use shades or

    light reflector

    Temperature Always warm inside

    as heat cant

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    escape through the

    glass. If too hot,

    use heat regulator,

    shades and

    ventilation

    Water Automatic sprinkler

    25. REMEMBER: In highly industrial areas,photosynthesis might be affected due to

    dust and smoke covering the stomata ,

    hence inhibits diffusion of carbon

    dioxide.

    26. The importance of photosynthesis is toensure continuous existence of life

    on earth as photosynthesis supplies

    oxygen to living organisms

    27. Food preservation

    Drying Food placed under

    hot sun water in

    the food

    evaporated food

    dehydrated- inhibitgrowth of microbes

    Pickling sugar and

    salt solution

    Vinegar

    The solution is

    hypertonic

    towards , water

    diffuses out by

    osmosis. Food

    dehydrated- inhibit

    growth of microbes

    Vinegar- acid

    medium not

    suitable formicrobes to live

    Pasteurisation Milk is heated:-63 C

    for 30 minutes//

    72 C for 15

    seconds followed

    by rapid cooling

    Fermentation Use yeast which

    produces ethanol

    inhibit the

    activity of

    microbes

    CHAPTER 7

    1. Aerobic and Anaerobic respiration

    Aerobic Anaerobic

    Definati

    on

    Oxidation

    of glucose

    completely

    Breakdown of

    glucose

    incompletely

    Substrat

    es

    Glucose &

    oxygen

    Glucose

    Product

    s

    Carbon

    dioxide,

    water, 38

    ATP

    Human:-

    Lactic acid, 2

    ATP

    Yeast:-

    Ethanol, CO2

    Sites Mitochondri

    a

    Cytoplasma

    2. Respiratory surface of different

    organisms

    Human Alveli

    Frogs Lungs, Skin

    Fish Lamella

    Insect Tracheol

    Ameoba Plasma membrane

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    3. General Adaptation of Respiratory

    surface

    Moist surface Allow oxygen to

    dissolve before

    diffusion occurs

    Thin wall Allow rapid

    diffusion of gases

    Numerous in

    number- alveoli,

    tracheal and lamella

    Large surface area

    for more exchange

    of gases to occur

    Alveoli and frog

    lungs covered

    with network of

    blood capillaries

    Gills contain

    numerous bloodcapillaries

    Allow more

    transport of gases

    4. REMEMBER:- Tracheols are embeddedin body

    tissues. Therefore, no transport of

    gases required

    5. NOTE:- Frog lungs : Unlike human

    lungs , there is

    no alveolus. Exchange of gases

    occurs through the wall of the lungs.

    Therefore, the wall is moist, thin and

    covered with blood capillaries

    6. COUNTERCURRENT EXCHANGE :- toallow efficiency of the gases exchange at

    the respiratory surface of fish. The

    mechanism MAXIMIZES THE OXYGEN

    TRANSFER BECAUSE AS WATER

    FLOWS OVER THE GILLS IN ONE

    DIRECTION, THE BLOOD FLOWS IN

    THE OPPOSITE DIRECTION.

    7. Oxygen is transported to body tissues bybinding with haemoglobin in RBC to

    form oxyhaemoglobin.

    8. Carbon dioxide is transported in three

    ways:-

    a) In a form ofcarbonic acid bydissolving in blood plasma.

    b) In a form ofcarbaminohaemoglobinby binding with haemoglobin

    c) In a form ofbicarbonate ions

    9. J-tube experiment:-

    a) The tube is immersed in potassiumhydroxidefirst as the solution only

    absorb carbon dioxide.

    b) Later the tube is immersed inpotassium pyrogallate solution to

    absorb oxygen

    c) Do not immerse the tube inpotassium pyrogallate first, as it

    can absorb both carbon dioxide

    and oxygen. Therefore, unable to

    determine the concentration of both

    gases.

    10. Points to remember in explaining

    regulatory mechanism of blood pH

    a) During vigorous exercise, moreCO2 produced,

    thus blood pH becomes lower

    than normal

    b) Detected by peripheralchemoreceptor ( at the

    carotid arteries and arch of aorta)

    and central

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    chemoreceptor ( at the medulla

    oblongata)

    c) Receptors generate impulses whichare sent to

    the breathing center at the

    medulla oblongata

    d) Breathing centre interprate theinformation

    and produces appropriate

    responses

    e) Impulses are then sent torespiratory

    muscles(intercostals and diaphragm

    muscles)

    and cardiac muscles.

    f) Increase the contraction of thethree muscles

    g) Increase breathing , ventilation

    and heart beat

    rate

    h) Remove excess carbon dioxide,return the

    blood pH to normal

    11. Points to remember in explaining the

    intake of oxygen by plants for

    respiration

    a) When stomata opens, oxygen

    diffuses in and dissolves in water

    found in the air spaces

    b) As oxygen in the air space is higher in

    concentration than in the cells,

    oxygen diffuses into the cells,

    12. COMPENSATION POINT: The rate ofcarbon dioxide production is equal to the

    rate of carbon dioxide consumption. The

    rate ofphotosynthesis is equal to the

    rate ofrespiration.

    13. REMEMBER:- For plants to grow, therate of photosynthesis must always

    be HIGHER than the rate of

    respiration as excess sugar can be

    used for growth and other important

    living processes.

    CHAPTER 8.

    1. Problems faced by mangrove plants

    a) Muddy soft soil (water loggedcondition) easy to collapse

    b) Exposed to strong winds easy to

    collapse

    c) Exposed to high intensities of sunlight

    higher

    rate of transpiration

    d) Surrounded by sea water high

    concentration of

    salt

    2. Structural adaptation of mangrove plants

    and therefore no other plants can grow in

    mangrove swamp

    a) Long cable root provide

    support

    b) Aerial roots (pneumatophores)-allowing gases exchange during low

    tide

    c) Small leaves with sunken

    stomata reduce transpiration

    d) Hydathodes (pores on thelower epidermis) remove excess salt

    e) Cell sap of the root hair cell is

    always hypertonic towards

    surrounding water

    f) Viviparous seeds germinate

    while still attaching to the mother

    plants increase the chances of

    survival

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    3. REMEMBER THE DIFFERENT TYPES OFROOT BELONG TO DIFFERENT

    MANGROVE SPESIES.

    4. REMEMBER THE ZONING AND BE ABLETO IDENTIFY THE ZONE IN WHICHDIFFERENT MANGROVE SPESIES

    BELONG TO

    5. Point to remember in explainingcolonization and succession in a

    mangrove swamp

    a) The physical changes that cause

    succession to occur are:-

    i) Soil becomes more compactand

    firmer , and the river bankbecomes higher due to

    accumulation ofsilt and mud which

    are trapped by the root of the

    mangrove plants

    ii) The shore extends further to

    the sea as more sediments

    deposited

    6. Point to remember in explaining

    colonization and succession in an

    abandoned pond

    a) The physical changes that cause

    succession to occur are:-

    i) The pond becomes shallower

    due to :-

    - soil erosion form the

    sides of the pond

    - The decomposition of

    dead plants

    which forms organic

    matters. The

    organic matters settled at

    the bottomof the pond.

    7. REMEMBER ALL THE THREEFORMULAE IN DETERMINING A

    POPULATION USING QUADRAT

    SAMPLING

    8. REMEMBER ALL THE FORMULA INDETERMINING A POPULATION USING

    THE TECHNIQUE CAPTURE, MARK,

    RELEASE, RECAPTURE.

    9. Why Nitrogen cycyle is important ???

    Plants cannot absorbed atmospheric

    nitrogen directly. But they need nitrogen

    to synthesize protein. Therefore,

    nitrogen need to be converted in a

    form of ammonium, nitrites or

    nitrates as onlythese three can be

    absorbed by plants

    10. Nitrogen Cycle

    a) Nitrogen fixation:-

    - Lightning

    - Nitrogen fixing bacteria

    - Rhizobium sp. living in the root nodules ofleguminous plants . It fixes atmospheric

    nitrogen into ammonium

    -Nostoc sp. live freely in soil fixesatmospheric nitrogen into ammonium

    b) Decomposition

    Dead plants and animals are

    decomposed by microorganisms to

    form ammonium compound

    c) Nitrification

    - Oxidation of ammoniumcompound into nitrites by

    Nitrosomans sp.

    - Oxidation of nitrites into nitrates by Nitrobacter sp.

    d) Denitrification

    Denitrifying bacteria breaks down

    nitrates into gases nitrogen

    11. WHAT IS THE EFFECT OF DESTROYINGANY OF THE MICROBES INVOLVED IN

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    NITROGEN CYCLE ON THE GROWTH

    OF HERBIVORES ?????

    a) If nitrogen fixing bacteria ordecomposer is killed no ammonium

    can be produced, therefore, no nitrites,

    no nitrates to be absorbed by plants.REMEMBER, NITRATES IS

    ABSORBED TO OBTAIN NITROGEN

    TO SYNTHESIZE PROTEINS IN

    PLANTS. IF PLANTS ARE LACKING

    OF PROTEINS, LESS PROTEIN

    TRANSFERRED TO HERBIVORS-

    LESS PROTEIN FOR THE

    HERBIVORES TO GROW.

    12.